# Heat and Temperature HC Verma Exercise Questions Solutions Vol-2 Chapter-23

Heat and Temperature HC Verma Exercise Questions Solutions Vol-2 Chapter-23 Concept of Physics Vol-2 for ISC Class-12. Step by Step Solution of  Exercise  Questions of Ch-23 Heat and Temperature  HC Verma Concept of Physics . Visit official Website CISCE for detail information about ISC Board Class-11 Physics.

## Heat and Temperature HC Verma Exercise Questions Solutions Vol-2 Chapter-23

 Board ISC and other board Publications Bharti Bhawan Publishers Ch-23 Heat and Temperature Class 11 Vol 2nd writer H C Verma Book Name Concept of Physics Topics Solution of Exercise Questions Page-Number 12, 13, 14

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Objective-I

Objective-II

Exercise

### Heat and Temperature Exercise HC Verma Questions Solutions

(HC Verma Ch-23 Concept of Physics Vol-2 for ISC Class-12)

Page-12,

#### Question-1 :-

The steam point and the ice point of a mercury thermometer are marked as 80° and 20°. What will be the temperature on a centigrade mercury scale when this thermometer reads 32°?

Given:
Ice point of a mercury thermometer, T0 = 20° C
Steam point of a mercury thermometer, T100 = 80° C
Temperature on thermometer that is to be calculated in centigrade scale, T1 = 32° C​
Temperature on a centigrade mercury scale, T, is given as:

Therefore, the temperature on a centigrade mercury scale will be 20oC.

Now , ΔT = T2 -T1 =T2-10 ° C

⇒ T2 = ∆T + T1

= 208.81 + 10

⇒ T2 = 218.8 ≅ 219°C

Therefore, ​the temperature at which the ball will fall is 219 °C.

#### Question-21 :-

A glass window is to be fit in an aluminium frame. The temperature on the working day is 40°C and the glass window measures exactly 20 cm × 30 cm. What should be the size of the aluminium frame so that there is no stress on the glass in winter even if the temperature drops to 0°C? Coefficients of linear  expansion for glass  and aluminium are 9.0 × 10–6 °C–1 and 24 ×100–6°C–1 , respectively.

Given:
At 40oC, the length and breadth of the glass window are 20 cm and 30 cm, respectively.
Coefficient of linear expansion of glass,

αg =  9.0 × 10–6 °C–1

Coefficient of linear expansion for aluminium,

αAl = 24 ×100–6 °C–1

The final length of aluminium should be equal to the final length of glass so that there is no stress on the glass in winter, even if the temperature drops to 0 °C.
​Change in temperature,

Δθ  = 40 °C

Let the initial length of aluminium be l.

l(1−αAl∆θ)=20(1−αg∆θ)

⇒ l(1−24×10–6×40) = 20(1−9×10–6×40)

⇒ l(1−0.00096) = 20(1−0.00036)

Therefore, the size of the aluminium frame should be 20.012 cm × 30.018 cm.

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