AC Circuit Containing R and C Numerical Class-12 Nootan ISC Physics Solution

AC Circuit Containing R and C Numerical Class-12 Nootan ISC Physics Solution Ch-12 Alternating Current. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail  information about ISC Board Class-12 Physics.

AC Circuit Containing R and C Numerical Class-12 Nootan ISC Physics Solution

AC Circuit Containing R and C Numerical Class-12 Nootan ISC Physics Solution Ch-12 Alternating Current

Board ISC
Class 12
Subject Physics
Book Nootan
Chapter-12 Alternating Current
Topics Numericals on AC Circuit Containing R and C
Academic Session 2025-2026

Numericals on AC Circuit Containing R and C

Class-12 Nootan ISC Physics Solution Ch-12 Alternating Current.

Que-28: In the given AC circuit, find out the potential difference across the (i) resistor, (ii) capacitor.

In the given AC circuit, find out the potential difference across the (i) resistor, (ii) capacitor.

Ans-
In the given AC circuit, find out the potential difference across the (i) resistor, (ii) capacitor.

Que-29: A 5 V AC source is connected to a C-R circuit. The PD across C is 3 V. Find the PD across R.

Ans- V = √(Vc² + VR²)

=> 5 = √(3² + VR²)

=> VR² = 4 volt

Que-30: Find the impedance of the given circuit for

Find the impedance of the given circuit for

(i) direct current, (ii) alternating current of frequency (10 / pi) kHz.

Ans- (i) XC = 1/2πfC

for direct current f = 0

=> XC = ∞

∴ Z = ∞

again for AC

XC = 1/2πfC = 1/2π x 10/π x 10³ x 2 x 10^-6 = 25 Ω

∴ Z = √(Xc² + R²)

=> √(25² + 20²) = 32 Ω

Que-31: A capacitor in series with a resistance of 30 Ω is connected to AC mains. The reactance of the capacitor is 40 Ω. Calculate the phase difference between the current and the supply voltage.

Ans- tan φ = XC/R = 40/30

=> φ = tan^-1 (4/3)

Que-32: An alternating emf of 100 V-50 Hz is applied across a 10 µF capacitor and 100 Ω resistor in series. Calculate the reactance of the capacitor, the current flowing and the average power supplied.

Ans-
An alternating emf of 100 V-50 Hz is applied across a 10 µF capacitor and 100 Ω resistor in series. Calculate the reactance of the capacitor, the current flowing and the average power supplied.

Que-33: A 50 W-100 V lamp is to be used at 200 V-50 Hz electric mains. Find the capacitance required to be connected in series with the lamp.

Ans- i = 50/100 = 0.5 A

VC= √(V² – VR²)

=> √(200² – (100)²) = 100√3

XC = VC/i = 100√3/0.5 = 200√3 Ω

XC = 1/2πfC

=> C = 1/XC.2πf

=> 1/(200√3 x 2 x 3.14 x 50) = 9.2 μF

— : End of AC Circuit Containing R and C Numerical Class-12 Nootan ISC Physics Solution Ch-12. :–

Return to : –  Nootan Solutions for ISC Class-12 Physics

Thanks

Please share with your friends

Leave a Comment

This site uses Akismet to reduce spam. Learn how your comment data is processed.

error: Content is protected !!