ML Aggarwal Integers Exe-1.5 Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-1.5 Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.

## ML Aggarwal Integers Exe-1.5 Class 7 Maths Solutions

Board | ICSE |

Publications | Avichal Publishig Company (APC) |

Subject | Maths |

Class | 7th |

Chapter-1 | Integers |

Writer | ML Aggarwal |

Book Name | Understanding |

Topics | Solution of Exe-1.5 Questions |

Edition | 2023-2024 |

**Integers Exe-1.5**

ML Aggarwal Class 7 ICSE Maths Solutions

Page-23

**Question 1. 7 – 8 ÷ (-2) + 3 × (-4)**

**Answer:**

7 – 8 ÷ (-2) + 3 × (-4)

= 7 + (-8/2)

+ 3 × (-4)

= 7 + 4 + 3 × (-4) ( use of BODMAS)

= 7 + 4 – 12

= 11 – 12

= – 1

**Question 2. 9 – {7 – 24 ÷ (8 + 6 × 2 – 16)}**

**Answer:**

9 – { 7 – 24 ÷ (8 + 6 × 2 – 16 ) }

= 9 – { 7 – 24 ÷ (8 + 12 – 16 ) }

= 9 – { 7 – 24 ÷ 4 }

= 9 – ( 7 – (24/4))

= 9 – [ 7 – 6 ]

= 9 – 1

= 8

**Question 3. -11 – [-6 – {3 – 5(8 ÷ 4 – 1)}]**

**Answer:**

-11 [ -6 –{ 3 – 5 ( 8 ÷ 4 – 1 ) } ]

= -11 [ -6 –{ 3 – 5 ( 2 – 1 ) } ]

= -11 [ -6 –{ 3 – 5 × 1} ]

= -11 [ -6 –{ 3 – 5 } ]

= -11 [ -6 – ( -2 ) ]

= -11 – (-4)

= -11 +4

= -7

**Question 4. (-3) × (12) ÷ (-4) + 3 × 6**

**Answer:**

(-3) × (12) ÷ (-4) + 3 × 6

= -3 × (-12/-4) + 3 × 6

= -9 + 18

= 9

**Question 5. 14 ÷ (3 of 2 – 3 + 4) – 9(5 – 3)**

**Answer:**

14 ÷ ( 6 – 3 + 4 ) – 9(2)

= 14 ÷ 7 – 9 × 2

= 2 – 18

= -16

— : End of ML Aggarwal Integers Exe-1.5 Class 7 ICSE Maths Solutions :–

Return to **– **ML Aggarwal Maths Solutions for ICSE Class -7

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