ML Aggarwal Data Handling Exe-19.2 Class 8 ICSE Ch-19 Maths Solutions

ML Aggarwal Data Handling Exe-19.2 Class 8 ICSE Ch-19 Maths Solutions. We Provide Step by Step Answer of  Exe-19.2 Questions for Data Handling as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-8.

ML Aggarwal Data Handling Exe-19.2 Class 8 ICSE Maths Solutions

Board ICSE
Publications Avichal Publishig Company (APC)
Subject Maths
Class 8th
Chapter-19 Data Handling
Writer ML Aggarwal
Book Name Understanding
Topics Solution of Exe-19.2 Questions
Edition 2023-2024

Data Handling Exe-19.2

ML Aggarwal Class 8 ICSE Maths Solutions

Page-330

Question 1. The following data represents the different number of animals in a zoo. Prepare a pie chart for the given data.

Animals Deer Tiger Elephant Giraffe Reptiles
Number of animals 40 10 30 15 25

Answer:

Animals Number of animals Central degree
DeerTiger

Elephant

Giraffe

Reptiles

4010

30

15

25

(3600 × 40) / 120 = 1200(3600 × 10) / 120 = 300

(3600 × 30) / 120 = 900

(3600 × 15) / 120 = 450

(3600 × 25) / 120 = 750

Total 120 3600

Pie chart for the data is given below:

Question 1. The following data represents the different number of animals in a zoo. Prepare a pie chart for the given data.


Data Handling Exe-19.2

ML Aggarwal Class 8 ICSE Maths Solutions

Page-331

Question 2. The following data represents the monthly expenditure of a family (in T) on various items. Draw a pie chart to represent this data.

Items Food House rent Education Savings Health Others
Expenditure (in Rs) 12500 5000 7500 10000 5000 10000

Answer:

Items Expenditure (in Rs) Central angles
FoodHouse rent

Education

Savings

Health

Others

125005000

7500

10000

5000

10000

(12500 × 3600) / 50000 = 900(5000 × 3600) / 50000 = 360

(7500 × 3600) / 50000 = 540

(10000 × 3600) / 50000 = 720

(5000 × 3600) / 50000 = 360

(10000 × 3600) / 50000 = 720

Total 50000 3600

Pie chart representing the above given data is given:

Question 2. The following data represents the monthly expenditure of a family (in T) on various items. Draw a pie chart to represent this data.

Question 3. The following data represents the percentage distribution of the expenditure incurred in publishing a book.

Items Paper cost Printing cost Binding Royalty Transportationcost Promotion cost
Expenditure (in %) 25% 20% 20% 10% 15% 10%

Draw a pie chart to represent this data.

Answer:

Items Expenditure Central angles
Paper costPrinting cost

Binding

Royalty

Transportation cost

Promotion cost

25%20%

20%

10%

15%

10%

(3600 × 25) / 100 = 900(3600 × 20) / 100 = 720

(3600 × 20) / 100 = 720

(3600 × 10) / 100 = 360

(3600 × 15) / 100 = 540

(3600 × 10) / 100 = 360

Total 100% 3600

Pie chart representing the above given data is given:
Question 3. The following data represents the percentage distribution of the expenditure incurred in publishing a book.

Question 4. The following data represents the number of students got admission in different streams of a college:

Stream Science Arts Commerce Law Management
Number of students 400 300 500 250 350

Draw a pie chart to represent this data.

Answer:

Stream Number of students Central angle
ScienceArts

Commerce

Law

Management

400300

500

250

350

(400 × 3600) / 1800 = 800(300 × 3600) / 1800 = 600

(500 × 3600) / 1800 = 1000

(250 × 3600) / 1800 = 500

(350 × 3600) / 1800 = 700

Total 1800 3600

Pie chart representing the above given data is given below:
Question 4. The following data represents the number of students got admission in different streams of a college:

Question 5. The adjoining pie chart shows the expenditure of a country on various sports during year 2012. Study the pie chart carefully and answer the following questions:

Question 5. The adjoining pie chart shows the expenditure of a country on various sports during year 2012. Study the pie chart carefully and answer the following questions:

(i) What percent of total expenditure is spent on cricket?
(ii) How much percent more is spent on hockey than that on tennis?
(iii) If the total amount spent on sports in 2012 is ₹1,80,00,000, then find amount spent on Badminton,
(iv) If the total amount spent on sports in 2012 is ₹2,40,00,000 then find the amount spent on cricket and hockey together.

Answer:

The given pie chart represents the expenditure of a country on various sports during the year 2012.

(i) Given that expenditure on a cricket = 900

(90 / 3600) × 100% = 25%

Therefore, 25% of expenditure is spent on cricket

(ii) Given that expenditure on a hockey = 750

(70 / 3600) × 100% = (125 / 6)%
= 20(5/6)%

Expenditure on tennis = 500

Hence, (50 / 3600) × 100% = (125 / 9)% = 13.9%

(125 / 6) – (125 / 9) = 125 / 18

= (375 – 250) / 18

= 125 / 18

= 6.95% more

Therefore, 6.95% more is spent on hockey than that on tennis

(iii) Total amount spent on sports = Rs 1,80,00,000

Total amount spent on Badminton = Rs 1,80,00,000 × (60 / 3600)

= Rs 30,00,000

(iv) If the total amount spent on sports = 2,40,00,000

Total amount spent on cricket and hockey together = 900 + 750

= 1650

= (1650 / 3600) × 2, 40, 00,000

= 1, 10, 00, 000

Question 6. The adjoining pie chart shows the number of students enrolled in class VI to class X of a school.

Question 6. The adjoining pie chart shows the number of students enrolled in class VI to class X of a school.
If 1440 students are enrolled from VI to X, then answer the following questions:

(i) How many students are enrolled in class VIII?
(ii) How many students are more in class IX than in class X?
(iii) What is the sum of students enrolled in VII and VIII?
(iv) Find the ratio of students enrolled in VI to students enrolled in X.

Answer:

The given pie chart represents the enrolment of students from class VI to class X in a school.

Total number of students enrolled from VI to X = 1440 students

(i) Enrolment of class VIII = (85 / 3600) × 1440 = 340 students

(ii) Difference in X and IX class enrolment = 750 – 500

= 250

(25 / 3600) × 1440 = 100 students

Therefore, 100 students are more in class IX than in class X

(iii) Sum of students enrolled in VII and VIII classes = 700 + 850

= 1550

(155 / 3600) × 1440 = 620 students

Therefore, the sum of students enrolled in Classes VI and VIII = 620 students

(iv) Ratio between the students enrolled in VI to students enrolled in X classes = 800: 500

= 8: 5

Therefore, the ratio between the students enrolled in VI to students enrolled in X classes is 8: 5

— End of Data Handling Exe-19.2 Class 8 ICSE Maths Solutions :–

Return to : ML Aggarwal Maths Solutions for ICSE Class -8

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