ML Aggarwal Knowing Our Numbers Exe-1.3 Class 6 ICSE Maths Solutions

ML Aggarwal Knowing Our Numbers Exe-1.3 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of  Exe-1.3 Questions for Knowing Our Numbers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

ML Aggarwal Knowing Our Numbers Exe-1.3 Class 6 ICSE Maths Solutions

Board ICSE
Publications Avichal Publishig Company (APC)
Subject Maths
Class 6th
Chapter-1 Knowing Our Numbers
Writer ML Aggarwal
Book Name Understanding
Topics Solution of Exe-1.3 Questions
Edition 2023-2024

Knowing Our Numbers Exe-1.3

ML Aggarwal Class 6 ICSE Maths Solutions

Page-12

Question 1. Write all possible 2-digits numbers that can be formed by using the digits 2, 3 and 4. Repetition of digits is not allowed. Also find their sum.

Answer:

The given digits are 2, 3, 4 and repetition of digits is not allowed.

Out of the given digits, the possible ways of choosing the two digits are 2, 3; 2, 4; 3, 4

Using the digits 2 and 3, the numbers are 23 and 32

Similarly, Using the digits 2 and 4, the numbers are 24 and 42

Using the digits 3 and 4, the numbers are 34 and 43

Hence, all possible 2-digit numbers are 23, 32, 24, 42, 34, 43

∴ Sum of above numbers

= 23 + 34 + 32 + 24 + 43 + 42 = 198.

Question 2. Write all possible 3-digits numbers using the digits 3, 1 and 5. Repetition of digits is not allowed.

Answer:

We are required to write 3-digit numbers using the digits 1, 3, 5 and the repetition of the digits is not allowed.

Keeping 1 at unit’s place, 3-digit number obtained are 351 and 531.

Keeping 3 at unit’s place, 3-digit number obtained are153 and 513.

Keeping 5 at unit’s place, 3-digit number obtained are 315 and 135.

Hence, all possible 3-digit numbers are : 315, 351, 153, 135, 531, 513

Question 3. Write all possible 3-digits numbers using the digits 7, 0 and 6. Repetition of digits is not allowed. Also, find their sum.

Answer:

we are required to write 3 –digit numbers using the digits 0,6,7 and the repetition of the digits is not allowed.

Keeping 0 at unit’s place, 3-digit number obtained are 670 and 760.

Keeping 6 at unit’s place, 3-digit number obtained are 706.

Keeping 7 at unit’s place, 3-digit number obtained are 607.

Keeping 7 at unit’s place, 3- digit number obtained are 607.

Hence, all possible 3- digit numbers are : 670, 760, 607, 706.

∴ Sum of above numbers
= 670 + 760 + 607 + 706 = 2743

Question -4. Write all possible 2-digit numbers using the digits 4, 0 and 9. Repetition of digits is not allowed. Also find their sum.

Answer:

The given digits are 0, 4, 9 and repetition of digits is not allowed.
Out of the given digits, the possible ways of choosing the two digits are 4, 0; 4, 9; 9, 0

Using the digits 4 and 0, the number are 40.

Similarly, Using the digits 4 and 9, the numbers are 49 and 94.
Using the digits Hence, all possible 2-digit numbers are 40, 49, 90, 94
∴ Sum of above numbers = 40 + 49 + 90 + 94 = 273

Question 5. Write all possible 2-digit numbers that can be formed by using the digit 3, 7 and 9. Repetition of digits is allowed.

Answer:

The given digits are 3, 7, 9 and repetition of digits is not allowed. Out of
the given digits, the possible ways of choosing the two digits are 3, 7; 3, 9; 7, 9
Using the digits 3 and 7, the numbers are 37, 73, 33 and 77.
Similarly, Using the digits 3 and 9, the numbers are 39, 93, and 99.
Using the digits 7 and 9, the numbers are 79 and 97.
Hence, all possible 2-digit numbers are
37, 73, 33, 77, 39, 93, 99, 79, 97

Question 6. Write all possible numbers using the digits 3,1 and 5. Repetition of digits is not allowed.

Answer:

The given digits are 1,3, 5 and repetition of digits is not allowed.
The one-digit numbers that can be formed are 1, 3 and 5.
We are required to write 2-digit numbers.

Out of the given digits, the possible ways of choosing the two digits are 1, 3, 1, 5, 3, 5
Using the digits 1 and 3, the numbers are13 and 31.
Similarly, Using the digits 1 and 5, the numbers are 15 and 51.
Using the digits 3 and 5, the numbers are 35 and 53.
Hence, all possible 2-digitt numbers are 13, 31, 15, 51, 35, 53
Now, We are required to write 3-digit numbers using the digits 1, 3, 5 and the repetition of the digits is not allowed. Keeping 1 at unit’s place, 3-digit number obtained are 351 and 531.

Keeping 3 at unit’s place, 3-digit number obtained are 153 and 513.
Keeping 5 at unit’s place, 3-digit number obtained are 315 and 135.
Hence, all possibe 3-digit numbers are : 315, 351, 153, 135, 531, 513
All possible numbers using the digits 3, 1 and 5 are :
1, 3, 5, 31, 13, 35, 53, 15, 51, 315, 153, 351, 531, 513, 135.

Question -7. How many 6-digit numbers are there in all ?

Answer:

The lowest 6-digit number is 100,000 and the highest is 999,999.

Subtract 999,999−100,000=899,999, but then add 1, because we want to include both 100,000 and 999,999.

Question -8. Write down the greatest number and the smallest number of 4-digits that can be formed by the digits 7, 5,0 and 4 using each digit only once.

Answer:

The greatest 4 digit number are – 7540

The smallest 4 digits number are – 4057

Question 9. Rearrange the digits of the number 5701024 to get the largest number and the smallest number of 7 digits.

Answer:

The greatest 7 digit numbers is – 7542100

The smallest 7 digit number is – 1002457

Question 10.

Keeping the place value of digit 3 in the number 730265 same, rearrange the digits of the given number to get the largest number and smallest number of 6 digits.

Answer:

Keeping the same place values of digit 3 in the number 730265 and rearranging the digits of the given number,
Greatest number of 6 digits= 736520 Smallest number of 6 digits = 230567.

Question-11. From smallest and greatest 4-digit numbers by using any one digit twice from the digits:

(i) 5, 2, 3, 9
(ii) 6, 0, 1, 4
(iii) 4, 6, 1, 5, 8.

Answer:

(i) Greatest number: 9953

Smallest number: 2235

(ii) Greatest number:

Smallest number: 6641

Smallest number: 1004

(iii) Greatest number: 8865

Smallest number: 1145

Question -12. Write

(i) the greatest number of 6 digits
(ii) the smallest number of 7 digits. Also find their difference.

Answer:

The greatest number  of 6 digits : 999999

The smallest number of 7 digits: 1000000.

Their differences are = 1000000 – 999999 = 1.

Question -13. Write the greatest 4-digit number of distinct digits.

Answer:

the greatest 4-digit number of distinct digits.-9876

Question -14. Write the smallest 4-digit number of distinct digits.

Answer:

the smallest 4-digit number of distinct digits -1234

Question -15. Write the greatest 6-digit number using three different digits.

Answer:

the greatest 6-digit number using three different digits- 999987

Question -16. Write the smallest 7-digit number using four different digits.

Answer:

the smallest 7-digit number using four different digits- 1000234

Question- 17. Write the greatest and the smallest 4-digit numbers using four different digits with the conditions as given:

(i) Digit 7 is always at units place.
(ii) Digit 4 is always at tens place.
(iii) Digit 9 is always at hundreds place.
(iv) Digit 2 is always at thousands place.

Answer:

(i) 9867; 1027

(ii) 9847; 1042

(iii) 8976; 1902

(iv) 2987; 2013

—  : End of ML Aggarwal Knowing Our Numbers Exe-1.3 Class 6 ICSE Maths Solutions :–

Return to   ML Aggarwal Maths Solutions for ICSE Class -6

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