# ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions

ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of  Exe-1.4 Questions for Knowing Our Numbers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

## ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions

 Board ICSE Publications Avichal Publishig Company (APC) Subject Maths Class 6th Chapter-1 Knowing Our Numbers Writer ML Aggarwal Book Name Understanding Topics Solution of Exe-1.4 Questions Edition 2023-2024

### Knowing Our Numbers Exe-1.4

ML Aggarwal Class 6 ICSE Maths Solutions

Page-15

#### Question-1 . In a particular year, a company manufactured 8570435 bicycles and next year it manufactured 8756430 bicycles. In which year more bicycles were manufactured and by how many?

Next year it manufactured more bicycles by –

(8756430 – 8570435 = 185995)

#### Question-2. What number must be subtracted from 1,02,59,756 to get 77,63,835

1,02,59,756 – 77,63,835 = 2495921

#### Question-3. The sale receipt of a company during a year was Rs. 30587850. Next year it increased by Rs. 6375490. What was the total sale receipt of the company during these two years?

30587850 + 6375490 = 67551190

#### Question-4. A machine manufactures 23875 screws per day. How many screws did it produce in the year 2016? Assume that the machine worked on all the days of the year.

: 23875 x 366 = 8738250 (leap year)

#### Question-5. A merchant had Rs. 78,592 with him. He placed an order for purchasing 54 bicycles at Rs. 970 each. How much money will remain with him after the purchase.

: 54 bicycles at Rs. 970 each = 54 x 970 = 52380

Money remain with him after the purchase = 78,592 – 52380 = 26212

#### Question- 6. Amitabh is 1 m 82 cm tall and his wife is 35 cm shorter then him. What is his wife’s height?

: 1 m 82 cm – 35 cm

182 cm – 35 cm

= 147 cm.

= 1 m + 47cm

#### Question-7. The mass of each gas cylinder is 21 kg 270 g. What is the total mass of 28 such cylinders?

21 kg 270 gm = 21000 + 270 = 21270 gm

Now, 21270 x 28 = 595560 gm = 595 kg 560 gm.

#### Question-8. In order to make a shirt, 2 m 25 cm cloth is needed. What length of cloth is required to make 18 such shirts?

: 2 m 25 cm = 2 x 100 + 25 = 200 + 25 = 225 cm

Now, 225 x 18 = 4050 cm = 40 m 50 cm

#### Question-9. The total mass of 12 packets of sweets, each of same size, is 15 kg 600 g. What is the mass of each such packet?

Total mass of 12 packets of sweets

= 15kg 600g

= 15 × 1000 + 600g

= 15600 g

Total mass of one packet of sweets

= 15600 – 12 = 1300g

= 1 kg 300g

#### Question-10. A vessel has 4 litres 500 milliliters of orange juice. In how many glasses, each of 25 mL   capacity, can it be filled?

: 4 litres 500 milliliters  = 4 x 1000 + 500 = 4000 + 500 = 4500 ml

4500 / 25 = 180 glass

#### Question- 11. To stitch a trouser, 1 m 30 cm cloth is needed. Out of 25 m cloth, how many trousers can be switched and how many cloth is needed.

1 x 100 + 30 cm = 100 + 30 cm = 130 cm.

Now, 25m = 2500 cm

number of trousers  = 2500 cm /  130 cm.

number of trousers  = 19

30 cm left

—  : End of ML Aggarwal Knowing Our Numbers Exe-1.4 Class 6 ICSE Maths Solutions :–

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