ML Aggarwal Knowing Our Numbers Exe-1.5 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-1.5 Questions for Knowing Our Numbers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.

## ML Aggarwal Knowing Our Numbers Exe-1.5 Class 6 ICSE Maths Solutions

Board | ICSE |

Publications | Avichal Publishig Company (APC) |

Subject | Maths |

Class | 6th |

Chapter-1 | Knowing Our Numbers |

Writer | ML Aggarwal |

Book Name | Understanding |

Topics | Solution of Exe-1.5 Questions |

Edition | 2023-2024 |

**Knowing Our Numbers Exe-1.5**

ML Aggarwal Class 6 ICSE Maths Solutions

Page-20

**Question 1. Round off each of the following numbers to their nearest tens:**

(i) 77

(ii) 903

(iii) 1205

(iv) 999

**Answer:**

(i) 77–nearest tens= 80

(ii) 903 nearest tens= 900

(iii) 1205 nearest tens= 1210

(iv) 999 nearest tens= 1000

**Question- 2. Estimate each of the following numbers to their nearest hundreds:**

(i) 1246

(ii) 32057

(iii) 53961

(iv) 555555

**Answer:**

(i) 1246 — nearest hundreds 1200

(ii) 32057– nearest hundreds 32100

(iii) 53961 nearest hundreds 5400

(iv) 555555 nearest hundreds 555600

**Question 3. Estimate each of the following numbers to their nearest thousands:**

(i) 5706

(ii) 378

(iii) 47,599

(iv) 1,09,736

**Answer:**

(i) 5706– nearest thousands:6000

(ii) 378– nearest thousands:0

(iii) 47,599– nearest thousands:48000

(iv) 1,09,736– nearest thousands:1,10,000

**Question 4. Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):**

(i) 439 + 334 + 4317

(ii) 8325 – 491

(iii) 1,08,734-47,599

(iv) 4,89,348 – 48,365

**Answer:**

**(i) 439 + 334 + 4317**

rounding off to nearest hundreds

400+300+4300

=5000

a closer estimate (by rounding off to nearest tens):

440+330+4320

=5090

**(ii) 8325 – 491**

rounding off to nearest hundreds

8300-500

=7800

a closer estimate (by rounding off to nearest tens):

8330-490

=7840

**(iii) 1,08,734-47,599**

rounding off to nearest hundreds

108700 – 47600 = 61100

a closer estimate (by rounding off to nearest tens):

108730 – 47600

= 61130

**(iv) 4,89,348 – 48,365**

rounding off to nearest hundreds

489300 – 48400 = 440900

a closer estimate (by rounding off to nearest tens):

489350 – 48370

= 440980

**Question 5. Estimate each of the following by rounding off each number nearest to its greatest place:**

(i) 730 + 998

(ii) 5,290 + 17,986

(iii) 796-314

(iv) 28,292 – 21,496

**Answer:**

(i) 730 + 998= 700+1000= 1700

(ii) 5,290 + 17,986= 5000+18000=23000

(iii) 796-314=800-300=500

(iv) 28,292 – 21,496=28000-21000=7000

**Question 6. Estimate the following products by rounding off each of its factors nearest to its greatest place:**

(i) 578 × 161

(ii) 9650 × 27

**Answer:**

(i) 578 × 161=600 x 200 = 120000

(ii) 9650 × 27= 10000 x 30 = 300000

**Question -7. Estimate the following products by rounding off each of its factors nearest to its hundreds place:**

(i) 5281 × 3491

(ii) 1387 × 888

**Answer:**

(i) 5281 × 3491= 5300 x 3500 = 1,85,50,000

(ii) 1387 × 888= 1400 x 900 = 12,60,000

**Question -8. Estimate the following quotients by rounding off each number to its nearest ens:**

(i) 423 ÷ 29

(ii) 777 ÷ 27

**Answer:**

(i) 423 ÷ 29 = 430 ÷ 30 = 14

(ii) 777 ÷ 27 = 780 ÷ 30 = 26

**Knowing Our Numbers Exe-1.5**

ML Aggarwal Class 6 ICSE Maths Solutions

Page-21

**Question -9. Estimate the following ****quotients ****by rounding off each number to its nearest hundreds :**

(i) 2472 ÷ 493

(ii) 7459 ÷ 286

**Answer:**

(i) 2472 ÷ 493 = 2500 ÷ 500 = 5

(ii) 7459 ÷ 286 = 7500 ÷ 300 = 25

— : End of ML Aggarwal Knowing Our Numbers Exe-1.5 Class 6 ICSE Maths Solutions :–

Return to **–** ML Aggarwal Maths Solutions for ICSE Class -6

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