Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics Nageen Prakashan Chapter-6 Solved Numericals. Step by step Solutions of Kumar and Mittal ISC Physics Class-12 Nageen Prakashan Numericals Questions. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.
Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics Chapter-6 Nageen Prakashan of Kumar and Mittal
| Class: | 12 |
| Subject: | Physics |
| Chapter 6: | DC Circuits and Measurements |
| Board | ISC |
| Writer /Publications | Nootan / Nageen Prakashan/Kumar and Mittal |
| Topics | Solved Numericals of page 272 , 273, 274, 275 |
Nootan Solutions Chapter-6 DC Circuits and Measurements ISC Class-12 Physics( Nageen Prakashan of Kumar and Mittal )
page-number : 272
Question 1,
The storage battery ………….. of Battery.
Answer
I = V / R Applying Ohm Law
= 12 / 0.4
= 30 Amp
Question 2
A cell …………… cell
Answer
i = E / (R+r)
= 5 / (9+1)
= 0.5 Amp
Question 3
Potential difference …………. cell.
Answer
V = E – i r
4 = 6 – 2 r
2 r = 2
r = 1 ohm
Question 4
The emf ……….. resistor
Answer
Question 5
The potential …………….. cell
Answer
Question 6
a battery ……….. battery
Answer
Question 7
A 200 ohm …………….. circuit
Answer
Question 8
A high ……………… wire
Answer
Question 9
in the circuit ………….. of R
Answer
EMF of cell = reading of voltmeter when key is open
Question 10
A 10 V battery ……………….current
Answer
Question 11
Two battery ……………charging.
Answer
During charging
V – E = i r
V = E + i r
for first battery
V = 6.20 +20 x 0.01
=6.40 V
and for second battery
V = 12.45 + 0.03 x 20
=13.05 Volt
Question 12
Calculate ……………….. network
Answer
It is an example of wheat stone bridge
therefore 5 ohm resistor remain inactive
Question 13
find …………… potential
Answer
Since M and N are at same potential. therefore it is an example of wheat stone bridge
Question 14
The adjoining …………… calculate R
Answer
resistance of parallel combination = X
then according to rule of wheatstone bridge
Question 15
calculate ……………..0.4 ohm
Answer
page-number : 273
Question 16
the ……………. balanced
Answer
current through arm ABC= 60/30
=2 amp
current through arm ACD = 60/10 =6 amp
(a)
(b) since D is at higher potential therefore current will pass from D to B
(c) let for balance bridge R(DC)is X then by the rule of balanced wheatstone bridge
10/20 =3/X
i.e. X = 6 ohm
Question 17
calculate ……………… resistor
Answer
(I) equivalent resistance
Question 18
calculate ……………… 60 V
Answer
Resistance of the circuit
=18 x 2.5 = 45 V
Question 19
Find ……………. of R
Answer
Voltage across 10 ohm
120-100 =20V
current in the circuit
=20/10
=2 amp
total resistance of parallel combination
Question 20
What …………. negligible
Answer
(a) when Key is off 8 ohm become ineffective
Question 21
In steady …………………. circuit
Answer
PD across capacitor
= i R = 2 x 10 = 20 V
energy store in capacitor
Question 22
Compute ……………. resistor
Answer
the 2 ohm resistor in row of ammeter in series with other 3 , ohm resistor in parallel
therefore net resistance
Question 23
In the …………….. 75 ohm
Answer
Question 24
the …………….. voltameter
Answer
Resistance of circuit
Question 25
A network …………….. resistor
Answer
total external resistance
page-number : 274
Question 26
An 84 V DC ……………. connected
Answer
Question 27
Two cell ……………… each cell
Answer
in first case
Question 28
Two identical ……………. cell
Answer
as previous question
Question 29
50 bulb …………….under lit
Answer
total current taken by all bulb
= 50 x 0.6
= 30 amp
again current given by all accumulator
Question 30
three cell …………….. resistance
Answer
current through circuit
Question 31
Determined …………… diagram
Answer
those two cell are in parallel with internal resistance 3 ohm and 0 ohm
therefore effective emf
Question 32
In the ……………… negligible
Answer
Question 33
In the …………..
Answer
applying kirchaff law in loop
Question 34
Two cell ………………
Answer
applying kirchaff law
page-number : 275
Question 35
two cell of emf 6 V and 12 V …………..
Answer
Question 36
Two cell ……………..PDs.
Answer
this will same across cell also because the are in parallel
Question 37
three ……………….cell
Answer
r = 6 ohm
Question 38
Calculate …………….. resistance
Answer
applying kirchaff law
Question 39
In …………………. box
Answer
Question 40
In …………………… 70 cm
Answer
Question 41
A 3 V battery …………….reading .
Answer
(a)
reading of voltameter
3 x 0.5 = 1.5 V
(b)
if resistance of voltameter is 150 ohm then net resistance of 60 wire and voltameter
reading of voltameter
= i R = 0.505 x 2.94 =1.485 volt
Question 42
Potential ……………. potentiometer
Answer
Potential gradient = v / l
= 2/4
=0.5 v / m
Question 43
A 10 m Long ……………..potentiometer
Answer
again E = 0.0025 x 860
=2.15 V
max emf = p x total length
= 0.0025 x 1000
= 2.5 volt
Question 44
A potentiometer ………… AB
Answer
by the rule of wheat stone bridge
Question 45
A cell gives ……………… Cell
Answer
Question 46
A cell emf 1.25 V ………….. second cell .
Answer
Acording principle of potentiometer
= 2.25 V
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