Decimal Fractions ICSE Class-6th Concise Selina Mathematics Chapter-15 . We provide step by step Solutions of Exercise / lesson-15 Decimal Fractions for ICSE Class-6 Concise Selina Mathematics. Our Solutions contain all type Questions of Exe-15 A, Exe-15 B, Exe-15 C, Exe-15 D, Exe-15 E and Division Exercise to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-6 .
Decimal Fractions ICSE Class-6th Concise Selina Mathematics Chapter-15
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Exercise – 15 A Decimal Fractions ICSE Class-6th Concise Maths
Question -1.
Write the number of decimal places in each of the following :
(i) 7.03
(ii) 0.509
(iii) 146.2
(iv) 0.0065
(v) 8.03207
Answer-1
(i) 7.03, the decimal part is .03 which contains two digits.
Number 7.03 has 2 decimal places.
(ii) 0.509, the decimal part is 0.509 which contains three digits.
Number 0.509 has 3 decimal places
(iii) 146.2, the decimal part is .2 which contains one digits.
Number 146.2 has 1 decimal places.
(iv) 0.0065, the decimal part is .0065 which contains four digits.
Number 0.0065 has 4 decimal places
(v) 8.03207, the decimal part is .03207 which contains five digits.
Number 8.03207 has 5 decimal places.
Question- 2.
Convert the given unlike decimal fractions into like decimal fractions:
(i) 1.36, 239.8 and 47.008
(ii) 507.0752, 8.52073 and 0.808
(iii) 459.22, 7.03093 and 0.200037
Answer-2
(i) 1.36 = 1.360
239:8 = 239.800
47.008 = 47.008
(ii) 507.0752 = 507.07520
8.52073 = 8.52073
0.808 = 0.80800
(iii) 459.22 = 459.220000
7.03093 = 7.030930
0.200037 = 0.200037
Question -3.
Change each of following fractions to a decimal fraction :
Answer-3
Question -4.
Convert into a decimal fraction :
Answer-4
Question- 5.
Change the given decimals fractions to fractions in their lowest terms :
(i) 0.05
(ii) 3.95
(iii) 4.005
(iv) 0.876
(v) 50.06
(vi) 0.01075
(vii) 4.8806
Answer-5
Decimal Fractions Exe-15 B of ICSE Class-6th Mathematics
Question- 1.
Add the following :
(i) 0.243, 2.47 and 3.009
(ii) 0.0736, 0.6095 and 0.9107
(iii) 1.01, 257 and 0.200
(iv) 18, 200.35, 11.72 and 2.3
(v) 0.586, 0.0586 and 0.00586
Answer-1
Question -2.
Find the value of :
(i) 6.8 – 2.64
(ii) 2 – 1.0304
(iii) 0.1 – 0.08
(iv) 0.83 – 0.342
Answer-2
Question- 3.
Subtract :
(i) 0.43 from 0.97
(ii) 2.008 from 22.1058
(iii) 0.18 from 0.6
(iv) 1.002 from 17
(v) 83 from 92.05
Answer-3
(i) 0.43 from 0.97
Question- 4.
Simplify :
(i) 3.5 – 2.43 + 0.075
(ii) 7.84 + 0.3 – 4.016
(iii) 2.987 – 1.25 – 0.54
(iv) 52.9 – 231.666 + 204
(v) 8.57 – 6.4432 – 1.70 + 0.683
Answer-4
(i) 3.5 – 2.43 + 0.075
= 3.500 + 0.075 – 2.43
= 3.575 – 2.430 = 1.145
(ii) 7.84 + 0.3 – 4.016
= 7.840 + 0.300 – 4.016
= 8.140 – 4.016
= 4.124
(iii) 2.987 – 1.25 – 0.54
= 2.987 – 1.79
= 2.987 – 1.790
= 1.197
(iv) 52.9 – 231.666 + 204
= 52.9 – 231.666 + 204.0
= 256.9 – 231.666
= 256.900 – 231.666
= 25.234
Question -5.
From the sum of 75.75 and 4.9 subtract 28.465.
Answer-5
From the sum of 75.75 and 4.9 subtract 28.465.
Question – 6.
Subtract the sum of 8.14 and 12.9 from 32.7.
Answer-6
Subtract the sum of 8.14 and 12.9 from 32.7.
Question -7.
Subtract the sum of 34.27 and 159.8 from the sum of 20.937 and 200.6.
Answer-7
Subtract the sum of 34.27 and 159.8 from the sum of 20.937 and 200.6
Question- 8.
From the sum of 2.43 and 4.349 subtract the sum of 0.8 and 3.15.
Answer-8
From the sum of 2.43 and 4.349 subtract the sum of 0.8 and 3.15.
Question -9.
By how much does the sum of 18.0495 and 34.9644 exceed the sum of 7.6752 and 24.876?
Answer-9
Question- 10.
What least number must be added to 89.376 to get 1000?
Answer-10
Decimal Fractions Solved Questions of ICSE Class-6th Concise Mathematics Exercise – 15 C Selina Solutions
Question -1.
Multiply :
(i) 5.6 and 8
(ii) 38.46 and 9
(iii) 0.943 and 62
(iv) 0.0453 and 35
(v) 7.5 and 2.5
(vi) 4.23 and 0.8
(vii) 83.54 and 0.07
(viii) 0.636 and 1.83
(ix) 6.4564 and 1000
(x) 0.076 and 100
Answer-1
(i) 5.6 x 8 = 44.8
(ii) 38.46 x 9 = 346.14
(iii) 0.943 and 62
Question -2.
Evaluate :
(i) 0.0008 x 26
(ii) 0.038 x 95
(iii) 1.2 x 2.4 x 3.6
(iv) 0.9 x 1.8 x 0.27
(v) 1.5 x 1.5 x 1.5
(vi) 0.025 x 0.025
(vii) 0.2 x 0.002 x 0.001
Answer-2
(i) 0.0008 – 26
Since, 8 x 26 = 208
0.0008 x 26 = 0.0208
Question -3.
Multiply each of the following numbers by 10, 100 and 1000 :
(i) 3.9
(ii) 2.89
(in) 0.0829
(iv) 40.3
(v) 0.3725
Answer-3
(i) 3.9 x 10 = 39
3.9 x 100 = 390.0 = 390
3.9 x 1000 = 3900.0 =3900
(ii) 2.89 x 10 = 28.9
2.89 x 100 = 289
2.89 x 1000 = 2890.00 = 2890
(iii) 0.0829 x 10 = 0.829
0.0829 x 100 = 8.29
0.0829 x 1000 = 82.9
(iv) 40.3 x 10 = 403
40.3 x 100 = 4030
40.3 x 1000 = 40300
(v) 0.3725 x 10 = 3.725
0.3725 x 100 = 37.25
0.3725 x 1000 = 372.5
Question- 4.
Evaluate :
(i) 8.64 ÷ 8
(ii) 0.0072 ÷ 6
(iii) 20.64 ÷ 16
(iv) 1.602 ÷ 15
(v) 13.08 ÷ 4
(vi) 3.204 ÷ 9
(vii) 3.024 ÷ 12
(viii) 5.15 ÷ 5
(ix) 3 ÷ 5
Answer-4
Question- 5.
Divide each of the following numbers by 10,100 and 1000 :
(i) 49.79
(ii) 0.923
(iii) 0.0704
Answer-5
Question -6.
Evaluate :
(i) 9.4 ÷ 0.47
(ii) 6.3 ÷ 0.09
(iii) 2.88 ÷ 1.2
(iv) 8.64 ÷ 1.6
(v) 37.188 ÷ 3.6
(vi) 16.5 ÷ 0.15
(vii) 3.2 ÷ 0.005
(viii) 3.24 ÷ 0.0016
Answer-6
Question -7.
Fill in the blanks with 10,100,1000, or 10000 etc.:
(i) 7.85 x ………….. = 78.5
(ii) 0.442 x ………. = 442
(in) 0.0924 x ………… = 9.24
(iv) 0.00187 x …………. = 18-7
(v) 2.6 x …………. = 2600
(vi) 0.08 x ………… = 80
(vii) 96.7 ÷ ………….. = 0.967
(viii) 5.2 ÷ ……………. = 0.52
(ix) 33.15 ÷ ……………….. = 0.03315
(x) 0.7 ÷ ………… = 0.007
(xi) 0.00672 x ……… = 67.2
Answer-7
(i) 7.85 x 10 = 78.5
(ii) 0.442 x 1000 = 442
(iii) 0.0924 x 100 = 9.24
(iv) 0.00187 x 10000 = 18.7
(v) 2.6 x 1000 = 2600
(vi) 0.08 x 1000 = 80
(vii) 96.7 ÷ 100 = 0.967
(viii) 5.2 ÷ 10 = 0.52
(ix) 33.15 ÷ 1000 = 0.03315
(x) 0.7 ÷ 100 = 0.007
(xi) 0.00672 x 10000 = 67.2
Question -8.
Evaluate :
(i) 9.32 – 28.54 ÷ 10
(ii) 0.234 x 10 + 62.8
(iii) 3.06 x 100 – 889.4 ÷ 100
(iv) 2.86 x 7.5 + 45.4 ÷ 0.2
(v) 97.82 x 0.03 – 0.54 ÷ 0.3
Answer-8
(i) 9.32 – 28.54 ÷ 10
= 9.32 – 2.854
= 9.320-2.854
=6.466
(ii)
0.234×10+62.8
=2.34+62.80
=65.14
(iii)
3.06 x 100 – 889.4 ÷ 100
3.06 x 100 – 8.89.4
= 306 – 8.894
= 297.106
(iv)
2.86 x 7.5 + 45.4 ÷ 0.2
(v)
97.82 x 0.03 – 0.54 ÷ 0.3
Selina Solutions Decimal Fractions ICSE Class-6th Mathematics Exercise – 15 D
Question- 1.
Express in paise :
(i) Rs. 8.40
(ii) Rs. 0.97
(iii) Rs. 0.09
(iv) Rs. 62.35
Answer-1
(i) Rs. 8.40 = 8.40 x 100 paise [1Rs. = 100 Paise]
Question -2.
Express in rupees :
(i) 55 P
(ii) 8 P
(iii) 695 P
(iv) 3279 P
Answer-2
Question -3.
Express in centimetre (cm) :
(i) 6 m
(ii) 8.54 m
(iii) 3.08 m
(iv) 0.87 m
(v) 0.03 m
(vi) 25.04 m
Answer-3
(i) 6 x 100 = 600 cm
(ii) 8.54 x 100 = 854 cm
(iii) 3.08 x 100 = 308 cm
(iv) 0.87 x 100 = 87 cm
(v) 0.03 x 100 = 3 cm
(vi) 25.04 x 100 = 2504 cm
Question -4.
Express in metre (m) :
(i) 250 cm
(ii) 2328 cm
(iii) 86 cm
(iv) 4 cm
(v) 107 cm
Answer-4
= 1.07 m
Question- 5.
Express in gramme (gm) :
(i) 6 kg
(ii) 5.543 kg
(iii) 0.078 kg
(iv) 3.62 kg
(v) 4.5 kg
Answer-5
(i) 6 x 1000 = 6000 gm
(ii) 5.543 x 1000 = 5543 gm
(iii) 0. 078 kg = 0.078 x 1000 g = 78 g (1 kg = 1000 g)
(iv) 3.62 x 1000 = 3620 gm
(v) 4.5 x 1000 = 4500 gm
Question- 6.
Express in kilogramme (kg) :
(i) 7000 gm
(ii) 6839 gm
(iii) 445 gm
(iv) 8 gm
(iv) 93 gm
(vi) 13545 gm
Answer-6
Question- 7.
Add (giving answer in rupees) :
(i) Rs. 5.37 and Rs. 12
(ii) Rs. 24.03 and 532 paise
(iii) 73 paise and Rs. 208
(iv) 8 paise and Rs. 1536
Answer-7
Question -8.
Subtract :
(i) Rs. 35.74 from Rs. 63.22
(ii) 286 paise from Rs. 7.02
(iii) Rs. 0.55 from 121 paise
Answer-8
Question- 9.
Add (giving answer in metre) :
(i) 2.4 m and 1.78 m
(ii) 848 cm and 2.9 m
(iii) 0.93 m and 64 cm
Answer-9
Question -10.
Subtract (giving answer in metre) :
(i) 5.03 m from 19.6 m
(ii) 428 cm from 1033 m
(iii) 0.84 m from 122 cm
Answer-10
Question -11.
Add (giving answer in kg) :
(i) 2.06 kg and 57.864 kg
(ii) 778 gm and 1.939 kg
(iii) 0.065 kg and 4023 gm
Answer-11
Question -12.
Subtract (giving answer in kg) :
(i) 9.462 kg from 15.6 kg
(ii) 4317 gm from 23 kg
(iii) 0.798 kg from 4169 gm
Answer-12
Exercise – 15 E Decimal Fractions ICSE Class-6th Concise Selina Mathematics
Question -1.
The cost of a fountain pen is Rs. 13.25. Find the cost of 8 such pens.
Answer-1
Cost of 1 fountain Pen = Rs. 13.25
Cost of 8 fountain Pen = 13.25 x 8 = 106.00 = Rs. 106
Question- 2.
The cost of 25 identical articles is Rs. 218.25. Find the cost of one article.
Answer-2
Question -3.
The length of an iron rod is 10.32 m. The rod is divided into 4 pieces of equal lengths. Find the length of each piece.
Answer-3
The length of iron rod = 10.32 m
Dividing in 4 equal parts = 10.32/4 = 2.58 m
Question -4.
What will be the total length of cloth required to make 5 shirts, if 2.15 m of cloth is needed for each shirt?
Answer-4
Cloth required for each shirt = 2.15 m
Cloth required for 5 shirts = 2.15 x 5 m = 10.75 m
Question -5.
Find the distance walked by a boy in 1
Answer-5
Question -6.
83 note-books are sold at Rs. 15.25 each. Find the total money (in rupees) obtained by selling these note-books.
Answer-6
Sale price of 1 note-book = Rs. 15.25
Sale of 83 books = Rs. 15.25 x 83 = Rs. 1265.75 paise
Question -7.
If length of one bed-cover is 2.1 m, find the total length of 17 bed-covers.
Answer-7
Length of one bed-cover = 2.1 m
Length of 17 bed-cover = 17 x 2.1 = 35.7 m
Question -8.
A piece of rope is 10 m 67 cm long. Another rope is 16 m 32 cm long. By how much is the second rope longer than the first one?
Answer-8
Length of one rope = 10 m 67 cm
Length of another rope = 16 m 32 cm
Difference in length = 16 m 32⁄100 cm – 10 m 67⁄100 cm
= 16.32 m – 10.67 m
= 5.65 m or 5 m 65 cm.
Question -9.
12 cakes of soap together weigh 5 kg and 604 gm. Find the weight of
(i) One cake in both kg and gramme
(ii) 5 cakes in kg.
Answer-9
Question -10.
Three strings of lengths 50 m 75 cm; 68 m 58 cm and 121 m 3 cm, respectively, are joined together to get a single string of greatest length, And the length of the single string obtained.
If this single string is then divided into 12 equal pieces ; find the length of each piece.
Answer-10
1st string 50 m 75 cm = 50.75 m
2nd string 68 m 58 cm = 68.58 m
3rd string 121 m3 cm= 121.03 m
On joining three total length = 240.36 m
Now, one string = 240.36 m
Dividing 12 parts = 240.36⁄12 = 20.3 m.
Revision Exercise of Decimal Fractions for ICSE Class-6th Mathematics
Question -1.
Write the following decimal numbers in ascending order of value
(i) 5.054, 5.250, 5.245 and 5.0543
(ii) 62.443, 62.434, 62.344 and 62.444
Answer-1
(i) 5.054, 5.250, 5.245 and 5.0543
Writing them in like decimals :
5.0540, 5.2500, 5.2450, 5.0543
Now arranging in ascending order :
5.0540, 5.0543, 5.2450, 5.2500
=> 5.054 < 5.0543 < 5.245 < 5.250
(ii) 62.443, 62.434, 62.344 and 62.444
There are in like decimals :
Now writing in ascending order.
62.344, 62.434, 62.443, 62.444
or 62.344 < 62.434 < 62.443 < 62.444
Question -2.
What number added to 0.805 gives 1?
Answer-2
The required number will be formed by subtracting 0.805 from 1
Required number = 1 – 0.805 = 1.000 – 0.805 = 0.195
Question- 3.
What must be subtracted from 3 to get 2.462?
Answer-3
The required number can be formed by subtracting 2.462 from 3
Required number = 3 – 2.462 = 3.000 – 2.462 = 0.538
Question -4.
By how much should 83.407 be decreased to get 27.78?
Answer-4
The required number can be formed by subtracting 27.78 from 83.407
Required number = 83.407 – 27.78 = 83.407 – 27.780 = 55.627
Question -5.
Two articles weigh 32.674 kg and 40.038 kg respectively. Find :
(i) the total weight of both the articles.
(ii) the difference in the weights of both the articles.
Answer-5
Weight of first article = 32.674 kg
Weight of second article = 40.038 kg
(i) Total weight of both the articles = (32.674 + 40.038) kg = 72.712 kg
(ii) Difference between the weights of the articles = (40.038 – 32.674) kg = 7.364 kg
Question -6.
By how much does the sum of 34.07 and 15.239 exceed the sum of 16.40 and 27.08?
Answer-6
Sum of 34.07 and 15.239 = 34.070 + 15.239 = 49.309
and sum of 16.40 and 27.08 = 16.40 + 27.08 = 43.48
Difference between their sums = 49.309 – 43.48 = 49.309 – 43.480 = 5.829
Question 7.
The cost of 1 kg of fruit is Rs. 27.50. What is the cost of 3.6 kg of fruit?
Answer-7
Cost of 1 kg fruit = Rs. 27.50
Cost of 3.6 kg fruit = Rs. 27.50 x 3.6 = Rs. 99.00
Question -8.
Evaluate :
(i) 0.8 x 0.8 x 0.8
(ii) 0.8 ÷ 0.8 x 0.8
(iii) 0.8 x 0.8 ÷ 0.8
(iv) 0.8 ÷ 0.8 of 0.8
(v) 0.8 of 0.8 ÷ 0.8
Answer-8
(i) 0.8 x 0.8 x 0.8 = 0.512
(ii) 0.8 ÷ 0.8 x 0.8
Question -9.
Evaluate :
(i) 3.5 x (4.2 + 2.6)
(ii) 3.5 x 4.2 + 3.5 x 2.6
Are (i) and (ii) equal ?
Answer-9
(i) 3.5 x (4.2 + 2.6) = 3.5 x (6.8) = 23.8
(ii) 3.5 x 4.2 + 3.5 x 2.6 = 14.7 + 9.1 = 23.8
Yes results of (i) and (ii) are equal.
Question- 10.
Evaluate :
(i) (3.87 – 2.09) x 2.4
(ii) 3.87 x 2.4 – 2.09 x 2.4
Are (i) and (ii) equal ?
Answer-10
(i) (3.87 – 2.09) x 2.4 = 1.78 x 2.4 = 4.272
(ii) 3.87 x 2.4 – 2.09 x 2.4 = 9.288 – 5.016 = 4.272
Yes, results of (i) and (ii) are equal.
Question -11.
A 4.85 m long pole is divided into 5 equal parts. Find the length of each part.
Answer-11
Length of pole = 4.85 m
It is divided into 5 equal parts Length of each part = 4.85 ÷ 5 m = 0.97 m
Hence length of each part = 0.97 m
Question 12.
A car can run 16.8 km consuming one litre of petrol. How many kilometres will it run on 3.7 litres of petrol ?
Answer-12
A car can go in one litre = 16.8 km
It will go in 3.7 litres of petrol = 16.8 x 3.7 km = 62.16 km
Question -13.
A certain amount of money is distributed among 28 persons. If each person gets Rs. 62.45 and Rs. 5.78 is left, find the original amount of money.
Answer-13
Number of persons = 28
Each person gets = RS. 62.45
Total amount distributed to 28 persons = Rs. 62.45 x 28 = Rs. 1748.60
Amount left undistributed = Rs. 5.78
Total amount = Rs. 1748.60 + 5.78 = Rs. 1754.38
Question -14.
Complete the following table :
Answer-14
The given table has been completed as follows:
Question- 15.
The difference between two numbers is 47.364. If the smaller number is 31.855 ; find the bigger one.
Answer-15
Difference of two number = 47.364
Smaller number = 31.855
Bigger number = 47.364 + 31.855 = 79.219
— End of Decimal Fractions Solutions :–
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