Ratio and Proportion MCQs Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions Ch-8. In this article you will learn Multiple Choice Questions on Ratio and Proportion. Visit official Website **CISCE** for detail information about ICSE Board Class-6 Mathematics.

## Ratio and Proportion MCQs Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions Ch-8

Board | ICSE |

Publications | Goyal brothers Prakashan |

Subject | Maths |

Class | 6th |

Ch-8 | Ratio and Proportion |

Writer | RS Aggrawal |

Book Name | Foundation |

Topics | Solution of Exe-8C (MCQs) |

Academic Session | 2023 – 2024 |

### MCQs on Ratio and Proportion for Class 6

(Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions Ch-8)

**Que-1: The ratio 108:135 in the simplest form is **

(a) 23:27 (b) 27:25 (c) 3:5 (d) 4:5

**Sol: **(d) 4:5

**Reason: **The HCF of the numerator and denominator of 108 and 135 is 270.

= (108÷27)/(135÷27)

= 4/5.

**Que-2: If 30:42 :: 55:x, then the value of x is**

(a) 95 (b) 76 (c) 114 (d) 38

**Sol: **(b) 76

**Reason: **30/42 = 55/x

x = (55×42)/30

x = 77

**Que-3: If 30:42 :: 55:x, then the value of x is**

(a) 77 (b) 66 (c) 88 (d) 35

**Sol: **(a) 77

**Reason: **30/42 = 55/x

x = (55×42)/30

x = 77

**Que-4: If 7:9 :: x:63, then the value of x is**

(a) 42 (b) 49 (c) 35 (d) 56

**Sol: **(b) 49

**Reason: **7/9 = x/63

x = (7×63)/9

x = 49

**Que-5: If a:b :: c:d, then**

(a) ac = bd (b) ab = cd (c) ad = bc (d) none of these

**Sol: **(c) ad = bc

**Reason: **If a:b :: c:d then a/b = c/d

which can be written as b/a = d/c

ad = bc

**Que-6: 504 is divided into two parts in the ratio 5:7. The larger number is**

(a) 210 (b) 294 (c) 395 (d) none of these

**Sol: **(b) 294

**Reason: **Amount – 504

Ratio = 5:7

5x+7x = 504

12x = 504

x = 504/12

x = 42

larger number is 7x

= 7×42 = 294

**Que-7: Rs1520 is divided between A and B in the ratio 8:11. Then, A’s share is**

##### (a) Rs880 (b) Rs720 (c) Rs640 (d) Rs560

**Sol: **(c) Rs640

**Reason: **Amount – Rs1520

Ratio = 8:11

8x+11x = 1520

19x = 1520

x = 1520/19

x = 80

A’s share is 8x

= 8×80 = 640.

**Que-8: The ratio of boys and girls in a school is 13:8. If the number of girls is 840, the total strength of the school is**

(a) 1365 (b) 2730 (c) 2205 (d) 1820

**Sol: **(c) 2205

**Reason: **let the ratios be 13x and 8x

no. of girls

8x = 840

x = 840÷8

= 105

no. of girls = 840

no. of boys = 13x

= 13*105 = 1365

so,

total strength = 1365+840

= 2205 students

**Que-9: The sides of a triangle are in the ratio 1:3:5 and its perimeter is 90cm. The length of its largest side is**

(a) 36cm (b) 40cm (c) 50cm (d) 54cm

**Sol: **(c) 50cm

**Reason: **The sides of the triangle are in the ratio 1:3:5.

Let x be any number such that the sides are 1x cm, 3x cm and 5x cm.

1x + 3x + 5x = 90

⇒ 9x = 90

⇒ x = 90/9 = 10

First side = 1x = 1 × 10 = 10 cm

Second side = 3x = 3 × 10 = 30 cm

Third side = 5x = 5 × 10 = 50 cm

The length of the largest side is 50 cm.

**Que-10: To reduce a ratio a:b to its simplest form, we divide each one of a and b by**

(a) the HCF of a and b (b) the LCM of a and b (c) ab (d) none of these

**Sol: **(a) the HCF of a and b

**Reason: **The ratio a : b is said to be in the simplest form if the H.C.F. of a and b is 1. If the H.C.F. of ‘a’ and ‘b’ is not 1, then divide ‘a’ and ‘b’ by the H.C.F. of ‘a’ and ‘b’, the ratio will be reduced to the lowest form.

— : Ratio and Proportion MCQs Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions :–

**Return to :- ICSE Class -6 RS Aggarwal Goyal Brothers Math Solutions**

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