# Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics

Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics Nageen Prakashan Chapter-6 Solved Numericals. Step by step Solutions of Kumar and Mittal ISC Physics Class-12 Nageen Prakashan Numericals Questions. Visit official Website CISCE for detail information about ISC Board Class-12 Physics.

## Nootan Solutions DC Circuits and Measurements ISC Class-12 Physics Chapter-6 Nageen Prakashan of Kumar and Mittal

 Class: 12 Subject: Physics Chapter 6: DC Circuits and Measurements
 Board ISC Writer /Publications Nootan / Nageen Prakashan/Kumar and Mittal Topics Solved Numericals of page 272 , 273, 274, 275

### Nootan Solutions Chapter-6 DC Circuits and Measurements ISC Class-12 Physics( Nageen Prakashan of Kumar and Mittal )

page-number : 272

Question 1,

The storage battery …………..   of Battery.

Answer

I = V / R Applying Ohm Law

= 12 / 0.4

= 30 Amp

Question 2

A cell ……………  cell

Answer

i = E / (R+r)

= 5 / (9+1)

= 0.5 Amp

Question 3

Potential difference …………. cell.

Answer

V = E – i r

4 = 6 – 2 r

2 r = 2

r = 1 ohm

Question 4

The emf ……….. resistor

Answer

Question 5

The potential …………….. cell

Answer

Question 6

a battery ……….. battery

Answer

Question 7

A 200 ohm …………….. circuit

Answer

Question 8

A high ……………… wire

Answer

Question 9

in the circuit ………….. of R

Answer

EMF of cell = reading of voltmeter when key is open

Question 10

A 10 V battery ……………….current

Answer

Question 11

Two battery ……………charging.

Answer

During charging

V – E = i r

V = E + i r

for first battery

V = 6.20 +20 x 0.01

=6.40 V

and for second battery

V = 12.45 + 0.03 x 20

=13.05 Volt

Question 12

Calculate ……………….. network

Answer

It is  an example of wheat stone bridge

therefore 5 ohm resistor remain inactive

Question 13

find …………… potential

Answer

Since M and N are at same potential. therefore it is an example of wheat stone bridge

Question 14

The adjoining …………… calculate R

Answer

resistance of parallel combination = X

then according to rule of wheatstone bridge

Question 15

calculate ……………..0.4 ohm

Answer

page-number : 273

Question 16

the ……………. balanced

Answer

current through arm ABC= 60/30

=2 amp

current through arm ACD = 60/10 =6 amp

(a)

(b) since D is at higher potential therefore current will pass from D to B

(c) let for balance bridge R(DC)is X then by the rule of balanced wheatstone bridge

10/20 =3/X

i.e. X = 6 ohm

Question 17

calculate ……………… resistor

Answer

(I) equivalent resistance

Question 18

calculate ……………… 60 V

Answer

Resistance of the circuit

=18 x 2.5 = 45 V

Question 19

Find …………….  of R

Answer

Voltage across 10 ohm

120-100 =20V

current in the circuit

=20/10

=2 amp

total resistance of parallel combination

Question 20

What …………. negligible

Answer

(a) when Key is off  8 ohm  become ineffective

Question 21

In steady …………………. circuit

Answer

PD across capacitor

= i R = 2 x 10 = 20 V

energy store in capacitor

Question 22

Compute ……………. resistor

Answer

the 2 ohm resistor in row of ammeter in series with other 3 , ohm resistor in parallel

therefore net resistance

Question 23

In the …………….. 75 ohm

Answer

Question 24

the …………….. voltameter

Answer

Resistance of circuit

Question 25

A network …………….. resistor

Answer

total external resistance

page-number : 274

Question 26

An 84 V DC ……………. connected

Answer

Question 27

Two cell ……………… each cell

Answer

in first case

Question 28

Two identical ……………. cell

Answer

as previous question

Question 29

50 bulb …………….under lit

Answer

total current taken by all bulb

= 50 x 0.6

= 30 amp

again current given by all accumulator

Question 30

three cell …………….. resistance

Answer

current through circuit

Question 31

Determined …………… diagram

Answer

those two cell are in parallel with internal resistance 3 ohm and 0 ohm

therefore effective emf

Question 32

In the ……………… negligible

Answer

Question 33

In the …………..

Answer

applying kirchaff law in loop

Question 34

Two cell ………………

Answer

applying kirchaff law

page-number : 275

Question 35

two cell of emf 6 V and 12 V …………..

Answer

Question 36

Two cell ……………..PDs.

Answer

this will same across cell also because the are in parallel

Question 37

three ……………….cell

Answer

r = 6 ohm

Question 38

Calculate …………….. resistance

Answer

applying kirchaff law

Question 39

In …………………. box

Answer

Question 40

In …………………… 70 cm

Answer

Question 41

A 3 V battery …………….reading .

Answer

(a)

reading of voltameter

3 x 0.5 = 1.5 V

(b)

if resistance of voltameter is 150 ohm then net resistance of 60  wire and voltameter

reading of voltameter

= i R = 0.505 x 2.94 =1.485 volt

Question 42

Potential …………….  potentiometer

Answer

Potential gradient = v / l

= 2/4

=0.5 v / m

Question 43

A 10 m Long ……………..potentiometer

Answer

again E = 0.0025 x 860

=2.15 V

max emf = p x total length

= 0.0025 x 1000

= 2.5 volt

Question 44

A potentiometer ………… AB

Answer

by the rule of wheat stone bridge

Question 45

A cell gives ………………  Cell

Answer

Question 46

A cell emf 1.25 V ………….. second cell .

Answer

Acording principle of potentiometer

= 2.25 V

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