ML Aggarwal Equation of Straight Line MCQs Class 10 ICSE Maths Solutions Ch-12. We Provide Step by Step Answer of MCQs Questions for Ch-12 Equation of Straight Line as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-10.

## ML Aggarwal Equation of Straight Line MCQs Class 10 ICSE Maths Solutions Ch-12

Board | ICSE |

Subject | Maths |

Class | 10th |

Chapter-12 | Equation of Straight Line |

Writer / Book | Understanding |

Topics | Solutions of MCQs |

Academic Session | 2024-2025 |

### Equation of Straight Line MCQs

Class 10 ICSE Maths ML Aggarwal Solutions Ch-12

**Choose the correct answer from the given four options (1 to 13) :**

**Question- 1**

**The slope of a line parallel to y-axis is**

**(a) 0**

**(b) 1**

**(c) – 1**

**(d) not defined**

**Answer -1**

Slope of a line parallel to y-axis is not defined. (d)

Page-247

**Question -2**

**The slope of a line which makes an angle of 30° with the positive direction of x-axis is**

**(a) 1**

**(b) 1/√3**

**(c) √3**

**(d) -1/√3**

**Answer -2**

Slope of a line which makes an angle of 30°

with positive direction of x-axis = tan 30°

= 1/√3 (b)

**Question -3**

**The slope of the line passing through the points (0, – 4) and ( – 6, 2) is**

**(a) 0**

**(b) 1**

**(c) – 1**

**(d) 6**

**Answer -3**

Slope of the line passing through the points (0, -4) and (-6, 2)

**Question- 4**

**The slope of the line passing through the points (3, – 2) and ( – 7, – 2) is**

**(a) 0**

**(b) 1**

**(c) -1/10**

**(d) not defined**

**Answer- 4**

Slope of the line passing through the points (3, -2) and (-7, -2)

**Question- 5**

**The slope of the fine passing through the points (3, – 2) and (3, – 4) is**

**(a) – 2**

**(b) 0**

**(c) 1**

**(d) not defined**

**Answer- 5**

The slope of the line passing through (3, -2) and (3, -4)

=(-4+2)/(3-3)

=-2/0

(d)

### Equation of Straight Line MCQs

Class 10 ICSE Maths ML Aggarwal Solutions Ch-12

**Question -6**

**The inclination of the line y = √3x – 5 is**

**(a) 30°**

**(b) 60°**

**(c) 45°**

**(d) 0°**

**Answer -6**

The inclination of the line y = √3x – 5 is

√3 = tan 60° = 60° (b)

**Question- 7**

**If the slope of the line passing through the points (2, 5) and (k, 3) is 2, then the value of k is**

**(a) -2**

**(b) -1**

**(c) 1**

**(d) 2**

**Answer- 7**

Slope of the line passing through the points (2, 5) and (k, 3) is 2, then

m = (y_{2} – y_{1})/(x_{2} – x_{1})

⇒ 2 = (3 – 5)/(k – 2)

⇒ 2 = (-2)/(k – 2)

⇒ 2k – 4 = -2

⇒ 2k = 4 – 2

= 2

⇒ k = 2/2 = 1

**Question- 8**

**The slope of a line parallel to the line passing through the points (0, 6) and (7, 3) is**

**(a) -1/5**

**(b) 1/5**

**(c) -5**

**(d) 5**

**Answer -8**

Slope of the line parallel to the line passing through (0, 6) and (7, 3)

Slope of the line =

=(3-6)/(7-0)

=-3/7

(b)

**Question -9**

**The slope of a line perpendicular to the line passing through the points (2, 5) and ( – 3, 6) is**

**(a) -1/5**

**(b) 1/5**

**(c) -5**

**(d) 5**

**Answer -9**

Slope of the line joining the points (2, 5), (-3, 6)

= (y_{2 }– y_{1})/(x_{2 }– x_{1})

= (6 – 5)/(-3 – 2)

= 1/-5 = -1/5

∴ Slope of the line perpendicular to this line = 5

**Question- 10**

**The slope of a line parallel to the line 2x + 3y – 7 = 0 is**

**(a) -2/3**

**(b) 2/3**

**(c) -3/2**

**(d) 3/2**

**Answer -10**

The slope of a line parallel to the line 2x + 3y – 7 = 0

slope of the line

3y = – 2x + 7

⇒ y = -2/3 + 7/3

= -2/3

### Class 10 ICSE Maths ML Aggarwal Solutions Ch-12

Equation of Straight Line MCQs

**Question -11**

**The slope of a line perpendicular to the line 3x = 4y + 11 is**

**(a) 3/4**

**(b) -3/4**

**(c) 4/3**

**(d) -4/3**

**Answer -11**

slope of a line perpendicular to the line 3x = 4y + 11 is

⇒ 4y = 3x – 11

⇒ y = 3/4 x – 11/4

Slope = 3/4

∴ Slope of the line perpendicular to this line = -4/3 (∵ m × n = -1)

**Question -12**

**If the lines 2x + 3y = 5 and kx – 6y = 7 are parallel, then the value of k is**

**(a) 4**

**(b) – 4**

**(c) 1/4**

**(d) -1/4**

**Answer -12**

lines 2x + 3y = 5 and kx – 6y = 7 are parallel

Slope of 2x + 3y = 5 = Slope of kx – 6y = 7

⇒ 3y – 2x + 5

⇒ y = -2/3 ×x + 5/3

Slope of 2x + 3y = 5 is -2/3

And slope of kx – 6y = 7

6y = kx – 7

⇒ y = (k/6)×x – 7/6

∴ Slope = k/6

Since both lines are parallel

∴ -2/3 = k/6

⇒ k = (-2 × 6)/3

= -4

so option (b) is correct

**Question -13**

**If the line 3x – 4y + 7 = 0 and 2x + ky + 5 = 0 are perpendicular to each other, then the value of k is**

**(a) 3/2**

**(b) -3/2**

**(c) 2/3**

**(d) -2/3**

**Answer-13**

(a) 3/2

Line 3x – 4y + 7 = 0 and 2x + ky + 5 = 0 are perpendicular to each other

∴ Product of their slopes = (m_{1}×m_{2}) = -1

Slope of 3x – 4y + 7 = 0

⇒ 4y = 3x + 7

⇒ y = 3/4 x + 7/4

Slope (m_{1}) = 3/4

And slope of 2x + ky + 5 = 0

ky = -2x – 5

y = (-2/k) ×x – 5/k

∴ Slope (m_{2}) = -2/k

Since the given lines are perpendicular to each other

∴ 3/4 × -2/k = -1

⇒ -6/4k = -1

⇒ -k = -6/4

⇒ k = 3/2

— : End ML Aggarwal Equation of Straight Line MCQs Class 10 ICSE Maths Ch-12 : –

Return to :- ML Aggarwal Solutions for ICSE Class-10

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