Integers Class- 7th RS Aggarwal Exe-1 A Goyal Brothers ICSE Math Solution . We provide step by step Solutions of lesson-1 Integers for ICSE Class-7 Foundation RS Aggarwal Mathematics of Goyal Brothers Prakashan . Our Solutions contain all type Questions of Exe-1 A to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7 Mathematics.
Integers Class- 7th RS Aggarwal Exe-1A Goyal Brothers ICSE Math Solution
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 7th |
| Chapter-1 | Integers |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-1A |
| Academic Session | 2023 – 2024 |
Exercise – 1 A
Integers Class- 7th RS Aggarwal Exe-1A Goyal Brothers ICSE Math Solution
Question: 1. Write all integers between :
(i) -9 and -3
Answer: To Find:- write all integers between -9 and -3.
Solution:- This question can easily be solved by just writing the integers between two numbers. We have to just write the numbers between two numbers.
= Hence the integers are -8,-7,-6,-5,-4,-3,-2,-1,0,1,2.
(ii) -33 and -26
Answer: To Find:- write all integers between -33 and -26.
Solution:- This question can easily be solved by just writing the integers between two numbers. We have to just write the numbers between two numbers.
= Hence the integers are −32,−31,−30,−29,−28,−27.
(iii) -5 and 2
Answer: To Find:- write all integers between -5 and 2.
Solution:- This question can easily be solved by just writing the integers between two numbers. We have to just write the numbers between two numbers.
= Hence the integers are -4, -3, -2, -1, 0, 1.
(iv) -1 and 6
Answer: To Find:- write all integers between -1 and 6.
Solution:- This question can easily be solved by just writing the integers between two numbers. We have to just write the numbers between two numbers.
= Hence the integers are 0,1,2,3,4,5.
Question: 2. Compare the integers :
(i) -16 and -61
Answer: -16 > -61
∴ a > b in positive integers but -a < -b in negative integers
(ii) -39 and 13
Answer: -39 < 13
∴ every positive number is always greater than any negative number
(iii) -236 and -362
Answer: -236 > -362
∴ a > b in positive integers but -a < -b in negative integers
(iv) -2 and 0
Answer: -2 < 0
∴ 0 is greater than every negative number
Question: 3. Evaluate :
(i) 20 – Ι -11 Ι
Answer: Given, 20 – Ι -11 Ι
= 20 – 11 [∴ Ι -11 Ι = 11 (Rule)]
= 9
(ii) Ι -23 Ι – Ι -16 Ι
Answer: Given, Ι -23 Ι – Ι -16 Ι
= 23 – 16
= 7
(iii) Ι -137 Ι + Ι -13 Ι
Answer: Given, Ι -137 Ι + Ι -13 Ι
= 137 + 13
= 150
(iv) 6 – Ι -4 Ι
Answer: Given, 6 – Ι -4 Ι
= 6 – 4
= 2
Question: 4. Arrange the following integers in ascending order :
(i) -9, 11, -23, 41, -37, 0, -5
Answer: Given, -9, 11, -23, 41, -37, 0, -5
Ascending order : −37,<−23,<−9,<-5,<0,<11,<41
= −37, −23, −9, -5, 0, 11, 41.
(ii) -31, 19, -50, -8, -23, 3, 8
Answer: Given, -31, 19, -50, -8, -23, 3, 8
Ascending order : −50,<−31,<−23,<−8,<3,<8,<19
= −50, −31, −23, −8, 3, 8, 19
(iii) -2, 12, -43, 31, 7, -35, -10
Answer: Given, -2, 12, -43, 31, 7, -35, -10
Ascending order : −43,<−35,<−10,<−2,<7,<12,<31
= −43, −35, −10, −2, 7, 12, 31
Question: 5. Arrange the following integers in descending order :
(i) -24, 16, -40, -5, -13, 6, -1
Answer: Given: -24, 16, -40, -5, -13, 6, -1
Descending order: 16,>6,>−1,>−5,>−13,>−24,>−40
= 16, 6, −1, −5, −13, −24, −40
(ii) 0, -7, 19, -23, -3, 8, 46
Answer: Given: 0, -7, 19, -23, -3, 8, 46
Descending order: 46,>19,>8,>0,>-3,>-7,>-23
= 46, 19, 8, 0, -3, -7, -23
(iii) -31, -13, -49, 4, 37, -9, -52
Answer: Given: -31, -13, -49, 4, 37, -9, -52
Descending order: 37,>4,>-9,>-13,>-31,>-49,>-52
= 37, 4, -9, -13, -31, -49, -52
Question: 6. Fill in the blanks :
(i) 0 is grater than every negative integer.
(ii) Every negative integer is less than every positive integer.
(iii) For any two positive integers a and b, if a < b, then -a > -b.
(iv) Modulus of a negative integer is always positive.
(v) The largest negative integer is -1.
(vi) The smallest positive integer is 1.
— : end of Integers Class-7th RS Aggarwal Exe-1A Goyal Brothers ICSE Math Solution :–
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