Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers Prakashan ICSE Foundation Maths Solutions. We provide step by step Solutions of ICSE Class-6 **Foundation RS Aggarwal Mathematics** of Goyal Brothers Prakashan. In this article you would learn about Simplification of fraction using BODMAS rules.. Visit official Website **CISCE** for detail information about ICSE Board Class-6 Mathematics.

## Fractions Class 6 RS Aggarwal Exe-4F Simplification Goyal Brothers Prakashan ICSE Foundation Maths Solutions.

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 6th |

Ch-4 | Fraction |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-4F |

Academic Session | 2023 – 2024 |

### Simplification of fraction ussing BODMAS rules

Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers Prakashan ICSE Foundation Maths Solutions.

**Page- 80**

**Exercise- 4F**

**Que-1: Find :**

**(i) 1/8 of 40 (ii) 4/11 of 4*(2/5) (iii) 1*(3/5) of 6*(1/4)
(iv) 3/4 of Rs1 (v) 5/8 of 1 km (vi) 5/12 of 1 hour**

**Solution- **(i) 1/8 x 40

= 5 Ans.

(ii) 4/11 x 22/5

= 8/5 = 1*(3/5) Ans.

(iii) 8/5 x 25/4

= 10 Ans.

(iv) 3/4 x 1

= 0.75 = 75 paisa

(v) 5/8 x 1

= 0.625 = 625 Ans.

(vi) 5/12 x 1

= 0.25 = 25 minutes Ans.

**Simplify :**

**Que-2: 1*(1/6) ÷ 1*(5/9) x 3*(1/3)**

**Solution- **7/6 ÷ 14/9 x 10/3

= 7/6 x 9/14 x 10/3

= 5/2 = 2*(1/2) Ans.

**Que-3: 1*(1/3) ÷ 3/7 of 2*(5/8) + 1*(1/9)**

**Solution- **4/3 ÷ 3/7 x 21/8 + 10/9

= [4/3 x 8/9] + 10/9

= 32/27 + 10/9

= (32 + 30)/27

= 62/27 = 2*(8/27) Ans.

**Que-4: 6*(1/5) ÷ 3*(1/10) of 2*(1/2) ÷ 1/4**

**Solution- **31/5 ÷ 31/10 x 5/2 ÷ 1/4

= 31/5 ÷ 31/4 ÷ 1/4

= 31/5 x 4/31 x 4

= 16/5 = 3*(1/5) Ans.

**Que-5: 3*(2/3) – 3/11 of 2*(3/4) ÷ 1*(1/4) x 1*(2/3) + 1/3**

**Solution- **11/3 – 3/11 x 11/4 ÷ 5/4 x 5/3 + 1/3

= 11/3 – 3/4 x 4/5 x 5/3 + 1/3

= 11/3 – 1/1 + 1/3

= (11 – 3 + 1)/3

= 9/3 = 3 Ans.

**Que-6: 2*(2/7) of 15*(3/4) x 2*(1/4) ÷ 4/7 of 2*(5/8)**

**Solution- **16/7 x 63/4 x 9/4 ÷ 4/7 x 21/8

= 36 x 9/4 ÷ 3/2

= 36 x 9/4 x 2/3

= 27 x 2 = 54 Ans

**Que-7: 1 ÷ 4/7 – 1/3 of 3*(3/4) + 1/2 ÷ 3**

**Solution- **1 ÷ 4/7 – 1/3 x 15/4 + 1/2 ÷ 3

= 1 x 7/4 – 5/4 + 1/2 x 1/3

= 1 x 7/4 – 5/4 + 1/6

= 7/4 – 5/4 + 1/6

= (21 – 15 + 2)/12

= 8/12 = 2/3

**Que-8: [2/3 + 4/9] of 3/5 ÷ 1*(2/3) x 1*(1/4) – 1/3**

**Solution- **[(6 + 4)/9] of 3/5 ÷ 5/3 x 5/4 – 1/3

= 10/9 x 3/5 x 3/5 x 5/4 – 1/3

= 2/3 x 3/4 – 1/3

= 2/4 – 1/3

= (6 – 4)/12

= 2/12 = 1/6 Ans.

**Que-9: [14/15 ÷ 1*(1/6) + 7/10] x 3/4 **

**Solution- **[14/15 ÷ 7/6 + 7/10] x 3/4

= [14/15 x 6/7 + 7/10] x 3/4

= [4/5 + 7/10] x 3/4

= [(8 + 7)/10] x 3/4

= 15/10 x 3/4

= 9/8 = 1*(1/8) Ans.

**Que-10: ****1/3[2*(1/2) + 3*(1/3)] ÷ 2/9[3*(1/8) – 1*(1/12)****]**

**Solution- **1/3 [5/2 + 10/3] ÷ 2/9 [25/8 – 13/12]

= 1/3 [(15 + 20)/6] ÷ 2/9 [(75 – 26)/24]

= 1/3 x 35/6 x 9/2 x 49/24

=

**Que-11: [1/4 – 1/9] ÷ [1/2 + 1/4 ÷ 1/3]**

**Solution- **[1/4 – 1/9] ÷ [1/2 + 1/4 ÷ 1/3]

= [(9 – 4)/36] ÷ [1/2 + 1/4 x 3]

= 5/36 ÷ [1/2 + 3/4]

= 5/36 ÷ [(2 + 3)/4]

= 5/36 ÷ 5/4

= 5/36 x 4/5

= 1/9 Ans.

**Que-12: 3*(7/8) – {1*(3/8) ÷ [2*(4/5) – 1*(7/10)]}**

**Solution- **31/8 – {11/8 ÷[14/5 – 17/10]}

= 31/8 – {11/8 ÷[(28 + 17)/10]}

= 31/8 – {11/8 ÷45/10}

= 31/8 – {11/8 x 10/45}

= 31/8 – 22/72

= ( – 22)/40

= 133/40 Ans.

**Que-13: 3****÷[3 x {3 – (3 – 1/4)}]**

**Solution**– 3÷[3×{3-(3-1\4)}]

= 3÷[3×{3-(3\1-1\4)}]

=3÷[3×{3-(11\4)}]

=3÷[3×{3\1-11\4}]

=3÷[3×{1\4}]

=3÷3\4

=3×4\3

=4 Ans.

**Que-14- 5*1/3-[2*(1/3) ÷ {3/4 – 1/2 x (7/10 – 3/5)}]**

**Solution- **5*1\3-[2*1/3÷{3/4-1/2×(7/10-3/50)}]

=16/3[7/3÷{3/4-1/2×(7-6/10)}]

=16/3-[7/3÷{3/4-1/2×(1/10)}]

=16/3-[7/3÷{3/4-1/2×1/10}]

=16/3-[7/3÷{3/4-1/20}]

=16/3-[7/3÷{15-1/20}]

=16/3-[7/3÷{14/20}]

=16/3-[7/3÷{7/10}]

=16/3-[7/3÷7/10]

=16/3-[7/3×10/7]

=16/3-[10/3]

=16/3-10/3

=6/3

=2 Ans.

**— : end of Fractions Class 6 RS Aggarwal Exe-4F Goyal Brothers ICSE Foundation Maths Solutions :–**

**Return to :- ICSE Class -7 RS Aggarwal Goyal Brothers Math Solutions**

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