Mean Peak and rms Values of AC Numerical Class-12 Nootan ISC Physics Solution Ch-12 Alternating Current. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
Mean Peak and rms Values of AC Numerical Class-12 Nootan ISC Physics Solution Ch-12 Alternating Current
| Board | ISC |
| Class | 12 |
| Subject | Physics |
| Book | Nootan |
| Chapter-12 | Alternating Current. |
| Topics | Numericals on Mean Peak and rms Values of AC |
| Academic Session | 2025-2026 |
Numericals on Mean Peak and rms Values of AC
Class-12 Nootan ISC Physics Solution Ch-12 Alternating Current.
Que-1: An alternating current is given by I = 50 sin 100 πt. Find the frequency of current, mean current during a positive half-cycle, virtual current and the current at t = (1/300) s.
Ans-
Que-2: A hot-wire ammeter in an AC circuit reads 10 A (rms value). What is the peak current?
Ans- peak current = Iv √2
=> 10 x √2 = 10 x 1.414
=> 14.1 A
Que-3: If the peak alternating current in a circuit is 21.2 A, find out the reading of an ammeter connected in the circuit.
Ans- Iv = Io/√2
=> 21.2/√2 = 15 A
Que-4: The equation of an AC voltage is V = 100√2 sin(100πt). Find the rms value and the frequency of the voltage.
Ans- V = 100√2 sin100 πt
=> Vo sin2π ft
=> Vo = 100√2
=> Vrms = Vo/√2 =100 V
and f = 50 Hz
Que-5: The electric main in a house is marked 220 V-50 Hz. Write down the equation for the instantaneous voltage. The only variable in this equation should be t. (ISC 2005)
Ans- f = 50 Hz
Vo = Vrms√2 = 220√2 volt
=> V = Vo sin2π ft
=> 220√2 sin100π t
Que-6: The current and voltage in a circuit are given by I = 3.5 sin (628t + 30°) ampere, V = 28 sin (628t – 30°) volt. Determine (i) peak value, (ii) root-mean-square value, (iii) time-period of the current and (iv) phase difference between voltage and current.
Ans- I = 3.5 sin (628 t + 30°)
=> Io = 3.5 A
Irms = 3.5/√2 = 2.47 A
628 t = 2πt/T = 6.25 t /T
=> T = 0.01
and Δφ = 30°-(-30°) = 60°
— : End of Mean Peak and rms Values of AC Numerical Class-12 Nootan ISC Physics Solution Ch-12. :–
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