# ML Aggarwal Decimals Check Your Progress Class 6 ICSE Maths Solutions

ML Aggarwal Decimals Check Your Progress Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of  Check Your Progress Questions for Decimals as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

## ML Aggarwal Decimals Check Your Progress Class 6 ICSE Maths Solutions

 Board ICSE Publications Avichal Publishig Company (APC) Subject Maths Class 6th Chapter-7 Decimals Writer ML Aggarwal Book Name Understanding Topics Solution of Check Your Progress Questions Edition 2023-2024

ML Aggarwal Class 6 ICSE Maths Solutions

Page-154

(i) 6.015
(ii) 0.876
(iii) 23.375

(i) 5/8

(ii) 2(31/125)

(iii) 13(7/40)

#### Question 3. Arrange the following decimal numbers in ascending order:

(i) 123.8, 74.205, 74.209, 7.4209
(ii) 85.01, 85.1, 85.001, 85.103

(i) 7.4209, 74.205, 74.209, 123.8
(ii) 85.001, 85.01, 85.1, 85.103

#### Question 4. Arrange the following decimal numbers in desending order:

(i) 6.45, 4.65, 6.405, 64.5, 6.54
(ii) 73.5, 35.7, 7.35, 7.53, 7.035

(i) 64.5 > 6.54 > 6.45 > 6.405 > 4.65
(ii) 73.5 > 35.7 > 7.53 > 7.35 > 7.035

#### Question 5. If the school bags of Garima and Nakul weigh 5.2 kg and 4.832 kg respectively, find

(i) the total weight.
(ii) the difference in weight of the bags.

Weight of Garima’s bag = 5.2 kg.
Weight of Nakul’s bag = 4.832 kg.

#### Question 6. Evaluate the following:

(i) 31.42 – 17.853 – 6.43
(ii) 13.01 – 5.428 – 3.703 + 2.99.

(i) 31.42 – 17.853 – 6.43

#### Question 8. Convert 2435 m to km and express the result as mixed fraction.

2435 m = 2435/1000 km

[ ∵ 1 km = 1000 m]

= 2.435 km

Firstly, convert the fraction 2435/1000 into the simplest form, for this dividing the numerator and denominator by 5, we get 2435/1000 km = 487/200 km

#### Question 10. Asha purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour (aata). Find the total weight of his purchases.

Weight of rice purchased
= 5 kg 400 g = 5 kg + 400 g
= 5 kg + 400/1000  kg [∵ 1 g = 1/1000  kg]
= 5 kg + 0.400 kg
= (5 + 0.400) kg = 5.400 kg
Weight of sugar purchased
= 2 kg 20 g = 2 kg + 20 g
= 2 kg = 20/1000  kg [∵ 1 g = 1/1000  kg]
= 2 kg + 0.020 kg = 2.020 kg
Weight of flour purchased
= 10 kg 850 g = 10 kg + 850 g
= 10 kg + 850/1000  kg [∵ 1 g = 1/1000  kg]
= 10 kg + 0.850 kg
= (10 + 0.850) kg = 10.850 kg
∴ Total weight of his purchases is

#### Question 11. 1 kg of pure milk contains 0.263 kg of fat. How much fat is there 15.5 kg of milk?

1 kg of pure milk contains fat = 0.263 kg
∴ 15.5 kg of milk contain fat