Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics Nageen Prakashan Chapter-6 Solved Numericals. Step by step Solutions of Kumar and Mittal ISC Physics Class-12 Nageen Prakashan Numericals Questions. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.

## Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics Chapter-6 Nageen Prakashan of Kumar and Mittal

 Class: 12 Subject: Physics Chapter 6: DC Circuits and Measurements
 Board ISC Writer /Publications Nootan / Nageen Prakashan/Kumar and Mittal Topics Solved Numericals of page 272 , 273, 274, 275

### Nootan Solutions Chapter-6 DC Circuits and Measurements ISC Class-12 Physics( Nageen Prakashan of Kumar and Mittal )

page-number : 272

Question 1,

The storage battery …………..   of Battery.

I = V / R Applying Ohm Law

= 12 / 0.4

= 30 Amp

Question 2

A cell ……………  cell

i = E / (R+r)

= 5 / (9+1)

= 0.5 Amp

Question 3

Potential difference …………. cell.

V = E – i r

4 = 6 – 2 r

2 r = 2

r = 1 ohm

Question 4

The emf ……….. resistor

Question 5

The potential …………….. cell

Question 6

a battery ……….. battery

Question 7

A 200 ohm …………….. circuit

Question 8

A high ……………… wire

Question 9

in the circuit ………….. of R

EMF of cell = reading of voltmeter when key is open

Question 10

A 10 V battery ……………….current

Question 11

Two battery ……………charging.

During charging

V – E = i r

V = E + i r

for first battery

V = 6.20 +20 x 0.01

=6.40 V

and for second battery

V = 12.45 + 0.03 x 20

=13.05 Volt

Question 12

Calculate ……………….. network

It is  an example of wheat stone bridge

therefore 5 ohm resistor remain inactive

Question 13

find …………… potential

Since M and N are at same potential. therefore it is an example of wheat stone bridge

Question 14

resistance of parallel combination = X

then according to rule of wheatstone bridge

Question 15

calculate ……………..0.4 ohm

page-number : 273

Question 16

the ……………. balanced

current through arm ABC= 60/30

=2 amp

current through arm ACD = 60/10 =6 amp

(a)

(b) since D is at higher potential therefore current will pass from D to B

(c) let for balance bridge R(DC)is X then by the rule of balanced wheatstone bridge

10/20 =3/X

i.e. X = 6 ohm

Question 17

calculate ……………… resistor

(I) equivalent resistance

Question 18

calculate ……………… 60 V

Resistance of the circuit

=18 x 2.5 = 45 V

Question 19

Find …………….  of R

Voltage across 10 ohm

120-100 =20V

current in the circuit

=20/10

=2 amp

total resistance of parallel combination

Question 20

What …………. negligible

(a) when Key is off  8 ohm  become ineffective

Question 21

PD across capacitor

= i R = 2 x 10 = 20 V

energy store in capacitor

Question 22

Compute ……………. resistor

the 2 ohm resistor in row of ammeter in series with other 3 , ohm resistor in parallel

therefore net resistance

Question 23

In the …………….. 75 ohm

Question 24

the …………….. voltameter

Resistance of circuit

Question 25

A network …………….. resistor

total external resistance

page-number : 274

Question 26

An 84 V DC ……………. connected

Question 27

Two cell ……………… each cell

in first case

Question 28

Two identical ……………. cell

as previous question

Question 29

50 bulb …………….under lit

total current taken by all bulb

= 50 x 0.6

= 30 amp

again current given by all accumulator

Question 30

three cell …………….. resistance

current through circuit

Question 31

Determined …………… diagram

those two cell are in parallel with internal resistance 3 ohm and 0 ohm

therefore effective emf

Question 32

In the ……………… negligible

Question 33

In the …………..

applying kirchaff law in loop

Question 34

Two cell ………………

applying kirchaff law

page-number : 275

Question 35

two cell of emf 6 V and 12 V …………..

Question 36

Two cell ……………..PDs.

this will same across cell also because the are in parallel

Question 37

three ……………….cell

r = 6 ohm

Question 38

Calculate …………….. resistance

applying kirchaff law

Question 39

In …………………. box

Question 40

In …………………… 70 cm

Question 41

A 3 V battery …………….reading .

(a)

3 x 0.5 = 1.5 V

(b)

if resistance of voltameter is 150 ohm then net resistance of 60  wire and voltameter

= i R = 0.505 x 2.94 =1.485 volt

Question 42

Potential …………….  potentiometer

Potential gradient = v / l

= 2/4

=0.5 v / m

Question 43

A 10 m Long ……………..potentiometer

again E = 0.0025 x 860

=2.15 V

max emf = p x total length

= 0.0025 x 1000

= 2.5 volt

Question 44

A potentiometer ………… AB

by the rule of wheat stone bridge

Question 45

A cell gives ………………  Cell

Question 46

A cell emf 1.25 V ………….. second cell .

Acording principle of potentiometer

= 2.25 V

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— End of Nootan Solutions DC Circuits and Measurements Numericals :–

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