ML Aggarwal Knowing Our Numbers Exe-1.5 Class 6 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-1.5 Questions for Knowing Our Numbers as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-6.
ML Aggarwal Knowing Our Numbers Exe-1.5 Class 6 ICSE Maths Solutions
Board | ICSE |
Publications | Avichal Publishig Company (APC) |
Subject | Maths |
Class | 6th |
Chapter-1 | Knowing Our Numbers |
Writer | ML Aggarwal |
Book Name | Understanding |
Topics | Solution of Exe-1.5 Questions |
Edition | 2023-2024 |
Knowing Our Numbers Exe-1.5
ML Aggarwal Class 6 ICSE Maths Solutions
Page-20
Question 1. Round off each of the following numbers to their nearest tens:
(i) 77
(ii) 903
(iii) 1205
(iv) 999
Answer:
(i) 77–nearest tens= 80
(ii) 903 nearest tens= 900
(iii) 1205 nearest tens= 1210
(iv) 999 nearest tens= 1000
Question- 2. Estimate each of the following numbers to their nearest hundreds:
(i) 1246
(ii) 32057
(iii) 53961
(iv) 555555
Answer:
(i) 1246 — nearest hundreds 1200
(ii) 32057– nearest hundreds 32100
(iii) 53961 nearest hundreds 5400
(iv) 555555 nearest hundreds 555600
Question 3. Estimate each of the following numbers to their nearest thousands:
(i) 5706
(ii) 378
(iii) 47,599
(iv) 1,09,736
Answer:
(i) 5706– nearest thousands:6000
(ii) 378– nearest thousands:0
(iii) 47,599– nearest thousands:48000
(iv) 1,09,736– nearest thousands:1,10,000
Question 4. Give a rough estimate (by rounding off to nearest hundreds) and also a closer estimate (by rounding off to nearest tens):
(i) 439 + 334 + 4317
(ii) 8325 – 491
(iii) 1,08,734-47,599
(iv) 4,89,348 – 48,365
Answer:
(i) 439 + 334 + 4317
rounding off to nearest hundreds
400+300+4300
=5000
a closer estimate (by rounding off to nearest tens):
440+330+4320
=5090
(ii) 8325 – 491
rounding off to nearest hundreds
8300-500
=7800
a closer estimate (by rounding off to nearest tens):
8330-490
=7840
(iii) 1,08,734-47,599
rounding off to nearest hundreds
108700 – 47600 = 61100
a closer estimate (by rounding off to nearest tens):
108730 – 47600
= 61130
(iv) 4,89,348 – 48,365
rounding off to nearest hundreds
489300 – 48400 = 440900
a closer estimate (by rounding off to nearest tens):
489350 – 48370
= 440980
Question 5. Estimate each of the following by rounding off each number nearest to its greatest place:
(i) 730 + 998
(ii) 5,290 + 17,986
(iii) 796-314
(iv) 28,292 – 21,496
Answer:
(i) 730 + 998= 700+1000= 1700
(ii) 5,290 + 17,986= 5000+18000=23000
(iii) 796-314=800-300=500
(iv) 28,292 – 21,496=28000-21000=7000
Question 6. Estimate the following products by rounding off each of its factors nearest to its greatest place:
(i) 578 × 161
(ii) 9650 × 27
Answer:
(i) 578 × 161=600 x 200 = 120000
(ii) 9650 × 27= 10000 x 30 = 300000
Question -7. Estimate the following products by rounding off each of its factors nearest to its hundreds place:
(i) 5281 × 3491
(ii) 1387 × 888
Answer:
(i) 5281 × 3491= 5300 x 3500 = 1,85,50,000
(ii) 1387 × 888= 1400 x 900 = 12,60,000
Question -8. Estimate the following quotients by rounding off each number to its nearest ens:
(i) 423 ÷ 29
(ii) 777 ÷ 27
Answer:
(i) 423 ÷ 29 = 430 ÷ 30 = 14
(ii) 777 ÷ 27 = 780 ÷ 30 = 26
Knowing Our Numbers Exe-1.5
ML Aggarwal Class 6 ICSE Maths Solutions
Page-21
Question -9. Estimate the following quotients by rounding off each number to its nearest hundreds :
(i) 2472 ÷ 493
(ii) 7459 ÷ 286
Answer:
(i) 2472 ÷ 493 = 2500 ÷ 500 = 5
(ii) 7459 ÷ 286 = 7500 ÷ 300 = 25
— : End of ML Aggarwal Knowing Our Numbers Exe-1.5 Class 6 ICSE Maths Solutions :–
Return to – ML Aggarwal Maths Solutions for ICSE Class -6
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