ML Aggarwal Integers Exe-3.3 Class 6 ICSE Maths Solutions
ML Aggarwal Integers Exe-3.3 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-3.3 Questions for Integers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.
ML Aggarwal Integers Exe-3.3 Class 6 ICSE Maths Solutions
| Board | ICSE |
| Publications | Avichal Publishig Company (APC) |
| Subject | Maths |
| Class | 6th |
| Chapter-3 | Integers |
| Writer | ML Aggarwal |
| Book Name | Understanding |
| Topics | Solution of Exe-3.3 Questions |
| Edition | 2023-2024 |
Integers Exe-3.3
ML Aggarwal Class 6 ICSE Maths Solutions
Page-55
Question 1. Evaluate the following, using the number line:
(i) 4 – (-2)
(ii) -4 – (-2)
(iii) 3 – 6
(iv) -3 – (-5)
Answer:
(i) Start form 4 on the number line.
Move 2 units to the digits we reach at 6
so 4 – (-2)
= 4 + 2 = 6
Question 2. Subtract :
(i) -6 from 9
(ii) 6 from -9
(iii) -6 from -9
(iv) -725 from -63
(v) -376 from 10
(vi) 92 from -620
Answer:
(i) 9 – (-6)
= 9 + 6 = 15
(ii) -9 – (-6)
= 9 + 6 = 15
(iii) 9 – (-6)
= -9 + 6 = -3
(iv) -63 – (-725)
= -63 – (-725) =+ 662
(v) 10 – (-376)
= 10 + 376 = 386
(vi) -620 – 92
= -712
Question 3. Evaluate the following:
(i) -237 – (+ 1884)
(ii) -346 – (- 1275)
(iii) -190 – (-3512)
(iv) -2718 – (+ 6827)
Answer:
(i) -237 – (+1884)
= -273 – 18
– (237 + 1884) = -2121
(ii) -346 – (-1275)
= -346 + 1275
1275 – 346 = 929
(iii) -190 – (-3512)
= -3512 – 190
= 3322
(iv) -2718 – (+6827)
= -2718 – 6827
– (2718 + 6827) = -9545
Question 4.
(i) The sum of two integers is 17. If one of them is -35, find the other.
(ii) The sum of two integers is -80. If one of them is -90, then find the other.
Answer:
(i) One number = -35
sum of two int number = 17
second number = Sum of int – the given number =17 – (-35)
= 17 + 35 = 52
(ii) Sum of two integers = -80
One of the integers is -90.
The other integer = Sum of two integers – One of the integers
⇒The other integer = -80 – (-90) = -80 + 90 = 10
Hence, the other integer is 10.
Question 5. What must be added to -23 to get -9?
Answer:
The number to be added = x
so -23 + x = -9
required number = -9 -(-23)
= -9 + 23 = 14
Question 6. Find the predecessor of 0.
Answer:
Predecessor of 0 = 0 – 1
= -1
Question 7. Find the successor and the predecessor of the following integers:
(i) -31
(ii) -735
(iii) -240
Answer:
(i) Successor of -31 = -31 + 1 = -30
Predecessor of -31 = -31 – 1 = -32
(ii) Successor of -735 = -735 + 1 = -734
Predecessor of -735= -735 – 1 = -736
(iii) Successor of -240 = -240 + 1 = -239
Predecessor of -240 = -240 – 1 = -241
— : End of ML Aggarwal Integers Exe-3.3 Class 6 ICSE Maths Solutions :–
Return to – ML Aggarwal Maths Solutions for ICSE Class -6
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