Factorisation Class 9 RS Aggarwal MCQs Goyal Brothers ICSE Maths Solutions

Factorisation Class 9 RS Aggarwal MCQs Goyal Brothers ICSE Maths Solutions of Ch-4. In this article you will learn Multiple Choice Questions on Factorisation easily. Visit official Website CISCE for detail information about ICSE Board Class-9.

Factorisation Class 9 RS Aggarwal MCQs Goyal Brothers ICSE Maths Solutions of Ch-4

Board	ICSE
Subject	Maths
Class	9th
Chapter-4	Factorisation
Writer	RS Aggrawal
Topics	MCQs on Factorisation
Academic Session	2024-2025

MCQs on Factorisation

(Factorisation Class 9 RS Aggarwal Goyal Brothers ICSE Maths Solutions of Ch-4)

Page- 65,66

Multiple Choice Questions:

Que-1: b²-ac-bc+ab =

(a) (a+b)(b-c) (b) (b-a)(b-c) (c) (a-b)(b+c) (d) (a-b)(b-c)

Sol: (a) (a+b)(b-c)

Reason: b²-ac-bc+ab
b²+ab-ac-bc
b(b+a)-c(a+b)
(a+b)(b-c).

Que-2: The value of (1+x)²(1+y²) – (1+x²)(1+y)² is :

(a) 2(x-y)(1+xy) (b) (x-y)(1-xy) (c) 2(x-y)(1-xy) (d) 2(x+y)(1-xy)

Sol: (c) 2(x-y)(1-xy)

Reason: (1 + x)²(1 + y²) – (1 + x²)(1 + y)²
(1 + 2x + x²)(1 + y²) – (1 + x²)(1 + 2y + y²)
1 + y² + 2x + 2xy² + x² + x²y² – (1 + 2y + y² + x² + 2x²y + x²y²)
1 + y² + 2x + 2xy² + x² + x²y² – 1 – 2y – y² – x² – 2x²y – x²y²
2x + 2xy² – 2y – 2x²y
2x – 2y + 2xy² – 2x²y
2(x – y) + 2xy(y – x)
2(x – y) – 2xy(x – y)
2(x – y)(1 – 2xy)

Que-3: x^4 – y^4 = …………….. (x-y)(x²+y²)

(a) 0 (b) 1 (c) (x-y) (d) (x+y)

Sol: (d) (x+y)

Reason: (x²)² – (y²)² + (x+y)(x-y)
(x² + y² )(x² – y²) + (x+y)(x-y)
(x²+y²)(x+y)(x-y) + (x+y)(x-y)
(x+y)(x-y) ( x²+y²+1)
(x+y) is answer.

Que-4: 16(2a-b)² – 9(a+b)² =

(a) (5a-7b)(11a-b) (b) (5a+7b)(11a-b) (c) (5a-7b)(11a+b) (d) (5a+7b)(11a+b)

Sol: (a) (5a-7b)(11a-b)

Reason: 16(2a-b)² – 9(a+b)²
[4(2a-b)]² – [3(a+b)]²
[4(2a-b)+3(a+b)] [4(2a-b)-3(a+b)]
[8a-4b+3a+3b] [8a-4b-3a-3b]
(11a-b)(5a-7b).

Que-5: Factorisation of 3a(3a+2c) – 4b(b+c) is :

(a) (3a+2b)(3a+2b+2c) (b) (3a-2b)(3a-2b+2c) (c) (3a-2b)(3a+2b+2c) (d) (3a-2b)(3a+2b-2c)

Sol: (c) (3a-2b)(3a+2b+2c)

Reason: 3a(3a+2c) – 4b(b+c)
(3a*3a+3a*2c)-(4b*b+4b*c)
= 9a²+6ac-4b²+4bc
= (9a²-4b²)- (6ac+4bc)
= (3a+2b)(3a-2b)-2c(3a+2b)
= (3a+2b)(3a-2b-2c).

Que-6: 12a²-27b² =

(a) 3(2a+3b²)(2a-b²) (b) (2a+3b²)(3a-3b²) (c) 3(2a+3b²)(a-3b²) (d) 3(2a+3b²)(2a-3b²)

Sol: (d) 3(2a+3b²)(2a-3b²)

Reason: 12a²-27b²
3(4a²-9b²)
3[(2a)²-(3b)²]
3(2a+3b)(2a-3b).

Que-7: √3x²+11x+6√3 =

(a) (√3x+2)(x-3√3)(b) (√3x+2)(x+3√3) (c) (√3x-2)(x-3√3)(d) (x-2)(x+3√3)

Sol: (b) (√3x+2)(x+3√3)

Reason: √3x²+11x+6√3
= √3x²+9x+2x+6√3
=√3x(x+3√3)+2(x+3√3)
=(√3x+2)(x+3√3)

Que-8: 1-x^9 = (1-x)(1+x+x²) …………..

(a) (1-x³+x^6) (b) (1+x³+x^6) (c) (1-x³-x^6) (d) (1+x³-x^6)

Sol: (b) (1+x³+x^6)

Reason: 1 – x⁹ = (1 – x)(1 + x + x²)
1 – x⁹ = 1³ – (x³)³
a³ – b³ = (a – b)(a² + ab + b²)
= (1 – x³)(1² + (1 × x³) + (x³)²)
= (1³ – x³)(1 + x³ + x⁶)
= (1 – x)(1² + (1 × x) + x²)(1 + x³ + x⁶)
= (1 – x)(1² + x + x²)(1 + x³ + x⁶)
(1 + x³ + x⁶) is a answer.