ML Aggarwal Integers Exe-1.5 Class 7 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-1.5 Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-7.
ML Aggarwal Integers Exe-1.5 Class 7 Maths Solutions
| Board | ICSE |
| Publications | Avichal Publishig Company (APC) |
| Subject | Maths |
| Class | 7th |
| Chapter-1 | Integers |
| Writer | ML Aggarwal |
| Book Name | Understanding |
| Topics | Solution of Exe-1.5 Questions |
| Edition | 2023-2024 |
Integers Exe-1.5
ML Aggarwal Class 7 ICSE Maths Solutions
Page-23
Question 1. 7 – 8 ÷ (-2) + 3 × (-4)
Answer:
7 – 8 ÷ (-2) + 3 × (-4)
= 7 + (-8/2)
+ 3 × (-4)
= 7 + 4 + 3 × (-4) ( use of BODMAS)
= 7 + 4 – 12
= 11 – 12
= – 1
Question 2. 9 – {7 – 24 ÷ (8 + 6 × 2 – 16)}
Answer:
9 – { 7 – 24 ÷ (8 + 6 × 2 – 16 ) }
= 9 – { 7 – 24 ÷ (8 + 12 – 16 ) }
= 9 – { 7 – 24 ÷ 4 }
= 9 – ( 7 – (24/4))
= 9 – [ 7 – 6 ]
= 9 – 1
= 8
Question 3. -11 – [-6 – {3 – 5(8 ÷ 4 – 1)}]
Answer:
-11 [ -6 –{ 3 – 5 ( 8 ÷ 4 – 1 ) } ]
= -11 [ -6 –{ 3 – 5 ( 2 – 1 ) } ]
= -11 [ -6 –{ 3 – 5 × 1} ]
= -11 [ -6 –{ 3 – 5 } ]
= -11 [ -6 – ( -2 ) ]
= -11 – (-4)
= -11 +4
= -7
Question 4. (-3) × (12) ÷ (-4) + 3 × 6
Answer:
(-3) × (12) ÷ (-4) + 3 × 6
= -3 × (-12/-4) + 3 × 6
= -9 + 18
= 9
Question 5. 14 ÷ (3 of 2 – 3 + 4) – 9(5 – 3)
Answer:
14 ÷ ( 6 – 3 + 4 ) – 9(2)
= 14 ÷ 7 – 9 × 2
= 2 – 18
= -16
— : End of ML Aggarwal Integers Exe-1.5 Class 7 ICSE Maths Solutions :–
Return to – ML Aggarwal Maths Solutions for ICSE Class -7
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