DC Circuits and Measurements Numerical Class-12 Nootan ISC Physics Ch-6. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
DC Circuits and Measurements Numerical Class-12 Nootan ISC Physics Ch-6
| Board | ISC |
| Class | 12 |
| Subject | Physics |
| Book | Nootan |
| Chapter-6 | DC Circuits and Measurements. |
| Topics | Miscellaneous Numericals |
| Academic Session | 2025-2026 |
Miscellaneous Numericals on DC Circuits and Measurements Class 12 Physics
Que-39. Calculate in the given combination of four resistors : (i) equivalent resistance between points A and B, (ii) PD between A and B, (iii) currents in the various resistors.
Ans-39 (i) equivalent resistance = 12×9/12+9 = 12×9/21 = 36/7 Ω
(ii) PD across A and B = V = iR = 36/7 x 2 = 72/7
(iii) again I1/I2 = 9/12 = 3/4
I1 = 2 x 3/7 = 6/7 Amp
and I2 = 2 – 6/7 = 8/7 Amp
Que-40. Calculate the voltage drop across the 18 Ω resistor in the given circuit. The emf of the battery is 60 V.
Ans-40 Resistance of the circuit = 18 + 15×10/15+10
=> 18 + 150/25 = 24 Ω
Current in circuit = 60/24 = 2.5 A
PD across 18 Ω = 18 x 2.5 = 45 V
Que-41. Find, in the given circuit, currents in 10 Ω and 100 Ω resistors and the value of R.
Ans-41 Voltage across 10 ohm
120-100 =20V
current in the circuit
=20/10
= 2 amp
total resistance of parallel combination
=> Rx100/R+100
V = i x Rx100/R+100 = 100 V
=> 2 x Rx100/R+100 = 100
Que-42. What the ammeter A will read when (a) the key K is off, (b) the key K is on? The resistance of the ammeter is negligible.
Ans-42 Current = 9/4+2 = 1.2A
(b) When key is on then
total resistance = 2 8×4/8+4 = 56/12 = 14/3 = 14/3 Ω
and current = 9 / (14/3) = 27/14 A
again current in 8 and 4 Ω resistance
i8/i4 = 4/8 = 1/2
Therefore i4 = 2/3 x 27/14 = 9/7 A
Que-43. In steady state calculate the energy stored in the capacitor included in the given circuit.
Ans-43 PD across capacitor
= i R = 2 x 10 = 20 V
energy store in capacitor
=> 1/2 CV^2 = 1/2 x 2 x 10^-6 x (20)^2
=> 4 x 10^-4 J
Que-44. Compute the reading of the ammeter A in the given network of resistors.
Ans-44 the 2 Ω resistor in row of ammeter in series with other 3 , Ω resistor in parallel
therefore net resistance
=> 2 + 2/3 = 8/3 Ω
current (reading of ammeter)
=> V/R = 2 x 3 / 8 = 0.75 Amp
Que-45. In the given diagram, calculate the resistance of the voltmeter. The ammeter reading is 2 A, the voltmeter is 120 V and R is 75 Ω.
Ans-45 Current in R = V/R = 120/75 = 1.6 A
current in voltmeter = 2 – 1.6 = 0.4 Amp
Therefore resistance of voltmeter
=> R = V/i = 120/0.4 = 300 Ω
— : End of DC Circuits and Measurements Numerical Class-12 Nootan ISC Physics Ch-6. :–
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