# Magnetic Field Exercise HC Verma Solutions Ch-34 Vol-2

Magnetic Field Exercise HC Verma Solutions Ch-34 Vol-2 Concept of Physics Vol-2 for ISC Class-12. Step by Step Solution of Exercise Questions of Ch-34 Magnetic Field HC Verma Concept of Physics. Visit official Website CISCE for detail information about ISC Board Class-11 Physics.

## Magnetic Field Exercise HC Verma Solutions Ch-34 Vol-2

 Board ISC and other board Publications Bharti Bhawan Publishers Ch-34 Magnetic Field Class 12 Vol 2nd writer H C Verma Book Name Concept of Physics Topics Solution of Exercise Questions Page-Number 230, 231, 232, 233, 234, 235

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Magnetic Field Exercise HC Verma Questions Solutions

### (HC Verma Ch-34 Concept of Physics Vol-2 for ISC Class-12)

(Page-230)

#### Question-1 :-

An alpha particle is projected vertically upward with a speed of 3.0 × 104 km s−1 in a region where a magnetic field of magnitude 1.0 T exists in the direction south to north. Find the magnetic force that acts on the α-particle.

Answer-1 :-

Given:
Upward speed of the alpha particle,

v = 3 × 104 km/s

= 3 × 107 m/s
Magnetic field,

B = 1.0 T
The direction of the magnetic field is from south to north.
Charge of the alpha particle,

q = 2e,
where e is the charge of an electron.
= 2 × 1.6 × 10−19 C,

Magnetic force acting on the α-particle,

F‾ = qv‾ × B‾ in90°
= 2 × 1.6 × 10−19 × 3 × 10−7
= 9.6 × 10−19 N , towards west

The direction of magnetic force can be found using Fleming’s left-hand rule.

#### Question-2 :-

An electron is projected horizontally with a kinetic energy of 10 keV. A magnetic field of strength 1.0 × 10−7 T exists in the vertically upward direction.
(a) Will the electron deflect towards the right or left of its motion?
(b) Calculate the sideways deflection of the electron while travelling through 1 m. Make appropriate approximations.

Answer-2 :-

Given:
The kinetic energy of the electron projected in the horizontal direction, K.E = 10 keV = 1.6 × 10−15 J
Magnetic field,

B = 1 × 10−7 T
The direction of magnetic field is vertically upward.
(a) The direction can be found by the right-hand screw rule. So, the electron will be deflected towards left.
(b) Kinetic energy,

t= Time taken to cross the magnetic field
As there is no force acting on the electron in the horizontal direction, the velocity of the electron remain constant in this direction.
So, the time taken to cross a distance of 1m in the horizontal direction in the magnetic field,

s = 0.0148 = 1.5 × 10−2 cm

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