# ML Aggarwal Decimals Exe-7.5 Class 6 ICSE Maths Solutions

ML Aggarwal Decimals Exe-7.5 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-7.5 Questions for Decimals as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

## ML Aggarwal Decimals Exe-7.5 Class 6 ICSE Maths Solutions

Board | ICSE |

Publications | Avichal Publishig Company (APC) |

Subject | Maths |

Class | 6th |

Chapter-7 | Decimals |

Writer | ML Aggarwal |

Book Name | Understanding |

Topics | Solution of Exe-7.5 Questions |

Edition | 2023-2024 |

**Decimals Exe-7.5**

**ML Aggarwal Class 6 ICSE Maths Solutions**

Page-150

**Question 1. Express as rupees using decimals:**

(i) 75 paise

(ii) 1025 paise

(ii) 63 rupees 9 paise

**Answer:**

(i) 75 paise = ₹75/100 = ₹0.75

(ii) 1025 paise = ₹1025/100 = ₹10.25

(iii) 63 rupees 9 paise = ₹6309/100 = ₹63.09

**Question 2. Express as cm using decimals:**

(i) 8 mm

(ii) 263 mm

(iii) 13 cm 3 mm

**Answer:**

(i) 8 mm = 8/10 cm = 0.8 cm

(ii) 263 mm = 263/10 cm = 26.3 cm

(iii) 13 cm 3 mm = 13 cm × 3/10 cm = 13.3 cm

**Question 3. Express as metres using decimals:**

(i) 6 cm

(ii) 528 cm

(iii) 7 m 55 cm

**Answer:**

(i) 6 cm = 6/100 m = 0.06 m

(ii) 528 cm = 528/100 m = 5.28 m

(iii) 7 m 55 cm = 7 m + 55 cm

= 7 m + 55/100m = (7 + .55) m = 7.55 m

**Question 4. Express as km using decimals:**

(i) 5 m

(ii) 888 m

(iii) 15 km 88 m

**Answer:**

(i) 5 m = 5/1000 km = 0.005 km

(ii) 888 m = 888/1000 km = 0.888 km

(iii) 15 km 88 m = 15 km + 88 m

= 15 km + 88/1000 km = (15 + 0.88) kmsss

= 15.088 km

**Question 5. Express as kg using decimals:**

(i) 37 g

(ii) 100 g

(iii) 5 kg 8 g

**Answer:**

(i) 37g = 37/1000 kg = 0.037 kg

(ii) 100 g = 100/1000kg = 0.1 kg

(iii) 5kg 8g = 5kg + 8gm

= 5 kg = 8/1000kg.

= (5 + .008) kg = 5.008 kg

**Question 6. Express as kL using decimals:**

(i) 6L

(ii) 555L

(iii) 3 kL 95L

**Answer:**

(i) 6L = 6/1000 = 0.006 kL

(ii) 555L = 555/1000 = 0.555kL

(iii) 3 kL 95L = 3 + 95/1000 = 3.095 kL

**Question 7. Anita bought 2 m 70 cm cloth for her shirt and 2 m 85 cm cloth for her trouser. Find the total length of the cloth bought by her.**

**Answer:**

Cloth bought for her shirt

= 2 m 70 cm = 2 m + 70 cm

= 2 m + 70/100m = 2 m + 0.70 m (∵ 1 cm = 1/100m)

= (2 m + 0.70) m = 2.70 m

Cloth bought for her trouser

= 2 m 85 cm = 2 m + 85 cm

= 2 m + 85/100m = 2 m + 0.85 m (∵ 1 cm = 1/100m)

= (2 + 0.85) m = 2.85

∴ Total lengths of cloth bought is 2.70 m + 2.85 m = 5.55 m

**Question 8. Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?**

**Answer:**

Distance travelled by bus

= 15 km 268 m = 15 km + 268 m

= 15 km + 268/1000 km

= 15 km + 0.268 km

**Question 9. Rahul bought 4 kg 90 g apples, 2 kg 60 g grapes and 5 kg 300 g mangoes. Find the total weight of all the fruits he bought.**

**Answer:**

Weight of apples = 4 kg 90 g

= 4 kg + 0.09 kg

= (4 + 0.09) kg = 4.09 kg

Weight of grapes = 2 kg 60 g

= 2kg + 60/1000 (∵ 1g = 1/1000 kg)

= 2 kg + 0.06 kg

= (2 + 0.06) kg = 20.6 kg

Weight of mangoes = 5 kg 300 g

= 5 kg + 300/1000 kg (∵1g = 1/1000 kg)

= 5 kg + 0.3 kg

= (5 + 0.3) kg = 5.3 kg

Total weight of his purchases is

= 4.090 kg + 2.060 kg + 5.300 kg

= 11.450 kg

**Question 10. Rani had ₹18.50. She bought one ice¬cream for ₹11.75. How much money does she have now?**

**Answer:**

Money Rani had = ₹ 18.75

Ice-cream bought for ₹11.75

∴ Money she has now = ₹ 18.50 – ₹ 11.75 = ₹ 6.75

**Question 11. Tina had 20 m 5 cm long cloth. She cuts 4m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?**

**Answer:**

Length of cloth Tina had

= 20 m 5 cm = 20 m + 5 cm

Length of cloth cut of 4 m 50 cm

= 4 m + 50 cm

**Question 12. Ruby bought a watermelon weighing 5 kg 300 g. Out of which she gave 2 kg 680 g to her neighbour. What is the weight of the watermelon left with Ruby?**

**Answer:**

Total weight of watermelon = 5 kg 300 gm

∴Given to neighbour = 2 kg 680 gm

∴ Weight of watermelon left = 5 × 1000 + 300 gm – 2 × 1000 gm + 680 gm

= 5300 gm – 2680 gm = 2620 gm

= 2620/1000 = 2 kg 620 gm ⇒ 2.620 kg

**Question 13. The cost of 1 metre of cloth is ₹35.80. What will be cost of 9.8 metres of cloth?**

**Answer:**

Given : Cost of one metre cloth = ₹35.80

∴ Cost of 9.8 metre cloth is

Cost of 9.8 m cloth = ₹(35.80 × 9.8)

= ₹350.84

**Question 14. Farida bought some bags of cement, each weighing 49.8 kg. If the total weight of all the bags is 1792.8 kg, how many bags did she buy?**

**Answer:**

Total weight of bag = 1792.8 kg

Weight of cement bag = 49.8 kg

∴ The number of bags she bought

— : End of ML Aggarwal Decimals Exe-7.5 Class 6 ICSE Maths Solutions :–

Return to **–** ML Aggarwal Maths Solutions for ICSE Class -6

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