Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers ICSE Maths Solutions

Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers Prakashan ICSE Foundation Maths Solutions. We provide step by step Solutions of ICSE Class-6 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan. In this article you would learn about Simplification of fraction using BODMAS rules.. Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.

Fractions Class 6 RS Aggarwal Exe-4F Simplification Goyal Brothers Prakashan ICSE Foundation Maths Solutions.

Board	ICSE
Publications	Goyal brothers Prakashan
Subject	Maths
Class	6th
Ch-4	Fraction
Writer	RS Aggrawal
Book Name	Foundation
Topics	Solution of Exe-4F
Academic Session	2023 – 2024

Simplification of fraction ussing BODMAS rules

Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers Prakashan ICSE Foundation Maths Solutions.

Page- 80

Exercise- 4F

Que-1: Find :

(i) 1/8 of 40     (ii) 4/11 of 4*(2/5)   (iii) 1*(3/5) of 6*(1/4)
(iv) 3/4 of Rs1     (v) 5/8 of 1 km    (vi) 5/12 of 1 hour

Solution- (i) 1/8 x 40
= 5 Ans.

(ii) 4/11 x 22/5
= 8/5 = 1*(3/5) Ans.

(iii) 8/5 x 25/4
= 10 Ans.

(iv) 3/4 x 1
= 0.75 = 75 paisa

(v) 5/8 x 1
= 0.625 = 625 Ans.

(vi) 5/12 x 1
= 0.25 = 25 minutes Ans.

Simplify :

Que-2: 1*(1/6) ÷ 1*(5/9) x 3*(1/3)

Solution- 7/6 ÷ 14/9 x 10/3
= 7/6 x 9/14 x 10/3
= 5/2 = 2*(1/2) Ans.

Que-3: 1*(1/3) ÷ 3/7 of 2*(5/8) + 1*(1/9)

Solution- 4/3 ÷ 3/7 x 21/8 + 10/9
= [4/3 x 8/9] + 10/9
= 32/27 + 10/9
= (32 + 30)/27
= 62/27 = 2*(8/27) Ans.

Que-4: 6*(1/5) ÷ 3*(1/10) of 2*(1/2) ÷ 1/4

Solution- 31/5 ÷ 31/10 x 5/2 ÷ 1/4
= 31/5 ÷ 31/4 ÷ 1/4
= 31/5 x 4/31 x 4
= 16/5 = 3*(1/5) Ans.

Que-5: 3*(2/3) – 3/11 of 2*(3/4) ÷ 1*(1/4) x 1*(2/3) + 1/3

Solution- 11/3 – 3/11 x 11/4 ÷ 5/4 x 5/3 + 1/3
= 11/3 – 3/4 x 4/5 x 5/3 + 1/3
= 11/3 – 1/1 + 1/3
= (11 – 3 + 1)/3
= 9/3 = 3 Ans.

Que-6: 2*(2/7) of 15*(3/4) x 2*(1/4) ÷ 4/7 of 2*(5/8)

Solution- 16/7 x 63/4 x 9/4 ÷ 4/7 x 21/8
= 36 x 9/4 ÷ 3/2
= 36 x 9/4 x 2/3
= 27 x 2 = 54 Ans

Que-7: 1 ÷ 4/7 – 1/3 of 3*(3/4) + 1/2 ÷ 3

Solution- 1 ÷ 4/7 – 1/3 x 15/4 + 1/2 ÷ 3
= 1 x 7/4 – 5/4 + 1/2 x 1/3
= 1 x 7/4 – 5/4 + 1/6
= 7/4 – 5/4 + 1/6
= (21 – 15 + 2)/12
= 8/12 = 2/3

Que-8:  [2/3 + 4/9] of 3/5 ÷ 1*(2/3) x 1*(1/4) – 1/3

Solution- [(6 + 4)/9] of 3/5 ÷ 5/3 x 5/4 – 1/3
= 10/9 x 3/5 x 3/5 x 5/4 – 1/3
= 2/3 x 3/4 – 1/3
= 2/4 – 1/3
= (6 – 4)/12
= 2/12 = 1/6 Ans.

Que-9: [14/15 ÷ 1*(1/6) + 7/10] x 3/4 

Solution- [14/15 ÷ 7/6 + 7/10] x 3/4
= [14/15 x 6/7 + 7/10] x 3/4
= [4/5 + 7/10] x 3/4
= [(8 + 7)/10] x 3/4
= 15/10 x 3/4
= 9/8 = 1*(1/8) Ans.

Que-10: 1/3[2*(1/2) + 3*(1/3)] ÷ 2/9[3*(1/8) – 1*(1/12)]

Solution- 1/3 [5/2 + 10/3] ÷ 2/9 [25/8 – 13/12]
= 1/3 [(15 + 20)/6] ÷ 2/9 [(75 – 26)/24]
= 1/3 x 35/6 x 9/2 x 49/24
=

Que-11:  [1/4 – 1/9] ÷ [1/2 + 1/4 ÷ 1/3]

Solution- [1/4 – 1/9] ÷ [1/2 + 1/4 ÷ 1/3]
= [(9 – 4)/36] ÷ [1/2 + 1/4 x 3]
= 5/36 ÷  [1/2 + 3/4]
= 5/36 ÷  [(2 + 3)/4]
= 5/36 ÷ 5/4
= 5/36 x 4/5
= 1/9 Ans.

Que-12:  3*(7/8) – {1*(3/8) ÷ [2*(4/5) – 1*(7/10)]}

Solution- 31/8 – {11/8 ÷[14/5 – 17/10]}
= 31/8 – {11/8 ÷[(28 + 17)/10]}
= 31/8 – {11/8 ÷45/10}
= 31/8 – {11/8 x 10/45}
= 31/8 – 22/72
= ( – 22)/40
= 133/40 Ans.

Que-13:  3÷[3 x {3 – (3 – 1/4)}]

Solution–  3÷[3×{3-(3-1\4)}]

= 3÷[3×{3-(3\1-1\4)}]

=3÷[3×{3-(11\4)}]

=3÷[3×{3\1-11\4}]

=3÷[3×{1\4}]

=3÷3\4

=3×4\3

=4  Ans.

Que-14- 5*1/3-[2*(1/3) ÷ {3/4 – 1/2 x (7/10 – 3/5)}]

Solution- 5*1\3-[2*1/3÷{3/4-1/2×(7/10-3/50)}]

=16/3[7/3÷{3/4-1/2×(7-6/10)}]

=16/3-[7/3÷{3/4-1/2×(1/10)}]

=16/3-[7/3÷{3/4-1/2×1/10}]

=16/3-[7/3÷{3/4-1/20}]

=16/3-[7/3÷{15-1/20}]

=16/3-[7/3÷{14/20}]

=16/3-[7/3÷{7/10}]

=16/3-[7/3÷7/10]

=16/3-[7/3×10/7]

=16/3-[10/3]

=16/3-10/3

=6/3

=2 Ans.

— : end of Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers ICSE Foundation Maths Solutions :–

Return to :- ICSE Class -6 RS Aggarwal Goyal Brothers Math Solutions

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