Factorisation Class 9 OP Malhotra Exe-4D ICSE Maths Solutions Ch-4. We Provide Step by Step Solutions / Answer of Questions on Factorisation Using Difference of two squires. Visit official Website CISCE for detail information about ICSE Board Class-9 Mathematics.
Factorisation Class 9 OP Malhotra Exe-4D ICSE Maths Solutions Ch-4
| Board | ICSE |
| Publications | S Chand |
| Subject | Maths |
| Class | 9th |
| Chapter-4 | Factorisation |
| Writer | OP Malhotra |
| Exe-4D | Factorisation Using Difference of two squires |
| Edition | 2025-2026 |
Factorisation Using Difference of two squires
The difference of two squares factorization states that for any algebraic expressions a and b, the expression a² – b² can be factored as (a + b)(a – b). This method is based on recognizing the pattern where two perfect squares are subtracted from each other
Identify the pattern: Look for expressions in the form a² – b², where a and b are any algebraic terms.
Apply the formula: Factor the expression as (a + b)(a – b
Exercise- 4D
Factorisation Class 9 OP Malhotra Exe-4D ICSE Maths Solutions Ch-4
Factorise the following :
Que-1: x² – 4
Sol: x² – 4
= (x)² – (2)²
= (x + 2) (x – 2)
Que-2: y² – 25
Sol: y² – 25
= (y)² – (5)²
= (y + 5) (y – 5)
Que-3: a² -1
Sol: a² – 1
= (a)² – (1)²
= (a + 1) (a – 1)
Que-4: 9z² – 64
Sol: 9z² – 64
= (3z)² – (8)²
= (3z + 8) (3z – 8)
Que-5: 9x² – b²
Sol: 9x² – b²
= (3x)² – (b)²
= (3x + b) (3x – b)
Que-6: 25 – x²y²
Sol: 25 – x²y²
= (5)² – (xy)²
= (5 + xy) (5 – xy)
Que-7: 81a²x² – 49b²y²
Sol: 81a²x² – 49b²y²
= (9ax)² – (7by)²
= (9 ax + 7by) (9ax – 7by)
Que-8: x² – (1/4)
Sol: x² – (1/4)
= (x)² – (1/2)²
= (x + (1/2)) (x – (1/2))
Que-9: – 25 + (1/64)b²
Sol: – 25 + (1/64) b²
= (1/64) b² – 25
= (1/8b)² – (5)²
= ((1/8b) + 5) ((1/8b) – 5)
Que-10: (a²/9) − (b²/16)
Sol: (a²/9) – (b²/16)
= (a/3)² – (b/4)²
= {(a/3)+(b/4)} {(a/3)-(b/4)}.
Que-11: 2.25a² – b²
Sol: 2.25a² – b²
= (1.5a)² – (b)²
= (1.5a + b) (1.5a – b)
Que-12: 36a8 – 121
Sol: 36a8 – 121
= (6a4)² – (11)²
= (6a4 + 11) (6a4 – 11)
Evaluate the following :
Que-13: 54² – 36²
Sol: (54)² – (36)²
= (54 + 36) (54 – 36) {∵ a² – b² = (a + b) (a – b)}
= 90 x 18 = 1620.
Que-14: (3.2)² – (1.8)²
Sol: (3.2)² – (1.8)²
= (3.2 + 1.8) (3.2 – 1.8) {∵ a² – b² = (a + b) (a – b)}
= 5.0 x 1.4
= 7.0 = 7.
— : End of Factorisation Class 9 OP Malhotra Exe-4C ICSE Maths Solutions Ch-4 :–
Return to :- OP Malhotra Class 9 ICSE Maths Solutions
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