ML Aggarwal Pythagoras Theorem MCQs Class 9 ICSE Maths Solutions Ch-12. Step by Step Solutions of MCQs on Pythagoras Theorem of ML Aggarwal for ICSE Class 9th Mathematics. Visit official website CISCE for detail information about ICSE Board Class-9.
ML Aggarwal Pythagoras Theorem MCQs Class 9 ICSE Maths Solutions Ch-12
Board | ICSE |
Subject | Maths |
Class | 9th |
Chapter-12 | Pythagoras Theorem |
Topics | Solution of MCQs |
Academic Session | 2024-2025 |
MCQs on Pythagoras Theorem
ML Aggarwal Pythagoras Theorem Class 9 ICSE Maths Solutions Ch-12
Question 1. In a ∆ABC, if AB = 6√3 cm, BC = 6 cm and AC = 12 cm, then ∠B is
(a) 120
(b) 90°
(c) 60°
(d) 45°
Answer : (b) 90° is correct
Hint: Here largest side is 12 cm.
If square of the hypotenuse is equal to square of other two sides, then it is a right angled triangle.
∴ c² = a² + b²
AC² = AB² + BC²
(12)² = (63)² + (6)²
44 = 36 × 3 + 36
144 = 108 + 36
144 = 144
∴ ∆ABC is a right angled triangle and angle opposite to hypotenuse, ∠B = 90°.
Question 2. If the sides of a rectangular plot are 15 m and 8 m, then the length of its diagonal is
(a) 17 m
(b) 23 m
(c) 21 m
(d) 17 cm
Answer : (d) 17 cm is correct
Hint: so the the length of this diagonal is given by square root of sum of squares of sides.
length of diagonal =[152 +8)2 ])1/2
=(225 + 64)2 1/2
=(289)2 1/2=17
hence the length of diagonal is 17 m.
Question 3. The lengths of the diagonals of a rhombus are 16 cm and 12 cm. The length of the side of the rhombus is
(a) 9 cm
(b) 10 cm
(c) 8 cm
(d) 20 cm
Answer : (b) 10 cm is correct
Hint: A rhombus ABCD is there, the diagonals bisect each other at a point O. Let the side of rhombus be AB.
1st diagonal = AC =16 cm
2nd diagonal = BD = 12 cm
AO = AC/2 = 16/2= 8 cm
OB = BD/2 = 12/2 = 6 cm
By Pythagoras theorem,
AO2+ OB2 = AB2
8^2+6^2 = AB2
64+36 = AB2
100 = AB2
√100 = AB
10 cm = AB
So the length of the side is 10 cm.
Question 4. If a side of a rhombus is 10 cm and one of the diagonals is 16 cm, then the length of the other diagonals is
(a) 6 cm
(b) 12 cm
(c) 20 cm
(d) 12 cm
Answer : (b) 12 cm is correct
Hint: One diagonal of rhombus = 16 cm
Side = 10 cm
Question 5. If a ladder 10 m long reaches a window 8 m above the ground, then the distance of the foot of the ladder from the base of the wall is
(a) 18 m
(b) 8 m
(c) 6 m
(d) 4 m
Answer : (c) 6 m is correct
Hint: Length of ladder = 10 m
Height of window = 8 m
Question 6. A girl walks 200 m towards East and then she walks I5O m towards North. The distance of the girl from the starting point is
(a) 350 m
(b) 250 m
(c) 300 m
(d) 225 m
Answer : (b) 250 m is correct
Hint: A girl walks 200 m towards East and then walks I5O m towards North
Distance of girls from the stating point
Question 7. A ladder reaches a window 12 m above the ground on one side of the street. Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 9 m high. If the length of the ladder is 15 m, then the width of the street is
(a) 30 m
(b) 24 m
(c) 21 m
(d) 18 m
Answer : (c) 21 m is correct
Hint: Height of window = 12 m
Length of ladder = 15m
In right triangle ABC
EC = 12 m
width of street EB = EC + CB
= 9 + 12 = 21m
— : End of ML Aggarwal Pythagoras Theorem MCQs Class 9 ICSE Maths Solutions :–
Return to :- ML Aggarawal Maths Solutions for ICSE Class-9
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