ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-1.4 Questions for Knowing Our Numbers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.
ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions
| Board | ICSE |
| Publications | Avichal Publishig Company (APC) |
| Subject | Maths |
| Class | 6th |
| Chapter-1 | Knowing Our Numbers |
| Writer | ML Aggarwal |
| Book Name | Understanding |
| Topics | Solution of Exe-1.4 Questions |
| Edition | 2023-2024 |
Knowing Our Numbers Exe-1.4
ML Aggarwal Class 6 ICSE Maths Solutions
Page-15
Question-1 . In a particular year, a company manufactured 8570435 bicycles and next year it manufactured 8756430 bicycles. In which year more bicycles were manufactured and by how many?
Answer:
Next year it manufactured more bicycles by –
(8756430 – 8570435 = 185995)
Question-2. What number must be subtracted from 1,02,59,756 to get 77,63,835
Answer:
1,02,59,756 – 77,63,835 = 2495921
Question-3. The sale receipt of a company during a year was Rs. 30587850. Next year it increased by Rs. 6375490. What was the total sale receipt of the company during these two years?
Answer:
30587850 + 6375490 = 67551190
Question-4. A machine manufactures 23875 screws per day. How many screws did it produce in the year 2016? Assume that the machine worked on all the days of the year.
Answer:
: 23875 x 366 = 8738250 (leap year)
Question-5. A merchant had Rs. 78,592 with him. He placed an order for purchasing 54 bicycles at Rs. 970 each. How much money will remain with him after the purchase.
Answer:
: 54 bicycles at Rs. 970 each = 54 x 970 = 52380
Money remain with him after the purchase = 78,592 – 52380 = 26212
Question- 6. Amitabh is 1 m 82 cm tall and his wife is 35 cm shorter then him. What is his wife’s height?
Answer:
: 1 m 82 cm – 35 cm
182 cm – 35 cm
= 147 cm.
= 1 m + 47cm
Question-7. The mass of each gas cylinder is 21 kg 270 g. What is the total mass of 28 such cylinders?
Answer:
21 kg 270 gm = 21000 + 270 = 21270 gm
Now, 21270 x 28 = 595560 gm = 595 kg 560 gm.
Question- 8. In order to make a shirt, 2 m 25 cm cloth is needed. What length of cloth is required to make 18 such shirts?
Answer:
: 2 m 25 cm = 2 x 100 + 25 = 200 + 25 = 225 cm
Now, 225 x 18 = 4050 cm = 40 m 50 cm
Question-9. The total mass of 12 packets of sweets, each of same size, is 15 kg 600 g. What is the mass of each such packet?
Answer:
Total mass of 12 packets of sweets
= 15kg 600g
= 15 × 1000 + 600g
= 15600 g
Total mass of one packet of sweets
= 15600 – 12 = 1300g
= 1 kg 300g
Question-10. A vessel has 4 litres 500 milliliters of orange juice. In how many glasses, each of 25 mL capacity, can it be filled?
Answer:
: 4 litres 500 milliliters = 4 x 1000 + 500 = 4000 + 500 = 4500 ml
4500 / 25 = 180 glass
Question- 11. To stitch a trouser, 1 m 30 cm cloth is needed. Out of 25 m cloth, how many trousers can be switched and how many cloth is needed.
Answer:
1 x 100 + 30 cm = 100 + 30 cm = 130 cm.
Now, 25m = 2500 cm
number of trousers = 2500 cm / 130 cm.
number of trousers = 19
30 cm left
— : End of ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions :–
Return to – ML Aggarwal Maths Solutions for ICSE Class -6
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