ML Aggarwal Integers Exe-1.5 Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of  Exe-1.5 Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.

## ML Aggarwal Integers Exe-1.5 Class 7 Maths Solutions

 Board ICSE Publications Avichal Publishig Company (APC) Subject Maths Class 7th Chapter-1 Integers Writer ML Aggarwal Book Name Understanding Topics Solution of Exe-1.5 Questions Edition 2023-2024

### Integers Exe-1.5

ML Aggarwal Class 7 ICSE Maths Solutions

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#### Question 1. 7 – 8 ÷ (-2) + 3 × (-4)

7 – 8 ÷ (-2) + 3 × (-4)
= 7 + (-8/2)
+ 3 × (-4)
= 7 + 4 + 3 × (-4) ( use of BODMAS)
= 7 + 4 – 12
= 11 – 12
= – 1

#### Question 2. 9 – {7 – 24 ÷ (8 + 6 × 2 – 16)}

9 – { 7 – 24 ÷ (8 + 6 × 2 – 16 ) }
= 9 – { 7 – 24 ÷ (8 + 12 – 16 ) }
= 9 – { 7 – 24 ÷ 4 }
= 9 – ( 7 – (24/4))
= 9 – [ 7 – 6 ] = 9 – 1
= 8

#### Question 3. -11 – [-6 – {3 – 5(8 ÷ 4 – 1)}]

-11 [ -6 –{ 3 – 5 ( 8 ÷ 4 – 1 ) } ] = -11 [ -6 –{ 3 – 5 ( 2 – 1 ) } ] = -11 [ -6 –{ 3 – 5 × 1} ] = -11 [ -6 –{ 3 – 5 } ] = -11 [ -6 – ( -2 ) ] = -11 – (-4)
= -11 +4
= -7

#### Question 4. (-3) × (12) ÷ (-4) + 3 × 6

(-3) × (12) ÷ (-4) + 3 × 6
= -3 × (-12/-4) + 3 × 6
= -9 + 18
= 9

#### Question 5. 14 ÷ (3 of 2 – 3 + 4) – 9(5 – 3)

14 ÷ ( 6 – 3 + 4 ) – 9(2)
= 14 ÷ 7 – 9 × 2
= 2 – 18
= -16

—  : End of ML Aggarwal Integers Exe-1.5 Class 7 ICSE Maths Solutions :–

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