Decimals Class- 7th RS Aggarwal Exe-3B Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-3 Decimals for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-3B to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Decimals Class- 7th RS Aggarwal Exe-3B Goyal Brothers ICSE Math Solution
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-3 | Decimals |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-3B |
| Academic Session | 2023 – 2024 |
Exercise – 3B
Decimals Class- 7th RS Aggarwal Exe-3B Goyal Brothers ICSE Math Solution
1. Add :
(i) 9.67, 15.98
Solution: 9.67, 15.98
= 9.67 + 15.98
= 25.65
(ii) 6.9, 23.84
Solution: 6.9, 23.84
= 6.9 + 23.84
= 30.74
(iii) 35.67, 18.794, 4.9, 31.82
Solution: 35.67, 18.794, 4.9, 31.82
= 5.67 + 18.794 + 4.9 + 31.82
= 91. 184
(iv) 63.05, 24.839, 3.7, 16.85
Solution: 63.05, 24.839, 3.7, 16.85
= 63.05 + 24.839 + 3.7 + 16.85
= 108.439
2. Subtract :
(i) 2.975 from 8.23
Solution: 2.975 from 8.23
= 8.230 – 2.975 (convert 8.23 into like decimal)
= 5.255
(ii) 0.75 from 1.3
Solution: 0.75 from 1.3
= 1.30 – 0.75 (convert 1.3 into like decimal)
= 0.55
(iii) 6.054 from 11.26
Solution: 6.054 from 11.26
= 11.260 – 6.054 (convert 11.26 into like decimal)
= 5.206
(iv) 134.68 from 201.3
Solution: 134.68 from 201.3
= 201.30 – 134.68 (convert 201.3 into like decimal)
= 66.62
3. Take out 6.345 from 8.1.
Solution: 6.345 from 8.1
= 8.1 – 6.345
= 1.755
4. What is the difference between 68.5 and 0.685?
Solution: 68.5 and 0.685
= 68.5 – 0.685
= 67.815
5. What is the excess of 90 over 53.865?
Solution: 90 over 53.865
= 90.000 – 53.865 (convert 90 into like decimal)
= 36.135
6. What should be subtracted from 50 to get 34.57?
Solution: 50 to get 34.57
= 50.00 – 34.57 (convert 50 into like decimal)
= 15.43
7. What should be added to 63.47 to get 91?
Solution: 63.47 to get 91
= 91 – 63.47
= 27.53
8. Manish buys a ₹8.75 metro ticket with a ₹20 note. How much money does he get back?
Solution: Total money he had = ₹20
Expenditure on ticket = ₹8.75
= 20 – 8.75
= ₹11.25
He has ₹11.25 left
9. A baby increases in weight from 5.58 kg to 6.16 kg. How much weight has the baby gained?
Solution: 5.58 kg to 6.16 kg
= 6.16 – 5.58
= 0.58
10. Simplify :
(i) 67 + 13.85 – 29.904
Solution: 67 + 13.85 – 29.904
= 80.850 – 29.904
= 50.946
(ii) 16.753 + 4.06 – 13.89
Solution: 16.753 + 4.06 – 13.89
= 20.813 – 13.890
= 6.923
(iii) 1 – 10.5 + 12.213
Solution: 1 – 10.5 + 12.213
= 13.213 – 10.500
= 2.713
(iv) 81 – 15.68 -4.2
Solution: 81 – 15.68 -4.2
= 81 – 19.88
= 61.12
(v) 555 – 55.5 – 5.555
Solution: 555 – 55.5 – 5.555
= 555 – 61.055
= 433.945
(vi) 100 – 32.5 – 46.74 – 12.925
Solution: 100 – 32.5 – 46.74 – 12.925
= 100 – 92.165
= 7.835
— : end of Decimals Class- 7th RS Aggarwal Exe-3B Goyal Brothers ICSE Math Solution:–
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