Mutual Induction Numerical Class-12 Nootan ISC Physics Solution Ch-11 Electromagnetic Induction. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
Mutual Induction Numerical Class-12 Nootan ISC Physics Solution Ch-11 Electromagnetic Induction
| Board | ISC |
| Class | 12 |
| Subject | Physics |
| Book | Nootan |
| Chapter-11 | Electromagnetic Induction. |
| Topics | Numericals on Mutual Induction |
| Academic Session | 2025-2026 |
Numericals on Mutual Induction
Class-12 Nootan ISC Physics Solution Ch-11 Electromagnetic Induction.
Que-27: Two coils C1 and C2 are placed close to each other. The magnetic flux φ2 linked with the coil C2 varies with the current I1 flowing in coil C1, as shown in the figure. Find (i) the mutual inductance of the arrangement, and(ii) the rate of change of current (dl1/dt) that will induce an emf of 100 V in coil C2.
Ans- (i) M = φ2/I1
=> 10/4 = 2.5 H
(ii) e2 = M (di1/dt)
=> 100 = -2.5 (di1/dt)
=> (di1/dt) = -40 A s^-1
Que-28: The current in the primary of a transformer drops from 5 to 3 A in 2 s. If the mutual inductance between the two coils is 0.16 H, then calculate the induced emf in the secondary.
Ans- e2 = M (di1/dt)
=> 0.16 x (5-3/2) = 0.16 V
Que-29: The mutual inductance between two coils is 0.15 H. If a current of 20 A in the primary coil is cut off in 0.05 s, find the emf induced in the secondary coil. If the secondary coil has 60 turns, then find the flux-change in it.
Ans- e2 = M (di1/dt)
=> 0.15 x (20/0.05) = 60 V
e2 = N(dφ2/dt)
=> dφ2 = e2 x dt/N
=> 60 x 0.05 / 60 = 0.05 Wb
— : End of Mutual Induction Numerical Class-12 Nootan ISC Physics Solution Ch-11 Electromagnetic Induction. Step by step solutions of Kumar and Mittal . :–
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