Percentage Class 6 RS Aggarwal Exe-10C Goyal Brothers ICSE Maths Solutions 10. In this article you will learn about Application of Percentage. Visit official Website **CISCE** for detail information about ICSE Board Class-6 Mathematics.

## Percentage Class 6 RS Aggarwal Exe-10C Goyal Brothers ICSE Maths Solutions 10

Board | ICSE |

Subject | Maths |

Class | 6th |

Ch-10 | Percentage |

Exercise | 10C |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Application of Percentage |

Academic Session | 2024 – 2025 |

### Word Problems on Percentage

To solve Word Problems on Percentage you should have first practice previous exercise of percentage. There are variety of questions / word problems on application of percentage.

**Exercise- 10C**

( Percentage Class 6 RS Aggarwal Exe-10C Goyal Brothers ICSE Maths Solutions 10 )

**Que-1: In a class test, the marks were awarded out of 80. Kamal obtained 65% marks. How many marks did he gets ?**

**Sol: **Marks awarded out of 80

Kamal obtained = 65%

Marks he gets = 65% of 80

= (65/100) * 80

= 52

**Que-2: In an examination, Renu obtained 480 marks out of 750. What percentage of marks did she get ?**

**Sol: **Rennu obtained = 480 marks

Out of = 750 marks

** **480 / 750 * 100

= 48000 / 750

= 64 %

**Que-3: In her annual examination Geeta scored 39 marks out of 60 in English and 51 out of 75 in Hindi. In which subject her performance was better ?**

**Sol: **For English

percentage = (39/60)×100

= 13×5

= 65%

For Hindi

percentage = (51/75)×100

= 17×4

= 68%

In Hindi subject her performance was better.

**Que-4: In an examination, 640 students appeared. Of them, 544 passed and the rest failed. What percentage of the students failed ?**

**Sol: **Total number of students appeared= 640

Number of students passed= 544

So, number of students failed= 640-544

= 96.

Percentage of failed students=(96/640 x 100)%

= (0.15 x 100)%

= 15%

**Que-5: In an examination 1360 students appeared. Of them, 85% passed. How many students failed ?**

**Sol: **100% – 85% = 15% of the students failed.

15% of 1360

15/100 times 1360 = 204

Therefore, 204 students failed.

**Que-6: In an examination, a student has to secure 48% marks to pass. If Rahul gets 247 marks and fails by 5 marks, what are the maximum marks? **

**Sol: **Let’s denote the maximum marks as “M”. According to the given information, Rahul got 247 marks and failed by 5 marks, which means he needed 252 marks to pass (247 + 5).

Since 252 marks represent 48% of the maximum marks, we can set up the following equation:

(252 / M) * 100 = 48

Solving for M:

M = (252 * 100) / 48

M = 525

**Que-7: On a particular day, 96% of the students were present in a school. If the number of absentees a on that day was 82, find the total strength of a school.**

**Sol: **Percentage of students present= 96%

Percentage of total students absent= (100% – 96%)

= 4%

Number of students absent= 82

Since 4%= 82 students, the total strength of school = 96/4= 24

= 24 x 82

= 1986 + 82

= 2050

**Que-8: The population of a town was increased by 5% in a year. Last year its population was 20320. What is the present population of the town ?**

**Sol: **Increase in population = 5%*20320

Increase in population = (5*20320)/100

Performing multiplication and division

Increase in population = 1016

Present population = 20320 + 1016

Present population = 21,336

**Que-9: The price of a bat was Rs650. Now, its price has been increased by 6%. What is the increased price of that bat ?**

**Sol: **Price of bat = Rs650

Increased = 6%

650+6% of 650

650+0.06×650

650+39

689

**Que-10: The price of a cooler during last summer was quoted at Rs7250. In off season, the price has been reduced by 12%. What is the reduced price of a cooler ?**

**Sol: **Given that the price of the cooler was 7250 during summer.

Since the price was reduced by 12 %, we need to find what is 12% of 7250. It is calculated as,

12% of 7250

= (12/100) * 7250

= 870

So the price is reduced by 870. Hence the reduced price of the cooler is,

7250 – 870

= 6380.

**Que-11: The value of a car depreciates (decreases) by 10% every year. If the value of the new car is Rs225000, what will be its value after one year**

**Sol: **Cost of car is : 225000

Depreciation(10% every year) : 22500 (225000*10/100)

New Value : 202500 (Cost – Depreciation)

**Que-12: Ashish is 175 cm tall. His sister Annu is 8% shorter than him. What is Annu’s height ?**

**Sol: **Ashish is 175 cm taller than his sister.

Her sister Annu is 8% shorter than him

So, 8% of 175 cm

= 8/100×175

= 14cm.

So,

175 – 14

= 161 cm.

Her sister height is 161 cm.

**Que-13: An alloy consists of copper and zinc. It contains 60% copper and rest is zinc. Find the quantity of copper and zinc in 425g of his alloy.**

**Sol: **copper = 60%

zinc = 40%

wt of alloy=425g

wt. of Cu = (425×60)/100 = 255g

wt. of Zinc = (425×40)/100 = I70g

**Que-14: A tin contained 25 litres of oil. Due to leakage 2 litres of oil was lost. What percentage of oil is still there in the tin ?**

**Sol: **total amount of oil = 25 L

amount of oil lost = 2 L

amount of oil in tin after leakage = 25- 2 = 23 L

percentage of oil left in tin = (23/25) * 100 = 92%

**Que-15: An election was contested by two candidates A and B. In all there were 25000 voters. 80% of the votes were polled. If A got 60% of the total votes polled, how many votes did B get ?**

**Sol: **Total voters = 25000

80% of the votes were polled.

= (80/100)×25000 = 20000

A got 60% votes

= (60/100)×20000 = 12000

So,

B will get votes

= 20000−12000

= 8000

**Que-16: Mr. Mehta had Rs60000. Out of this money, he gave 20% to his daughter, 35% to his son, 30% to his wife and the rest he donated to a Charitable Trust. How much did he donate ?**

**Sol: **Daughter’s share = 60000 × 20%

= 60000 × (20/100)

= 12000

Son’s share = 60000 × 35%

= 60000 × (35/100)

= 21000

Wife’s share = 60000 × 30%

= 60000 × (30/100)

= 18000

Family’s share = 12000 + 21000 + 18000

Family’s share = 51000

Donated amount = total amount – family’s share

Donated amount = 60000 – 51000

Donated amount = Rupees 9000

–: Percentage Class 6 RS Aggarwal Exe-10C Goyal Brothers ICSE Maths Solutions : —

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