ISC English Language 2019 Class-12 Previous Year Question Papers Solved for practice. Step by step Solutions with Questions. By the practice of English Language 2019 Class-12 Solved Previous Year Question Paper you can get the idea of solving. Try Also other year except ISC English Language 2019 Class-12 Solved Question Paper of Previous Year for more practice. Because […]

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]]>**ISC English Language 2019 Class-12** Previous Year Question Papers Solved for practice. Step by step Solutions with Questions. By the practice of** English Language 2019 Class-12** Solved Previous Year Question Paper you can get the idea of solving.

Try Also other year except **ISC English Language 2019** **Class-12 **Solved Question Paper of Previous Year for more practice. Because only **ISC English Language 2019 Class-12** is not enough for complete preparation of next council exam. Visit official website **CISCE **for detail information about **ISC Class-12 English Language**.

-: Select Your Topics :-

**Maximum Marks: 100**

**Time allowed: Three hours**

(Candidates are allowed additional 15 minutes for only reading the paper. They must NOT start writing during this time.)

Attempt all four questions.

The intended marks for questions or parts of questions are given in brackets [ ].

(You are advised to spend not more than 50. minutes on Question 1, 40 minutes on Question 2, 30 minutes on Question 3 and 1 hour on Question 4.)

(You should begin each answer on a fresh page.)

Write a composition (in approximately 450-500 words) on any one of the following subjects : (25)

(You are reminded that you will be rewarded for orderly and coherent presentation of material, use of appropriate style and general accuracy of spelling, punctuation and grammar.)

(a) You have gone on a trekking expedition with a group of friends. As night closed in, you realised that you were separated from the group. Describe your initial feelings and the place where you got lost. How did you spend the night alone before you were reunited with your group?

(b) It is easy to advice others not to worry, but difficult for oneself to follow the same. Narrate an experience which made you realise the truth of this statement.

(c) ‘The best things in life come free’. Write for or against the statement.

(d) Photographs

(e) In order to be successful, one should rely on oneself and not expect others to help. Express your views on the given statement.

(f) Write an original short story beginning with the following words :

She was delighted to find the sealed envelope lying on her table. As she reached for it ……………………

**(a) A Trekking Expedition**

A trekking expedition is always interesting and thrilling. We a group of friends decided to go on trekking in Manali during the winter season. I was highly excited. I thought we would have tun all the way. So I took keen interest in making preparations.

Some of my friends had already had trekking experiences. They sounded less enthused than others in the group, including myself. When they cautioned us about the difficulties on the way I just pooh-poohed what they said

We decided to walk all the day to reach Manhar, a small sleepy village where the uncle of one of our friends lived. He said that we would stay at his place for the night, and then resume our journey back to Manali the next day. Throughout the day long journey we all enjoyed a lot. Though after some hours of trekking in the valley on zig-zag, rough paths we felt tired. We saw in thedistance a black bear, but it disappeared in no time.

In my enthusiasm I opted to take a short-route. No one accompanied me. I went on and on, all alone. After an hour, the sun suddenly disappeared, and black clouds came threateningly over me.

There was no one visible. Only a mixture of animal sounds struck my ears. I realized that I had got lost I tried to look for some hut to take shelter. In no time the rain started. I was full of fear. It was becoming difficult to find the way. I slipped once or twice. A sudden roar of some animal—maybe a tiger—gave me shivers of fright. Thankfully, no animal came on my way.

Suddenly my eyes fell on a deserted hut on a mound. I rushed, almost running, to the place. I was surprised that there was no one in the hut. But to my good luck, a cot and a blanket were there. There were a few packets of eatables I ate some and lay down on the cot after having secured the door.

I would never forget this trekking expedition. It taught me not to be over zealous at any time in life.

**(b) Easy to Advise Others**

I often get panicky near all kinds of tests and interviews. Though I prepare myself well for any such ordeal, I cann’t help worrying. My mind is full of all sorts of apprehensions. I ask myself what would happen if I fail. But once I face the test or interview I am full of energy and enthusiasm.

My elder sister used to advise me to give up worrying. She repeatedly made fun of me for worrying uselessly. She posed herself as a calm and focused person who could never have any worry in life. My parents praised her for this quality of hers. I would envy her. But now I know the truth. She is not a worry-less person.

About a year ago she was finding a job after doing her B. Tech. She was quite confident in the beginning. But somehow she failed to find a decent job of her liking. She kept her poise for sometime. Dark circles began to appear under her eyes. Whenever Father or Mother would enquire if she had any problem, her answer would be, “What do you say ? What problem? I have no worry at all.” No one was convinced with her reply, but no one dared to challenge her. I decided to keep a watch on her.

I could not find anything abnormal with her for quite some time. One day my sister attended an interview with no positive result. When she came back home she was as usual smiling. She said she was still hopeful, adding she disliked those who worry unnecessarily, as she looked at me with a glint of mischief in her eyes. I was peeved, and became all the more determined to find out the reality about her.

That very night, through the open window of her study, I found her before her table, lying her head down, sobbing and then screaming. I did not disturb her. The next day, when she was out, I crept in her room. I found a paper on her table, with some lines scribbled over and over again—’I am a failure. I am a failure….’ Undoubtedly, she was worrying too much. Then I realised the truth that it is easy to advise others not to worry, but difficult for oneself to follow the same.

**(c) The Best things in Life Come Free**

It is strange but true that the best things in life come free. What are those ‘best’ things ? Not cars, bungalows, money, gadgets or comforts. One has to pay dearly for all these things, but these are not the best things as they are not perennial. They do not provide happiness. Nor do they provide us contentment. Rather these things make us more and more unhappy, greedy and dishonest

The best things in life are health, happiness and contentment, and all the elements of nature— air, water, rain or sunshine. These things cannot be sold or bought. They are acquired, inborn or enjoyed freely. Let us take health, first of all. It is strange that most of the rich people are unhealthy. They spend a lot of money.

They go to gyms, consult doctors and health- instructors, but in vain. It is simple because they are devoid of those things which matter in life the most-internal happiness and contentment. Most of them remain stressed, and stress becomes the cause of several ailments. It is, however, equally true that many poor persons also remain unhealthy because of their greed and dissatisfaction in life.

Happiness and contentment are inter-dependent. Those who are contented are almost always happy. Both these things can be had free of cost.

No money is needed for them If you have faith in yourself if you are well-adjusted in life if you are free from common vices, you are sure to be happy and contented. And if you are truly happy and contented, you are physically and mentally healthy.

If one enjoys air and sunshine which come free and freely to us, one is bound to be healthy. A regular walk in the morning and in the evening is enough to keep one health}. God has given us many things free of cost. Fresh air in the morning is health-giving, and so is sunshine. Those who confine themselves in narrow, AC chambers and do not enjoy the bounties of nature can never remain healthy for long.

Therefore, it is truly said that the best things in life are free.

**(d) Photographs**

Photographs are significant as they revive old memories and remind us of persons long forgotten. They are also used for identification purpose on official documents. In fact, they serve many purposes. A family album of photographs is a useful heirloom. With the use of digital cameras photographs are saved and stored. The new generation likes these kinds of photographs which are easy to take and save. The men belonging to the old generations still prefer old kind of photo albums to on-line albums.

The process of taking photographs with a camera is known as photography. A person who takes up photography as a hobby is called amateur photographer whereas one w ho practises it as a profession is called a professional photographer. Professional photographers fall into different categories — news photographers, fashion photographers, portrait photographers,’ landscape photographers and event photographers

Photography as a hobby is quite exciting and useful. Those who are fond of travelling can become good photographers. Photographs of various objects and scenes of nature are always captivating. Photographs of birds and animals in their natural habitats are interesting as well as instructive.

From these photographs we learn a lot about the behaviour and life styles of various animals and birds. Shooting animals with a camera has become quite an interesting and profitable activity for some animal lovers. With the help of zoom lenses cameras can capture animals and birds from a great distance.

Family photographs are always thrilling. Adults looking at their childhood photographs get a rare pleasure. They go back in memory lanes and remember what they have forgotten. Dead ancestors come alive through family photographs

Scientific and technological advancements have come as a boon in photography. Now we have digital cameras, video cameras, movie cameras, etc. Our mobile phones are fitted with quality cameras. Within minutes, a picture can be taken and transmitted across the globe. Photographs of various kinds, as such, continue to excite us. They provide unexpected surprises at times. They can also become a good source of income.

**(e) Self-help**

It is truly said that even God helps those who help themselves. It is only self-help that guarantees success. If you continue to sit idle and wait for someone to come and help you, you are greatly mistaken. No one likes to help those who do not rely on their own resources. Success comes to those who are confident of themselves.

They may be poor or weak, but they know that only their own efforts can enable them to overcome all difficulties and obstacles on the way to glory and success. Therefore, they do not sit idle. Rather they work hard and achieve success. Someone has rightly said that if you go to a person for help, he may strike a bargain with you to his own advantage.

Take a look at history All great worriors and heroes fought their own battles. Lord Krishna could have defeated the Kauravas single-handedly, but he let the Pandavas fight their own battles.The Pandavas too sought his blessings and inspiration and put in their sincere efforts and won the war. Good general lead their soldiers from the front and do not expect their soldiers to win wars for them.

Self-help is the best in whatever field you are. When you start putting your efforts and do your best, others do watch you and come to your help unexpectedly. But if you do nothing, you are ignored even by your best well-wishers. They feel that you do not deserve any help. Those who leave everything to God or Fate, they, too, are in for a shock. They may continue to chant God’s name thousands of times, God remains aloof and unhelpful.

Therefore, one must depend on oneself to achieve anything in life. Help from others should not be expected or waited for.

(f) She was delighted to find the sealed envelope lying on her table. As she reached for it, something unexpected happened all of a sudden. A small monkey entered her room from the open window behind her study table, caught hold of the envelope and ran out from the window in no time.

She screamed loudly and called her father who was still at home. Father came in and enquired what had happened.

Amonkey…a monkey’, she murmured.

‘What monkey ?’ Father asked her confusedly.

Papa… a monky has taken my envelope having my certificates. Do something, please. I can see him on a tree in our garden’.

Father ran out, followed by Seema. They saw the monkey, sitting on a branch, trying to figure out what the envelope was and what it had. With a stick, Father tried to frighten the monkey. The monkey a mischievous rascal, giggled as it jumped to another branch, holding the envelope carefully as if it were a prize possession.

Ramu, our servant, came out with a more practical solution. He picked up some stones and threw them up aiming at the monkey. The Monkey remained adament and seemed to laugh down at us from his perch.

Then suddenly a crow flew over the monkey, and in fright the monkey’s hold on the envelope loosened and it fell down with a thud.

Seema rushed forward and caught hold of the envelope. Father went to his room. Seema opened the envelope, and was amused to find a few forms in it, sent to some Rakesh to be filled in for some job.

**(a)** You are Nitin/Nita from XYZ School. You wish to start applying to various colleges for admission after your ISC examination. In about 300 words, draft your personal profile using the guidelines given below : (20)

Your name, years spent in the school you are passing out from — academic interests and performance — cultural activities you participated in — sports — positions of leadership held during your stay in the school — your future plans and goals — two characteristics that you consider to be your strengths — two characteristics that set you apart from the others.

**(b)** As a member of the Student Council of your school, you wish to start an old clothes collection drive. These clothes are to be donated to an orphanage nearby. Write a proposal in not more than 150 words, stating the steps you would take to make it a

success.

**(a) Personal Profile**

1. Name : Nitin

2. Father’s Name : B K Aggarwal

3. Address : 25, Raju Park, New Delhi

4. Education : Studied in St. Joseph’s school, Allhabad Passed ISC exam seeming 95% marks, 2018

5. Academic Interests : Reading journals on Computer Science Interest in Artificial Intelligence

6. Cultural Activities : Participated in debates at the Inter School Level Won many First Prizes

7. Sports : Interest in playing cricket and Hocky

8. Position of Leadership : was Head Boy for 1 year at the school

9. Future Plans . want to do MS in Computer Science (Artificial Intelligence) desire to work in an MNC in the USA

10. Personality : hard work and sincerity in whatever I do innovative mind, applying theories to day-to-day life.

**(b) Proposal Heading Objectives**

- Proposal to start an old clothes collection drive
- the orphanage near our school needs clothing badly
- woollen clothes and blankets to be provided urgent
- a system to be developed to cater to all kinds of needs of the inmates of the orphanage
- the old clothes collection drive to be focused on the students of our school

List of Measures : students of senior classes o be requested to donae clothes liberally

- a parents’ meeting to be arranged to apprise then of the drive and to make a request for help.
- the morning assembly to be used for exhorting the students to donate and collect as many clothes sweaters, jackets. blankets. etc — as possible
- the Principal and the staff to be involved in the drive actively.

Conclusion :

- The humanitarian task to be undertaken by the student Council. will have a sobering influence and a novel experience for the students.

*— Amit*

*Member. Student Council*

*St. Joseph School. Allahabad*

Answer sections (a), (A) and (c).

(a) In each of the following items, sentence A is complete, while sentence B is not. Complete sentence B, making it as similar as possible to sentence A. Write sentence B in each case. (10)

Example:

(O)

(A) : All nooks and corners were checked.

(B) : No ……………………………………

Answer:

(O) No nook or corner was left unchecked.

(1)

(A) : He is so old that he cannot remember events of the past.

(B) : He is too ……………………………………

(2)

(A) : As soon as the bell rings, the children run out (o pIa,

(B) : No sooner ……………………………………

(3)

(A) : No other planet is as big as Jupiter.

(B) : Jupiter ……………………………………

(4)

(A) : He is forgetful as well as careless with his work.

(B) : Besides ……………………………………

(5)

(A) : It is probable that (lie ‘hip will reach the shore.

(B) : In all ……………………………………

(6)

(A) : She said that she would return the book to the library the next da’.

(B) : She said, ……………………………………

(7)

(A) : Only trained graduates need to apply for the post.

(B) : None ……………………………………

(8)

(A) : His attitude towards his parents has always puzzled flic.

(B) : I have ……………………………………

(9)

(A) : He loved his little daughter, but he was in mortal fear of her fierce temper.

(B) : All though ……………………………………

(10)

(A) : When she heard the news of her daughter’s result, she ‘.‘.as very happy.

(B) : On ……………………………………

(b) Fill in each blank with a suitable word. (Do not write the sentence.) (5)

(1) She turned …………………………………… the offer to work at the factory.

(2) To everyone’s surprise, he turned …………………………………… at the party.

(3) He broke …………………………………… in the middle of his speech at the function.

(4) The burglars broke …………………………………… the house when the family was away.

(5) He agreed to carry …………………………………… the manager’s orders.

(6) Sita’s daughter carried …………………………………… the family business when Sita went abroad.

(7) He ran …………………………………… from home at the age of ten.

(8) I ran …………………………………… my old friend in the market place.

(9) Her aunt looks …………………………………… her aging grandparents.

(10) The Principal looks/matters of complaint from teachers and students.

(c) Fill in the blanks in the passage given below with the appropriate form of the verb given in brackets. Do not write the passage, but write the verbs in the correct order. (5)

One day I …………………………………… (1) (be) in the lunch line, and there I saw a pile of apples. The teacher-in-charge …………………………………… (2) (stare) at me and said, ‘”Just …………………………………… (3) (take) one. God …………………………………… (4) (watch)”. So, I …………………………………… (5) (take) an apple, and the tine …………………………………… (6) (move) along. At the next table there …………………………………… (7) (be) a pile of chocolate chip cookies. I …………………………………… (8) (not know) what to do. “Psst,” the kid behind me …………………………………… (9) (whisper). …………………………………… (10) (take) all you want. God’s watching the apple.”

**(a)**

(1) He is too old to remember events of the past.

(2) No sooner does the bell ring than the children run out to play.

(3) Jupiter is the biggest planet.

(4) Besides being forgetíùl he is careless with his work.

(5) In all probability’ the ship will reach the shore.

(6) She said, “I will return the book to the library tomorrow.”

(7) None but the trained graduates need to apply for the pos

(8) 1 bave always been puzzled by his attitude towards his parents.

(9) Although he loved his little daughter, he was in mortal fear of her fierce temper.

(10) On heating the news of her daugher s result. she was very happy.

**(b)**

(1) down (2) up (3) down (4) into (5) out (6) on (7) away (8) across (9) aller (10) into

**(c)**

(1) was (2) stared (3) take (4) is watching (5) took (6) moved (7) was (8) did not know (9) whispered (10) Take

Read the passage given below and answer the questions (a), (b) and (c) that follow :

**(1)** At the Literary Society’s meeting, Isola read out the letters written to her Granny Pheen, when she was but a little girl. They were from a very kind man — a complete stranger. Isola told us how these letters came to be written.

**(2)** When Granny Pheen was nine years old, her cat died. Heartbroken, sitting in the middle of the road, she was sobbing her heart out.

**(3)** A carriage, driving far too fast, came within a whisker of running her down. A very big man in a dark coat with a fur collar, jumped out. leaned over Pheen and asked if he could help her. Granny Pheen said she was beyond help. Muffin, her cat, was dead.

**(4)** The man said, ‘Of course, Muffin’s not dead. You do know cats have nine lives, don’t you?’ When Pheen said yes, the man said, ‘Well, I happen to know your Muffin was only on her third life, so she has six lives left.’ Pheen asked how he knew. He said he always knew — cats would often appear in his mind and chat with him. Well, not in words, of course, but in pictures.

**(5)** He sat down on the road beside her and told her to keep still — very still. He would see if Muffin wanted to visit him. They sat in silence for several minutes, when suddenly the man grabbed Pheen’s hand.

**(6)** ‘Ah—yes! There she is ! She’s being bom this minute! In a mansion — in France. There’s a little boy petting her, he’s going to call her Solange. This Solange has great spirit, great verve — I can tell already ! She is going to have a long, venturesome life’.

**(7)** Granny Pheen was so rapt by Muffin’s new fate that she stopped ciying. The man said he would visit Solange every so often and find out how she was faring.

**(8) **He asked for Granny Pheen’s name and the name of the farm where she lived, got back into the carriage, and left.

**(9)** Absurd as all this sounds. Granny Pheen did receive eight long letters, Isola then read them out. They were all about Muffin’s life as the French cat — Solange. She was, apparently, something of a feline musketeer. She was no idle cat, lolling about on cushions, lapping up cream — she lived through one wild adventure after another — the only cat ever to be awarded the red rosette of the Legion of Honour.

**(10)** What a story this man had made up for Pheen — lively, witty, full of drama and suspense. We were enchanted, speechless at the reading. When it was over (and much applauded), I asked Isola if I could see the letters, and she handed them to me.

The writer had signed his letters with a grand flourish .

Very Truly Yours,

xyz

It was highly possible that Isola had inherited eight letters written by Oscar Wilde, for who else could have had such a preposterous name as Oscar Fingal O’Flahertie Willis wilde.

*Adapted from The Guernsey Literary & Potato Peel Pie Society —*

*By Mary Ann Shaffer & Annie Barrows*

**(a)**

(i) Given below are four words and phrases. Find the words which have a similar meaning in the passage : (4)

(1) adventurous

(2) cat-like

(3) appreciated

(4) received something on someone’s death

(ii) For each of the words given below, write a sentence of at least ten words using the same word unchanged in form, but with a different meaning from that which it carries in the passage : (4)

(1) kind (line 2)

(2) mind (line 13)

(3) still (line 15)

(4) sounds (line 26)

**(b)** Answer the following questions in your own words as briefly as possible :

(i) Where did Isola get the letters from to read at the Literary Society’s meeting? [2]

(ii) Who consoled Granny Pheen when she was heart-broken? What did he say about Muffin’s lives? [2]

(iii) What did the man say when Granny Pheen asked him how he knew about cats’ lives? [2]

(iv) According to the man, what was Muffin’s new fate ? [3]

**(c)** In not more than 100 words, summarise why the eight letters were a treasure to Granny Pheen. (Paragraphs 2 to 10). Failure to keep within the world limit will be penalised. You will be required to write the summary in the form of a connected passage in about 100 words. [8]

(i)

(1) venturesome

(2) feline

(3) applauded

(4) inherited

(ii)

(1) Kind : I am not that kind of girl who can be easily flattered.

(2) mind : Would you mind my smoking in your room for a while?

(3) still: I am sorry but there is still more bad new s for y ou.

(4) sounds : Try to be familiar with different sounds and smells of the forest.

(b)

(i) Isola got the letters from her Granny written to her by a stranger (in reality; Oscer Wilde) when she was but a small girl.

(ii) The stranger consoled Granny Pheen when she was heart-broken. He said that Muffin was not really dead, as a cat had nine lives, he added, she was on her third life.

(iii) he told Granny Pheen that he knew about cat’s lives as cats would often appear in his mind and chat with him.

(iv) According to the man, Muffin was being bom that minute in a mansion in France.

(c) Summary

When Granny Pheen was nine, her cat died. She was heart-broken. A man came and consoled her saying that her cat was not really dead. As a cat had nine lives, her cat was on her third life. She was actually being bom in amansion in France.

The man said that he knew aboutit as cats often appeared in his mind and chat with him. GrannyPheen stopped crying. The man went away and wrote her long letters aboutthe new life of her cat,, named Solange. Solange had been honored for her various adventures. These letters were read by her niece Isola at the Literary Society’s meeting.

-: End of **ISC English Language 2019 Class-12** Solved Previous Year Question Paper :-

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]]>ISC Physics 2019 Class-12 Solved Previous Year Question Paper for practice. Step by step Solutions with section-A, B, C and D. Visit official website CISCE for detail information about ISC Class-12 Physics. By the practice of ISC Physics 2019 Class-12 Solved Previous Year Question Paper you can get the idea of solving. Try Also other year except ISC […]

The post ISC Physics 2019 Class-12 Solved Previous Year Question Paper appeared first on ICSEHELP.

]]>**ISC Physics 2019 Class-12** Solved Previous Year Question Paper for practice. Step by step Solutions with section-A, B, C and D. Visit official website **CISCE **for detail information about **ISC Class-12 Physics**.

By the practice of** ISC Physics 2019 Class-12** Solved Previous Year Question Paper you can get the idea of solving. Try Also other year except **ISC Physics 2019** **Class-12 **Solved Question Paper of Previous Year for more practice. Because only **ISC Physics 2019 Class-12** is not enough for complete preparation of next council exam.

**-: Select Your Topics :-**

Maximum Marks: 70

Time allowed: Three hours

- Candidates are allowed additional 15 minutes for only reading the paper. They must NOT start writing during this time.

All questions are compulsory. - This question paper is divided into 4 Sections, A, B, C and D as follows :
- Section A: Question number 1 is of twelve marks. All parts of this question are compulsory.
- Section B: Question numbers 2 to 12 carry 2 marks each with two questions having internal choice.
- Section C: Question numbers 13 to 19 carry 3 marks each with two questions having internal choice.
- Section D: Question numbers 20 to 22 are long-answer type questions and carry 5 marks each.
- Each question has an internal choice.
- The intended marks for questions are given in brackets [ ].
- All working, including rough work, should be done on the same sheet as and adjacent to the rest of the answer.
- Answers to sub parts of the same question must be given in one place only.
- A list of useful physical constants is given at the end of this paper.
- A simple scientific calculator without a programmable memory may be used for calculations

( ISC Physics 2019 Class-12 Solved Previous Year Question Paper )

Question 1.

(A) Choose the correct alternative (a), (b). (c) or (d) for each of the questions given below : [5 × 1]

**(i) A closed surface in vacuum encloses charges -q and +3 q. The total electric flux emerging out of the surface is :**

(a) Zero

(b)

(c)

(d)

Answer:

(A) (i) (b)

**(ii). What is the angle of dip at a place where the horizontal component (B _{H}) and vertical component (B_{V}) of earth’s magnetic field are equal:**

(a) 130°

(b) 60°

(c) 45°

(d) 90°

Answer:

(A)

(ii) (c)

**(iii). A beam of light is incident at the polarizing angle of 35° on a certain glass plate. The refractive index of the glass plate is :**

(a) sin 35°

(b) tan 35°

(c) tan 55°

(d) sin 55°

Answer:

(A)

(iii) (b)

**(iv). In a gamma ray emission from nucleus :**

(a) only the number of protons change.

(b) the number of protons and neutrons, both change.

(c) there is no change in the number of protons and the number of neutrons.

(d) only the number of neutrons change

Answer:

(A)

(iv) (c)

**(v). The energy associated with light of which of the following colours is minimum**

(a) violet

(h) red

(c) green

(d) yellow

Answer:

(A)

(v) (a)

(B) Answer the following questions briefly and to the point. [7 × 1]

**(i) Define equipotential surface.**

Answer :- An equipotential surface is one on the surface of which the potential is same.

**(ii) Calculate the net emf across A and B shown in Figure 1 below :**

Answer :-8V

**(iiii) Why are the pole pieces of a horseshoe magnet in a moving coil galvanometer made cylindrical in shape ?**

Answer :-This is done to produce a radial magnetic field

**(iv) What is the value of power factor for a pure resistor connected to an alternating current source ?**

Answer :- one

**(v) What should be the path difference between two waves reaching a point for obtaining constructive interference in Young’s Double Slit experiment.**

Answer :- zero.

**(vi) Define critical angle for a given medium.**

Answer- It is defined as the angle of incidence in the denser medium for which the angle of refraction in the rarer medium is 90°.

**(vii) Name the series in the atomic spectra of the hydrogen atom that falls in the ultraviolet region.**

Answer :- Lyman series.

( ISC Physics 2019 Class-12 Solved Previous Year Question Paper )

Question 2. [2]

**In a potentiometer experiment, the balancing length with a resistance of 2 Ω is found to be 100 cm, while that of an unknown resistance is 500 cm. Calculate the value of the unknown resistance.**

Answer:

Given R_{1} =2Ω ,L_{1} = 100 cm, L_{2}= 500 cm, R_{2} = ?

Using the expression

Question 3. [2]

**A rectangular loop of area 5 m ^{H}. has 50 turns and carries a current of 1 A. It is held in a uniform magnetic field of 0. IT, at an angle of 30°. Calculate the torque experienced by the coil.**

Answer:

Given, A= 5 m2, n = 50, I = 1 A, B = 0.1T, θ= 30°, T= T

Question 4. [2]

**(a) A electric current I flows through an infinitely long conductor as shown in Figure 2(a) below. Write an expression and direction for the magnetic field at point P.**

Answer-

, perpendicular to the plane of the paper and directed inwards.

**(b) An electric current I flows through a circular loop as shown in Figure 2(b) below. Write an expression and direction for the magnetic field at the centre of the loop at point P.**

Answer:

, perpendicular to the plane of the paper and directed outwards.

Question 5. [2]

**A transformer is used to step up an alternating emf of 200 V to 440 V. If the primary coil has 1000 turns, calculate the number of turns in the secondary coil.**

Answer:

Question 6. [2]

**State any two properties of microwaves.**

Answer:

- They move with the speed of light.
- They can heat matter.

Question 7. [2]

**Write any one use for each of the following mirrors :**

**(a) Convex**

**(b) Concave**

Answer:

(a) Used as a rear view mirror.

(b) Used as a shaving mirror.

Question 8. [2]

**The deviation produced for violet, yellow and red lights for crown glass are 3.75°. 3.25° and 2.86° respectively. Calculate the dispersive power of the crown glass.**

Answer:

Given δ_{V} = 3.75°, δ_{Y} = 3.25°, δ_{R} = 2.86°

Using the expression for dispersive power

Question 9. [2]

**(a) What is meant by mass defect ?**

Answer:

This is the difference in mass of the constituent nucleons and the nucleus formed.

**(b) What conclusion is drawn from Rutherford’s scattering experiment of α -particles ?**

Answer : – That the entire positive charge and 99 % mass is concentrated in the center of the atom called the nucleus.

Question 10. [2]

Define the following with reference to photoelectric effect:

**(i) Threshold frequency (f _{0})**

Answer :-

It is the minimum frequency below which photoelectric effect does not take place.

**(ii) Stopping potential (V _{s})**

Answer :-

It is the negative potential of the anode for which even the fasts moving electrons cannot reach it.

Question 11. [2]

**(a) The half-life of radium is 1550 years. Calculate its disintegration constant (λ).**

Or

**(b) Copy and complete the following table for a radioactive element whose half-life is 10 minutes. Assume that you have 30 g of this element at t = 0.**

Answer:

Question 12. [2]

**Define frequency modulation and state any one advantage of frequency modulation (FM) over amplitude modulation (AM).**

Answer:

When the frequency of the carrier wave changes in accordance with the frequency of the signal it is called frequency modulation. External noise does not have any effect on frequency modulation.

( ISC Physics 2019 Class-12 Solved Previous Year Question Paper )

Question 13. . [3]

**Obtain an expression for electric potential ‘V’ at a point in an end-on position i.e., axial position of an electric dipole.**

Answer:

Consider an electric dipole consisting of -q and +q charges separated by a distance 2a as shown in figure below. Let P be the point of observation where the electric potential has to be found. Let it be at a distance r from the center O of the dipole. Let us suppose that the dipole is placed in vacuum.

Question 14. [3]

**Three capacitors of capacitance C _{1} = 3 μf C_{2} = 6 μf and C_{3} = 10 μf are connected to a 10 V battery as shown in Figure 3 below :**

Calculate: .

(a) Equivalent capacitance.

(b) Electrostatic potential energy stored in the system.

Answer:

Question 15. [3]

**(a) Obtain the balancing condition for the Wheatstone bridge arrangement as shown in Figure 4 below:**

(b) Draw a labelled circuit diagram of a potentiometer to measure the internal resistance ‘r’ of a cell. Write the working formula (derivation is not required).

Answer:

(a) Consider the diagram as shown below. The distribution of current in accordance with Kirchhoff’s rules is shown.

Applying Kirchhoff’s loop rule to the closed loop ABDA, we have

…(1)

b) The circuit diagram is as shown:

Question 16. [3]

**(a) A ray of light is incident on a prism whose refractive index is 1.52 at anagle of 40°. If the angle of emergence is 60°, calculate the angle of the prism.**

Or

**(b) Calculate the focal length of a convex lens whose radii of curvature of two surfaces is 10 cm and 15 cm respectively and its refractive index is 1.5.**

Answer:

Question 17. [3]

**Derive the law of reflection using Huygens’s Wave Theory.**

Answer:

Consider a plane wave front AB incident obliquely on a plane reflecting surface MM’. Let us consider the situation when one end A of wave front strikes the mirror at an angle i but the other end B has still to cover distance BC. Time required for this will be t = BC/ c.

According to Huygens’s principle, point A starts emitting secondary wavelets and in time t, these will cover a distance c,t = BC and spread. Hence, with point A as center and BC as radius, draw a circular arc. Draw tangent CD on this arc from the point C. Obviously. CD is the reflected wave front inclined at an angle r. As incident wave front and reflected wave front both are in the plane of paper, 1st law of reflection is proved.

To prove second law of reflection, consider ΔABC and ΔADC. BC = AD (by construction)

∠ABC = ∠ADC = 90° and AC is common. Therefore, the two triangles are congruent and, hence, ∠B AC = ∠DCA or ∠i = ∠r i.e., the angle of reflection is equal to the angle of incidence, which is the second law of reflection.

Question 18. [3]

**State any two Bohr’s postulates and write the energy value of the ground state of the hydrogen atom.**

Answer:

- Only those orbits are allowed for which the angular momentum of the electron about the nucleus is an integral multiple of h/2h , where h is Planck’s constant.
- Energy is radiated when an electron “jumps” from one allowed stationary orbit to another.

E = -13.6 eV

Question 19. [3]

With reference to semiconductors answer the following :

**(i) What is the change in the resistance of the semiconductor with increase in temperature ?**

Answer:- It decreases.

**(ii) Name the majority charge carriers in n-type semiconductor.**

Answer:- Electrons.

**(iii) What is meant by doping ?**

Answer:- It is the addition of an impurity in a pure semiconductor.

**( ISC Physics 2019 Class-12** Solved Previous Year Question Paper )

Question 20. [5]

**(a) An alternating emf of 200 V, 50 Hz is applied to an L – R circuit, having a resistance R of 10 Ω . and an inductance L of 0.05 H connected in series. Calculate :
(1) Impedance.
(2) Current flowing in the circuit.**

**(ii) Draw a labelled graph showing the variation of inductive reactance (XL) verses frequency (f).
OR
(i) An a.c. source of emf e = 200 sin ωt is connected to a resistor of 50 Ω
Calculate:
(1) Average current (I**

Question 21. [5]

**(a) Draw a neat labelled ray diagram showing the formation of an image at the least distance of distinct vision D by a simple microscope. When the final image is at D. derive an expression for its magnifying power at D.
(b) Draw a neat labelled diagram of Young’s Double Slit experiment. Show that β =λD/d , where the terms have their usual meaning (either for bright or dark fringe).**

Answer:

(a) The diagram is as shown:

**
**(b) Consider a point P on the viewing screen; the screen is located at a perpendicular distance D from the screen containing the slits S

where it is assumed that r_{1} and r_{2} are parallel, which is approximately true because D is much greater than d. The value of this path difference determines whether or not the two waves are in phase, when they arrive at point P.

If the path difference is either zero or some integral multiple of the wavelength, the waves are in phase at P and constructive interference results. Therefore, the condition for bright fringes, or constructive interference, at P is given by

…………(2)

In order to find the position of maxima measured vertically from O to P i.e., y we assume that D >> d. Under these conditions, θ is small, and so the approximation sin θ ~ tan θ. Therefore, from triangle POQ in figure, we find that

Question 22.

(a)

** (i) Draw a labelled circuit diagram of a half wave rectifier and give its output waveform.**

**(ii) Draw a symbol of NOR gate and write its truth table.**

Or

(b)

(i) Draw a neat circuit diagram to study the input and output characteristics of a common emitter transistor.

(ii) Draw the symbol for AND gate and write its truth table.

Answer:

-: End of **ISC Physics 2019 Class-12** Solved Previous Year Question Paper :-

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]]>**ISC Maths 2019 Class-12** Solved Previous Year Question Paper for practice. Step by step Solutions with section-A, B and C. Visit official website **CISCE **for detail information about** ISC** Board **Class-12 Maths**.

By the practice of** ISC Maths 2019 Class-12** Solved Previous Year Question Paper you can get the idea of solving. Try Also other year except **ISC Maths 2019** **Class-12 **Solved Question Paper of Previous Year for more practice. Because only **ISC Maths 2019 Class-12** is not enough for complete preparation of next council exam.

**-: Select Your Topics :-**

Time Allowed: 3 Hours

Maximum Marks: 100

(Candidates are allowed additional 15 minutes for only reading the paper. They must NOT start writing during this time.)

- The Question Paper consists of three sections A, B and C.
- Candidates are required to attempt all questions from Section A and all questions either from Section B or Section C.
- Section A: Internal choice has been provided in three questions of four marks each and two questions of six marks each.
- Section B: Internal choice has been provided in two questions of four marks each.
- Section C: Internal choice has been provided in two questions of four marks each.
- All working, including rough work, should be done on the same sheet as, and adjacent to the rest of the answer.
- The intended marks for questions or parts of questions are given in brackets [ ].
- Mathematical tables and graph papers are provided

(ISC Maths 2019 Class-12 Solved Previous Year Question Paper )

(i) If f: R → R, f(x) = x^{3} and g: R → R, g (x) = 2x^{2} + 1, and R is the set of real numbers, then find fog(x) and gof(x).

(ii) Solve: sin (2 tan^{-1}x) = 1.

(iii) Using determinants, find the values of k, if the area of triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units.

(iv) Show that (A + A’) is symmetric matnx. if A =

(v) f(x) = is not defined at x = 3. What value should be assigned to f(3) for continuity of f(x) at x = 3?

(vi) Prove that the function f(x) = x^{3} – 6x^{2} + 12x + 5 is increasing on R.

(vii) Evaluate:

(viii) UsingL Hospital’s Rule, evaluate:

(ix) Two balls are drawn from an urn containing 3 white, 5 red and 2 black balls, one by one without replacement. What is the probability that at least one ball is red?

(x) If events A and B are independent, such that P( A) = , P (B) = , find P(A∪B).

Solution:

If f: A → A and A = R – {}, show that the function f(x) = is one-one onto. Hence, find f^{-1}.

Solution:

Given function is:

(a) Solve for x:

Solution:

Use properties of determinants prove that:

Solution:

(a) Show that the function f(x) = |x – 4|, x ∈ R is continuous, but not differentiable at x = 4.

Or

(b) Verify the Lagrange’s mean value theorem for the function:

f(x) = x + in the interval [1, 3]

Solution:

Thus, f(x) is continuous at x = 4.

For differentiability at x = 4.

When x < 4, f(x) = -(x – 4), which being polynomial function is differentiable for all x < 4.

When x > 4, f(x) = x – 4, which being polynomial function is differentiable for all x > 4.

When x = 4

Hence, f(x) is not differentiable at x = 4.

Or

(b) Let f(x) = x + in the inverval [1, 3]

Since, f(x) is a polynomial function, therefore, it is continuous and derivable in (1, 3).

⇒ f satisfies conditions of Mean Value theorem in [1, 3],

Thus, there exists atleast one real c ∈ (1, 3) such that

Hence, Mean Value theorem for the given function is verified in the given interval

Solution:

A 13 m long ladder is leaning against a wall, touching the wall at a certain height from the ground level. The bottom of the ladder is pulled away from the wall, along the ground, at the rate of 2 m/s. How fast is the height on the wall decreasing when the foot of the ladder is 5 m away from the wall?

Solution:

Let at any instant of time t, the height of the top of the ladder be y and its foot be at distance x from the wall, then

Solution:

Solve the differential equation:

Solution:

Given the differential equation is

**Question 10. [4]**

Bag A contains 4 white balls and 3 black balls, while Bag B contains 3 white balls and 5 black balls. Two balls are drawn from Bag A and placed in Bag B. Then, what is the probability of drawing a white ball from Bag B?

Solution:

Here, we have three cases

Case 1: Two balls drawn from Bag A are White.

Case 2: Two balls drawn from Bag A are Black.

Case 3: Two balls drawn from Bag A are one White and other Black.

Solve the following system of linear equations using matrix method:

Solution:

(a) The volume of a closed rectangular metal box with a square base is 4096 cm^{3}. The cost of polishing the outer surface of the box is ₹ 4 per cm^{2}. Find the dimensions of the box for the minimum cost of polishing it.

Or

(b) Find the point on the straight line 2x + 3y = 6, which is closest to the origin.

Solution:

(a) Let x be the side of the square base andy be its height.

**Question 13. [6]**

Solution:

(a) Given three identical Boxes A, B and C, Box A contains 2 gold and 1 silver coin, Box B contains 1 gold and 2 silver coins and Box C contains 3 silver coins. A person chooses a Box at random and takes out a coin. If the coin drawn is of silver, find the probability that it has been drawn from the Box which has the remaining two coins also of silver.

Or

(b) Determine the binomial distribution where mean is 9 and standard deviation is . Also, find the probability of obtaining at most one success.

Solution:

(a) Let E_{1}, E_{2}, E_{3} be the three events of the selection of three bags A, B and C respectively.

Let S be the event that the coin drawn is of silver, we have

(ISC Maths 2019 Class-12 Solved Previous Year Question Paper )

Question 15. [3 × 2]

(a) If and are perpendicular vectors, 13 and = 5. find the value of .

(b) Find the length of the perpendicular from origin to the plane

(c) Find the angle between the two lines 2x = 3y = -z and 6x = -y = -4z.

Solution:

(a) Here, and are perpendicular vectors

(b) Length of the perpendicular from the origin O(0, 0, 0) to the given plane

(c) Given lines are:

Hence, the lines are perpendicular to each other

Solution:

(a) Find the equation of the plane passing through the intersection of the planes 2x + 2y – 3z – 7 = 0 and 2x + 5y + 3z – 9 = 0 such that the intercepts made by the resulting plane on the x – axis and the z – axis are equal.

Or

(b) Find the equation of the lines passing through the point (2, 1, 3) and perpendicular to the lines

Solution:

(a) Given planes are:

2x + 2y – 3z – 7 = 0 … (i)

and 2x + 5y + 3z – 9 = 0 … (ii)

Equation of the plane passing through the intersection of the planes (i) and (ii) is:

Draw a rough sketch and find the area bounded by the curve x^{2} = y and x + y = 2.

Solution:

The given curves are: x^{2} = y

Which is an upward parabola with vertex at origin

And line x + y = 2 ⇒ y = 2 – x

x^{2} = 2 – x

⇒ x^{2} + x – 2 = 0

⇒ (x + 2)(x – 1) = 0

⇒ x = -2 and x = 1

Now, y = 2-(-2) = 4

and y = 2 – 1 ⇒ y = 1

⇒ y = 4 and y = 1

Thus, the points of intersection are (-2, 4) and (1, 1)

Required area of shaded region

(ISC Maths 2019 Class-12 Solved Previous Year Question Paper )

(a) A company produces a commodity with ₹ 24,000 as fixed cost. The variable cost estimated to be 25% of the total revenue received on selling the product, is at the rate of ₹ 8 per unit. Find the break-even point.

(b) The total cost function for a production is given by C (x) = x^{2} – 7x + 27.

Find the number of units produced for which M.C. = AC.

(M.C. = Marginal Cost and A.C. = Average Cost)

(c) If = 18, = 100, σ_{x} = 14, σ_{y} = 20 and correlation coefficient r_{xy} = 0.8, find the reggression equation of y on x.

Solution:

(a) Suppose that x number of the unit be produced and sold.

As each unit’s variable cost is 25% of revenue

The variable cost of x units = 25 % of ₹ 8x = ₹ 2x

Total cost of producing x units C(x) = TFC + TVC = ₹ (24000 + 2x)

Price of one unit = ₹ 8

Total revenue of selling x units = R(x) = ₹ 8x

At break-even values,

C(x) = R(x)

⇒ 24000 + 2x = 8x

⇒ 24000 = 6x

⇒ x = 4000

(b) Total cost function for a production

(a) The following results were obtained with respect to two variables x and y:

Σx = 15, Σy = 25, Σxy = 83, Σx^{2} = 55, Σy2 = 135 and n = 5

(i) Find the regression coefficient bxy.

(ii) Find the regression equation of x on y.

Or

(b) Find the equation of the regression line of y on x, if the observations (x, y) are as follows:

(1, 4), (2, 8), (3, 2), (4, 12), (5, 10), (6, 14), (7, 16), (8, 6), (9, 18)

Also, find the estimated value of y when x = 14.

Solution:

(a) The cost function of a product is given by C (x) = – 45x^{2} – 900x + 36, where x is the number of units produced. How many units should be produced to minimise the marginal cost?

Or

(b) The marginal cost function of x units of a product is given by MC = 3x^{2} – 10x + 3. The cost of producing one unit is ₹ 7. Find the total cost function and average cost function.

Solution:

A carpenter has 90, 80 and 50 running feet respectively of teak wood, plywood and rosewood which is used to produce product A and product B. Each unit of product A requires 2, 1 and 1 running feet and each unit of product B requires 1, 2 and 1 running feet of teak wood, plywood and rosewood respectively. If product A is sold for ₹ 48 per unit and product B is sold for ₹ 40 per unit, how many units of product A and product B should be produced and sold by the carpenter, in order to obtain the maximum gross income?

Formulate the above as a Linear Programming Problem and solve it, indicating clearly the feasible region in the graph.

Solution:

Let x units of product A and y units of product B be produced and sold by the carpenter. Then information given in the statement is tabulated as:

Then the LPP is maximise P = 48x + 40y

Subject to the constraints:

2x + y ≤ 90 …..(i)

x + 2y ≤ 80 ….. (ii)

x + y ≤ 50 ….. (iii)

x ≥ 0, y ≥ 0

Draw the graphs of equations (i), (ii), (iii)

Then shaded region is the required feasible region which is bounded with comer points

O(0, 0), A(45, 0), B(40, 0), C(20, 30) and D(0, 40).

At O(0, 0), the value of P = 0 + 0 = 0

At A(45, 0), the value of P = 48 × 45 + 0 = 2160

At B(40,10), the value of P = 48 × 40 + 40 × 10 = 2320 → Maximum

At C(20, 30), the value of P = 48 × 20 + 40 × 30 = 2160

At D(0, 40), the value of P = 0 + 40 × 40 = 1600

We have the maximum value of P as ₹ 2320 and it is obtained at the vertex B (40, 10).

Hence, the maximum gross income of the carpenter should make 40 units of product A and 10 units of product B.

-: End of ISC Maths 2019 Class-12 Solved Previous Year Question Paper :-

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]]>**ICSE Computer Application 2017 Paper** Solved Previous Year for for practice so that student of class 10th **ICSE** can achieve their goals in next exam of council. Hence by better practice and Solved Question Paper of Previous Year including **2017** is very helpful for **ICSE** student. By the practice of **Computer Application**** 2017 **Solved Question** Paper ICSE **Previous Year you can get the idea of solving. Try Also other year except **Computer Application**** 2017 **Solved Question Paper ICSE Previous Year for practice. Because only **Computer Application**** 2017 **Solved Question Paper **ICSE** Previous Year is not enough for preparation of council exam.

General Instructions :

- Answers to this Paper must he written on the paper provided separately.
- You will not be allowed to write during the first 15 minutes.
- This time is to be spent in reading the Question Paper.
- The time given at the head of this Paper is the time allowed for writing the answers.
- This Paper is divided into two Sections.
- Attempt all questions from Section A and any four questions from Section B.
- The intended marks for questions or parts of questions are given in brackets
**[ ]**.

**(a) What is inheritance ? [2]**

**(b) Name the operators listed below r [2]**

**(0 <**

**(it) + +**

**(iii) &&**

**(iv) ? :**

**(c) State the number of bytes occupied by char and int data types. [2]**

**(d) Write one difference between / and % operator. [2]**

**(e) String x[ ] = {“SAMSUNG”, “NOKIA”, “SONY”, “MICROMAX”, “BLACKBERRY”}; [2]**

**Give the output of the following statements :**

**(i) System.out.prindn(x[1]);**

**(ii) System.out.println(x[3].length{ )); ,**

(a) Inheritance in java is a mechanism in which one object acquires all the. properties and behaviors of parent object.

The idea behind inheritance in java is that you can create new classes that are built upon existing classes. When you inherit from an existing class, you can reuse methods ‘and fields of parent class, and you can add new methods and fields also.

(b) (i) Comparison operator

(ii) Unary operator

(iii) Logical operator

(iv) Ternary operator

(c) The char data occupies two bytes whereas int data type occupies four bytes.

(d) The / operator is used for division whereas % operator is used to find the remainder.

(e) (i) NOKIA

(ii) 8

**(a) Name the following : [2]**

**(i) A keyword used to call a package in the program.**

**(ii) Any one reference data type.**

**(b) What are the two ways of invoking functions? [2]**

**(c) State the data type and value of res after the following is executed: [2]**

**char ch = ‘t’;**

**res=Character. toUpperCase(ch);**

**(d) Give the output of the following program segment and also mention the number of times**

**the loop is executed: [2]**

**int a,b;**

**for (a=6, b=4; a< =24; a=a + 6)**

**{**

**if (a%b= =0)**

**break;**

**}**

**System, out .println(a);**

**(e) Write the output: [2]**

**charch= ‘F’;**

**int m= ch;**

**m=m+5;**

**System.out.println(m+ ” ” +ch)**;

(a) (i) import

(ii) Array

(b) By Value and By Reference

(c) int type and value is 84.

(d) Output is 12. Twice.

In the loop : for (a = 6, b=4; a< =24; a = a+6), the value of a will be

incrementing as 6, 24 and upon incrementing the value to 42, the loop will terminate. Accordingly the loop has to execute two times.

But within the loop there is a condition : if(a%b = =0) break;

This means when remainder on dividing a by b comes out to be 0 (at 24/4 = 0), the condition breaks and from the above it is clear that value of a is incremented from 6 to 24 when the loop executes second time.

(e) 75 F

**(a) Write a Java expression for the following : [2]**

**ax ^{5} + bx^{3} + c**

**(f) Write the output for the following : [2]**

**String s= “Today is Test”;**

**System.out.println(s.indexOf(‘T’));**

**System.out.println(s.substring(0, 7) + ” ” + “Holiday”);**

**(g) What are the values stored in variables r! and r2: [2]**

**(i) double r _{1}=Math.abs(Math.min(-2.83,-5.83));**

** ****(h) Give the output of the following code: [2]**

**String A = “26”, B=”100″;**

**String D =A+B+”200″;**

**int x = Integer.parselnt(A);**

**int y = Integer.parselnt(B);**

**int d = x+y;**

**System.out.println(“Result 1 = ”+D);**

**System.out.prinln(“Result 2 = “+d); ,**

**(i) Analyze the given program segment and answer the following questions : [2]**

**for(int i=3;i< =4;i+ +) {**

**for(int j=2;j<i;j+ +) {**

**System.out.print(” “); }**

**System.out.println(“WIN”); }**

**(i) How many times does the inner loop execute ?**

**(ii) Write the output of the program segment.**

**(f) What is the difference between the Scanner class functions nextQ and nextLine()? [2]**

(a) a.Math.pow(x,5) + b.Math.pow(x,3) +c;

(b) 6

(c) An object is a software bundle of related state and behavior. A class is a blueprint or prototype from which objects are created. An instance is a single and unique unit of a class.

(d) int i =1;

int d = 5;

for(i = 1; i < = 5; i+ +) {

d = d*2;

System.out.println(d);

}

(e) Constructors must be named with the same name as the class name. They cannot return anything, even void (the object itself is the implicit return).

Functions must be declared to return something, although it can be void.

(f) 0

Today i Holiday

(g) r1 = 5.83 .

r2 = 4.0

(h) Result 1 = 26100200

Result 2 = 126

(i) (i) Once

(ii) WIN

WIN

(j)next ( ) can read the input only till the space. It cannot read two words separated by space.

Also, next( ) places the cursor in the same line after reading the input.

nextLine( ) reads input including space between the words (that is, it reads till the end of line \n). Once the input is read, nextLine( ) positions the cursor in the next line.

Attempt any four questions from this Section.

The answers in this Section should consist of the Programs in either BlueJ environment or any

program environment with Java as the base.

Each program should be written using Variable descriptions/Mnemonic Codes so that the logic

of the program is clearly depicted.

Flow-Charts and Algorithms are not required.

**Define a class ElectricBill with the following specifications : [15]**

**class : ElectricBill**

**Instance variables /data member :**

**String n – to store the name of the customer**

**int units – to store the number of units consumed**

**double bill – to store the amount to be paid**

**Member methods :**

**void accept ( ) – to accept the name of the customer and number of units consumed**

**void calculate ( ) – to calculate the bill as per the following tariff :**

**write a main method to create an object of the class and call the above member methods.**

import java.io.*;

class ElectricBill {

String n;

int units;

double bill ;

void accept() throws IOException {

BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

System.out.print(“Name of the customer = “);

n = reader.readLine( );

System.out.print( “Number of units consumed = “);

String un = reader. readLine( );

units=Integer .parselnt(un);

}

void calculate!) {

if(units < = 100)

bill = 2.00*units;

if(units< =300) bill = 3.00*units; if (units > 300)

bill = 5.00*units;

}

void print( ) {

System.out.println(“Naine of the customer:” +n);

System.out.println(“Number of units consumed:” +units);

System.out.println(“Bill amount:” + bill);

}

public static void main(String argsQ) throws IO

Exception { ElectricBill eb = new ElectricBill( );

eb. accept!);

eb.calculate();

}

}

**Write a program to accept a number and check and display whether it is a spy number or not. (A number is spy if the sum of its digits equals the product of its digits.) [15]**

**Example : consider the number 1124,**

**Sum of the digits = l + l+ 2 + 4 = 8**

**Product of the digits = 1×1 x2x4 = 8**

class Spy {

public static void main(int n) {

int sum = 0;

int multiple = 1;

int a;

int p = n;

// a stores each digit extracted and p creates a backup of input.

while(n ! = 0) {

a = n % 10; ,

sum = sum + a;

multiple = multiple * a;

n = n/10;

}

System.out.println(“The sum of ” +p +” is ”+sum);

System.out.println(“The product of “+p +” is ” + multiple);

if(sum = = multiple) {

System.out.println(“Aha, ” + “It is a Spy Number Where Sum = Product”);

}

else {

System.out.println(” It is NOT a Spy Number Where Sum ft Product”);

}

}

}

**Using switch statement, write a menu driven program for the following : [15]**

**(i) To find and display the sum of the series given below :**

**S = x ^{1} -x^{2} + x^{2} – x^{4} + x^{5} – x^{20}**

import java.io.*;

class SwitchStatement {

public static void main(String argsQ) throws IOException {

InputStreamReader reader = new InputStreamReader(System.in);

BufferedReader input = new BufferedReader(reader);

System.out.println(“l-Sum of Series:”);

System.out.println(“2-Display Special Series:”);

System.out.println(“Enter your choice:”);

String n1 = input.readLine( );

int ch = Integer.parselnt(nl);

System.out.println(“Enter Number of Terms

String t = input.readLine();

int n = Integer.parselnt(t);

switch (ch) {

case 1:

int sign = -1;

double term = 0;

double sum = 0;

int x = 2;

System.out.println(“Value of x: ” +x);

System.out.println(“Number of terms: ” +n);

sum + = x; // First term added here,

for (int i = 2; i < = n; i+ +){

term = sign * Math.pow(x,i);

sum + = term;

sign *= -1;

}

System.out.println(“Sum of Series +sum);

break;

case 2 :

int num;

System.out.println(“Enter the number of terms: ”);

String tm = input.readLine(); .

num = Integer.parselnt(tm);

int s = 0, c;

for (c = 1; c < = num; c+ +){

s = s * 10 + 1;

System.out.print(s + ” “);

}

break;

}

}

}

**Write a program to input integer elements into an array of size 20 and perform the following operations: [15]**

**(i) Display largest number from the array.**

**(ii) Display smallest number’from the array.**

**(iii) Display sum of all the elements of the array.**

import java.util.Scanner;

class LargeSmallSum {

public static void main(String args[ ]) {

int n;

int max, min, sum = 0;

int i, j;

Scanner s = new Scanner(System.in);

System.out.print(“Enter no. of elements you want in array:”);

n = s.nextlnt();

int a[ ] = new int[n];

System.out.println(“Enter all the elements:”);

for (i = 0; i < n; i+ +) {

a[i] = s.nextlntO;

}

max = a[0];

min = a[0];

for(i = 0; i < n ; i + +) { if(a[i] > max) {

max = a[i];

}

if (a[i] < min) {

min = a[i];

}

}

System.out.println(“Maximum Number is:”+max);

System.out.println(“Smallest Number is:” +min);

for(i = 0; i < n; i+ +) {

sum = sum + a[i];

}

System.out.println(“Sum of the Numbers is:” +sum);

}

}

**Design a class to overload a function check ( ) as follows : [15]**

**(i) void check (String str, char ch) – to find and print the frequency of a character in a string.**

**Example : ***

**Input:**

**str = “success”**

**ch = ‘s’ .**

**Output:**

**number of s present is = 3**

**(ii) void check(String si) – to display only vowels from string si, after converting it to lower case.**

**Example:**

**Input:**

**s1 = “computer”**

**Output:**

**o u e**

class CharacterVowel {

public void checkering str, char ch) {

int c = 0, code,i,s;

str = str.toLowerCase( );

int len = str.length( );

for (code = 97; code < 122; code+ +) {

c = 0;

for (i = 0; i < len; i+ +) {

ch = str.charAt(i);

s = (int) ch;

if(s = = code)

c = c + 1;

}

ch = (char)code;

if(c ! = 0)

System.out.println(“Frequency of “+ch+ “is” +c);

}

}

public void check(String si) {

int i;

**c**har ch=0, chr=0;

for(i=0;i<s1.length();i+ +) {

ch = s1.charAt(i);

if(Character.isUpperCase(ch))

chr = Character. toLo werCase(ch);

if((s1 .charAt(i)==’a’) 11 (s1 .charAt(i) = ‘u’) | j(s1 .charAt(i) = = ‘o’)| | (s1 .charAt(i)==’i’) 11 (s1 .charAt(i) = = ‘e’))

System.out.println(s1 .charAt(i));

}

}

}

**Write a program to input forty words in an array. Arrange these words in descending order of alphabets, using selection sort technique. Print the sorted array. [15]**

import java.util.Scanner;

class Descending {

public static void main(String args[ ]) {

int n;

String temp;

Scanner s = new Scanner(System.in);

System.out.print(“Enter number of words you want to enter:”);

n = s.nextlnt( );

String names[ ] = new String[n];

Scanner s1 = new Scanner(System.in);

System.out.println(“Enter all words:”);

for(int i = 0; i < n; i+ +) {

names[i] = s1.nextLine[( );

}

for (int i = 0; i < n; i+ +){

for (int j = i + 1; j < n;j++){

if (names[i].compareTo(namesG]) < 0) {

temp = names [i];

names[i] = namesG];

names[j] = temp;

}

}

}

System.out.print(“Words in Descending Order:”);

for (int i = 0;i<n-l;i++){

System.out.print(names[i] + “,”);

}

System.out.print(names[n – 1]);

}

}

**-:Try Also :-**

**ICSE Solved Paper Class-10 Previous Year Question with Sample ,Model and Specimen**

The post ICSE Computer Application 2017 Paper Solved Previous Year appeared first on ICSEHELP.

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