Kinetic Theory of Gases Obj-2 HC Verma Solutions Vol-2 Ch-24
Kinetic Theory of Gases Obj-2 HC Verma Solutions Vol-2 Ch-24 Concept of Physics for Class-12. Step by Step Solutions of Objective -2 (MCQ-2) Questions of Chapter-24 Kinetic Theory of Gases (Concept of Physics) .Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
Kinetic Theory of Gases Obj-2 (MCQ-2) HC Verma Solutions Ch-24 Vol-2 Concept of Physics for Class-12
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|Publications||Bharti Bhawan Publishers|
|Chapter-24||Kinetic Theory of Gases|
|Book Name||Concept of Physics|
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Kinetic Theory of Gases Obj-2 (MCQ-2) HC Verma
HC Verma Solutions of Ch-24 Vol-2 Concept of Physics for Class-12
Consider a collision between an oxygen molecule and a hydrogen molecule in a mixture of oxygen and hydrogen kept at room temperature. Which of the following are possible?
(a) The kinetic energies of both the molecules increase.
(b) The kinetic energies of both the molecules decrease.
(c) kinetic energy of the oxygen molecule increases and that of the hydrogen molecule decreases.
(d) The kinetic energy of the hydrogen molecule increases and that of the oxygen molecule decreases.
The options (c) and (d) are correct
According to Kinetic theory, postulates collision between molecules are elastic. This means that kinetic energy after any collision is conserved because while one one gains kinetic energy, another loses it. Both options, (c) and (d) consider the conservation of kinetic energy in the collision.
Consider a mixture of oxygen and hydrogen kept at room temperature. As compared to a hydrogen molecule an oxygen molecule hits the wall
(a) with greater average speed
(b) with smaller average speed
(c) with greater average kinetic energy
(d) with smaller average kinetic energy
The option (b) with smaller average speed is correct
The average speed of molecules is given by √8kT/πm .
We observe that greater the mass, lesser is the average speed of the molecule. Since an oxygen molecule is heavier than a hydrogen molecule, the oxygen molecule will hit the wall with smaller average speed.
Which of the following quantities is zero on an average for the molecules of an ideal gas in equilibrium?
(a) Kinetic energy
The option (b) Momentum is correct
The molecules move in all possible directions in an ideal gas at equilibrium. Since momentum is a vector quantity for every direction of motion of the molecules, there exists an opposite direction of motion of the other. Hence, the average momentum is zero for an ideal gas at equilibrium.
Keeping the number of moles, volume and temperature the same, which of the following are the same for all ideal gases?
(a) Rms speed of a molecule
(d) Average magnitude of momentum.
The option (c) Pressure is correct
Pressure of an ideal gas is given by PV = 1/3 mnu2 .
The average momentum of a molecule in a sample of an ideal gas depends on
(b) number of moles
(d) none of these.
The option (d) none of these. is correct
Average momentum of a gas sample is zero, so it does not depend upon any of these parameters.
(a) The kinetic energy of 1 mole
(b) The kinetic energy of 1 g
(c) The number of molecules in 1 mole
(d) The number of molecules in 1 g
The options (a) and (c) are correct
Number of molecules in 1 mole of an ideal is the same for all ideal gases because ideal gases obey Avogadro’s law.
Consider the quantity MkT/pV of an ideal gas where M is the mass of the gas. It depends on the
(a) temperature of the gas
(b) volume of the gas
(c) pressure of the gas
(d) nature of the gas.
The option (d) nature of the gas. is correct
In an ideal gas, the equation of state is given by PV=nRT
Multiplying both sides by mass of the gas M, we get
Now, n N_A gives the total number of molecules of the gas .
gives the mass of a single molecule .
is the mass of a single molecule of the gas, Molecular mass is a property of the gas .
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