Factorisation Class 9 OP Malhotra Exe-4A ICSE Maths Solutions Ch-4. We Provide Step by Step Solutions / Answer of Questions on Factorisation OP Malhotra Maths. Visit official Website CISCE for detail information about ICSE Board Class-9 Mathematics.
Factorisation Class 9 OP Malhotra Exe-4A ICSE Maths Solutions Ch-4
| Board | ICSE |
| Publications | S Chand |
| Subject | Maths |
| Class | 9th |
| Chapter-4 | Factorisation |
| Writer | OP Malhotra |
| Exe-4A | Factorisation by taking common |
| Edition | 2025-2026 |
Factorisation by Taking Common
To factorize an expression by taking out the common factor, identify the greatest common factor (GCF) of all terms and then write the expression as a product of the GCF and the remaining factors
Step for Factorisation by Taking Common
- Identify the Common Factor: Look for the largest number and/or variable that divides each term in the expression without leaving a remainder.
- Factor out the Common Factor: Divide each term in the expression by the common factor and place the common factor outside a set of parentheses.
- Write the Remaining Factors: The terms inside the parentheses will be the result of dividing each original term by the common factor.
Exercise- 4A
Factorisation Class 9 OP Malhotra Exe-4A ICSE Maths Solutions Ch-4
Factorise :
Que-1: 8x + 16y
Sol: 8x + 16y
= 8 (x – 2y)
Que-2: ax – 2ay
Sol: ax – 2ay
= a (x – 2y)
Que-3: 25xy – 50y
Sol: 15xy – 50y
= 25y (x – 2)
(H.C.F. of 25, 50 = 25)
Que-4: abc – ac
Sol: abc – ac
= ac (b – 1)
Que-5: – 121m – 11m²
Sol: – 121 m – 11m²
= 11 m (- 11 – m) (H.C.F. of 121, 11, = 11)
Que-6: a²b + ab²
Sol: a²b + ab²
= ab (a + b)
Que-7: 24x³y – 30x²y
Sol: 24x³y – 30x²y
= 6x²y (4x – 5)
(H.C.F. of 24, 30 = 6)
Que-8: – 9x³ – 12x² + 3x
Sol: – 9x³ – 12x² + 3x
= – 3x (3x² + 4x – 1)
(H.C.F. of 9, 12, 3 = 3)
Que-9: 25a²bc³ – 35ab²c³ + 45a³bc²
Sol: 25a²bc³ – 35ab²c³ + 45a³bc²
(H.C.F. of 25, 35, 45 = 5)
= 5abc² (5ac – 7bc + 9a²)
Que-10: – x – y – z
Sol: – x – y – z
= – 1 (x + y + z)
Que-11: x(x – y) + (x – y)
Sol: x (x – y) + (x – y)
= (x – y) (x + 1)
Que-12: (x + y) – (x + y)²
Sol: (x + y) – (x + y)²
= (x + y) – (x + y) (x + y)
= (x + y) (1 – x – y) .
Que-13: a (x – y) – b (y – x)
Sol: a (x – y) – b (y – x)
= a (x – y) + b (x – y)
= (x – y) (a + b)
Que-14: (a – b)4 + (a – b)³
Sol: (a – b)4 + (a – b)³
= (a – b)³ [(a – b) + 1 ]
= (a – b)³ (a – b + 1)
Que-15: (x – y)6 + (y – x)5
Sol: (x – y)6 + (y – x)5
= (x – y)6 – (x – y)5
= (x – y)5 (x – y – 1)
— : End of Factorisation Class 9 OP Malhotra Exe-4A ICSE Maths step by step Solutions :–
Return to :– OP Malhotra S Chand Solutions for ICSE Class-9 Maths
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