Electric Potential Numerical on Electric Dipole Class-12 Nootan ISC Physics Ch-3. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
Electric Potential Numerical on Electric Dipole Class-12 Nootan ISC Physics
| Board | ISC |
| Class | 12 |
| Subject | Physics |
| Book | Nootan |
| Chapter-3 | Electric Potential |
| Topics | Numerical on Electric Dipole |
| Academic Session | 2025-2026 |
Numerical on Electric Dipole
Electric Potential Numerical on Electric Dipole Class-12 Nootan ISC Physics Ch-3
Que-30:Two point charges of +1.0 × 10^-6 C and -1.0 x 10^-6 C are 2.0 cm apart from each other. This electric dipole is situated in a uniform electric field of 1.0 x 10^5 V/m. What will be the maximum torque acting on it due to the field? What will be the work done for rotating it through 180° from the equilibrium position?
Ans: p = 2lq = 2 x 10^-2 x 1 x 10^-6
= 2 x 10^-8 cm
(i) again max torque = pE
= 2 x 10^-8 x 1 x 10^5
= 2 x 10^-3 Nm
(ii) again work done = +pE(1-cos θ)
for θ = 180°
W = +pE(1-(-1))
= 2 pE = 4 x 10^-3 J
Que-31: An electric dipole of length 2 cm is placed with its axis making an angle of 60° to a uniform electric field of 10^5 N/C. If it experiences a torque of 8√3 N-m, calculate (i) magnitude of the charge on the dipole and (ii) potential energy of the dipole.
Ans-31 (i) 𝜏 = pEsin
=> 8√3 = p x 10^5 x √3/2
=> p = 16 x 10^-5 = 2lq
=> 16 x 10^-5 = 2 x 10^-2 x q
=> q = 8 x 10^-3 C
(ii) again potential energy
= -pEcosθ
= -16 x 10^-5 x 10^5 x 1/2
= -8 J
Que-32: Two point charges of +3 µC and -3 µC are at a distance 3 x 10^-3 m apart from each other. Calculate (i) electric potential at a distance of 0.6 m from the dipole in broad-side-on position, (ii) electric potential at the same point after rotating the dipole through 90°.
Ans-32 given 2l = 3 x 10^-3 m
q = 3 x 10^-6 C
∴ dipole moment = 2lq = 3 x 10^-3 x 3 x 10^-6
= 9 x 10^-9 cm
(i) again potential at broad side on position is always zero
(ii) When dipole is rotated by 90° the aforesaid point will come at axial line then
E.f = 1/4πϵo 2p/r^3
= 9 x 10^9 x 2 x 10^-9/(0.6)^3
= 225 V
— : End Electric Potential Numerical on Electric Dipole Class-12 Nootan ISC Physics Ch-3 :–
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