ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions

ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of  Exe-1.4 Questions for Knowing Our Numbers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions

Board ICSE
Publications Avichal Publishig Company (APC)
Subject Maths
Class 6th
Chapter-1 Knowing Our Numbers
Writer ML Aggarwal
Book Name Understanding
Topics Solution of Exe-1.4 Questions
Edition 2023-2024

Knowing Our Numbers Exe-1.4

ML Aggarwal Class 6 ICSE Maths Solutions

Page-15

Question-1 . In a particular year, a company manufactured 8570435 bicycles and next year it manufactured 8756430 bicycles. In which year more bicycles were manufactured and by how many?

Answer:

Next year it manufactured more bicycles by –

(8756430 – 8570435 = 185995)

Question-2. What number must be subtracted from 1,02,59,756 to get 77,63,835

Answer:

1,02,59,756 – 77,63,835 = 2495921

Question-3. The sale receipt of a company during a year was Rs. 30587850. Next year it increased by Rs. 6375490. What was the total sale receipt of the company during these two years?

Answer:

30587850 + 6375490 = 67551190

Question-4. A machine manufactures 23875 screws per day. How many screws did it produce in the year 2016? Assume that the machine worked on all the days of the year.

Answer:

: 23875 x 366 = 8738250 (leap year)

Question-5. A merchant had Rs. 78,592 with him. He placed an order for purchasing 54 bicycles at Rs. 970 each. How much money will remain with him after the purchase.

Answer:

: 54 bicycles at Rs. 970 each = 54 x 970 = 52380

Money remain with him after the purchase = 78,592 – 52380 = 26212

Question- 6. Amitabh is 1 m 82 cm tall and his wife is 35 cm shorter then him. What is his wife’s height?

Answer:

: 1 m 82 cm – 35 cm

182 cm – 35 cm

= 147 cm.

= 1 m + 47cm

Question-7. The mass of each gas cylinder is 21 kg 270 g. What is the total mass of 28 such cylinders?

Answer:

21 kg 270 gm = 21000 + 270 = 21270 gm

Now, 21270 x 28 = 595560 gm = 595 kg 560 gm.

Question- 8. In order to make a shirt, 2 m 25 cm cloth is needed. What length of cloth is required to make 18 such shirts?

Answer:

: 2 m 25 cm = 2 x 100 + 25 = 200 + 25 = 225 cm

Now, 225 x 18 = 4050 cm = 40 m 50 cm

Question-9. The total mass of 12 packets of sweets, each of same size, is 15 kg 600 g. What is the mass of each such packet?

Answer:

Total mass of 12 packets of sweets

= 15kg 600g

= 15 × 1000 + 600g

= 15600 g

Total mass of one packet of sweets

= 15600 – 12 = 1300g

= 1 kg 300g

Question-10. A vessel has 4 litres 500 milliliters of orange juice. In how many glasses, each of 25 mL   capacity, can it be filled?

Answer:

: 4 litres 500 milliliters  = 4 x 1000 + 500 = 4000 + 500 = 4500 ml

4500 / 25 = 180 glass

Question- 11. To stitch a trouser, 1 m 30 cm cloth is needed. Out of 25 m cloth, how many trousers can be switched and how many cloth is needed.

Answer:

1 x 100 + 30 cm = 100 + 30 cm = 130 cm.

Now, 25m = 2500 cm

number of trousers  = 2500 cm /  130 cm.

number of trousers  = 19

30 cm left

—  : End of ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions :–

Return to   ML Aggarwal Maths Solutions for ICSE Class -6

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