Profit Loss and Discount ICSE Class-7th Concise Selina Maths Solutions Chapter-9 . We provide step by step Solutions of Exercise / lesson-9 Profit Loss and Discount for ICSE Class-7 Concise Selina Mathematics. Our Solutions contain all type Questions with Exe-9 A , Exe-9 B and Exe-9 C, to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-7.
Profit Loss and Discount ICSE Class-7th Concise Selina Maths Solutions Chapter-9
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Exercise – 9 A Solved Questions of Profit Loss and Discount for ICSE Class-7th
Question 1.
Find the gain or loss percent, if
(i) C.P. = Rs. 200 and S.P.: = Rs. 224
(ii) C.P. = Rs. 450 and S.P. = Rs. 400
(iii) C.P. = Rs. 550 and gain = Rs . 22
(iv) CP. = Rs. 216 and loss = Rs. 72
(v) S.P. = Rs. 500 and loss : = Rs. 100
(vi) S.P. = Rs. 12 and profit = Rs. 4
(vii) C.P. = Rs. 5 and gain = 60 P
Answer
(i)
C.P. = Rs. 200 and S.P. = Rs. 224
∴ Gain = S.P. – C.P.
= Rs. 224 – Rs. 200 =
Rs. 24
Gain % = (gain×100)/C.P
= (24×100)/200=12%
(ii)
C.P. = Rs. 450 and S.P. = Rs. 400
∴ Loss = C.P. – S.P.
= Rs. 450 – Rs. 400 = Rs. 50
Loss % =(Loss×100)/C.P
=(50×100)/450
=100/9
=11 (1/9)%
(iii)
C.P. = Rs. 550 and gain = Rs . 22
∴ S.P. = C.P. + gain
= Rs. 550 + Rs. 22 = Rs. 572
Gain % = (Gain×100)/C.P
=(22×100)/550=4%
(iv)
CP. = Rs. 216 and loss = Rs. 72
∴ S.P. = C.P. – loss
= Rs. 216 – Rs. 72 = Rs. 144
Loss % = (Loss×100)/C.P
=(72×100)/216
=100/3
= 33 (1/3)%
(v)
S.P. = Rs. 500 and loss : = Rs. 100
∴ C.P. = S.P. + loss
= Rs. 500 + Rs. 100 = Rs. 600
Loss % = (Loss×100)/C.P
=(100×100)/600
=50/3
= 16 (2/3)%
(vi)
S.P. = Rs. 12 and profit = Rs. 4
∴ C.P. = S.P. – gain
= Rs. 12 – Rs. 4 = Rs. 8
Gain % = (gain×100)/S.P
=(4×100)/8
=50%
(vii)
C.P. = Rs. 5 and gain = 60 P
∴ S.P.= C.P. + gain
= Rs. 5 + Rs. 60 P = Rs. 5.60
Gain % = (gain×100)/C.P
=(0.60×100)/5
=(60×100)100×5
=12%
Question 2.
Find the selling price, if:
(i) C.P. = Rs. 500 and gain = 25%
(ii) C.P. = Rs. 60 and loss = 12 1/2%
(iii) C.P. = Rs. 150 and loss = 20%
(iv) C.P. = Rs. 80 and gain = 2.5%
Answer
(i)
C.P. = Rs. 500 and gain = 25%
S.P. = C.P.(100+gain %)/100
= (500(100+25))/100
=Rs. (500×125)/100
= Rs. 625
(ii)
C.P. = Rs. 60 and
(iii)
C.P. = Rs. 150 and loss = 20%
S.P. = C.P.(100-loss %)/100
= 150(100-20)/100
= (150×80)/100
= Rs. 120
(iv)
C.P. = Rs. 80 and gain = 2.5%
S.P. = C.P.(100+gain %)/100
=80(100+2.5)/100
= (80×102.5)/100
= (Rs.80×1025)/(100×10)
= Rs. 82
Question 3.
Rohit bought a tape-recorder for Rs. 1,500 and sold it for Rs. 1,800. Calculate his profit or loss percent.
Answer
C.P. of tape-recorder = Rs. 1500
S.P. = Rs. 1800
∴ Gain = S.P. – C.P.
= Rs. 1800 – Rs. 1500 = Rs. 300
Gain % = (Gain×100)/C.P.
= (300×100)/1500
= 20 %
Question 4.
An article bought for Rs. 350 is sold at a profit of 20%. Find its selling price.
Answer
C.P. of article = Rs. 350
Profit = 20%
∴ S.P. = C.P.(100+Profit%)/100
=Rs. (350(100+20))/100
= Rs. (350×120)/100
= Rs. 420
Question 5.
An old machine is bought for Rs. 1,400 and is sold at a loss of 15%. Find its selling price.
Answer
C.P. of the machine = Rs. 1400
Loss = 15%
∴ S.P. =C.P(100-Loss%)/100
= (1400(100-15))/100
= Rs. (1400×85)/100
= Rs. 1190
Question 6.
Oranges are bought at 5 for Rs. 10 and sold at 6 for Rs. 15. Find profit or loss as percent.
Answer
L.C.M. of 5 and 6 = 30
Let 30 oranges are brought
∴ C.P. of 30 oranges = (30×10)/5 = Rs. 60
and S.P. of 30 oranges = (30×15)/6 = Rs. 75
Gain = S.P. – C.P.
= Rs. 75 – Rs. 60 = Rs. 15
∴ Gain % = (gain×100)/C.P
= (15×10)/60
=25%
Question 7.
A certain number of articles are bought at 3 for Rs. 150 and all of them are sold at 4 for Rs. 180. Find the loss or gain as percent.
Answer
L.C.M. of 3 and 4 = 12
Let 12 articles are brought
∴ C.P. of 12 articles = Rs. (150×12)/3 = Rs. 600
and S,P, of 12 articles = Rs. (180×12)/4 = Rs. 540
Loss = C.P. – S.P.
= Rs. 600 – Rs. 540 = Rs. 60
Loss % = (Loss×100)/C.P.
=(60×100)/600
=10%
Question 8.
A vendor bought 120 sweets at 20 p each. In his house, 18 were consumed and he sold the remaining at 30 p each. Find his profit or loss as percent.
Answer
Quantity of sweets bought = 120
∴ C.P. of 120 sweets =(120×20)/100
= Rs. 24
No. of sweets consumed = 18
Balance sweets = 120 – 18 = 102
∴ S.P. of 102 sweets
= (102×30)/100
=3060/100
= Rs. 30.60
Gain = S.P. – C.P.
= Rs. 30.60 – Rs. 24 = Rs. 6.60
Gain % = (gain×100)/C.P
= (6.60×100)/24
=(660×100)/(100×24)
=55/2
=27.5%
Question 9.
The cost price of an article is Rs. 1,200 and selling price is 
(i) selling price of the article
(ii) profit or loss as percent.
Answer
Cost price (C.P.) = Rs. 1200
∴ S.P. =5/4 of C.P.
= (5/4)×1200
= Rs. 1500
∴ Gain = S.P. – C.P.
= Rs. 1500 – Rs. 1200 = Rs. 300
∴ Gain % =(gain×100)/C.P.
=(300×100)/1200
=25%
Question 10.
The selling price of an article is Rs. 1,200 and cost price is
find :
(i) cost price of the article ;
(ii) profit or loss as percent.
Answer
(i) S.P. of an article = Rs. 1200
∴ C.P. =5/4 of C.P.
=(5/4)×1200
= Rs. 1500
(ii) Loss = C.P. – S.P
= Rs. 1500 – Rs. 1200 = Rs. 300
Loss% = (Loss×100)/C.P.
= (300×100)/1500
=(100/5)
=20%
Exercise – 9 B Profit Loss and Discount ICSE Class-7th Concise
Question 1.
Find the cost price, if:
(i) S.P. = Rs. 21 and gain = 5%
(ii) S.P. = Rs. 22 and loss = 12%
(iii) S.P. = Rs. 340 and gain = Rs. 20
(iv) S.P. = Rs. 200 and loss = Rs. 50
(v) S.P. = Re. 1 and loss = 5 p.
Answer
(i)
S.P. = Rs. 21 and gain = 5%
∴ C.P. = (S.P.×100)/(100+gain %)
= (21×100)/(100+5)
= (21×100)/105
= Rs. 20
(ii)
S.P. = Rs. 22 and loss = 12%
∴ C.P. = (S.P.×100)/(100-loss %)
=(22×100)/(100-12)
=(22×100)/88
= Rs. 25
(iii)
S.P. = Rs. 340 and gain = Rs. 20
∴ C.P. = S.P. – Gain
= Rs. 340 – Rs. 20 = Rs. 320
(iv)
S.P. = Rs. 200
loss = Rs. 50
∴ C.P. = S.P. + Loss
= Rs. 200 + Rs. 50 = Rs. 250
(v)
S.P. = Re. 1 and loss = 5 p.
∴ C.P. = S.P. + Loss
= Rs. 1 + 5 p
= Rs 1.05
Question 2.
By selling an article for Rs. 810, a loss of 10 percent is suffered. Find its cost price.
Answer
S.P. of an article = Rs. 810
Loss = 10 %
∴ C.P. = (S.P.×100)/(100-Loss%)
= (810×100)/(100-10)
=(810×100)/90
Rs. 900
Question 3.
By selling a scooter for Rs. 9,200, a man gains 15%. Find the cost price of the scooter.
Answer
S.P. of the scooter = Rs. 9200
Gain = 15%
∴ C.P. =(S.P.×100)/(100+gain%)
=(9200×100)/(100+15)
=(9200×100)/115
= Rs. 8000
Question 4.
On selling an article for Rs. 2,640, a profit of 10 percent is made. Find
(i) cost price of the article
(ii) new selling price of it, in order to gain 15%
Answer
S.P. of an article = Rs. 2640
Gain = 10%
(i) ∴ C.P. = (S.P.×100)/(100+gain%)
= Rs. (2640×100)/(100+10)
= Rs. (2640×100)/110
Rs. 2400
(ii) In second case, Gain = 15%
∴ S.P. = (C.P.(100+gain %))/100
= Rs. 2400(100+15)/100
= Rs. (2400×115)/100
Rs. 2760
Question 5.
A T.V. set is sold for Rs. 6800 at a loss of 15%. Find
(i)cost price of the T.V. set.
(ii)new selling price of it, in order to gain 12%
Answer
S.P. of the T.V. set = Rs. 6800
Loss = 15%
(i) ∴ C.P. = (S.P×100)/(100-loss%)
= Rs. (6800×100)/(100-15)
= Rs. (6800×100)/85
= Rs. 8000
(ii) In second case, gain = 12 %
∴ S.P. = (C.P.(100+12))/100
= Rs. (8000(100+12))/100
= Rs. (8000×112)/100
= Rs. 8960
Question 6.
A fruit seller bought mangoes at Rs. 90 per dozen and sold them at a loss of 8 percent. How much will a customer pay for.
(i) one mango
(ii) 40 mangoes
Answer
C.P. of 1 dozen or 12 mangoes = Rs. 90
Loss = 8 %
∴ S.P. of 1 dozen or 12 mangoes
= (C.P.×(100-loss%))/100
= Rs. 90(100-8)/100
=(90×92)/100
=828/10
= Rs. 82.80
(i) S.P. of 1 mango = 82.80/12
= Rs. 6.90
(ii) S.P. of 40 mangoes = Rs. 6.90 × 40
= Rs. 276
Question 7.
By selling two transistors for Rs. 00 each, a shopkeeper gains 20 percent on one transistor and loses 20 percent on the other.
Find :
(i) C.P. of each transistor
(ii) total C.P. and total S.P. of both the transistors
(iii) profit or loss percent on the whole.
Answer
S.P. of first transistor = Rs. 600
Gain = 20%
(i) ∴ C.P. = (S.P.×100)/(100+gain %)
=(600×100)/(100+20)
=(600×100)/120
=Rs.500
S.P. of the second transistor = Rs. 600
Loss = 20%
∴ C.P. of the second transistor
=(S.P.×100)/(100-loss%)
=(600×100)/(100-20)
=Rs. (600×100)/80
= Rs. 750
∴ C.P. of the two transistors are Rs. 500 and Rs. 750
(ii) Total C.P. of both the transistors
= Rs. 500 + Rs. 750 = Rs. 1250
and total S.P. of both the transistors
= Rs. 600 + Rs. 600 = Rs. 1200
(iii) Total loss = C.P. – S.P.
= 1250 – 1200 = Rs. 50
∴ loss % =(loss×100)/C.P.
=(50×100)1250
=4%
Question 8.
Mangoes are bought at 20 for Rs. 60. If
they are sold at 33
Find:
(i) selling price of each mango.
(ii) S.P. of 8 mangoes.
Answer
C.P. of 20 mangoes = Rs. 60
Gain = 33 (1/3)%
=100/3%
∴ S.P. of 20 mangoes =C.P.×(100+gain %)/100
=60(100+(100/3))/100
= Rs. (60×400)/(100×3)
= Rs. 80
(i) S.P. of 1 mango = Rs. 80/20
= Rs. 4
(ii) S.P. of 8 mangoes = Rs. 4 × 8
= Rs. 32
Question 9.
Find the cost price of an article, which is sold for Rs. 4050 at a loss of 10%. Also, find the new selling price of the article which must give a profit of 8%.
Answer
S.P. of an article = Rs. 4050
Loss = 10%
(i) ∴ C.P. of the article = (S.P×100)/(100-loss %)
=(4050×100)/(100-10)
=(4050×100)/90
= Rs. 4500
(ii) When gain = 8 %
∴ New S.P. of the article
=(C.P.(100+gain %))/100
=(4500(100+8))/100
=(4500×108)/100
= Rs. 4860
Question 10.
By selling an article for ₹825, a man loses
Find :
(i) the cost price of the article,
(ii) the profit percent or the loss percent made, if the same article is sold for ₹1265.
Answer
S.P. of an article = ₹ 825
Loss = 1/3 of S.P. = (1/3)×825 = ₹ 275
(i) ∴ C.P. = S.P. + Loss
= ₹ 825 + ₹ 275 = ₹ 1100
(ii) In second case,
S.P. = ₹ 1265
∴ Gain = S.P. – C.P.
= ₹ 1265 – ₹ 1100 = ₹ 165
Gain % = (gain×100)/C.P.
= (165×100)/1100
=15%
Question 11.
Find the loss or gain as percent, if the C.P. of 10 articles, all of the same kind, is equal to S.P. of 8 articles.
Answer
C.P. of 10 articles = S.P. of 8 articles = ₹ 80 (Suppose)
∴ C.P. of 1 article =80/10
= ₹ 8
and S.P. of 1 article = 80/8
= ₹ 10
∴ Gain = S.P. – C.P. = ₹ 10 – ₹ 8 = ₹ 2
Gain % = (Gain×100)/C.P.
=(2×100)/8
=25%
Question 12.
Find the loss or gain as percent, if the C.P. of 8 articles, all of the same kind, is equal to S.P. of 10 articles.
Answer
C.P. of 8 articles = S.P. of 10 articles = ₹ 80 (suppose)
∴ C.P. of 1 article =80/8
= ₹ 10
and S.P. of 1 article =80/10
=₹8
∴ Loss = C.P. – S.P. = ₹ 10 – ₹ 8 = ₹ 2
Loss % = (Loss×100)/C.P.
=(2×100)/10
=20%
Question 13.
The cost price of an article is 96% of its selling price. Find the loss or the gain as percent on the whole.
Answer
Let S.P = ₹ 100
C.P. = 96 % of S.P.
Question 14.
The selling price of an article is 96% of its cost price. Find the loss or the gain as percent on the whole.
Answer
Let C.P. = ₹ 100
S.P. = 96% of C.P.
= ₹ (96/100)×100
=₹96
∴ Loss = ₹ 100 – ₹ 96 = ₹ 4
and loss percent =(Loss×100)/C.P.
=(4/100)×100%
= 4 %
Question 15.
Hundred oranges are bought for ₹350 and all of them are sold at the rate of ₹48 per dozen. Find the profit percent or loss percent made.
Answer
∵ C.P. of one orange = ₹(350/100)=₹3.50
and S.P. of one orange = ₹48/12=₹4
Clearly, Gain = ₹4 – ₹ 3.50 = ₹ 0.50
and gain percent =(Gain×100)/C.P.
= ₹ (0.50/3.50)×100%
=14 (2/7)%
Question 16.
Oranges are bought at 100 for ?80 and all of them are sold at ₹80 for ₹100. Find the loss or gain as percent in this transaction.
Solution:
Answer
∵ C.P. of one orange = ₹ 80/100
=₹0.8
and S.P. of one orange = ₹100/80
=₹1.25
Clearly, profit = ₹ 1.25 – ₹ 0.8 = ₹ 0.45
and profit 5 = ₹ (0.45/0.8)×100
=(45/8)×(100×10)/100
=450/8
=56.25%
∴ Profit % = 56.25 %
Question 17.
An article is bought for ₹5,700 and ₹1,300 is spent on its repairing, transportation, etc. For how much should this article be sold in order to gain 20% on the whole.
Answer
C.P. of an article = ₹ 5700
Amount spent on repair = ₹ 1300
Total cost price (C.P.) = ₹ 5700 + ₹ 1300 = ₹ 7000
Gain = 20%
∴ S.P. of an article = (C.P.×(100+Gain%))/100
= ₹ (7000×(100+20))/100
= ₹ (7000×120)/100
= ₹ (840000)/100
= ₹ 8400
∴ Selling price of an article (S.P.) = ₹ 8400
Exercise – 9 C ICSE Class-7 Maths
Question 1.
A machine is marked at ₹5000 and is sold at a discount of 10%. Find the selling price of the machine.
Answer
Marked price (M.P.) of the machine = ₹ 5000
Rate of discount = 10%
∴ Amount of discount = ₹ 5000×(10/100)
=₹500
∴ Selling price = M.P. – discount
= ₹ 5000 – ₹ 500
= ₹ 4500
Question 2.
shopkeeper marked a dinner set for ₹1000. He sold it at ₹900, what percent discount did he give ?
Answer
Marked price of a dinner set = ₹ 1000
and selling price (S.P.) = ₹ 900
∴ Amount of discount = Rs. 1000 – Rs. 900 = ₹ 100
∴ Discount percent = (Discount×100)/M.P.
=(100×100)/1000
=10%
Question 3.
A pair of shoes marked at ₹320, are sold at a discount of 15 percent.
Find :
(i) discount
(ii) selling price of the shoes.
Answer
Marked Price (M.P.) of shoes = ₹ 320
Rate of discount = 15%
(i) ∴ Amount of discount = ₹ (320×15)/100
=₹48
(ii) Selling price = M.P. – Discount
= ₹ 320 – 48
= ₹ 272
Question 4.
The list price of an article is ₹450 and it is sold for ₹360.
Find :
(i) discount
(ii) discount percent
Answer
List price (M.P.) of an article = ₹ 450
Selling price = ₹ 360
(i) ∴ Amount of discount = M.P. – S.P
= ₹ 450 – ₹ 360 = ₹ 90
(ii) Discount percent = (Discount×100)/M.P.
=(90×100)/450
=20%
Question 5.
A shopkeeper buys an article for₹300. He increases its price by 20% and then gives 10% discount on the new price. Find:
(i) the new price (marked price) of the article.
(ii) the discount given by the shopkeeper.
(iii) the selling price.
(iv) profit percent made by the shopkeeper.
Answer
C.P. of an article = ₹ 300
Increase in price = 20%
(i) ∴ Marked price (M.P.)
= (C.P.×(100+increase%))/100
₹=₹300(100+20)/100
₹=₹ (300×120)/100
=₹360
(ii) Rate of discount = 10%
Amount of discounts
₹=₹(360×10)/100
=₹ 36
(iii) Selling price = M.P. – discount
= ₹ 360 – 36 = ₹ 324
(iv) Net profit to the shopkeeper
= S.P. – C.P. = Rs. 324 – 300 = Rs. 24
Gain % = (gain×100)/C.P.
=(24×100)/300
=8%
Question 6.
A car is marked at Rs. 50,000. The dealer gives 5% discount on first Rs. 20,000 and 2% discount on the remaining Rs. 30,000.
Find :
(i) the total discount.
(ii) the price charged by the dealer.
Answer
Marked price (M.P.) of a car = Rs. 50000
Discount at the rate of 5% on first
Rs. 20000 = Rs. (20000×5)/100
= Rs. 1000
Discount at the rate of 2% on remaining
Rs. 30000 = Rs. (30000×2)/100
= Rs. 600
(i) ∴ Total discount = Rs. 1000 + Rs. 600
= Rs. 1600
(ii) Price charged by the dealer
= Rs. 50000 – Rs. 1600 = Rs. 48400
Question 7.
A dealer buys a T.V. set for Rs. 2500. He marks it at Rs. 3,200 and then gives a discount of 10% on it.
Find :
(i) the selling price of the T.V. set
(ii) the profit percent made by the dealer.
Answer
C.P. of a T.V. set = Rs. 2500, M.P. = Rs. 3200
Rate of discount = 10%
∴ Total discount = Rs. 3200×(10/100) = Rs. 320
(i) Sellin price = Rs. 3200 – Rs. 320 = Rs. 2880
(ii) Gain = S.P. – C.P.
= Rs. 2880 – Rs. 2500 = Rs. 380
∴ Gain% = (gain×100)/C.P.
=(380×100)/2500
=76/5
=15 (1/5)%
=15.2
Question 8.
A sells his goods at 15% discount. Find the price of an article which is sold for Rs. 680.
Answer
S.P. of an article = Rs. 680
Rate of discount = 15%
Let M.P. of the article = Rs. 100
∴ S.P. = Rs. 100 – 15 = Rs. 85
If S.P. is Rs. 85, then M.P. = Rs. 100
and if S.P. is Rs. 680, then M.P.
= Rs. (100×680)/85
= Rs. 800
Question 9.
A shopkeeper allows 20% discount on the marked price of his articles. Find the marked price of an article for which he charges Rs. 560.
Answer
Let Marked price (M.P.)
= Rs. 100
Discount = 20%
∴ S.P. of that article = Rs. 100 – 20
= Rs. 80
If S.P. is Rs. 80, then marked price
= Rs. 100
and if S.P. is Rs. 560, then marked price
= Rs. (100×560)/80
= Rs. 700
Question 10.
An article is bought for Rs. 1,200 and Rs. 100 is spent on its transportation, etc.
Find :
(i) the total C.P. of the article.
(ii) the selling price of it in order to gain 20% on the whole.
Answer
C.P. of an article = Rs. 1200
Amount spent on transportation = Rs. 100
(i) Total C.P. of that article = Rs. 1200 + 100
= Rs. 1300
(ii) Gain = 20%, S.P. = (C.P.×(100+gain%))/100
= (1300×(100+20))/100
=(1300×120)/100
= Rs. 1560
Question 11.
40 pens are bought at 4 for Rs. 50 and all of them are sold at 5 for Rs. 80
Find :
(i) C.P. of one pen.
(ii) S/P. of one pen.
(iii) Profit made by selling one pen.
(iv) Profit percent made by selling one pen.
(v) C.P. of 40 pens
(vi) S.P. of 40 pens.
(vii) Profit made by selling 40 pens.
(viii) Profit percent made by selling 40 pens. Are the results of parts (iv) and (viii) same? What conclusion do you draw from the above result ?
Answer
(i) C.P. of 4 pens = Rs. 50
∴ C.P. of 40 pens = (50×40)/4
= Rs. 500
and C.P. of 1 pen = 500/40 = Rs. 25/2
= Rs. 12.50
(ii) S.P. of pens = Rs. 80
∴ S.P. of 1 pen = Rs. 80/5
= Rs. 16
(iii) Profit on one pen = S.P. – C.P.
= Rs. 16.00 – 12.50
= Rs. 3.50
(iv) Profit percent = (Profit×100)/C.P.
= (3.50×100)/12.50
=(350×100)/1250
=28%
(v) C.P. of 40 pens = 40 × 12.50
= Rs. 500
(vi) S.P. of 40 pens = 40 ×16
= Rs. 640
(vii) Profit on 40 pens
= S.P. – C.P.
= Rs. 640 – 500
= Rs. 140
(viii) Profit on 40 pens = (Profit×100)/C.P.
= (140×100)/500
=28%
Yes, the results of (iv) and (viii) are same.
We see that profit of on equal number of articles remains the same.
Question 12
The C.P. of 5 identical articles is equal to S.P. of 4 articles. Calculate the profit percent or loss percent made if all the articles bought are sold.
Answer
C.P. of 5 articles = S.P. of 4 articles
Let C.P. of 5 articles = S.P. of 4 articles
= Rs. 100
∴ C.P. of 1 articles = Rs. 100/5
= Rs. 20
and S.P. of 1 article = Rs. 1004
= Rs. 25
∴ Profit = S.P. – C.P. = Rs. 25 – Rs.. 20
= Rs. 5
∴ Profit % = (Profit×100)/C.P.
=(5×100)/20
=25%
Question 13.
The C.P. of 8 pens is same as S.P. of 10 pens. Calculate the profit or loss percent made, if all the pens bought are considered to be sold
Answer
C.P. of 8 pens = S.P. of 10 pens = Rs. 100 (suppose)
∴ C.P. of 1 pen =100/8
= Rs. 12.50
and S.P. of 1 pen = 100/10
= Rs. 10
∴ Loss = C.P. – S.P.
= Rs. 12.50 – Rs. 10 = Rs. 2.50
Loss % = (Loss×100)/C.P.
=(2.50×100)/12.50
= (250×100×100)/(1250×100)
= 20%
Question 14.
A certain number of articles are bought at Rs. 450 per dozen and all of them are sold at a profit of 20%. Find the S.P. of:
(i) one article
(ii)seven articles.
Answer
C.P. of 1 dozen articles = Rs. 450
Profit = 20%
∴ S.P. = (C.P.×(100+Profit))/100
= Rs. (450×(100+20))/100
= Rs. (450×120)/100
= Rs. 540
(i) ∴ S.P. of 1 article
= Rs. 540/12
= Rs. 45
(ii) S.P. of 7 articles = Rs. 45 × 7
= Rs. 315
Question 15.
An article is marked 60% above the cost price and sold at 20% discount. Find the profit percent made.
Answer
Let cost price of an article = Rs. 100
∴ Marked price = Rs. 100 + 60 = Rs. 160
Rate of discount = 20%
∴ S.P. = (M.P.×(100-Discount %))/100
= (160×(100-20))/100
= (160×80)/100
= Rs. 128
Profit = S.P. – C.P.
= Rs. 128 – 100 = Rs. 28
∴ Profit % = (Profit×100)/C.P.
= (28×100)/100
=28%
— End of Profit Loss and Discount Solutions :–
Return to – Concise Selina Maths Solutions for ICSE Class -7
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