ML Aggarwal Decimals Check Your Progress Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of Check Your Progress Questions for Decimals as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

## ML Aggarwal Decimals Check Your Progress Class 6 ICSE Maths Solutions

Board | ICSE |

Publications | Avichal Publishig Company (APC) |

Subject | Maths |

Class | 6th |

Chapter-7 | Decimals |

Writer | ML Aggarwal |

Book Name | Understanding |

Topics | Solution of Check Your Progress Questions |

Edition | 2023-2024 |

**Decimals Check Your Progress **

**ML Aggarwal Class 6 ICSE Maths Solutions**

Page-154

**Question 1. Convert the following decimal numbers into fractions (in lowest terms).**

(i) 6.015

(ii) 0.876

(iii) 23.375

**Answer:**

**Question 2. Write the following fractions as decimals numbers:**

(i) 5/8

(ii) 2(31/125)

(iii) 13(7/40)

**Answer:**

**Question 3. Arrange the following decimal numbers in ascending order:**

(i) 123.8, 74.205, 74.209, 7.4209

(ii) 85.01, 85.1, 85.001, 85.103

**Answer:**

(i) 7.4209, 74.205, 74.209, 123.8

(ii) 85.001, 85.01, 85.1, 85.103

**Question 4. Arrange the following decimal numbers in desending order:**

(i) 6.45, 4.65, 6.405, 64.5, 6.54

(ii) 73.5, 35.7, 7.35, 7.53, 7.035

**Answer:**

(i) 64.5 > 6.54 > 6.45 > 6.405 > 4.65

(ii) 73.5 > 35.7 > 7.53 > 7.35 > 7.035

**Question 5. If the school bags of Garima and Nakul weigh 5.2 kg and 4.832 kg respectively, find**

(i) the total weight.

(ii) the difference in weight of the bags.

**Answer:**

Weight of Garima’s bag = 5.2 kg.

Weight of Nakul’s bag = 4.832 kg.

**Question 6. Evaluate the following:**

(i) 31.42 – 17.853 – 6.43

(ii) 13.01 – 5.428 – 3.703 + 2.99.

**Answer:**

(i) 31.42 – 17.853 – 6.43

**Question 7. By how much does the sum of 15.453 and 31.647 exceed the sum of 18.47 and 19.506?**

**Answer:**

**Question 8. Convert 2435 m to km and express the result as mixed fraction.**

**Answer: **

2435 m = 2435/1000 km

[ ∵ 1 km = 1000 m]

= 2.435 km

Firstly, convert the fraction 2435/1000 into the simplest form, for this dividing the numerator and denominator by 5, we get 2435/1000 km = 487/200 km

**Question 9. Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?**

**Answer:**

**Question 10. Asha purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour (aata). Find the total weight of his purchases.**

**Answer:**

Weight of rice purchased

= 5 kg 400 g = 5 kg + 400 g

= 5 kg + 400/1000 kg [∵ 1 g = 1/1000 kg]

= 5 kg + 0.400 kg

= (5 + 0.400) kg = 5.400 kg

Weight of sugar purchased

= 2 kg 20 g = 2 kg + 20 g

= 2 kg = 20/1000 kg [∵ 1 g = 1/1000 kg]

= 2 kg + 0.020 kg = 2.020 kg

Weight of flour purchased

= 10 kg 850 g = 10 kg + 850 g

= 10 kg + 850/1000 kg [∵ 1 g = 1/1000 kg]

= 10 kg + 0.850 kg

= (10 + 0.850) kg = 10.850 kg

∴ Total weight of his purchases is

**Question 11. 1 kg of pure milk contains 0.263 kg of fat. How much fat is there 15.5 kg of milk?**

**Answer:**

1 kg of pure milk contains fat = 0.263 kg

∴ 15.5 kg of milk contain fat

**Question 12. The product of two numbers is 15.275. If one number is 4.7, find the other.**

**Answer:**

The product of two number = 15.275

One number = 4.7

∴ Then other is = 15.275/4.7 = 3.25

— : End of ML Aggarwal Decimals Check Your Progress Class 6 ICSE Maths Solutions :–

Return to **–** ML Aggarwal Maths Solutions for ICSE Class -6

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