ML Aggarwal Matrices Exe-8.3 Class 10 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-8.3 Questions as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-10.

## ML Aggarwal Matrices Exe-8.3 Class 10 ICSE Maths Solutions Ch-8

Board | ICSE |

Subject | Maths |

Class | 10th |

Chapter-8 | Matrices |

Writer / Book | Understanding |

Topics | Solutions of Exe-8.3 |

Academic Session | 2024-2025 |

### Matrices

( ML Aggarwal Matrices Exe-8.3 Class 10 ICSE Maths Solutions )

**Question- 1**

**If , is the product AB possible ? Give a reason. If yes, find AB. (2011)**

**Answer- 1**

Yes, the product is possible because of

number of column in A = number of row in B

i.e., (2 x 2). (2 x 1) = (2 x 1) is the order of the matrix.

**Question- 2**

**If , find AB and BA, Is AB = BA ?**

**Answer -2**

First finding AB

Now Finding BA

Therefore AB is not equal to BA

### **Matrices Exe-8.3 Questions**

ML Aggarwal Class 10 ICSE Maths Solutions

Page-157

**Answer- 1**

Yes, the product is possible because of

number of column in A = number of row in B

i.e., (2 x 2). (2 x 1) = (2 x 1) is the order of the matrix.

**Answer -2**

First finding AB

Now Finding BA

Therefore AB is not equal to BA

**Answer-3**

#### AB=

**Answer -4**

**Answer -5**

**Answer -6**

sin 30= 1/2 and cos 60 = 1/2

sin 90=1 cos 0 =1

**Answer-7**,

AB=

**Answer -8**

**Answer-9**

**(i) A(B + C) **

** **

** (ii) (B + C)A**

**Answer-10**

**Answer-11**

**Answer -12**

**Answer-13**

**AC+ B² -10 C**

**Answer-14**

**Answer-15**

**Answer -16**

Given

X² – 2X – 3I = 0

Solution =

or

X =

∴ X² =

**Answer-17**

Given

**Answer-18**

Given

A² =

comparing 1+x =0

x = -1

**Answer-19**

Comparing the corresponding elements,

– 3x + 4 = -5

-3x = -5 – 4 = -9

x = -9/-3 = 3

Therefore, x = 3 and y = -10.

Comparing, we get

8x = 16

⇒ x = 16/8 = 2

And, 9y = 9

y = 9/9 = 1

**Answer-20**

Given

On comparing the corresponding elements,

2x + y = 3 … (i)

3x + y = 2 … (ii)

Subtracting,

-x = 1 ⇒ x = -1

Substituting the value of x in (i),

2(-1) + y = 3

-2 + y = 3

y = 3 + 2 = 5

Therefore, x = -1 and y = 5.

**Answer -21**

Given

Comparing the corresponding elements

2y = 0

⇒ y = 0

3x = 9

⇒ x = 3

Hence x = 3, y = 0.

**Answer -22**

Given

Comparing the corresponding elements

a = 3, b = 4, c = 2, d = 5

**Answer -23**

A = and

B =

A² = B

A x A = B

on comparing x=36

**Answer-24**

Given

A² =

Corresponding the corresponding elements

3x = 36

⇒ x = 12

Hence x = 12.

**Answer-25**

Given

A = and B = find x and y when A² = B

We have A^{2} = B

Two matrices are equal if each and every corresponding element is equal

⇒ 4x = 16 and 1 = –y

⇒ x = 4 and y = –1.

**Answer -26**

given

** ****Answer-27**

⇒

** ****Answer -28**

Given

A² =

**Answer -29**

**given**

**Answer-30**

Given

(i) M is the order of 1 x 2

let M = [x y]

**Answer -31**

We have

** ****Answer-32**

** **

Let matrix X = [x y]

**Answer -33**

(i) given

**Answer-34**

A =

BA = I, where I is unity matrix of order 2

#### Answer-35

**(i)**

(ii)

**Answer-36**

and AB = C

— : End of ML Aggarwal Matrices Exe-8.3 for Class 10 ICSE Maths Solutions :–

Return to :- ML Aggarwal Solutions for ICSE Class-10

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