ML Aggarwal Matrices Exe-8.1 Class 10 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-8.1 Questions for Matrices as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-10.
ML Aggarwal Matrices Exe-8.1 Class 10 ICSE Maths Solutions
Board | ICSE |
Subject | Maths |
Class | 10th |
Chapter-8 | Matrices |
Writer / Book | Understanding |
Topics | Solutions of Exe-8.1 |
Academic Session | 2024-2025 |
Matrices Exe-8.1 Questions
ML Aggarwal Class 10 ICSE Maths Solutions
Page-142
Question-1. Classify the following matrices:
Answer :
(i) It is square matrix of order 2
(ii) It is row matrix of order 1 × 3
(iii) It is column matrix of order 3 × 1
(iv) It is matrix of order 3 × 2
(v) It is matrix of order 2 × 3
(vi) It is zero matrix of order 2 × 3
Question -2
(i) If a matrix has 4 elements, what are the possible order it can have ?
(ii) If a matrix has 8 elements, what are the possible order it can have ?
Answer:
(i) It can have 1 × 4, 4 × 1 or 2 × 2 order
(ii) It can have 1 × 8, 8 × 1,2 × 4 or 4 × 2 order
Matrices Exe-8.1 Questions
ML Aggarwal Class 10 ICSE Maths Solutions
Page-143
Question -3. Construct a 2 x 2 matrix whose elements aij are given by
(i) aij = 2i – j
(ii) aij = i.j
Answer:
Question -4. Find the values of x and y if :
Answer:
Comparing corresponding elements,
2x + y = 5 …(i)
3x – 2y = 4 …(ii)
Multiply (i) by 2 and (ii) by ‘1’ we get
4x + 2y = 10, 3x – 2y = 4
Adding we get, 7x = 14 ⇒ x = 2
Substituting the value of x in (i)
2 x 2 + y = 5 ⇒ 4 + y = 5
y = 5 – 4 = 1
Hence x = 2, y = 1
Question- 5. Find the value of x if
Answer:
Comparing the corresponding terms, we get.
-y = 2
⇒ y = -2
3x + y = 1
3x = 1 – y
Substituting value of y
3x = 1 – (-2)
3x = 1 + 2
3x = 3
x = 3/3
x = 1
Therefore x = 1 and y = -2
Question -6
If ,find values of x and y
Answer:
Comparing the corresponding terms, we get.
x + 3 = 5
⇒ x = 5 – 3 = 2
⇒ y – 4 = 3
⇒ y = 3 + 4 = 7
x = 2, y = 7
Question- 7. Find the values of x, y and z if
Answer:
Comparing the corresponding elements of equal Matrices
x + 2 = -5
⇒ x = -5 – 2 = -7
5z = -20
z = -20/5
z = – 4
y2 + y – 6 = 0
y2 + 3y – 2y – 6 = 0
y (y + 3) – 2 (y + 3) = 0
y + 3 = 0 or y – 2 = 0
y = -3 or y = 2
So x = -7, y = -3, 2 and z = -4
Question -8. Find the values of x, y, a and b if
Answer:
Comparing corresponding elements
x – 2 = 3, y = 1
x = 3 + 2 = 5
a + 2b = 5 ……(i)
3a – b = 1 ……..(ii)
Multiply (i) by 1 and (ii) by 2
a + 2b = 5 ……(i)
6a – 2b = 2 ……..(ii)
adding both equation
7a = 7
a = 7/7
a = 1
Substituting the value of a in Equ (i)
1 + 2b = 5
2b = 5 -1
2b = 4
b = 4/2
b = 2
Question -9. Find the values of a, b, c and d if
Answer -9
Comparing the corresponding terms, we get.
3 = d ⇒ d = 3
⇒ 5 + c = – 1
⇒ c = -1 – 5
⇒ c = -6
a + b = 6 and ab = 8
Now using (a – b)2 = (a + b)2 – 4 ab
(6)2 – 32 = 36 – 32 = 4 = (± 2)2
a – b = ± 2
If a – b = 2
a + b = 6
Adding the both equations
2a = 4
a = 4/2
a = 2
b = 6 – 4
b = 2
now
a – b = -2
And a + b = 6
Adding equations
2a = 4
a = 4/2
a = 2
Also, b = 6 – 2 = 4
a = 2 and b = 4
— : End of ML Aggarwal Matrices Exe-8.1 Class 10 ICSE Maths Solutions :–
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