Displacement Current Numerical Class-12 Nootan ISC Physics Solution Ch-13

Displacement Current Numerical Class-12 Nootan ISC Physics Solution Ch-13 Electromagnetic Waves Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.

Displacement Current Numerical Class-12 Nootan ISC Physics Solution Ch-13 Electromagnetic Waves

Board	ISC
Class	12
Subject	Physics
Book	Nootan
Chapter-13	Electromagnetic Waves
Topics	Numericals on Displacement Current
Academic Session	2025-2026

Numericals on Displacement Current

Class-12 Nootan ISC Physics Solution Ch-13 Electromagnetic Waves

Que-1: The rate of change of magnitude of the electric field in the empty space between the plates of a parallel plate capacitor is 4 x 10^8 Vm^-1 s^-1. If the area of each plate of the capacitor is 0.01 m², calculate the displacement current.

Ans- We have

dE/dt = 4 x 10^8 V m^-1 s^-1 , A = 0.01 m²

Then displacement current

Id = εo . A . dE/dt

= 8.85 x 10^-12 x 0.01 x 4 x 10^8

= 3.54 x 10^-5 A

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