Magnetic Classification of Substances Numerical Class-12 Nootan ISC Physics Solution Ch-10. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
Magnetic Classification of Substances Numerical Class-12 Nootan ISC Physics Solution
| Board | ISC |
| Class | 12 |
| Subject | Physics |
| Book | Nootan |
| Chapter-10 | Magnetic Classification of Substances |
| Topics | Numericals on Magnetic Classification of Substances |
| Academic Session | 2025-2026 |
Numericals on Magnetic Classification of Substances
Class-12 Nootan ISC Physics Solution Ch-10.
Que-1. A paramagnetic salt has a magnetic moment of 5.0 A m² at a temperature of 4 K in a magnetic field of 1.0 T. Find its magnetic moment at a temperature of 3 K in a magnetic field of 1.5 T.
Ans- m ∝ B/T
=> m1/m2 = B1/B2 x T1/T2
=> 5/m2 = 1/1.5 x 3/4 = 1/2
=> m2 = 10 A m²
Que-2. A cylindrical rod magnet has a length of 5.0 cm and a diameter of 1.0 cm. It has a uniform magnetization of 5.3 x 10³ A m^-1. Find its magnetic moment.
Ans- M = m/v
=> M = Magnetization
V = Volume
m = magnetic dipole moment
=> m = MV
=> 5.3 x 10³ x 0.05 x 3.14 x (0.005)²
=> 20.8 x 10^-3 A m²
Que-3. The magnetic field induction in a material placed in a magnetizing field of 2000 A m^-1 is 1.0 N A^-1 m^-1. Find (i) magnetic permeability, (ii) relative permeability, (iii) magnetic susceptibility and (iv) intensity of magnetization for the material.
Ans-(i) μ = B/H = 1/2000 = 5 x 10^-4 N A^-2
(ii) μr = μ/μo = 5 x 10^-4 / 4π x 10^-7 = 398
(iii) Xm = μr – 1 = 398 – 1 = 397
(iv) M = XmH = 397 x 2000 = 7.94 x 10^5 A m^-1
Que-4. What is the value of the magnetic susceptibility of aluminium, if its relative permeability is 1.000022? (ISC 2011, 07)
Ans- μr = 1 + Xm
=> Xm = μ – 1
=> 1.000022 – 1 = 0.000022
— : End of Magnetic Classification of Substances Numerical Class-12 Nootan ISC Physics Solution Ch-10. :–
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