# Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics

**Nootan Solutions DC Circuits** and Measurements ISC Class-12 Physics Nageen Prakashan Chapter-6 Solved Numericals. Step by step Solutions of Kumar and Mittal ISC Physics Class-12 Nageen Prakashan Numericals Questions. Visit official Website **CISCE** for detail information about ISC Board Class-12 Physics.

## Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics Chapter-6 Nageen Prakashan of Kumar and Mittal

Class: | 12 |

Subject: | Physics |

Chapter 6: | DC Circuits and Measurements |

Board | ISC |

Writer /Publications | Nootan / Nageen Prakashan/Kumar and Mittal |

Topics | Solved Numericals of page 272 , 273, 274, 275 |

### Nootan Solutions Chapter-6 DC Circuits and Measurements ISC Class-12 Physics( Nageen Prakashan of Kumar and Mittal )

page-number : 272

**Question 1,**

The storage battery ………….. of Battery.

**Answer**

I = V / R Applying Ohm Law

= 12 / 0.4

= 30 Amp

**Question 2**

A cell …………… cell

Answer

i = E / (R+r)

= 5 / (9+1)

= 0.5 Amp

**Question 3**

Potential difference …………. cell.

**Answer**

V = E – i r

4 = 6 – 2 r

2 r = 2

r = 1 ohm

**Question 4**

The emf ……….. resistor

**Answer**

**Question 5**

The potential …………….. cell

**Answer**

**Question 6**

a battery ……….. battery

**Answer**

**Question 7**

A 200 ohm …………….. circuit

**Answer**

**Question 8**

A high ……………… wire

**Answer**

**Question 9**

in the circuit ………….. of R

**Answer**

EMF of cell = reading of voltmeter when key is open

**Question 10**

A 10 V battery ……………….current

**Answer**

**Question 11**

Two battery ……………charging.

**Answer**

During charging

V – E = i r

V = E + i r

for first battery

V = 6.20 +20 x 0.01

=6.40 V

and for second battery

V = 12.45 + 0.03 x 20

=13.05 Volt

**Question 12**

Calculate ……………….. network

**Answer**

It is an example of wheat stone bridge

therefore 5 ohm resistor remain inactive

**Question 13**

find …………… potential

**Answer**

Since M and N are at same potential. therefore it is an example of wheat stone bridge

**Question 14**

The adjoining …………… calculate R

**Answer**

resistance of parallel combination = X

then according to rule of wheatstone bridge

**Question 15**

calculate ……………..0.4 ohm

**Answer**

page-number : 273

**Question 16**

the ……………. balanced

**Answer**

current through arm ABC= 60/30

=2 amp

current through arm ACD = 60/10 =6 amp

(a)

(b) since D is at higher potential therefore current will pass from D to B

(c) let for balance bridge R(DC)is X then by the rule of balanced wheatstone bridge

10/20 =3/X

i.e. X = 6 ohm

**Question 17**

calculate ……………… resistor

**Answer**

(I) equivalent resistance

**Question 18**

calculate ……………… 60 V

**Answer**

Resistance of the circuit

=18 x 2.5 = 45 V

**Question 19**

Find ……………. of R

**Answer**

Voltage across 10 ohm

120-100 =20V

current in the circuit

=20/10

=2 amp

total resistance of parallel combination

**Question 20**

What …………. negligible

**Answer**

(a) when Key is off 8 ohm become ineffective

**Question 21**

In steady …………………. circuit

**Answer**

PD across capacitor

= i R = 2 x 10 = 20 V

energy store in capacitor

**Question 22**

Compute ……………. resistor

**Answer**

the 2 ohm resistor in row of ammeter in series with other 3 , ohm resistor in parallel

therefore net resistance

**Question 23**

In the …………….. 75 ohm

Answer

**Question 24**

the …………….. voltameter

**Answer**

Resistance of circuit

**Question 25**

A network …………….. resistor

**Answer**

total external resistance

**page-number : 274**

**Question 26**

An 84 V DC ……………. connected

**Answer**

**Question 27**

Two cell ……………… each cell

**Answer**

in first case

**Question 28**

Two identical ……………. cell

**Answer**

as previous question

**Question 29**

50 bulb …………….under lit

**Answer**

total current taken by all bulb

= 50 x 0.6

= 30 amp

again current given by all accumulator

**Question 30**

three cell …………….. resistance

**Answer**

current through circuit

**Question 31**

Determined …………… diagram

**Answer**

those two cell are in parallel with internal resistance 3 ohm and 0 ohm

therefore effective emf

**Question 32**

In the ……………… negligible

**Answer**

**Question 33**

In the …………..

**Answer**

applying kirchaff law in loop

**Question 34**

Two cell ………………

**Answer**

applying kirchaff law

page-number : 275

**Question 35**

two cell of emf 6 V and 12 V …………..

**Answer**

**Question 36**

Two cell ……………..PDs.

**Answer**

this will same across cell also because the are in parallel

**Question 37**

three ……………….cell

**Answer**

r = 6 ohm

**Question 38**

Calculate …………….. resistance

**Answer**

applying kirchaff law

**Question 39**

In …………………. box

**Answer**

**Question 40**

In …………………… 70 cm

**Answer**

**Question 41**

A 3 V battery …………….reading .

**Answer**

(a)

reading of voltameter

3 x 0.5 = 1.5 V

(b)

if resistance of voltameter is 150 ohm then net resistance of 60 wire and voltameter

reading of voltameter

= i R = 0.505 x 2.94 =1.485 volt

**Question 42**

Potential ……………. potentiometer

**Answer**

Potential gradient = v / l

= 2/4

=0.5 v / m

**Question 43**

A 10 m Long ……………..potentiometer

**Answer**

again E = 0.0025 x 860

=2.15 V

max emf = p x total length

= 0.0025 x 1000

= 2.5 volt

**Question 44**

A potentiometer ………… AB

**Answer**

by the rule of wheat stone bridge

**Question 45**

A cell gives ……………… Cell

**Answer**

**Question 46**

A cell emf 1.25 V ………….. second cell .

**Answer**

Acording principle of potentiometer

= 2.25 V

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