KE PE and Total Energy in SHM Numerical Class-11 Nootan ISC Physics

KE PE and Total Energy in SHM Numerical Class-11 Nootan ISC Physics Ch-23 Simple Harmonic Motion. Step by step solutions of Kumar and Mittal Physics of Nageen Prakashan as council latest prescribe guideline for upcoming exam. Visit official Website  CISCE for detail information about ISC Board Class-11 Physics.

KE PE and Total Energy in SHM Numerical Class-11 Nootan ISC Physics

KE PE and Total Energy in SHM Numerical Class-11 Nootan ISC Physics Ch-23 Simple Harmonic Motion

Board ISC
Class 11
Subject Physics
Book Nootan
Chapter-23 Simple Harmonic Motion.
Topics Numericals on KE PE and Total Energy in SHM
Academic Session 2025-2026

KE PE and Total Energy in SHM

Q-11. A body whose mass is 0.50 kg is executing SHM. Its period is 0.1 s and amplitude 10 cm. When the body is at a distance of 5 cm from the mean position, then find out its acceleration, force acting upon it and its potential energy.

Ans: Given  m = 0.5 kg  T = 0.1 s  A = 10 cm = 0.1 m

=> ω = 2 π / T = 2 π / 0.1 = 20 π

acceleration = ω² x

=> (20 π)² x 5 x 10^-2 = 197.2 m s^-2

F = m a

=> 0.5 x 197.2 = 98.6 N

Potential Energy (U) = 1/2 m ω² x²

=> 1/2 x 0.5 x (20 π)² x (5 x 10^-2)² = 2.465 J

Q-12. A body of mass 8 kg is executing SHM whose amplitude is 30 cm. When the body is in a position of maximum displacement, then the force acting on it is 60 N. Calculate: (i) time-period, (ii) acceleration, potential energy and kinetic energy at 12 cm displacement.

Ans: m = 8 kg  A = 30 cm = 0.3 m

F = m ω² a

=> ω² = F / m a = 60 / 8 x 0.3

(i) ω = √600 / 24 => T = 2 π / ω

=> 2 π √24 / 600 = 1.256  s

(ii) α = ω² x

=> α = (600 / 24) x 12 x 10^-2 = 3 m s^-2

(iii) U = 1/2 m ω² x²

=> (1 / 2) x 8 x (600 / 24) x (12 x 10^-2)² = 1.44 J

K = 1/2 m ω² (a² – x²)

=> (1 / 2) x 8 x (600 / 24) x (0.3² – 0.12²) = 7.56 J

Q-13. Two exactly identical simple pendulums are oscillating with amplitudes 2 cm and 6 cm. Calculate the ratio of their energies of oscillation.

Ans:  E1 / E2 = a1² / a2² = (2/6)²

=> 1 : 9

— : End of KE PE and Total Energy in SHM Numerical Class-11 Nootan ISC Physics Ch-23  :–

Return to : – – Nootan Solutions for ISC Physics Class-11

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