Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers Prakashan ICSE Foundation Maths Solutions. We provide step by step Solutions of ICSE Class-6 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan. In this article you would learn about Simplification of fraction using BODMAS rules.. Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.
Fractions Class 6 RS Aggarwal Exe-4F Simplification Goyal Brothers Prakashan ICSE Foundation Maths Solutions.
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 6th |
| Ch-4 | Fraction |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-4F |
| Academic Session | 2023 – 2024 |
Simplification of fraction ussing BODMAS rules
Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers Prakashan ICSE Foundation Maths Solutions.
Page- 80
Exercise- 4F
Que-1: Find :
(i) 1/8 of 40 (ii) 4/11 of 4*(2/5) (iii) 1*(3/5) of 6*(1/4)
(iv) 3/4 of Rs1 (v) 5/8 of 1 km (vi) 5/12 of 1 hour
Solution- (i) 1/8 x 40
= 5 Ans.
(ii) 4/11 x 22/5
= 8/5 = 1*(3/5) Ans.
(iii) 8/5 x 25/4
= 10 Ans.
(iv) 3/4 x 1
= 0.75 = 75 paisa
(v) 5/8 x 1
= 0.625 = 625 Ans.
(vi) 5/12 x 1
= 0.25 = 25 minutes Ans.
Simplify :
Que-2: 1*(1/6) ÷ 1*(5/9) x 3*(1/3)
Solution- 7/6 ÷ 14/9 x 10/3
= 7/6 x 9/14 x 10/3
= 5/2 = 2*(1/2) Ans.
Que-3: 1*(1/3) ÷ 3/7 of 2*(5/8) + 1*(1/9)
Solution- 4/3 ÷ 3/7 x 21/8 + 10/9
= [4/3 x 8/9] + 10/9
= 32/27 + 10/9
= (32 + 30)/27
= 62/27 = 2*(8/27) Ans.
Que-4: 6*(1/5) ÷ 3*(1/10) of 2*(1/2) ÷ 1/4
Solution- 31/5 ÷ 31/10 x 5/2 ÷ 1/4
= 31/5 ÷ 31/4 ÷ 1/4
= 31/5 x 4/31 x 4
= 16/5 = 3*(1/5) Ans.
Que-5: 3*(2/3) – 3/11 of 2*(3/4) ÷ 1*(1/4) x 1*(2/3) + 1/3
Solution- 11/3 – 3/11 x 11/4 ÷ 5/4 x 5/3 + 1/3
= 11/3 – 3/4 x 4/5 x 5/3 + 1/3
= 11/3 – 1/1 + 1/3
= (11 – 3 + 1)/3
= 9/3 = 3 Ans.
Que-6: 2*(2/7) of 15*(3/4) x 2*(1/4) ÷ 4/7 of 2*(5/8)
Solution- 16/7 x 63/4 x 9/4 ÷ 4/7 x 21/8
= 36 x 9/4 ÷ 3/2
= 36 x 9/4 x 2/3
= 27 x 2 = 54 Ans
Que-7: 1 ÷ 4/7 – 1/3 of 3*(3/4) + 1/2 ÷ 3
Solution- 1 ÷ 4/7 – 1/3 x 15/4 + 1/2 ÷ 3
= 1 x 7/4 – 5/4 + 1/2 x 1/3
= 1 x 7/4 – 5/4 + 1/6
= 7/4 – 5/4 + 1/6
= (21 – 15 + 2)/12
= 8/12 = 2/3
Que-8: [2/3 + 4/9] of 3/5 ÷ 1*(2/3) x 1*(1/4) – 1/3
Solution- [(6 + 4)/9] of 3/5 ÷ 5/3 x 5/4 – 1/3
= 10/9 x 3/5 x 3/5 x 5/4 – 1/3
= 2/3 x 3/4 – 1/3
= 2/4 – 1/3
= (6 – 4)/12
= 2/12 = 1/6 Ans.
Que-9: [14/15 ÷ 1*(1/6) + 7/10] x 3/4
Solution- [14/15 ÷ 7/6 + 7/10] x 3/4
= [14/15 x 6/7 + 7/10] x 3/4
= [4/5 + 7/10] x 3/4
= [(8 + 7)/10] x 3/4
= 15/10 x 3/4
= 9/8 = 1*(1/8) Ans.
Que-10: 1/3[2*(1/2) + 3*(1/3)] ÷ 2/9[3*(1/8) – 1*(1/12)]
Solution- 1/3 [5/2 + 10/3] ÷ 2/9 [25/8 – 13/12]
= 1/3 [(15 + 20)/6] ÷ 2/9 [(75 – 26)/24]
= 1/3 x 35/6 x 9/2 x 49/24
=
Que-11: [1/4 – 1/9] ÷ [1/2 + 1/4 ÷ 1/3]
Solution- [1/4 – 1/9] ÷ [1/2 + 1/4 ÷ 1/3]
= [(9 – 4)/36] ÷ [1/2 + 1/4 x 3]
= 5/36 ÷ [1/2 + 3/4]
= 5/36 ÷ [(2 + 3)/4]
= 5/36 ÷ 5/4
= 5/36 x 4/5
= 1/9 Ans.
Que-12: 3*(7/8) – {1*(3/8) ÷ [2*(4/5) – 1*(7/10)]}
Solution- 31/8 – {11/8 ÷[14/5 – 17/10]}
= 31/8 – {11/8 ÷[(28 + 17)/10]}
= 31/8 – {11/8 ÷45/10}
= 31/8 – {11/8 x 10/45}
= 31/8 – 22/72
= ( – 22)/40
= 133/40 Ans.
Que-13: 3÷[3 x {3 – (3 – 1/4)}]
Solution– 3÷[3×{3-(3-1\4)}]
= 3÷[3×{3-(3\1-1\4)}]
=3÷[3×{3-(11\4)}]
=3÷[3×{3\1-11\4}]
=3÷[3×{1\4}]
=3÷3\4
=3×4\3
=4 Ans.
Que-14- 5*1/3-[2*(1/3) ÷ {3/4 – 1/2 x (7/10 – 3/5)}]
Solution- 5*1\3-[2*1/3÷{3/4-1/2×(7/10-3/50)}]
=16/3[7/3÷{3/4-1/2×(7-6/10)}]
=16/3-[7/3÷{3/4-1/2×(1/10)}]
=16/3-[7/3÷{3/4-1/2×1/10}]
=16/3-[7/3÷{3/4-1/20}]
=16/3-[7/3÷{15-1/20}]
=16/3-[7/3÷{14/20}]
=16/3-[7/3÷{7/10}]
=16/3-[7/3÷7/10]
=16/3-[7/3×10/7]
=16/3-[10/3]
=16/3-10/3
=6/3
=2 Ans.
— : end of Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers ICSE Foundation Maths Solutions :–
Return to :- ICSE Class -6 RS Aggarwal Goyal Brothers Math Solutions
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