ML Aggarwal Integers Exe-3.3 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of  Exe-3.3 Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

## ML Aggarwal Integers Exe-3.3 Class 6 ICSE Maths Solutions

 Board ICSE Publications Avichal Publishig Company (APC) Subject Maths Class 6th Chapter-3 Integers Writer ML Aggarwal Book Name Understanding Topics Solution of Exe-3.3 Questions Edition 2023-2024

### Integers Exe-3.3

ML Aggarwal Class 6 ICSE Maths Solutions

Page-55

#### Question 1. Evaluate the following, using the number line:

(i) 4 – (-2)
(ii) -4 – (-2)
(iii) 3 – 6
(iv) -3 – (-5)

(i) Start form 4 on the number line.

Move 2 units to the digits we reach at 6

so 4 – (-2)

= 4 + 2 = 6

#### Question 2. Subtract :

(i) -6 from 9
(ii) 6 from -9
(iii) -6 from -9
(iv) -725 from -63
(v) -376 from 10
(vi) 92 from -620

(i) 9 – (-6)

= 9 + 6 = 15

(ii) -9 – (-6)

= 9 + 6 = 15

(iii) 9 – (-6)

= -9 + 6 = -3

(iv) -63 – (-725)

= -63 – (-725)   =+ 662

(v) 10 – (-376)

= 10 + 376 = 386

(vi) -620 – 92

= -712

#### Question 3. Evaluate the following:

(i) -237 – (+ 1884)
(ii) -346 – (- 1275)
(iii) -190 – (-3512)
(iv) -2718 – (+ 6827)

(i) -237 – (+1884)

= -273 – 18

– (237 + 1884) = -2121

(ii) -346 – (-1275)

= -346 + 1275

1275 – 346 = 929

(iii) -190 – (-3512)

= -3512 – 190

= 3322

(iv) -2718 – (+6827)

= -2718 – 6827

– (2718 + 6827) = -9545

#### Question 4.

(i) The sum of two integers is 17. If one of them is -35, find the other.

(ii) The sum of two integers is -80. If one of them is -90, then find the other.

(i) One number = -35

sum of two int number = 17

second  number = Sum of int – the given number =17 – (-35)

= 17 + 35 = 52

(ii) Sum of two integers = -80

One of the integers is -90.

The other integer = Sum of two integers – One of the integers

The other integer = -80 – (-90) = -80 + 90 = 10

Hence, the other integer is 10.

#### Question 5. What must be added to -23 to get -9?

The number to be added = x

so -23 + x = -9

required number = -9 -(-23)

= -9 + 23 = 14

#### Question 6. Find the predecessor of 0.

Predecessor of 0 = 0 – 1

= -1

#### Question 7. Find the successor and the predecessor of the following integers:

(i) -31
(ii) -735
(iii) -240

(i) Successor of -31 = -31 + 1 = -30

Predecessor  of -31 = -31 – 1 = -32

(ii) Successor of -735 = -735 + 1 = -734

Predecessor  of -735= -735 – 1 = -736

(iii) Successor of -240 = -240 + 1 = -239

Predecessor  of -240 = -240 – 1 = -241

—  : End of ML Aggarwal Integers Exe-3.3 Class 6 ICSE Maths Solutions :–

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