Reflection of Light Exe-7B Numericals Concise Physics ICSE Class-9 Selina Publishers

Reflection of Light Exe-7B Numericals Concise Physics ICSE Class-9 Selina Publishers. There is the solutions of Numerical Questions of your latest textbook which is applicable in 2024-25 academic session. Visit official Website CISCE for detail information about ICSE Board Class-9.

Reflection of Light Exe-7B Numericals

Concise Physics ICSE Class-9 Selina Publishers

Board	ICSE
Class	9
Subject	Physics
Writer / Publication	Concise Selina Publishers
Chapter-7	Reflection of Light
Exe-7B	Images Formed by a pair of Mirrors
Topics	Solution of Exe-7(B) Numericals
Academic Session	2024-2025

Exercise- 7B Images Formed by a Pair of Mirrors

page -174

Numericals :

Que: 1- State the number of images of an object placed between two mirrors, formed in each case when mirrors are inclined to each other at (a) 90°, and (b) 60°.

Solution- (a) Angle between the mirrors,  θ = 90^oNow, n = 360^o / θ^o = 360^o / 90^o = 4, which is even.

Hence number of images formed will be (n-1); i.e., 4 – 1 = 3 images

(b) Angle between the mirrors,  θ = 60^o

Now, n = 360^o / θ^o = 360^o / 60^o = 6, which is even.

Hence number of images formed will be (n-1); i.e., 6-1 = 5 images.

Que : 2- An object is placed (i) asymmetrically (ii) symmetrically, between two plane mirrors inclined at an angle of 50°. Find the number of images formed.

Solution- Angle between the mirrors, θ = 50^o

Now, n = 360^o / θ^o = 360^o / 50^o = 7.2  7, which is odd.

(i) When placed asymmetrically, number of images formed will be n, i.e. 7.

(ii) When placed symmetrically, number of images formed will be (n-1); i.e. 7-1 = 6 images

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