ML Aggarwal Probability MCQs Class 10 ICSE Maths Solutions Ch-22

ML Aggarwal Probability MCQs Class 10 ICSE Maths Solutions Ch-22. We Provide Step by Step Answer of MCQs Questions for Ch-22 Matrices as council prescribe guideline for upcoming board exam. Visit official Website CISCE for detail information about ICSE Board Class-10.

ML Aggarwal Probability MCQs Class 10 ICSE Maths Solutions Ch-22

Board ICSE
Subject Maths
Class 10th
Chapter-22 Probability
Writer / Book Understanding
Topics Solutions of MCQs
Academic Session 2024-2025

Probability Multiple Choice Questions

ML Aggarwal Probability MCQs Class 10 ICSE Maths Solutions Ch-22

Choose the correct answer from the given four options (1 to 20):

Question 1 Which of the following cannot be the probability of an event?
(a) 0.7
(b) 2/3
(c) – 1.5
(d) 15%

Answer 1

– 1.5 (negative) can not be a probability as a probability is possible 0 to 1. (c)

Question 2 If the probability of an event is p, then the probability of its complementary event will be
(a) p – 1
(b) p
(c) 1 – p
(d) 1-1/p

Answer 2

Complementary of p is 1 – p
Probability of complementary even of p is 1 – p. (c)

Question 3 Out of one digit prime numbers, one selecting an even number is
(a) 1/2
(b) 1/4
(c) 4/9
(d) 2/5

Answer 3

One digit prime numbers are 2, 3, 5, 7 = 4
Probability of an even prime number (i.e , 2) = 1/4 (b)

Question 4 When a die is thrown, the probability of getting an odd number less than 3 is
(a) 1/6
(b) 1/3
(c) 1/2
(d) 0

Answer 4

A die is thrown
Total number of events = 6
Odd number less than 3 is 1 = 1
Probability = 1/6 (a)

Question 5 A fair die is thrown once. The probability of getting an even prime number is
(a) 1/6
(b) 2/3
(c) 1/3
(d) 1/2

Answer 5

A fair die is thrown once
Total number of outcomes = 6
Prime numbers = 2, 3, 5 and even prime is 2
Probability of getting an even prime number = 1/6 (a)

Question 6 A fair die is thrown once. The probability of getting a composite number is
(a) 1/3
(b) 1/6
(c) 2/3
(d) 0

Answer 6

A fair die is thrown once
Total number of outcomes = 6
Composite numbers are 4, 6 = 2
Probability = 2/6 = 1/3 (a)

Question 7 If a fair dice is rolled once, then the probability of getting an even number or a number greater than 4 is
(a) 1/2
(b) 1/3
(c) 5/6
(d) 2/3

Answer 7

A fair dice is thrown once.
Total number of outcomes = 6
Even numbers or a number greater than 4 = 2, 4, 5, 6 = 4
Probability = 4/6 = 2/3 (d)

Question 8 If a letter is chosen at random from the letters of English alphabet, then the probability that it is a letter of the word ‘DELHI’ is
(a) 1/5
(b) 1/26
(c) 5/26
(d) 21/26

Answer 8

Total number of English alphabets = 26
Letter of Delhi = D, E, L, H, I. = 5
Probability = 5/26 (c)

Question 9 A card is selected at random from a pack of 52 cards. The probability of its being a red face card is
(a) 3/26
(b) 3/13
(c) 2/13
(d) 1/2 

Answer 9

Total number of card = 52
No. of red face card = 3 × 2 = 6
.’. Probability = 6/52 = 3/26 (a)


ML Aggarwal Probability MCQs Class 10 ICSE Maths Solutions Ch-22

Page 544

Question 10 If a card is drawn from a well-shuffled pack of 52 playing cards, then the probability of this card being a king or a jack is
(a) 1/26
(b) 1/13
(c) 2/13
(d) 4/13

Answer 10 

Total number of cards 52
Number of a king or a jack = 4 + 4 = 8
.’. Probability = 8/52 = 2/13 (c)

Question 11 The probability that a non-leap year selected at random has 53 Sundays is.
(a) 1/365
(b) 2/365
(c) 2/7
(d) 1/7

Answer 11

Number of a non-leap year 365
Number of Sundays = 53
In a leap year, there are 52 weeks or 364 days
One days is left
Now we have to find the probability of a Sunday out of remaining 1 day
∴ Probability = 1/7 (d)

Question 12 A bag contains 3 red balk, 5 white balls and 7 black balls. The probability that a ball drawn from the bag at random will be neither red nor black is
(a) 1/5
(b) 1/3
(c) 7/15
(d) 8/1

Answer 12 

In a bag, there are
3 red balls + 5 white balls + 7 black balls
Total number of balls = 15
One ball is drawn at random which is neither
red not black
Number of outcomes = 5
Probability = 5/15 = 1/3 (b)

Question 13 A bag contains 4 red balls and 5 green balls. One ball is drawn at random from the bag. The probability of getting either a red ball or a green ball is
(a) 4/9
(b) 5/9
(c) 0
(d) 1

Answer 13 

In a bag, there are
4 red balls + 5 green balls
Total 4 + 5 = 9
One ball is drawn at random
Probability of either a red or a green ball = 9/9 = 1 (d)

Question 14 One ticket is drawn at random from a bag containing tickets numbered 1 to 40. The probability that the selected ticket has a number which is a multiple of 5 is
(a) 1/5
(b) 3/5
(c) 4/5
(d) 1/3

Answer 14

There are t to 40 = 40 tickets in a bag
No. of tickets which is multiple of 5 = 8
(5, 10, 15, 20, 25, 30, 35, 40)
Probability = 8/40 = 1/5 (a)

Question 15 If a number is randomly chosen from the numbers 1,2,3,4, …, 25, then the probability of the number to be prime is
(a) 7/25
(b) 9/25
(c) 11/25
(d) 13/25

Answer 15

There are 25 number bearing numbers 1, 2, 3,…,25
Prime numbers are 2, 3, 5, 7, 11, 13, 17 19, 23 = 9
Probability being a prime number = 9/25 (b)

Question 16 A box contains 90 cards numbered 1 to 90. If one card is drawn from the box at random, then the probability that the number on the card is a perfect square is
(a) 1/10
(b) 9/100
(c) 1/9
(d) 1/100

Answer 16

In a box, there are
90 cards bearing numbers 1 to 90
Perfect squares are 1, 4, 9, 16, 25, 36, 49, 64, 81 = 9
Probability of being a perfect square = 9/90 = 1/10 (a)

Question 17 If a (fair) coin is tossed twice, then the probability of getting two heads is
(a) 1/4
(b) 1/2
(c) 3/4
(d) 0

Answer 17

A coin is tossed twice
Number of outcomes = 2 x 2 = 4
Probability of getting two heads (HH = 1) = 1/4 (a)

Question 18 If two coins are tossed simultaneously, then the probability of getting at least one head is
(a) 1/4
(b) 1/2
(c) 3/4
(d) 1

Answer 18

Two coins are tossed
Total outcomes = 2 × 2 = 4
Probability of getting at least one head (HT,TH,H,H) = 3/4 (c)

Question 19 Lakshmi tosses two coins simultaneously. The probability that she gets almost one head
(a) 1
(b) 3/4
(c) 1/2
(d) 1/7

Answer 19

Two coins are tossed
Total number of outcomes = 2 × 2 = 4
Probability of getting at least one head = (HT, TH, RH = 3) = 3/4 (b)

Question 20 The probability of getting a bad egg in a lot of 400 eggs is 0.035. The number of bad eggs in the lot is
(a) 7
(b) 14
(c) 21
(d) 28

Answer 20

Total number of eggs 400
Probability of getting a bad egg = 0.035
Number of bad eggs = 0.035 of 400 = 400×35/1000 = 14 (b)

— : End of ML Aggarwal Probability MCQs Class 10 ICSE Maths Solutions Ch-22 : –

Return to :- ML Aggarwal Solutions for ICSE Class-10

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