## Chemistry 2017 Solved Paper Previous Year Question ICSE

Chemistry 2017 Solved Paper Previous Year Question ICSE with Sample Paper for 2020 and Other Previous Year Solved Question for practice so that student of Class 10th ICSE can achieve their goals in next exam of council. Sample paper for Chemistry for 2020 exam also given . Hence by better practice and Solved Question Paper of Previous Year including 2017 is very helpful for ICSE student. By the practice of Chemistry 2017 Solved Question Paper ICSE Previous Year you can get the idea of solving. Try Also other year except Chemistry 2017 Solved Question Paper ICSE Previous Year for practice. Because only Chemistry 2017 Solved Question Paper ICSE Previous Year is not enough for preparation of council exam.

(Two hours)

### Answers to this Paper must be written on the paper provided separately.

You will not be allowed to write during the first 15 minutes.

This time is to be spent in reading the Question Paper.

The time given at the head of this paper is the time allowed for writing the answers.

Section I is compulsory. Attempt any four questions from Section II.

The intended marks for questions or parts of questions are given in brackets [ ].

### Previous Year Solved Question Paper Chemistry 2017

Section-I [40 Marks]

(Attempt all questions from this Section)

Question 1.

(a) Fill in the blanks from the choices given in brackets: [5]

(i) The energy required to remove an electron from a neutral isolated gaseous atom and convert it into a positively charged gaseous ion is called ………. (electron affinity, ionisation potential, electronegativity)
(ii) The compound that does not have a lone pair of electrons is (water, ammonia, carbon tetrachloride)
(iii) When a metallic oxide is dissolved in water, the solution formed has a high concentration of ions. (H+, H3O+, OH)
(iv) Potassium sulphite on reacting with hydrochloric acid releases ………….. gas. (Cl2, SO2, H2S)
(v) The compound formed when ethene reacts with Hydrogen is ………………………… (CH4, C2H6, C3H8)

(a) (i) ionisation potential
(ii) carbon tetrachloride
(iii) OH
(iv) SO2
(v) C2H6

(b) Choose the correct answer from the options given below: [5]

(i) A chloride which forms a precipitate that is soluble in excess of ammonium hydroxide, is:
1. Calcium chloride
2. Ferrous chloride
3. Ferric chloride
4. Copper chloride

4. Copper chloride

(ii) If the molecular formula of an organic compound is CioH18 it is:
1. alkene
2. alkane
3. alkyne
4. Not a hydrocarbon

3. alkyne

(iii) Which of the following is a common characteristic of a covalent compound?
1. high melting point
2. consists of molecules
3. always soluble in water
4. conducts electricity when it is in the molten state

2. consists of molecules

(iv) To increase the pH value of a neutral solution, we should add:
1. an acid
2. an acid salt
3. an alkali
4. a salt

3. an alkali

(v) Anhydrous iron(III) chloride is prepared by:
1. direct combination
2. simple displacement
3. decomposition
4. neutralization

1. direct combination

(c) Identify the substance underlined, in each of the following cases: [5]

(i) Cation that does not form a precipitate with ammonium hydroxide but forms one with sodium hydroxide.
(ii) The electrolyte used for electroplating an article with silver.
(iii) The particles present in a liquid such as kerosene, that is a non electrolyte.
(iv) An organic compound containing – COOH functional group.
(v) A solid formed by reaction of two gases, one of which is acidic and the other basic in nature.

(i) Copper
(ii) Sodium argento cyanide
(iii) molecules
(iv) Carboxylic acid
(v) Ammonium chloride

(d) Write a balanced chemical equation for each of the following: [5]

(i) Action of cold and dilute Nitric acid on Copper.
(ii) Reaction of Ammonia with heated copper oxide.
(iii) Preparation of methane from iodomethane.
(iv) Action of concentrated sulphuric acid on Sulphur.
(v) Laboratory preparation of ammonia from ammonium chloride.

(i) 3Cu + 8HNO3 → 3CU(NO3 )2 + 4H2O + 2NO↑
(ii) 2NH3 + 3CuO → 3Cu + 3H2O + N2
(iii) CH3I + 2[H] → CH4 + HI
(iv) S + 2H2SO4 → 3SO2+ 2H2O
(v) 2NH4Cl + Ca(OH)2 → CaCl2 + 2H2O + 2NH3

(e) State one relevant observation for each of the following reactions: [5]

(i) Addition of ethyl alcohol to acetic acid in the presence of concentrated Sulphuric acid.
(ii) Action of dilute Hydrochloric acid on iron (II) sulphide.
(iii) Action of Sodium hydroxide solution on ferrous sulphate solution.
(iv) Burning of ammonia in air.
(v) Action of concentrated Sulphuric acid on hydrated copper sulphate.

(i) Fruity smell due to formation of ester is there.
(ii) Rotten egg smell due to formation of hydrogen sulphide.
(iii) Dirty green precipitates of ferrous hydroxide are formed.
(iv) Yellowish green flame is produced when ammonia bums in air.
(v) Hydrated copper sulphate which is blue in colour change to anhydrous copper sulphate which is white in

(f) (i) Draw the structural formula for each of the following: [5]

1. 2, 3 – dimethyl butane
2. diethyl ether
3. propanoic acid
(ii) From the list of terms given, choose the most appropriate term to match the given de-scription.
(calcination, roasting, pulverisation, smelting)
1. Crushing of the ore into a fine powder.
2. Heating of the ore in the absence of air to a high temperature.

1. (i)  2, 3 – dimethyl butane

2. (diethyl ether) C2H5 – O – C2H5

3. propanoic acid CH3 – CH2 – COOH

(ii) 1. Pulverisation
2. Calcination

(g) (i) Calculate the number of gram atoms in 4.6 grams of sodium (Na = 23). [5]

(ii) Calculate the percentage of water of crystallization CuSO4.5H2O (H = 1,O = 16, S = 32, Cu = 64)
(iii) A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.

(i) 23 g of sodium → 1 gram atom
1 g of sodium → $\frac{1}{23}$ gram atom
4.6 g of sodium → = $\frac{1}{23} \times \frac{4.6}{10}=\frac{2}{100}$ =0.02gatoms

(ii) Molecular mass of CUSO4.5H2O
= [64 + 32+4 x 16] + 5[18] – [64 + 32+64] + [90] = 160+90
= 250
% of water of crystallisation =$\frac{90}{250} \times 100$
= 36%

(iii) E.F. = XY2
E.F.W. = V.D.
M.W. = 2 × V.D.
M.W. = 2 × [E.F.W.] So molecular formula = (XY2)2 = X2Y4

(h) Match the atomic number 2,4, 8,15, and 19 with each of the following: [5]

(i) A solid non-metal belonging to the third period.
(ii) A metal of valency 1.
(iii) A gaseous element with valency 2.
(iv) An element belonging to Group 2.
(v) A rare gas.

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