ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-7.2 Questions for Percentage and its Applications as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-8.

**ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE Maths Solutions**

Board | ICSE |

Publications | Avichal Publishig Company (APC) |

Subject | Maths |

Class | 8th |

Chapter-7 | Percentage and its Applications |

Writer | ML Aggarwal |

Book Name | Understanding |

Topics | Solution of Exe-7.2 Questions |

Edition | 2023-2024 |

**Percentage and its Applications Exe-7.2**

ML Aggarwal Class 8 ICSE Maths Solutions

Page-120

**Question 1. ****Find the profit or loss percentage, when:**

**(i) C.P. = ₹ 400, S.P. = ₹ 468**

**(ii) C.P. = ₹ 13600, S.P. = ₹ 12104**

**Answer:**

**(i) C.P. = ₹ 400, S.P. = ₹ 468**

Profit = S.P. – C.P.

= 468 – 400

= ₹ 68

Profit % = (Profit × 100)/ C.P.

= (68 × 100)/ 400

= 17 %

**(ii) C.P. = ₹ 13600, S.P. = ₹ 12104**

Loss = C.P. – S.P.

= 13600 – 12104

= ₹ 1496

Here

Loss % = [Loss/C.P. × 100] %

= [1496/ 13600 × 100] %

= 1496/ 136 %

= 11 %

**Question 2. ****By selling an article for ₹ 1636.25, a dealer gains ₹ 96.25. Find his gain per cent.**

**Answer:**

S.P. of an article = ₹ 1636.25

Gain = ₹ 96.25

So the C.P. = S.P. – Gain

= 1636.25 – 96.25

= ₹ 1540

Gain % = [Gain/ C.P. × 100] %

= [96.25/1540 × 100] %

= 9625/1540 %

= 1925/308 %

= 25/4 %

= 6 ¼ %

**Question 3. ****By selling an article for ₹ 770, a man incurs a loss of ₹ 110. Find his loss percentage.**

**Answer:**

S.P. of an article = ₹ 770

Loss = ₹ 110

C.P. = S.P. + Loss

= 770 + 110

= ₹ 880

Loss % = [Loss/ C.P. × 100] %

= [110/ 880 × 100] %

= 100/8 %

= 25/2 %

= 12.5 %

**Question 4. **** Rashida bought 25 dozen eggs at the rate of ₹ 9.60 per dozen. 30 eggs were broken in the transaction and she sold the remaining eggs at one rupee each. Find her gain or loss percentage.**

**Answer:**

C.P. of one dozen eggs = ₹ 9.60

C.P. of 25 dozen eggs = 25 × 9.60 = ₹ 240

No. of eggs = 25 dozen = 25 × 12 = 300

No. of eggs broken in transaction = 30

No. of remaining eggs = 300 – 30 = 270

S.P. of one egg = ₹ 1

S.P. of 270 eggs = 1 × 270 = ₹ 270

So the profit = S.P. – C.P.

= 270 – 240

= ₹ 30

Profit % = [Profit/ C.P. × 100] %

= [30/240 × 100] %

= 100/8 %

= 25/2 %

= 12.5 %

**Question 5. ****The cost of an article was ₹ 20000 and ₹ 1400 were spent on its repairs. If it is sold for a profit of 20 %, find the selling price of the article.**

**Answer:**

Cost of an article = ₹ 20000

Cost of its repair = ₹ 1400

So the total cost = 20000 + 1400 = ₹ 21400

Profit = 20 %

S.P. = [C.P. × (100 + Profit %)]/ 100

= [21400 × (100 + 20)]/ 100

= (21400 × 120)/ 100

= ₹ 25680

**Question 6. ****A shopkeeper buys 200 bicycles at ₹ 1200 per bicycle. He spends ₹ 30 per bicycle on transportation. He also spends ₹ 4000 on advertising. Then he sells all the bicycles at ₹ 1350 per piece. Find his profit or loss. Also, calculate it as a percentage.**

**Answer:**

C.P. of one bicycle = ₹ 1200

C.P. of 200 bicycle = 1200 × 200 = ₹ 240000

Expenditure on transportation for one bicycle = ₹ 30

Expenditure on transportation for 200 bicycle = 30 × 200 = ₹ 6000

Expenditure on advertising = ₹ 4000

Net C.P. of the bicycle = 240000 + 6000 + 4000

= ₹ 250000

S.P. of 200 bicycle at ₹ 1350 per bicycle = 200 × 1350

= ₹ 270000

So profit = S.P – C.P.

= 270000 – 250000

= ₹ 20000

Profit % = [Profit/ C.P. × 100] %

= [20000/ 250000 × 100] %

= 200/25 %

= 8%

**Question 7. ****The cost price of an article is 90% of its selling price. Find his profit percentage.**

**Answer:**

Consider ₹ x as the S.P. of an article

C.P. of an article = 90% of ₹ x

= 90/100 × ₹ x

= ₹ 9x/10

Profit = S.P. – C.P.

= x – 9x/10

Taking LCM

= (10x – 9x)/ 10

= ₹ x/10

Profit % = [Profit/ C.P. × 100] %

= [x/10/ 9x/10 × 100] %

= [x/10 × 10/9x × 100] %

= 100/ 9 %

= 11 1/9 %

**Question 8. ****Rao bought notebooks at the rate of 4 for ₹ 35 and sold them at the rate of 5 for ₹ 58. Calculate**

**(i) his gain percentage.**

**(ii) the number of notebooks he should sell to earn a profit of ₹ 171.**

**Answer:**

Consider the number of note books bought = 20

Here the LCM of 4 and 5 is 20

C.P. of the note books = 35/4 × 20

= 35 × 5

= ₹ 175

S.P. of the note books = 58/5 × 20

= 58 × 4

= ₹ 232

**(i) Gain = S.P. – C.P.**

= 232 – 175

= ₹ 57

Here

Gain % = [Gain/ C.P. × 100] %

= [57/ 175 × 100] %

= [57/7 × 4] %

So we get

= 228/7 %

= 32 4/7 %

**(ii) When the profit is ₹ 57, the number of note books sold = 20**

When the profit is ₹ 1, the number of note books sold = 20/57

When the profit is ₹ 171, the number of note books sold = 20/57 × 171

= 20 × 3

= 60

**Question 9. ****A vendor buys bananas at 3 for a rupee and sells at 4 for a rupee. Find his profit or loss percentage.**

**Answer:**

Consider the number of bananas bought = 12

Here LCM f 3 and 4 is 12

C.P. of bananas = 1/3 × 12 = ₹ 4

S.P. of bananas = ¼ × 12 = ₹ 3

Loss = C.P. – S.P.

= 4 – 3

= ₹ 1

Loss % = [Loss/ C.P. × 100] %

= [1/4 × 100] %

= 100/4 %

= 25 %

**Question 10. **** A shopkeeper buys a certain number of pens. If the selling price of 5 pens is equal to the cost price of 7 pens, find his profit or loss percentage.**

**Answer:**

Consider ₹ x as the C.P. of 7 pens

C.P. of 1 pen = ₹ x/7

S.P. of 5 pens = ₹ x

S.P. of 1 pen = ₹ x/5

Profit = S.P. – C.P.

= x/7 – x/5

Taking LCM

= (7x – 5x)/ 35

= ₹ 2x/ 35

Profit % = Profit/C.P. × 100 %

= 2x/ 35/ x/7 × 100 %

= 2x/35 × 7/x × 100 %

= 2/5 × 100 %

= 2 × 20 %

= 40 %

**Percentage and its Applications Exe-7.2**

ML Aggarwal Class 8 ICSE Maths Solutions

Page-121

**Question 11. ****Find the selling price, when:**

**(i) Cost price = ₹ 2360, Profit = 8 %**

**(ii) Cost price = ₹ 380, Loss = 7.5 %**

**Answer:**

**(i) Cost price = ₹ 2360, Profit = 8%**

We know that

S.P. = (100 + Profit %)/ 100 × C.P.

= (100 + 8)/ 100 × 2360

= 108/ 100 × 2360

= 108/ 10 × 236

= ₹ 2548.80

**(ii) Cost price = ₹ 380, Loss = 7.5 %**

S.P. = (100 – Loss %)/ 100 × C.P.

= (100 – 7.5)/ 100 × 380

= 92.5/ 100 × 380

= 9.25 × 38

= ₹ 351.50

**Question 12. ****A dealer bought a number of eggs at ₹ 18 a dozen and sold them at 50% profit. Find the selling price per egg.**

**Answer:**

C.P. of one dozen eggs = 12 eggs = ₹ 18

Profit = 15%

S.P. of 12 eggs = [1 + 50/ 100] of ₹ 18

= (150/100 × 18)

= (3/2 × 18)

= 3 × 9

= ₹ 27

S.P. of 1 egg = ₹ 27/12

= ₹ 9/4

= ₹ 2.25

**(ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE )**

**Question 13. Mr. Ghosh purchased wrist watches worth 60000. He sold one-third of them at a profit of 30o, one-third at a profit of 20% and the remaining at a loss of %. Calculate his overall profit or loss percentage.**

**Answer:**

**Question 14. A laptop and a mobile phone were bought for 40000 and 24000 respectively. The shopkeeper made a profit of 8% on laptop and a loss of 12% on mobile phone. Find his gain or loss percent on the whole transaction.**

**Answer:**

**Question 15. Salman bought 40 chairs at 175 each. He sold one-fourth of them at a loss of 8%. At what price each must he sell the remaining chairs so as to gain 10% on the whole deal?**

**Answer:**

**Question 16. A shopkeeper sold two electronic gadgets for 44000 each. The shopkeeper made a loss of 12% on one and a profit of 10% on the other. Find his overall gain or loss.**

**Answer:**

**Question 17. The manufacturing price of a T.V. set is 12000. The company sold it to a dealer at 20% profit and the dealer sold it to a customer at 12.5%% profit. Find the price which the customer has to pay.**

**Answer:**

**Question 18. Find the cost price, when :**

(i) sellings price = 450, loss = 10%

(ii) selling price = R690, profit = 15%

**Answer:**

**Question 19. By selling an almirah for 3920, a shopkeeper would gain 12%. If it is sold for 4375, find his gain or loss percentage.**

**Answer:**

**Question 20. By selling a bicycle at R1334, a shopkeeper would suffer a loss of 8%. At how much amount should he sell it to make a profit of 12(1/2)%?**

**Answer:**

**Question 21. By selling a tie for 252, a shopkeeper gains 5%. At what price should he sell the tie to gain 35%%?**

**Answer:**

**Question 22. A shopkeeper sells a bag at 12% profit. If he had sold it for 39 more, he would have made 18% profit. Find the cost price of the bag for the shopkeeper.**

**Answer:**

**Question 23.** **A shopkeeper sells a sweater at a loss of 5%. If he had sold it for 260 more, he would have made a profit of 15 %. Calculate the purchase price of the sweater.**

**Answer:**

**Question 24. Janki sold her leather purse at 8% loss. If she had sold it for 150 more, she would have made 12% profit. Find the selling price of the purse.**

**Answer:**

— : End of ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE Maths Solutions :–

Return to **– ML Aggarwal Maths Solutions for ICSE Class -8**

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