Factorisation Class 9 OP Malhotra Exe-4C ICSE Maths Solutions Ch-4. We Provide Step by Step Solutions / Answer of Questions on Factorisation Using squire of (a+b) or (a-b). Visit official Website CISCE for detail information about ICSE Board Class-9 Mathematics.
Factorisation Class 9 OP Malhotra Exe-4C ICSE Maths Solutions
| Board | ICSE |
| Publications | S Chand |
| Subject | Maths |
| Class | 9th |
| Chapter-4 | Factorisation |
| Writer | OP Malhotra |
| Exe-4C | Factorisation Using squire of (a+b) or (a-b) |
| Edition | 2025-2026 |
Factorisation Using squire of (a+b) or (a-b)
Factorizing an expression using the squares of (a+b) or (a-b) involves recognizing patterns and applying the formulas (a+b)² = a² + 2ab + b² and (a-b)² = a² – 2ab + b². These formulas can be used to factorize trinomials (expressions with three terms) that fit this pattern
Exercise- 4C
Factorisation Class 9 OP Malhotra Exe-4C ICSE Maths Solutions Ch-4
Factorise :
Que-1: x² + 4x + 4
Sol: x² + 4x + 4
= (x)² + (2 × x × 2) + (2)²
= (x + 2)²
Que-2: x² + 6x + 9
Sol: x² + 6x + 9
= (x)² + (2 x X x 3) + (3)²
= (x + 3)²
Que-3: x² – 10x + 25
Sol: x² – 10x + 25
= (x)² – (2 × x × 5) + (5)²
= (x – 5)²
Que-4: 4x² – 4x + 1
Sol: 4x² – 4x + 1
= (2x)² – (2 × 2x × 1) + (1)²
= (2x – 1)²
Que-5: 1 – 8x + 16x²
Sol: 1 – 8x + 16x²
= (1)² – (2 x 1 x 4x) + (4x)²
= (1 – 4x)²
Que-6: 49x4 + 168x²y² + 144y4
Sol: 49x4 + 168x²y² + 144y4
= (7x²)² + (2 x 7x² x 12y²) + (12y)²
= (7x² + 12y²)²
Que-7: x² + x +(1/4)
Sol: x² + x + (1/4)
= (x)² + (2 × x × (1/2)) + (1/2)²
= (x + (1/2))²
Que-8: 25p² + (5p/2q) + (1/16q²)
Sol: 25p² + (5p/2q) + (1/16q²)
= (5p)² + (2 x 5p x (1/4q)) x (1/4q)²
= (5p + (1/4q))²
— : End of Factorisation Class 9 OP Malhotra Exe-4C ICSE Maths Solutions Ch-4 :–
Return to :- OP Malhotra Class 9 ICSE Maths Solutions
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