Electro-Magnetism ICSE Class-10 Concise Physics Selina Solutions

Electro-Magnetism ICSE Class-10 Concise Physics Selina Solutions Chapter-10. We Provide Step by Step Answer of Exercise-10(A), MCQs-10(A), Exercise-10(B), MCQ-10(B), Exercise-10(C), MCQ-10(C) and Numericals -10(C)  Questions of Exercise-10 Electro-Magnetism ICSE Class-10 Concise Class-10 . Visit official Website CISCE  for detail information about ICSE Board Class-10.

Electro-Magnetism ICSE Class-10 Concise Physics Selina Solutions Chapter-10


-: Select Exercise :-

Exe – 10 (A), 

MCQ – 10 (A)

Exe – 10 (B),  

MCQ – 10 (B)

Exe – 10 (C), 

MCQ – 10 (C) ,

Num – 10 (C),

Note:- Read the chapter Electro-Magnetism carefully and then solve All the example given in your text book before starting Solution of Chapter – 10 Electro-Magnetism exercise. Do not forget using keyword in your answer in exam of council.


 Exercise – 10 (A) Electro-Magnetism ICSE Class-10 Concise Physics Selina

Question 1

By using a compass needle describe how can you demonstrate that there is a magnetic field around a current carrying conductor.

Answer 1

Experiment:

In Fig , AB is a wire lying in the north- south direction and connected to a battery through a rheostat and a tapping key. A compass needle is placed just below the wire. It is observed that

(1)When the key is open i.e., no current passes through the wire, the needle shows no                    deflection and it points in the N-S direction (i.e. along the earth’s magnetic field). In this              position, the needle is parallel to the wire as shown in Fig. (a).

(2)When the key is pressed, a current passes in the wire in the direction from A to B (i.e. From

south to north) and the north pole(N) of the needle deflects towards the west [Fig. (b)].

(3)When the direction of current in the wire is reversed by reversing the connections at the

terminals of the battery, North Pole (N) of the needle deflects towards the east [Fig. (c)].

(4)If the compass needle is placed just above the wire, the North Pole (N) deflects towards

east when the direction of current in wire is from A to B [Fig. (d)], but the needle deflects

towards west as in fig (e), if the direction of current in wire is from B to A.

The above observations of the experiment suggest that a current carrying wire produces a

magnetic field around it.

By using a compass needle describe how can you demonstrate that there is a magnetic field around a current carrying conductor.

Question 2

Draw a diagram showing the three magnetic field lines due to a straight wire carrying current. Also show the direction of current in the wire.

Answer 2

magnetic field lines due to a straight wire carrying current.

Question 3

How is magnetic field due to a straight current carrying wire affected if current in wire is (a) decreased, (b) reversed?

Answer 3

(a) On decreasing the current the magnetic field lines become rarer.

(b) The direction of magnetic field lines will get reversed.

Question 4

State a law, which determines the direction of magnetic field around a current carrying wire.

Answer 4

Right hand thumb rule determines the direction of magnetic field around a current carrying wire.

It states that if we hold the current carrying conductor in right hand such that the thumb points in the direction of flow of current, then the fingers encircle the wire in the direction of the magnetic fields lines.

Question 5

A straight wire lying in a horizontal plane carries a current from north to south.

(a) What will be the direction of magnetic field at a point just underneath it?

(b) Name the law used to arrive at this answer in part (a).

Answer 5

(a) The direction of magnetic field at a point just underneath is towards east.

(b) Right hand thumb rule.

Question 6

What will happen to a compass needle when the compass is placed below a wire and a current is made to flow through the wire? Give reasons to justify your answer.

Answer 6

A current carrying conductor produces a magnetic field around it and the magnetic needle in this magnetic field experience a torque due to which it deflects to align itself in the direction of magnetic field.

Question 7

Draw a labelled diagram showing the three magnetic field lines of a loop carrying current. Mark the direction of current and the direction of magnetic field by arrows in your diagram.

Answer 7

 three magnetic field lines of a loop carrying current

Question 8

A wire, bent into a circle, carries current in an anticlockwise direction. What polarity does this face of the coil exhibit?

Answer 8

Face of the coil exhibit North polarity.

Question 9

What is the direction of magnetic field at the centre of coil carrying current in (i) clockwise, (ii) anticlockwise direction?

Answer 9

(i) Along the axis of coil inwards.

(ii) Along the axis of coil outwards.

Question 10

Draw a diagram to represent the magnetic field lines along the axis of a current carrying solenoid. Mark arrows to show the direction of current in the solenoid and the direction of magnetic field lines.

Answer 10

Question 11

Name and state the rule by which the polarity at the ends of a current carrying solenoid is determined.

Answer 11

Right hand thumb rule: If we hold the current carrying conductor in right hand such that the thumb points in the direction of flow of current, then the fingers encircle the wire in the direction of the magnetic fields lines.

Question 12

The  diagram in. Fig 10.17 shows a small magnet placed near a solenoid AB. Current is switched on in the solenoid by pressing the key K. (a) State the polarity at the ends A and B. (b) Will the magnet be attracted or repelled? Give a reason for your answer.

Answer 12

(a) A – North pole, B – South pole.

(b) The magnet will be repelled because the end of the solenoid near the north pole of magnet becomes the north pole as current at this face is anticlockwise and the two like poles repel.

Question 13

The following diagram shows a spiral coil wound on a hollow cardboard tube AB. A magnetic compass is placed close to it. Current flows by closing the key. (a) What will be the polarity at the ends A and B? (b) How will the compass needle be affected? Give reason.

Answer 13

(a) A – North pole, B – South pole.

(b) The north pole of compass needle will deflect towards west.

Reason: The end A of the coil behaves like north pole which repels north pole of compass needle towards west.

Question 14

State two ways by which the magnetic field due to a solenoid can be made stronger.

Answer 14

The magnetic field due to a solenoid can be made stronger by using:

(i) By increasing the number of turns of winding in the solenoid.

(ii) By increasing the current through the solenoid.

Question 15

Why does a current carrying freely suspended solenoid rest along a particular direction? State the direction in which it rests.

Answer 15

A current carrying freely suspended solenoid at rest behaves like a bar magnet. It is because a current carrying solenoid behaves like a bar magnet. It align itself in north south direction.

Question 16

What effect will there be on a magnetic compass when it is brought near a current carrying solenoid?

Answer 16

The needle of the compass will rest in in the direction of magnetic field due to solenoid at that point.

Question 17

How is the magnetic field due to a solenoid carrying current affected if a soft iron bar is introduced inside the solenoid?

Answer 17

Magnetic field due to a solenoid carrying current increases if a soft iron bar is introduced inside the solenoid.

Question 18

Complete the following sentences:

(a)When current flows in a wire, it creates ________.

(b) On reserving the direction of current in a wire, the magnetic field produced by it gets _____.

(C)A current carrying solenoid behaves like a _________.

(D)A current carrying solenoid when freely suspended, it always rest in __________ direction.

Answer 18

(A)When current flows in a wire, it creates magnetic field around it.

(B) On reserving the direction of current in a wire, the magnetic field produced by it gets reversed.

(C)A current carrying solenoid behaves like a bar magnet

(D)A current carrying solenoid when freely suspended, it always rest in north-south direction.

Question 19

You are required to make an electromagnet from a soft iron bar by using a cell, an insulated coil of copper and a switch. (a) Draw a circuit diagram to represent the process. (b) Label the poles of the electromagnet.

Answer 19

Question 20

The fig 10.19  in shows a coil wound around a soft iron bar XY. (a) State the polarity at the end X and Y as the switch is pressed. (b)Suggest one way of increasing the strength of electromagnet so formed.

Answer 20

(a)X-north pole, Y –south pole.

(b)By reducing resistance of circuit by mean of rheostat to increase current.

Question 21

(a) What name is given to a cylindrical coil of diameter less than its length?

(b) If a piece of soft iron is placed inside the coil mentioned in part (a) and current is passed in the coil from a battery, what name is then given to the device so obtained?

(c) Give one use of the device mentioned in part (b).

Answer 21

(a) Solenoid is a cylindrical coil of diameter less than its length.

(b) The device so obtained is electromagnet.

(c) It is used in electric relay.

Question 22

Show with the aid of the diagram how a wire is wound on a U-shaped piece of soft iron in order to make it an electromagnet. Complete the circuit diagram and label the poles of the electromagnet.

Answer 22

Question 23

What is an electromagnet? Name two factors on which the strength of magnetic field of an electromagnet depends and state how does it depend on the factors stated by you.

Answer 23

An electromagnet is a temporary strong magnet made from a piece of soft iron when current flows in the coil wound around it. It is an artificial magnet.

The strength of magnetic field of an electromagnet depends on:

(i) Number of turns: The strength of magnetic increases on increasing the number of turns of winding in the solenoid.

(ii) Current: The strength of magnetic field increases on increasing the current through the solenoid.

Question 24

Figure shows the current flowing in the coil of wire wound around the soft iron horse shoe core. (a) State the polarities developed at the ends A and B.

(b) How will the polarity at the ends A and B change on reversing the direction of current.

(c) Suggest one way increase the strength of magnetic filed produce.

Answer 24

(a)At A-south pole and at B-north pole.

(b)Polarity will also reverse. A will become north pole and B will become south pole.

(c)By increasing the number of turns

Question 25

State two ways through which the strength of an electromagnet can be increased.

Answer 25

the strength of an electromagnet can be increased by following ways:

(i) By increasing the number of turns of winding in the solenoid.

(ii) By increasing the current through the solenoid.

Question 26

Name one device that uses an electromagnet.

Answer 26

Electric bell

Question 27

State two advantages of an electromagnet over a permanent magnet.

Answer 27

1.An electromagnet can produce a strong magnetic field.

2.The strength of the magnetic field of an electromagnet can easily be changed by changing the current in its solenoid.

Question 28

State two differences between an electromagnet and a permanent magnet.

Answer 28

differences between an electromagnet and a permanent magnet

Electromagnet Permanent magnet
It is made up of soft iron It is made up of steel.
The magnetic field strength can be changed. The magnetic field strength cannot be changed.
The electromagnets of very strong field can be made. The permanent magnets are not so strong.

Question 29

Why is soft iron used as the core of the electromagnet in an electric bell?

Answer 29

The soft iron bar acquires the magnetic properties only when an electric current flows through the solenoid and loses the magnetic properties as the current is switched off. That’s why soft iron is used as the core of the electromagnet in an electric bell.

Question 30

How is the working of an electric bell affected, if alternating current be used instead of direct current?

Answer 30

If an a.c. source is used in place of battery, the core of electromagnet will get magnetized, but the polarity at its ends will change. Since attraction of armature does not depend on the polarity of electromagnet, so the bell will still ring on pressing the switch.

Question 31

The incomplete diagram of an electric bell is given in figure. Draw winding of coil on the core and complete the electric circuit in the diagram

working of an electric bell

Answer 31

Question 32

Name the material used for making the armature of an electric bell. Give a reason for your answer.

Answer 32

The material used for making the armature of an electric bell is soft iron which can induce magnetism rapidly.


Selina Physics Solution “Electro-MagnetismExercise 10 (A) – Multiple Choice Type :

 Question 1

The presence of magnetic field at a point can be detected by :

(a) A strong magnet

(b) A solenoid

(c) A compass needle

(d) A current carrying wire

Answer 1

The presence of magnetic field at a point can be detected by a compass needle.

Note: In the presence of a magnetic field, the needle of compass rests only in the direction of magnetic field and in the absence of any magnetic field, the needle of compass can rest in any direction. In the earth’s magnetic field alone, the needle rests along north-south direction.

Question 2

On reversing the direction of current in a wire, the magnetic field produced by it:

(a) Gets reversed in direction

(b) Increases in strength

(c) Decreases in strength

(d) Remains unchanged in strength and direction

Answer 2

By reversing the direction of current in a wire, the magnetic field produced by it gets reversed in direction.

Hint: On reversing the direction of current in a wire, the polarity of the faces of the wire also reverses. Thus, the direction of magnetic field produced by it also gets reversed.


Selina Physics Solution Electro-Magnetism For Class 10th

Exercise 10 – (B)

 Question 1

Name three factors on which the magnitude of force on a current carrying conductor placed in a magnetic field depends and state how does the force depend on the factors stated by you.

Answer 1

The magnitude of force on a current carrying conductor placed in a magnetic field depends on:

(i) On strength of magnetic field B.

(ii) On current I in the conductor.

(iii) On length of conductor.

Magnitude of force on a current carrying conductor placed in a magnetic field depends directly on these three factors.

Question 2

State condition when magnitude of force on a current carrying conductor placed in a magnetic field is (a) zero,(b) maximum

Answer 2

(a)When current in the conductor is in the direction of magnetic field force will be zero.

(b) When current in the conductor is normal to the magnetic field.

Question 3

How will the direction of force be changed, if the current is reversed in the conductor placed in a  magnetic field?

Answer 3

Direction of force is also reversed.

Question 4

Name and state the law which is used to determine the direction of force on a current carrying conductor placed in a magnetic field.

Answer 4

Fleming’s left hand rule: Stretch the forefinger, middle finger and the thumb of your left hand mutually perpendicular to each other. If the forefinger indicates the direction of magnetic field and the middle finger indicates the direction of current, then the thumb will indicate the direction of motion of conductor.

Question 5

State Fleming’s left handle rule.

Answer 5

Fleming’s left hand rule: Stretch the forefinger, middle finger and the thumb of your left hand mutually perpendicular to each other. If the forefinger indicates the direction of magnetic field and the middle finger indicates the direction of current, then the thumb will indicate the direction of motion of conductor.

Fleming's left handle rule.

Question 6

State the unit of magnetic field in terms of the force experienced by a current carrying conductor placed in a magnetic field.

Answer 6

Unit is: Newton/ampere x meter (or NA-1m-1).

Question 7

A flat coil ABCD is freely suspended between the pole pieces of a U-shaped permanent magnet with the plane of coil parallel to the magnetic field.

(a)What happens when a current is passed in the coil?

(b) When will coil come to rest?

(c) When will the couple acting on the coil be (i) maximum, (ii) minimum?

(d) Name an instrument which makes use of the principle stated above.

Answer 7

(a)The coil will experience a torque due to which it will rotate.

(b) The coil will come to rest when their plane become normal to the magnetic field.

(c) (i) When plane of a oil is parallel to the magnetic field,

(ii) When plane of coil is normal to the magnetic field.

(d) The instrument which makes use of the principle stated above is d.c. motor.

Question 8

A coil ABCD mounted on an axle is placed between the poles N and S of a permanent magnet.

(a) In which direction will the coil begin to rotate when current is passed through the coil in direction ABCD by connecting a battery at the ends A and D of the coil?

(b)Why is a commutator necessary for continuous rotation of coil?

(c) Complete the diagram with commutator, etc. for the flow of current in the coil.

Answer 8

(a)The coil begins to rotate in anticlockwise direction.

(b) This is because, after half rotation, the arms AB and CD get interchanged, so the direction of torque on coil reverses. To keep the coil rotating in same direction, commutator is needed to change the direction of current in the coil after each half rotation of coil.

Question 9

What is an electric motor? State its principle.

Answer 9

Electric motor: An electric motor is a device which converts the electrical energy into the mechanical energy.

Principle: An electric motor (dc motor) works on the principle that when an electric current is passed through a conductor placed normally in a magnetic field, a force acts on the conductor as a result of which the conductor begins to move and mechanical energy is obtained.

Question 10

Draw a labelled diagram of a d.c motor showing its main parts.

Answer 10

Question 11

What energy conversion does take place during the working of a d.c motor?

Answer 11

Electrical energy converts into mechanical energy.

Question 12

State two ways by which the speed of rotation of an electric motor can be increased.

Answer 12

The speed of rotation of an electric motor can be increased by:

(i)Increasing the strength of current.

(ii)Increasing the number of turns in the coil.

Question 13

Name two appliances in which an electric motor is used.

Answer 13

Electric motor is used in electrical gadgets like fan, washing machine, juicer, mixer, grinder etc.


Selina Physics Solution Electro-Magnetism For Class 10th

Exercise 10 – (B) Multiple Choice Type

Question 1

In an electric motor, the energy transformation is:

(a) From electrical to chemical

(b) From chemical to light

(c) From mechanical to electrical

(d) From electrical to mechanical

Answer 1

In an electric motor, the energy transformation is from electrical to mechanical.

Note: An electric motor is a device which converts electrical energy into mechanical energy.


Selina Physics Solution Electro-Magnetism For ICSE Class 10th Exe-10(C)

Question 1

(a) What is the electromagnetic induction?

(b) Describe one experiment to demonstrate the phenomenon of electromagnetic induction.

Answer 1

(a) Electromagnetic induction: whenever there is change in number of magnetic field lines associated with conductor, an electromotive force is developed between the ends of the conductor which lasts as long as the change is taking place.

(b) Demonstration of the phenomenon of electromagnetic induction:

In the figure:

(i)When the magnet is stationary there is no deflection in galvanometer. The pointer read zero. [Fig. (a)]

(ii)when the magnetwith north pole facing the solenoid is moved towards the solenoid, the galvanometer shows a deflection towards the right showing that a current flows in the solenoid in the direction as shown in [Fig (b)]

(iii) As the motion of magnet stops, the pointer of the galvanometer comes to the zero position [Fig (c)]. This shows that the current in the solenoid flows as long as the magnet is moving.

(iv)If the magnet is moved away from the solenoid, the current again flows in the solenoid, but now in a direction opposite to that shown in [Fig. (b)] and therefore the pointer of the galvanometer deflects towards left[ Fig. (d)].

(v)If the magnet is moved away rapidly i.e. with more velocity, the extent of deflection in the galvanometer increases although the direction of deflection remains the same.It shows that more current flows now.

(vi)If the polarity of the magnet is reversed and then the magnet is brought towards the solenoid, the current in solenoid flows in the direction opposite to that shown in Fig (b) and so the pointer of galvanometer deflect towards left [Fig. (e)].

Question 2

State Faraday’s laws of electromagnetic induction.

Answer 2

Faraday’s formulated two laws of electromagnetic induction:

(i) Whenever there is a change in the magnetic flux linked with a coil, an e.m.f. is induced. The induced e.m.f. lasts so long as there is a change in the magnetic flux linked with the coil.

(ii) The magnitude of the e.m.f. induced is directly proportional to the rate of change of the magnetic flux linked with the coil. If the rate of change of magnetic flux remains uniform, a steady e.m.f. is induced.

Question 3

State two factor on which the magnitude of induced e.m.f in a coil depend.

Answer 3

Magnitude of induced e.m.f depend upon:

(i)The change in the magnetic flux.

(ii)The time in which the magnetic flux changes

Question 4

(a)What kind of the energy change takes place when a magnet is moved towards a coil having a galvanometer at its ends?

(b)Name the phenomenon.

Answer 4

(a) Mechanical energy changes to the electrical energy.

(b) Phenomenon is called electromagnetic induction.

Question 5

(a) How would you demonstrate that a momentary current can be obtained by the suitable use of a magnet, a coil of wire and a galvanometer?

(b)What is the source of energy associated with the current obtained in part (a)?

Answer 5

(a)When there is a relative motion between the coil and the magnet, the magnetic flux linked with the coil changes. If the north pole of the magnet is moved towards the coil, the magnetic flux through the coil increases as shown in above figure. Due to change in the magnetic flux linked with the coil, an e.m.f. is induced in the coil. This e.m.f. causes a current to flow in the coil if the circuit of the coil is closed.

(b)The source of energy associated with the current obtained in part (a) is mechanical energy.

Question 6

(a)Describe briefly one way of producing an induced e.m.f.

(b)State one factor that determines the magnitude of induced e.m.f.

(c)What factor determines the direction of induced e.m.f.?

Answer 6

(a)

 Induced current can be produced by following activity:

(i) When the magnet is stationary there is no deflection in galvanometer. The pointer read zero. [Fig (a)]

(ii) and When the magnet with north pole facing the solenoid is moved towards the solenoid, the galvanometer shows a deflection towards the right showing that a current flows in the solenoid in the direction as shown in Fig (b)

(iii) As the motion of magnet stops, the pointer of the galvanometer to the zero position [Fig (c)]. This shows that the current in the solenoid flows as long as the magnet is moving.

(iv) If the magnet is moved away from the solenoid , the current again flows in the solenoid , but now in the direction opposite to that shown in [Fig. (b)] and therefore the pointer of the galvanometer deflects towards left [Fig. (d)].

(v) whenever If the magnet is moved away rapidly i.e. with more velocity, the extent of deflection in the galvanometer increases although the direction of deflection remains the same.It shows that more current flows now.

(vi) the polarity of the magnet is reversed and then the magnet is brought towards the solenoid, the current in solenoid flows in the direction opposite to that shown in Fig (b) and so the pointer of galvanometer deflect towards left [Fig. (e)].

(b)

 Magnitude of induced e.m.f depend upon:

(i)The change in the magnetic flux.

(ii)The time in which the magnetic flux changes.

(c) The direction of induced e.m.f depends on whether there is an increase or decrease in the magnetic flux.

Question 7

Complete the following sentences:

The current induced in a closed circuit only if there is ________.

Answer 7

The current induced in a closed circuit only if there is relative motion between magnet and coil

Question 8

In which of the following cases e.m.f. is induction?

(i)A current is started in a wire held near a loop of wire.

(ii)The current is stopped in a wire held near a loop of wire.

(iii)A magnet is moved through a loop of wire.

(iv)A loop of wire is held near a magnet.

Answer 8

(i)Yes.

(ii)Yes.

(iii)Yes.

(iv)No.

Question 9

A conductor is moving in a varying magnetic field. Name the law which determines the direction of current induced in the conductor.

Answer 9

Fleming’s right hand rule determines the direction of current induced in the conductor.

Question 10

State Fleming’s right hand rule.

Answer 10

Fleming’s right hand rule: Stretch the forefinger, middle finger and the thumb of your right hand mutually perpendicular to each other. If the forefinger indicates the direction of magnetic field and the thumb will indicates the direction of motion of conductor, then the middle finger indicates the direction of induced current.

Question 11

What is Lenz’s law?

Answer 11

Lenz’s law: It states that the direction of induced e.m.f. (or induced current) is such that it always tends to oppose the cause which produces it.

Question 12

Why does it more difficult to move a magnet towards a coil when the number of turns in the coil has been increased?

Answer 12

When a coil has a large number of turns, then magnitude of induced e.m.f. in the coil become more and then by Lenz’s law it will oppose more.

Question 13

Explain why an induced current must flow in such a direction so as to oppose the change producing it.

Answer 13

So that the mechanical energy spent in producing the change, is transformed into the electrical energy in form of induced current.

Question 14

Explain how does the  Lenz’s law to show the conservation of energy in electromagnetic induction.

Answer 14

Lenz’s law implies the law of conservation of energy. It shows that the mechanical energy spent in doing work, against the opposing force experienced by the moving magnet, is transformed into the electrical energy due to which current flows in the solenoid.

Question 15

The diagram in shows a coil of several turns of copper wire near a magnet NS. The coil is moved in the direction of arrow shown in the diagram.

(i) In what direction does the induced current flow in the coil?

(ii) Name the law used to arrive at the conclusion in part (i).

(iii) How would the current in coil be altered if

(a) the coil has twice the number of turns,

(b) the coil was made to move three times fast?

Answer 15

(i) When the coil is moved in the direction of magnet the North pole generates near this end and current starts flowing from A to B.

(ii) Lenz’s law.

(iii) (a)Current is directly proportional to the number of turns, therefore it will also become 2 times

(b) Current becomes thrice.

Question 16

The diagram in fig . 10.43  shows a fixed coil of several turns connected to a center zero galvanometer G and magnet NS which can move in the direction shown in the diagram.

(a)Describe the observation in the galvanometer if  (i) the magnet is moved rapidly, (ii) the magnet is kept stationary after it has move into the coil, (iii) the magnet is then rapidly pulled out of the coil.

(b) How would the observation in (i)of a part (a) change if a more powerful magnet is used?

Answer 16

(i)The pointer of galvanometer deflects towards left. The deflection lasts so long as the coil moves.

(ii)(a) Deflection becomes twice (b) Deflection becomes thrice.

Question 17

Name and state the principle of a simple a.c. generator. What is its use?

Answer 17

An A.C. generator works on the principle of ‘electromagnetic induction’.

Statement: Whenever a coil is rotated in a magnetic field, the magnetic flux linked with the coil changes, and therefore, an EMF is induced between the ends of the coil. Thus, a generator acts like a source of current if an external circuit containing load is connected between the ends of its coil.

Question 18

What determines the frequency of a.c. produced in a generator?

Answer 18

The number of rotations of the coil in one second or the speed of rotation of the coil.

Question 19

Complete the sentence:

An a.c. generator changes the ___________ energy to ___________ energy.

Answer 19

Mechanical, Electrical

Question 20

Draw a labelled diagram of a simple a.c generator.

Answer 20

a labelled diagram of a simple a.c generator.

Question 21

In an a.c generator the speed at which the coil rotates is doubled. How would this affect

(a)the frequency of output voltage

(b)the maximum output voltage.

Answer 21

(a)In an a.c generator, if the speed at which the coil rotates is doubled, the frequency is also doubled.

(b) Maximum output voltage is also doubled.

Question 22

State two ways to produce a higher e.m.f. in an a.c generator.

Answer 22

Two ways in an a.c generator to produce a higher e.m.f. are:

(1)By increasing the speed of rotation of the coil.

(2)By increasing the number of turns of coil.

Question 23

What energy conversion does take place in a generator when it is in use?

Answer 23

Mechanical energy changes into the electrical energy.

Question 24

State (i) two dis-similarities, and (ii) two similarity between a D.C. motor and an A.C. generator.

Answer 24

Two dissimilarities between D.C. motor and A.C. generator:

A.C. Generator D.C. Motor
1. A generator is a device which converts mechanical energy into electrical energy. 1. A D.C. motor is a device which converts electrical energy into mechanical energy
2. A generator works on the principle of electromagnetic induction. 2. A D.C. works on the principle of force acting on a current carrying conductor placed in a magnetic field.

Similarity: Both in A.C generator and D.C motor, a coil rotates in a magnetic field between the pole pieces of a powerful electromagnet.

Question 25

State one advantage of using a.c. over d.c.

Answer 25

The voltage of a.c. can be stepped up by the use of step-up transformer at the power generating station before transmitting it over long distances. It reduces the loss of electrical energy as heat in the transmission line wires. On the other hand, if d.c. is generated at the power generating station, its voltage cannot be increased for transmission, and so due to passage of high current in the transmission line wires, there will be a huge loss of electrical energy as heat in the line wires.

Question 26

For what purpose are the transformers used? Can they be used with a direct current source?

Answer 26

The purpose of the transformer is to step up or step down the a.c. voltage.

No, a transformer cannot be used with a direct current source.

Question 27

State two factors on which the magnitude of an induced e.m.f. in the secondary coils of a transformer depends.

Answer 27

The magnitude of an induced e.m.f. in the secondary coil of a transformer depends on the following two factors.

a)The ratio of number of turns in the secondary coil to the number of turns in the primary coil.

b)The magnitude emf applied in the primary coil.

Question 28

How an e.m.f. in the primary and secondary coils of a transformer related with the number of turns in these coils?

Answer 28

The relation is following:

S stands for secondary and P stands for primary.

Question 29

Draw a labelled diagram to show the various components of a step up transformer.

Answer 29

Step up transformer:

components of a step up transformer

Question 30

Name the device used to transform 12 V a.c. to 200 V a.c.Name the principle on which it works.

Answer 30

The device is step up transformer.

It works on the principle of electromagnetic induction.

Question 31

Draw a labelled diagram of a step-up transformer and explain how it works. State two characteristics of the primary coil as compared to its secondary coil.

Answer 31

Step-up transformer: The step-up transformer is used to change a low voltage alternating e.m.f. to a high voltage alternating e.m.f. of same frequency.

Working: When the terminals of primary coil are connected to the source of alternating e.m.f., a varying current flows through it which also produces a varying magnetic field in the core of the transformer. Thus, the magnetic field lines linked with the secondary coil vary and induce an e.m.f. in the secondary coil. The induced e.m.f. varies in the same manner as the applied e.m.f. in the primary coil varies, and thus, has the same frequency as that of the applied e.m.f.

The magnitude of e.m.f. induced in the secondary coil depends on the ‘turns ratio’ and the magnitude of the applied e.m.f.

For a transformer,

Two characteristics of the primary coil as compared to its secondary coil:

  1. The number of turns in the primary coil is less than the number of turns in the secondary coil.
  2. A thicker wire is used in the primary coil as compared to that in the secondary coil.

Question 32

Draw a labelled diagram of a device you would use to transform 200 V a.c to 15 V a.c. Name the device and explains how it works. Give its two uses.

Answer 32

The device is step down transformer.

setup transferm

Working: In a step down transformer, the number of turns in secondary coil are less than the number of turns in the primary coil i.e., turns ratio nS/NP<1.

As Es/Ep = NS/NP.

So Es/Eps is less than Ep.

Two uses of step down transformer are:

(i)With electric bells

(ii)At the power sub-stations to step-down the voltage before its distribution to the customers.

Question 33

Name the coil of which the wire is thicker in a (i) step up, (ii) step down transformer. Give reason to your answer.

Answer 33

(i) In case of a step-up transformer, thicker wire is used in the primary coil as compared to that in the secondary coil.

(ii) In a step-down transformer, the wire in the secondary coil is thicker than in the primary coil.

The use of thicker wire reduces its resistance and therefore reduces the loss of energy as heat in the coil. In step up NS > NP therefore ES > EP, but Is < IP i.e., more current flows in the primary coil. The reverse is the case of a step-down transformer. Thus, the thickness of the wire is chosen accordingly.

Question 34

(a)Complete the following diagram of a transformer and name the parts labelled A and B.

(b)Name the part you have drawn to complete the diagram.

(c) What is the material of this part?

(d)Is the transformer a step-up or step-down? Give reasons.

set up

Answer 34

A is the primary coil. B is the secondary coil.

We have drawn laminated core in the diagram.

The material of this part is soft iron.

This transformer a step-down transformer because the number of turns in primary coil is much greater than that in the secondary coil.

Question 35

The diagram shows the core of a transformer and its input and output connections.

(a) State the material used for the core and describe its structure.

(b)Complete the diagram of the transformer and connections by labelling all the parts joined by you

(c) Name the transformer: step up or step down?

Answer 35

(a) Soft iron core is used. The core is made up from the thin laminated sheets of soft iron of T and U shape, placed alternately one above the other and insulated from each other by paint or varnish coating over them.

(b)

(c) It is a step down transformer.

Question 36

The out put current of a transformer in which the voltage is stepped down are usually higher than the input current. Explain why?

Answer 36

The secondary win dings of a transformer in which the voltage is stepped down are usually made up of thicker than the primary because more current flows in the secondary coil. The use of thicker wire reduces its resistance and therefore the loss of energy as heat in the coil.

Question 37

Why the iron core of a transformer made is laminated instead of being in one solid piece?

Answer 37

To reduce the energy losses due to eddy currents.

Question 38

Complete the following sentences:

(i)In a step-up transformer, the number of turns in the primary is _______ than the number of turns in the secondary.

(ii)The transformer is used in _______ current circuits.

(iii)In a transformer, the frequency of A.C. voltage ________. (increase / decreases / remains same)

Answer 38

(i)In a step-up transformer, the number of turns in the primary is less than the number of turns in the secondary.

(ii)The transformer is used in alternating current circuits.

(iii)In a transformer, the frequency of A.C. voltage remain same.

Question 39

 How do the input and output powers in a transformer compare? State the assumption made?

Answer 39

A transformer is a device by which the amplitude of an alternating e.m.f. can be increased or decreased.

For an ideal transformer , when there is no loss of energy , the output power is equal to input power i.e.,

Power in secondary coil = power in primary coil

Question 40

Name two kinds of energy losses in a transformer. How is it minimized?

Answer 40

The energy loss in a transformer is called ‘copper loss’.

Copper losses: Primary and secondary coils of a transformer are generally made of copper wire. These copper wires have resistance. When current flows through these wires, a part of the energy is lost in the form of heat. This energy lost through the windings of the transformer is known as copper loss.

This loss can be minimized by using thick wires for the windings. Use of thick wire reduces its resistance and therefore reduces the loss of energy as heat in the coil.

  1. Loss due to eddy current.It can be minimised by using laminated core.

Question 41

Give two points of difference between a step up transformer and a step down transformer.

Answer 41

Step up transformer Step down transformer
It increases the a.c. voltage and decrease the current. It decreases the a.c. voltage and increase the current.
The wire of primary coil is thicker than that in the secondary coil. The wire in the secondary coil is thicker than that in the primary coil.

Question 42

Name the material of core in (a) electric bell, (b) electromagnet, (c) d.c. motor, (d) an a.c. generator and (e) transformer.

Answer 42

Soft iron is used in all.

Question 43

Name the transformer used in the (i) power generating station, (ii) power sub-station.

State the function of each transformer.

Answer 43

(i) Step-up transformer.

In power generating stations the alternating current generated is first stepped up from 11 kV to 132 kV.

(ii) Step-down transformer.

At the power sub-station, voltage is stepped down before its distribution to the consumers.

Transformers are used so as to reduce the loss of energy in the form of heat in the line wires used for transmission.


Selina Physics Solution Electro-Magnetism ICSE Class-10

Exercise – 10 (C) “Multiple Choice Type “

Question 1

The direction of induced current is obtained by :

(a) Fleming’s left hand rule

(b) Clock rule

(c) Right hand thumb rule

(d) leming’s right hand rule

Answer 1

Fleming’s right hand rule

Statement: According to Fleming’s right hand rule, if we stretch the thumb, middle finger and forefinger of our right hand mutually perpendicular to each other such that the forefinger indicates the direction of magnetic field and thumb indicates the direction of motion of conductor, then the middle finger will indicate the direction of induced current.

Question 2

In a step-up transformer :

(a) Ns = Np

(b) N< Np

(c) N> Np

(d) nothing can be said

Answer 2

Hint: Since a step-up transformer is used to change a low voltage alternating e.m.f. to a high voltage alternating e.m.f. of same frequency, the number of turns in the secondary coil is more than the number of turns in the primary coil, i.e. .


Selina Physics Solution Electro-Magnetism For ICSE Class 10th

Exercise – 10 (C) , Numericals

Question 1

The magnetic flux through a coil having 100 turns decreases from 5 milli weber to zero in 5 second.

Calculate the e.m.f. induced in the coil

Answer 1

Given that:

Decrease in the flux = 0.005 – 0 = 0.005 weber,

Number of tuns = 100 turns and

Time = 5 second

e.m.f. induced e = N × Rate of increase of magnetic flux

——————= 

∴ e.m.f. induced e = 0.1 V = 100 mV

Question 2

A primary coil of a transformer has 800 turns and the secondary has 8 turns. It is connected to a 220 V a.c supply. What will be the output voltage?

Answer 2

No. of turns in primary coil Np =800

No. of turns in secondary coil Np=8.

Input supply voltage Ep = 220 V.

We know that

Es =2.2 V.

Question 3

A transformer is designed to give a supply of 8 V to ring a house bell from the 240 V a.c mains. The primary coil has 4800 turns. How many turns will be in the secondary coil?

Answer 3

Input ac voltage Ep = 240 V.

Number of turns in primary coil Np = 4800

No. of turns in secondary coil Ns=?

Output voltage Es = 8 V.

We know that

Number of turns in secondary coil = 160.

Question 4

The input and output voltages of a transformer are 220 V and 44V respectively. Find

(a)the turns ratio

(b)the current in input circuit if the output current is 2 A.

Answer 4

(a)We know that

So turns ratio

=

(b)Output current Is= 2A, Es =44V.

Input current Ip =?,Ep =220 V.

We know that =Es Is =EpIp

Ip =

Return to Concise Selina ICSE Physics Class-10 

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