Convex Mirror Numerical Class-12 Nootan ISC Physics Solutions Ch-14 Reflection of Light Spherical Mirrors. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
Convex Mirror Numerical Class-12 Nootan ISC Physics Solutions Ch-14 Reflection of Light Spherical Mirrors
| Board | ISC |
| Class | 12 |
| Subject | Physics |
| Book | Nootan |
| Chapter-14 | Reflection of Light : Spherical Mirrors |
| Topics | Numericals on Convex Mirror |
| Academic Session | 2025-2026 |
Numericals on Convex Mirror
Class-12 Nootan ISC Physics Solutions Ch-14 Reflection of Light Spherical Mirrors.
Que-8: An object is placed at 18 cm in front of a spherical mirror. The image is formed at 3.0 cm behind the mirror. Find the focal length and the nature of the mirror.
Ans- u = -18 cm , v = +3 cm
m = -v/u = f / f-u
=> -3/-18 = f / f+18
=> 6f = f+18
=> f = +3.6 cm , convex
Que-9: An object is placed 15 cm away from a convex mirror of radius of curvature 90 cm. Find image’s position and magnification.
Ans- f = 90/2 = 45 cm , u = -15
m = f / f-u
= 45 / 45+15 = 0.75
m = -v/u
=> 0.75 = -v / -15
=> v = 11.25 cm , behind the mirror
Que-10: A 2 cm long object is placed at a distance of 100 cm from a convex mirror of radius of curvature 50 cm. Find the position, nature and length of the image.
Ans- f = 50/2 = 25 cm , u = -100 cm
m = f / f-u
= 25 / 25+100 = 0.2
m = I/O
=> 0.2 = I/2
=> I = 0.4
again m = -v/u
=> 0.2 = -v/-100
=> v = 20 cm , behind the mirror
Que-11: An object is placed in front of a convex mirror of radius of curvature 20 cm. Its image is formed 8 cm behind the mirror. Find the location of the object with respect to the mirror.
Ans- f = 20/2 = 10 cm , v = 10 cm
1/f = 1/v + 1/u
=> 1/10 = 1/8 + 1/u
=> u = -40 cm , in front the mirror
Que-12: The image formed by a convex mirror of focal length 30 cm is a quarter size of the object. Find the location of the object with respect to the mirror.
Ans- m = 1/4
f / f-u = 30 / 30-u
=> 120 = 30-u
=> u = -90 cm , in front the mirror
Que-13: The image formed by a convex mirror of radius of curvature 20 cm is half the size of the object. Find the position of the object and of its image.
Ans- m = 1/2 , f = 20/2 cm = 10 cm
m = f / f-u
=> 1/2 = 10 / 10-u
=> u = -10 cm , in front the mirror
again m = -v/u
=> 1/2 = -v/-100
=> v = 5 cm , behind the mirror
Que-14: When an object is placed at a distance of 60 cm from a convex mirror, the magnification produced is 1/2. Where should the object be placed to obtain a magnification of 1/3?
Ans- u1 = 60 cm , m1 = 1/2
u2 = ? , m2 = 1/3
=> 1/2 = f / f-u
=> 1/2= f / f+60
=> f = 60 cm
again 1/3 = f / f-u
=> 1/3 = 60 / 60-u
=> u = -120 cm , in front of the mirror
— : End of Convex Mirror Numerical Class-12 Nootan ISC Physics Solutions Ch-14 Reflection of Light Spherical Mirrors.–
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