Current Electricity Exe-9B Numericals Concise Physics ICSE Class 9 Selina Publishers. Numericals on Potential Differance and Resistance Questions of your latest textbook which is applicable in 2025-26 academic session. Visit official Website CISCE for detail information about ICSE Board Class-9 Physics.
Current Electricity Exe-9B Numericals Concise Physics ICSE Class 9 Selina Publishers
| oard | ICSE |
| Class | 9 |
| Subject | Physics |
| Writer / Publication | Concise selina Publishers |
| Chapter-9 | Current Electricity |
| Exe-9B | Potential Defferance and Resistance |
| Topics | Solution of Numericals |
| Academic Session | 2025-2025 |
Numericals on Potential Differance and Resistance
Current Electricity Exe-9B Concise Physics ICSE Class 9 Selina Publishers
Que-1: In transferring 1.5 C charge through a wire, 9 J of work is done. Find the potential difference across the wire.
Ans: Potential difference VA−VB between two points A and B is the work done per unit charge in taking a charge from B to A.
Potential difference, VA−VB=Work done / charge, where
VA is the potential at point A and VB is the potential at point B.
Hence, the potential difference across the wire is VA−VB = 9J / 1.5C = 6V.
Que-2: A cell of potential difference 12 V is connected to a bulb. The resistance of filament of bulb when it glows, is 24 Ω. Find the current drawn from the cell.
Ans: According to the Ohm’s law, the value of current is given as: I=V/R
The potential difference is 12 V and the resistance of filament of bulb when it glows, is 24 Ω.
Hence, the current drawn from the cell is: I=12V/24Ω = 0.5A
Que-3: A bulb draws current 1.5 A at 6.0 V. Find the resistance of the filament of bulb while glowing.
Ans: Current (I)=1.5 A
Potential difference or Voltage V=6.0V
Resistance R=?
According to Ohm’s Law:
V=IR
Then, R=V/ I
R = 6/1.5
R = 4.0 Ω.
Que-4: A current 0.2 A flows in a wire of resistance 15 Ω. Find the potential difference across the ends of the wire.
Ans: Current = 0.2 A.
resistance = 15 ohm.
V= I x R
V = 0.2 x 15
potential difference = 3.0 V.
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