Profit and Loss Discount Tax Class 8 RS Aggarwal Exe-7C Goyal Brothers ICSE Maths Solutions Ch-7. We provide step by step Solutions of council prescribe textbook / publication to develop skill and confidence. Visit official Website **CISCE** for detail information about ICSE Board Class-8 Mathematics.

## Profit and Loss Discount Tax Class 8 RS Aggarwal Exe-7C Goyal Brothers ICSE Maths Solutions Ch-7

Board | ICSE |

Publications | Goyal Brothers Prakashan |

Subject | Maths |

Class | 8th |

writer | RS Aggarwal |

Book Name | Foundation |

Ch-7 | Profit and Loss Discount Tax |

Exe-7C | Discount and Tax Questions Solved |

Edition | 2024-2025 |

### How to Solve Tax Discount Questions?

**Note: ** Before starting step by step solutions on discount one must know following topic clearly.

**MP**: It is the market price also called tag price catalogue price list price print price etc.

**Discount Rate**: Always given in percent.

**Discount Value:** Find out the discount value on MP(never on selling price) by using formula

Discount Value = MP x (Dis Rate /100)

**SP:** it is the selling price on which a customer buy the goods. calculate SP by using formula

SP = MP- Discount Value

**Tax:** Revenue taken by government is called tax. It is also given in percentage. It is always calculated on SP (never on MP) calculate tax by using formula

Tax Value = SP x (Tax Rate/100)

**Final Amount:** Amount paid by customer including tax is called final amount. calculate amount by using formula

Amount = SP + Tax Value

**Exercise- 7C**

(Profit and Loss Discount Tax Class 8 RS Aggarwal Exe-7C Goyal Brothers ICSE Maths Solutions Ch-7)

**Que-1: The marked price of a refrigerator is Rs16450. The shopkeepers offers an off-season discount of 16% on it. Find its selling price.**

**Sol: **M.P. = Rs16450

Discount = 16%

S.P. = M.P. – {(M.P.xD)/100}

S.P. = 16450 – {(16450×16)/100}

S.P. = 16450 – 2632

S.P. = Rs13818.

**Que-2: The price of a sweater was slashed down by a shopkeeper from Rs850 to Rs731. Find the rate of discount given by him.**

**Sol: **The price of a sweater was slashed down by a shopkeeper from rupees 850 to rupees 731..

MRP of sweater = Rs 850

Sold after discount = Rs 731

Difference = 850 – 731 = 119

= Rs 119.

Discount % = ( 119 x 100)/ 850

= ( 119 x 2) / 17

= 7 x 2

= 14 %

**Que-3: Find the rate of discount being given on a mini toy-gun whose selling price is Rs345 after deducting a discount of Rs30 on its marked price.**

**Sol: **SP (Selling Price) = 345

D (Discount) =30

MP = SP+D

= 375

Rate of Discount=(D×100)/MP

= (30×100)/375

= 8% ans.

**Que-4: After allowing a discount of 15%, a baby-suit was sold for Rs1156. Find its marked price.**

**Sol: **Let the marked price be x.

Selling price = Rs.1156

Discount = 15%

=> (100-15)% of x = 1156

=> 85% of x = 1156

=> 85/100 x = 1156

=> x = 1156 × 100/85

=> x = 1360

**Que-5: A calculator was bought for Rs435 after getting a discount of 13%. Find the marked price of the calculator.**

**Sol: **Let the marked price of the calculator be ₹x.

Selling price of the calculator= ₹435

Discount= 13%

₹x-13% of ₹x= ₹435

→ ₹x-₹13x/100= ₹435

→ ₹100x-13x/100= ₹ 435

→ ₹87x/100= ₹435

→ ₹87x= ₹43500

→ ₹x= ₹500

**Que-6: A dealer marked his goods 35% above cost price and allowed a discount of 20% on the parked price. Find his gain or loss per cent.**

**Sol: **Let C.P. of goods = Rs.100 (as 35% of 100 is Rs.35)

∴Marked price = Rs.100+35 = Rs.135

Rate of discount = 20%

Discount amount = 20% of 135

= (20/100)×135

= Rs.27

Now, selling price = M.P−Discount

= 135−27

= 108

Since, S.P>C.P

Profit amount = S.P−C.P

= 108−100

=8

Thus, Gain percent = (profit/C.P)×100

= (8/100)×100

= 8%

**Que-7: An article was marked 40% above cost price and a discount of 35% was given on its marked price. Find the gain or loss per cent made y the shopkeeper.**

**Sol: **Let say Cost Price of Article = 100C

article was marked 40% above cost price

= Marked Price = 100C + (40/100)100C = 140C

discount of 35% was given on its marked price

35 % Discount = (35/100) * 140C = 49C

Selling Price = Marked Price – Discount

= 140C – 49C

= 91C

Loss = 100C – 91C = 9C

Loss % = (9C/100C) * 100 = 9%

**Que-8: A dealer purchased a washing machine for Rs7660. After allowing a discount of 12% on its marked price, he gains 10%. Find the marked price.**

**Sol: **Cost Price + Profit = Selling Price

The Cost Price = Rs 7660, Profit/ Gain = 10% (Profit based upon cost). Hence,

7660 + 10% of 7660 = Selling Price

7660 + 766 = Selling Price

Selling Price = Rs 8426

Marked Price (MP) – Discount = Selling Price

MP – 12% of MP = 8426

(100MP – 12MP)/100 = 8426

88MP = 842600

MP = 842600 / 88

MP = Rs 9575

**Que-9: A shopkeeper bought a sewing machine for Rs3750. After allowing a discount of 10% on its marked price, he gains 26%. Find the marked price of the sewing machine.**

**Sol: **CP = 3750

gain = 26%

S.P. = (C.P. x g%)/100

S.P. = (3750 x 126)/100

S.P. = 4725

Discount = 10%

M.P. = (S.P. x 100)/Discount

M.P. = (4725 x 100)/90

M.P. = 5250.

**Que-10: After allowing a discount of 10% on the marked price, a trader still makes a profit of 17%. By what per cent is the marked price above cost price ?**

**Sol: **Given he gains 17% on selling price would be

Selling Price = (100 + 17% of 100) = Rs.117

Discount = 10%

Let x be the marked price.

Market Price – Discount = Selling Price

x – (10% of x) = 117

x – x/10 = 117

9x/10 = 117

x = 130

Cost price is 100

Selling price is 117

Marked price is 130

So, Market Price is 30% above Cost Price.

**Que-11: After allowing a discount of 12% on the marked price, a shopkeeper still gains 21%. By what per cent is the marked price above cost price ?**

**Sol: **Let the C.P. = Rs100

Gain% = 21%

Discount = 12%

S.P. = 121% of 100 = Rs. 121

M.P. = 121×(100/88) = Rs.137.5

M.P. Above% = 137.5−(100/100)×100

M.P. = 37.5 %

**Que-12: Find a single discount equivalent to two successive discounts of 20% and 10%.**

**Sol: **The successive discount are 10% and 20%.

Successive discount = X + Y – (XY)/100

Where,

X = First discount

Y = Second discount

Successive discount = X + Y – (XY)/100

X = 10%, Y = 20%

⇒ 10 + 20 – 200/100

⇒ 28%

∴ The single equivalent discount is 28%.

**Que-13: ****Find a single discount equivalent to two successive discounts of 40% and 5%.**

**Sol: **The percentage of two successive discounts are 40% and 5%.

The marked price of the item is Rs. 100

Price after first discount = {100-(100 × 40/100)}

= (100-40) = Rs. 60

Price after second discount = {60-(60×5/100)} = Rs. 57

Difference between the final price and the initial price = (100-57) = Rs. 43

Single equivalent discount = (100 × Total discount amount / Initial price)

= 100 × 43/100

= 43%

**Que-14: ****Find a single discount equivalent to three successive discounts of 20%, 5% and 1%.**

**Sol: **Let the Marked Price be 100.

First discount = 20% of 100 = 20

Price after first discount = 80

Second discount = 5% of 80 = 4

Price after second discount = 76

Third discount = 1% of 76 = 0.76

Price after third discount = 75.24

Hence, single discount = 100 – 75.24 = 24.76%

**Que-15: The marked price of a watch is Rs1375. If tax is charged at the rate of 4%, find the total cost of the watch.**

**Sol: **The marked price of a watch is rupees 1375.

if tax is charged at the rate of 4 percent.

4% is written in the decimal form.

= 0.04%

Tax price = 0.04 × 1375

= Rs 55

Total cost of the watch = Marked price of a watch + Tax price

= Rs1375 + Rs 55

= Rs 1430

**Que-16: Ravi buys a bicycle with a marked price of Rs12500. He gets a rebate of 10% on it. After getting the rebate, tax is charged at the rate of 6%. Find the amount he will have to pay for the bicycle.**

**Sol: **It is given that Ravi buys a bicycle of Rs 12500.He gets a rebate of 10%. And the tax is 6%.

As the rebate of the bicycle is 10% so the bicycle’s price is 90% of the original price.

= 0.9 × 12500

= Rs 11250

After the addition of tax, the amount becomes:

0.06 × 12500

= Rs 675

Therefore, the total amount he has to pay is:

Rs 11250 + Rs 675

= Rs 11925

**Que-17: The list price of the washing machine is Rs25000 and the shopkeeper gives a discount of 12% on the list price. On remaining amount, he charges a tax of 10%.**

Find : (i) the amount of tax, a customer has to pay, and (ii) the final price he has to pay for the washing machine.

**Sol: **PRICE OF THE WASHING MACHINE = RS.25000

DISCOUNT = 12%

(i) COST AFTER DISCOUNT= (25000×88)/100

= 22000

AMOUNT OF TAX = (22000×10)/100

= RS.2200

(ii) TOTAL AMOUNT HE HAS TO PAY

= RS.2200 + RS.22000

= RS.24200

**Que-18: Reena purchased a face cream for Rs113.40 including tax. If the printed price of the face cream is Rs105, find the rate of tax on it.**

**Sol: **113.4 Rs. is the price including tax of the face cream and 105 Rs. is the printed price of the face cream.

So, Reena has to pay (113.4-105) =8.4 Rs. as the tax for her purchase.

Hence, the percentage of tax she has to pay is given by

= {(113.4-105)/105} x 100

= (8.4/105) x 100

= 8%.

**Que-19: Vivek purchased a laptop for Rs34164, which includes 10% rebates on the marked price and then 4% tax on the remaining price. Find the marked price of the laptop.**

**Sol: **Let M.P. be x

Rebate = 10%

Price after rebate = x – (10x/100)

= 9x/10

Sales tax = 4%

Total money = (9x/10) + {(4/100) x (9x/10)}

= (9x/10) + (36x/1000) = 34164

= (936x/1000) = 34164

x = (34164×1000)/936

x = Rs36500.

**Que-20: Tanya buys an electric iron fir Rs712.80, which includes two successive discounts of 10% and 4% respectively on the marked price and then 10% tax on the remaining price. Find the marked price of the electric iron.**

**Sol: **Let the the marked price before both the discounts and the tax be Rs. x

First discount is 10 % and the second discount is 4 % and then the tax is added on the remaining amount.

x – 10 % discount

⇒ x – (x*10)/100

⇒ x – x/10

= 9x/10

So, after allowing first discount of 10 %, the price of iron is Rs. 9x/10. Now the second discount of 4 % will be given on this amount.

9x/10 – 4 % discount

⇒ 9x/10 – (9x/10*4/100)

⇒ 9x/10 – 9x/250

Taking LCM and then solving it.

⇒ (225x – 9x)/250

= 216x/250

So, after the second discount of 4 %, the remaining price of iron is Rs. 216x/250. Now, the tax 10 % will be charged on this amount.

216x/250 + 10 % tax = 712.80

⇒ 216x/250 + (216x/250*10/100) = 712.80

⇒ 216x/250 + 216x/2500 = 712.80

Taking the LCM of the denominators and then solving it.

⇒ (2160x + 216x)/2500 = 712.80

⇒ 2376x/2500 = 712.80

⇒ 2376x = 712.80*2500

⇒ x = 1782000/2376

⇒ x = 750

**Que-21: The price of the good processor inclusive of tax of 5% is Rs6930. If the tax is increased to 8%, how much more does the customer pay for it ?**

**Sol: **M.P. be x

S.P.1 = M.P. + T1

6930 = x + (5x/100)

6930 = (105x/100)

x = (6930×100)/105

x = 6600

S.P.2 = {1+(T/100)} x 6600

S.P.2 = (108/100) x 6600

S.P.2 = 7128

S.P. = S.P.2 – S.P.1

S.P. = 7128 – 6930

S.P. = 198.

**Que-22: The price of a laser printer including 7% tax, is Rs17334. How much less does a customer pay for it, if the tax on it is reduced to 4% ?**

**Sol: **Let the price of the laser printer without tax= Rs x

Therefore, Tax = 7% of Rs x

= Rs (7/100 × x)

= Rs 7/100x

So, price of the laser printer including tax

= Rs (x + 7/100x)

= Rs (x + 7/100x)

= Rs (100x + 7x /100)

= Rs 107x / 100

Given: The price of the laser printer including tax

= Rs 17334

Therefore, 107x / 100 = 17334

x = (17334×100)/107

x = 16200

So, Price of the laser printer without tax is Rs 16200

Given: Tax on it is reduced to 4%

Therefore, 4% of Rs 16200 = Rs ( 4/100 × 16200)

= Rs 648

Again 7% of Rs 16200 = Rs (7/100 × 16200)

= Rs 1134

Therefore, Amount of money less paid by the customer = Rs (1134 – 648)

= Rs 486

–: End of Profit and Loss Discount Tax Class 8 RS Aggarwal Exe-7C Goyal Brothers ICSE Maths Solutions Ch-7 :–

**Return to :- ICSE Class -8 RS Aggarwal Goyal Brothers Math Solutions**

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