ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE Maths Solutions. We Provide Step by Step Answer of Exe-7.2 Questions for Percentage and its Applications as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-8.
ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE Maths Solutions
| Board | ICSE |
| Publications | Avichal Publishig Company (APC) |
| Subject | Maths |
| Class | 8th |
| Chapter-7 | Percentage and its Applications |
| Writer | ML Aggarwal |
| Book Name | Understanding |
| Topics | Solution of Exe-7.2 Questions |
| Edition | 2023-2024 |
Percentage and its Applications Exe-7.2
ML Aggarwal Class 8 ICSE Maths Solutions
Page-120
Question 1. Find the profit or loss percentage, when:
(i) C.P. = ₹ 400, S.P. = ₹ 468
(ii) C.P. = ₹ 13600, S.P. = ₹ 12104
Answer:
(i) C.P. = ₹ 400, S.P. = ₹ 468
Profit = S.P. – C.P.
= 468 – 400
= ₹ 68
Profit % = (Profit × 100)/ C.P.
= (68 × 100)/ 400
= 17 %
(ii) C.P. = ₹ 13600, S.P. = ₹ 12104
Loss = C.P. – S.P.
= 13600 – 12104
= ₹ 1496
Here
Loss % = [Loss/C.P. × 100] %
= [1496/ 13600 × 100] %
= 1496/ 136 %
= 11 %
Question 2. By selling an article for ₹ 1636.25, a dealer gains ₹ 96.25. Find his gain per cent.
Answer:
S.P. of an article = ₹ 1636.25
Gain = ₹ 96.25
So the C.P. = S.P. – Gain
= 1636.25 – 96.25
= ₹ 1540
Gain % = [Gain/ C.P. × 100] %
= [96.25/1540 × 100] %
= 9625/1540 %
= 1925/308 %
= 25/4 %
= 6 ¼ %
Question 3. By selling an article for ₹ 770, a man incurs a loss of ₹ 110. Find his loss percentage.
Answer:
S.P. of an article = ₹ 770
Loss = ₹ 110
C.P. = S.P. + Loss
= 770 + 110
= ₹ 880
Loss % = [Loss/ C.P. × 100] %
= [110/ 880 × 100] %
= 100/8 %
= 25/2 %
= 12.5 %
Question 4. Rashida bought 25 dozen eggs at the rate of ₹ 9.60 per dozen. 30 eggs were broken in the transaction and she sold the remaining eggs at one rupee each. Find her gain or loss percentage.
Answer:
C.P. of one dozen eggs = ₹ 9.60
C.P. of 25 dozen eggs = 25 × 9.60 = ₹ 240
No. of eggs = 25 dozen = 25 × 12 = 300
No. of eggs broken in transaction = 30
No. of remaining eggs = 300 – 30 = 270
S.P. of one egg = ₹ 1
S.P. of 270 eggs = 1 × 270 = ₹ 270
So the profit = S.P. – C.P.
= 270 – 240
= ₹ 30
Profit % = [Profit/ C.P. × 100] %
= [30/240 × 100] %
= 100/8 %
= 25/2 %
= 12.5 %
Question 5. The cost of an article was ₹ 20000 and ₹ 1400 were spent on its repairs. If it is sold for a profit of 20 %, find the selling price of the article.
Answer:
Cost of an article = ₹ 20000
Cost of its repair = ₹ 1400
So the total cost = 20000 + 1400 = ₹ 21400
Profit = 20 %
S.P. = [C.P. × (100 + Profit %)]/ 100
= [21400 × (100 + 20)]/ 100
= (21400 × 120)/ 100
= ₹ 25680
Question 6. A shopkeeper buys 200 bicycles at ₹ 1200 per bicycle. He spends ₹ 30 per bicycle on transportation. He also spends ₹ 4000 on advertising. Then he sells all the bicycles at ₹ 1350 per piece. Find his profit or loss. Also, calculate it as a percentage.
Answer:
C.P. of one bicycle = ₹ 1200
C.P. of 200 bicycle = 1200 × 200 = ₹ 240000
Expenditure on transportation for one bicycle = ₹ 30
Expenditure on transportation for 200 bicycle = 30 × 200 = ₹ 6000
Expenditure on advertising = ₹ 4000
Net C.P. of the bicycle = 240000 + 6000 + 4000
= ₹ 250000
S.P. of 200 bicycle at ₹ 1350 per bicycle = 200 × 1350
= ₹ 270000
So profit = S.P – C.P.
= 270000 – 250000
= ₹ 20000
Profit % = [Profit/ C.P. × 100] %
= [20000/ 250000 × 100] %
= 200/25 %
= 8%
Question 7. The cost price of an article is 90% of its selling price. Find his profit percentage.
Answer:
Consider ₹ x as the S.P. of an article
C.P. of an article = 90% of ₹ x
= 90/100 × ₹ x
= ₹ 9x/10
Profit = S.P. – C.P.
= x – 9x/10
Taking LCM
= (10x – 9x)/ 10
= ₹ x/10
Profit % = [Profit/ C.P. × 100] %
= [x/10/ 9x/10 × 100] %
= [x/10 × 10/9x × 100] %
= 100/ 9 %
= 11 1/9 %
Question 8. Rao bought notebooks at the rate of 4 for ₹ 35 and sold them at the rate of 5 for ₹ 58. Calculate
(i) his gain percentage.
(ii) the number of notebooks he should sell to earn a profit of ₹ 171.
Answer:
Consider the number of note books bought = 20
Here the LCM of 4 and 5 is 20
C.P. of the note books = 35/4 × 20
= 35 × 5
= ₹ 175
S.P. of the note books = 58/5 × 20
= 58 × 4
= ₹ 232
(i) Gain = S.P. – C.P.
= 232 – 175
= ₹ 57
Here
Gain % = [Gain/ C.P. × 100] %
= [57/ 175 × 100] %
= [57/7 × 4] %
So we get
= 228/7 %
= 32 4/7 %
(ii) When the profit is ₹ 57, the number of note books sold = 20
When the profit is ₹ 1, the number of note books sold = 20/57
When the profit is ₹ 171, the number of note books sold = 20/57 × 171
= 20 × 3
= 60
Question 9. A vendor buys bananas at 3 for a rupee and sells at 4 for a rupee. Find his profit or loss percentage.
Answer:
Consider the number of bananas bought = 12
Here LCM f 3 and 4 is 12
C.P. of bananas = 1/3 × 12 = ₹ 4
S.P. of bananas = ¼ × 12 = ₹ 3
Loss = C.P. – S.P.
= 4 – 3
= ₹ 1
Loss % = [Loss/ C.P. × 100] %
= [1/4 × 100] %
= 100/4 %
= 25 %
Question 10. A shopkeeper buys a certain number of pens. If the selling price of 5 pens is equal to the cost price of 7 pens, find his profit or loss percentage.
Answer:
Consider ₹ x as the C.P. of 7 pens
C.P. of 1 pen = ₹ x/7
S.P. of 5 pens = ₹ x
S.P. of 1 pen = ₹ x/5
Profit = S.P. – C.P.
= x/7 – x/5
Taking LCM
= (7x – 5x)/ 35
= ₹ 2x/ 35
Profit % = Profit/C.P. × 100 %
= 2x/ 35/ x/7 × 100 %
= 2x/35 × 7/x × 100 %
= 2/5 × 100 %
= 2 × 20 %
= 40 %
Percentage and its Applications Exe-7.2
ML Aggarwal Class 8 ICSE Maths Solutions
Page-121
Question 11. Find the selling price, when:
(i) Cost price = ₹ 2360, Profit = 8 %
(ii) Cost price = ₹ 380, Loss = 7.5 %
Answer:
(i) Cost price = ₹ 2360, Profit = 8%
We know that
S.P. = (100 + Profit %)/ 100 × C.P.
= (100 + 8)/ 100 × 2360
= 108/ 100 × 2360
= 108/ 10 × 236
= ₹ 2548.80
(ii) Cost price = ₹ 380, Loss = 7.5 %
S.P. = (100 – Loss %)/ 100 × C.P.
= (100 – 7.5)/ 100 × 380
= 92.5/ 100 × 380
= 9.25 × 38
= ₹ 351.50
Question 12. A dealer bought a number of eggs at ₹ 18 a dozen and sold them at 50% profit. Find the selling price per egg.
Answer:
C.P. of one dozen eggs = 12 eggs = ₹ 18
Profit = 15%
S.P. of 12 eggs = [1 + 50/ 100] of ₹ 18
= (150/100 × 18)
= (3/2 × 18)
= 3 × 9
= ₹ 27
S.P. of 1 egg = ₹ 27/12
= ₹ 9/4
= ₹ 2.25
(ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE )
Question 13. Mr. Ghosh purchased wrist watches worth 60000. He sold one-third of them at a profit of 30o, one-third at a profit of 20% and the remaining at a loss of %. Calculate his overall profit or loss percentage.
Answer:
Question 14. A laptop and a mobile phone were bought for 40000 and 24000 respectively. The shopkeeper made a profit of 8% on laptop and a loss of 12% on mobile phone. Find his gain or loss percent on the whole transaction.
Answer:
Question 15. Salman bought 40 chairs at 175 each. He sold one-fourth of them at a loss of 8%. At what price each must he sell the remaining chairs so as to gain 10% on the whole deal?
Answer:
Question 16. A shopkeeper sold two electronic gadgets for 44000 each. The shopkeeper made a loss of 12% on one and a profit of 10% on the other. Find his overall gain or loss.
Answer:
Question 17. The manufacturing price of a T.V. set is 12000. The company sold it to a dealer at 20% profit and the dealer sold it to a customer at 12.5%% profit. Find the price which the customer has to pay.
Answer:
Question 18. Find the cost price, when :
(i) sellings price = 450, loss = 10%
(ii) selling price = R690, profit = 15%
Answer:
Question 19. By selling an almirah for 3920, a shopkeeper would gain 12%. If it is sold for 4375, find his gain or loss percentage.
Answer:
Question 20. By selling a bicycle at R1334, a shopkeeper would suffer a loss of 8%. At how much amount should he sell it to make a profit of 12(1/2)%?
Answer:
Question 21. By selling a tie for 252, a shopkeeper gains 5%. At what price should he sell the tie to gain 35%%?
Answer:
Question 22. A shopkeeper sells a bag at 12% profit. If he had sold it for 39 more, he would have made 18% profit. Find the cost price of the bag for the shopkeeper.
Answer:
Question 23. A shopkeeper sells a sweater at a loss of 5%. If he had sold it for 260 more, he would have made a profit of 15 %. Calculate the purchase price of the sweater.
Answer:
Question 24. Janki sold her leather purse at 8% loss. If she had sold it for 150 more, she would have made 12% profit. Find the selling price of the purse.
Answer:
— : End of ML Aggarwal Percentage and its Applications Exe-7.2 Class 8 ICSE Maths Solutions :–
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