OP Malhotra Class-11 The Straight Line S.Chand ISC Maths

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions Chapter-16. Step by step Solutions of OP Malhotra S.Chand ISC Class-11 Mathematics with Exe-16 (a), 16 (b), 16 (c), 16 (d), 16 (e), 16 (f), 16 (g), 16 (h), 16 (i), 16 (j), With Chapter Test. Visit official Website CISCE for detail information about ISC Board Class-12 Mathematics.

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Class: 11th
Subject: Mathematics
Chapter  : Ch-16 The Straight Line of Section -A
Board ISC
Writer  OP Malhotra
Publications S.Chand Publications 2020-21

-: Select Topics :-

Exe-16 (a)

Exe-16 (b)

Exe-16 (c)

Exe-16 (d)

Exe-16 (e)

Exe-16 (f)

Exe-16 (g)

Exe-16 (h)

Exe-16 (i)

Exe-16 (j)

Chapter Test


OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Straight Line
Any curve is said to be a straight line if two points are taken on the curve such that every point on the line segment joining any two points on it lies on the curve. General equation of a line is ax + by + c = 0.

Various Forms of the Equation of a Line
If a line is at a distance k and parallel to X-axis, then the equation of the line is y = ± k.

If a line is parallel to Y-axis at a distance c from Y-axis, then its equation is x = ± c.

Slope-intercept form: The equation of line with slope m and making an intercept c on the y-axis, is y = mx + c.

One point-slope form: The equation of a line which passes through the point (x1, y1) and has the slope of m is given by y – y1 = m (x – x1).

Position of Points is Relative to a Given Line

Let the equation of the given line be ax + by + c = 0 and let the coordinates of the two given points be P(x1, y1) and Q(x2, y2).
The two points are on the same side of the straight line ax + by + c = 0, If ax1 + by1 + c and ax2 + by2 + c have the same sign.

The two points are on the opposite sides of the straight line ax + by + c = 0, If ax1 + by1 + c and ax2 + by2 + c have opposite sign.

Condition of concurrency for three given lines
a1x + b1y + c1 = 0, a2x + b2y + c2 = 0 and a3x + b3y+ c3 = 0 is a3(b1c2 – b2c1) + b3(a2c1 – a1c2) + c3(a1b2 – a2b1) = 0

Slope of a Line

Tan θ is called the slope or gradient of line l if θ is the inclination of a line l. The slope of a line whose inclination is not equal to 900. It is denoted by ‘m’.

Thus, m = tan θ, θ ≠ 90°

If the slope of the y-axis is not defined, it is observed that the slope of the x-axis is zero.


Exe-16 (a)

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-4 to 16-5


Exe-16 (b)

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-10 to 16-11


Exe-16 (c)

 Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-14


Exe-16 (d)

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-18 to 16-19


Exe-16 (e)

OP Malhotra The Straight Line S.Chand ISC Maths Solutions

Page 16-21


Exe-16 (f)

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-23 to 16-24


Exe-16 (g)

Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-27


Exe-16 (h)

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-29 to 16-30


Exe-16 (i)

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-32


Exe-16 (j)

 Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-34


Chapter Test

OP Malhotra Class-11 The Straight Line S.Chand ISC Maths Solutions

Page 16-38

-: End of The Straight Line Solution :-

Return to :-  OP Malhotra S. Chand ISC Class-11 Maths Solutions


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30 thoughts on “OP Malhotra Class-11 The Straight Line S.Chand ISC Maths”

    • dear student / well wisher / Teacher
      the previous version of 2020-21 has been removed because council has decided to start new session from 1st April Therefore we are upgrading the solutions of 2021-22 editions
      Sorry for inconvenience
      thanks
      team icsehelp

      Reply
  1. Hey, there I found all other solution but none of straight line, ch 16 please resolve this issue I have been waiting almost 6 months for them

    Reply
      • Sir, is it possible to get answers this whole year as I have been waiting from months that answers will be provided one day but from urs side that day is never gonna come ! As well as in this pandemic situation there is no extra classes available (tution) and also I can’t ask 10 questions from a particular exercise from school teacher so will you just try to do in place of delaying it !!

        Reply
  2. please please pleaseeee upload the solutions. i sincerely appreciate all the effort that goes into providing us with these quality, free solutions. this is an important chapter and using this site as reference is the reason i have done well in all my papers. i really need these solutions. please upload them as soon as possible. than you for all that you do 🙂

    Reply

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