Ratio and Proportion MCQs Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions Ch-8. In this article you will learn Multiple Choice Questions on Ratio and Proportion. Visit official Website CISCE for detail information about ICSE Board Class-6 Mathematics.
Ratio and Proportion MCQs Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions Ch-8
| Board | ICSE |
| Publications | Goyal brothers Prakashan |
| Subject | Maths |
| Class | 6th |
| Ch-8 | Ratio and Proportion |
| Writer | RS Aggrawal |
| Book Name | Foundation |
| Topics | Solution of Exe-8C (MCQs) |
| Academic Session | 2023 – 2024 |
MCQs on Ratio and Proportion for Class 6
(Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions Ch-8)
Que-1: The ratio 108:135 in the simplest form is
(a) 23:27 (b) 27:25 (c) 3:5 (d) 4:5
Sol: (d) 4:5
Reason: The HCF of the numerator and denominator of 108 and 135 is 270.
= (108÷27)/(135÷27)
= 4/5.
Que-2: If 30:42 :: 55:x, then the value of x is
(a) 95 (b) 76 (c) 114 (d) 38
Sol: (b) 76
Reason: 30/42 = 55/x
x = (55×42)/30
x = 77
Que-3: If 30:42 :: 55:x, then the value of x is
(a) 77 (b) 66 (c) 88 (d) 35
Sol: (a) 77
Reason: 30/42 = 55/x
x = (55×42)/30
x = 77
Que-4: If 7:9 :: x:63, then the value of x is
(a) 42 (b) 49 (c) 35 (d) 56
Sol: (b) 49
Reason: 7/9 = x/63
x = (7×63)/9
x = 49
Que-5: If a:b :: c:d, then
(a) ac = bd (b) ab = cd (c) ad = bc (d) none of these
Sol: (c) ad = bc
Reason: If a:b :: c:d then a/b = c/d
which can be written as b/a = d/c
ad = bc
Que-6: 504 is divided into two parts in the ratio 5:7. The larger number is
(a) 210 (b) 294 (c) 395 (d) none of these
Sol: (b) 294
Reason: Amount – 504
Ratio = 5:7
5x+7x = 504
12x = 504
x = 504/12
x = 42
larger number is 7x
= 7×42 = 294
Que-7: Rs1520 is divided between A and B in the ratio 8:11. Then, A’s share is
(a) Rs880 (b) Rs720 (c) Rs640 (d) Rs560
Sol: (c) Rs640
Reason: Amount – Rs1520
Ratio = 8:11
8x+11x = 1520
19x = 1520
x = 1520/19
x = 80
A’s share is 8x
= 8×80 = 640.
Que-8: The ratio of boys and girls in a school is 13:8. If the number of girls is 840, the total strength of the school is
(a) 1365 (b) 2730 (c) 2205 (d) 1820
Sol: (c) 2205
Reason: let the ratios be 13x and 8x
no. of girls
8x = 840
x = 840÷8
= 105
no. of girls = 840
no. of boys = 13x
= 13*105 = 1365
so,
total strength = 1365+840
= 2205 students
Que-9: The sides of a triangle are in the ratio 1:3:5 and its perimeter is 90cm. The length of its largest side is
(a) 36cm (b) 40cm (c) 50cm (d) 54cm
Sol: (c) 50cm
Reason: The sides of the triangle are in the ratio 1:3:5.
Let x be any number such that the sides are 1x cm, 3x cm and 5x cm.
1x + 3x + 5x = 90
⇒ 9x = 90
⇒ x = 90/9 = 10
First side = 1x = 1 × 10 = 10 cm
Second side = 3x = 3 × 10 = 30 cm
Third side = 5x = 5 × 10 = 50 cm
The length of the largest side is 50 cm.
Que-10: To reduce a ratio a:b to its simplest form, we divide each one of a and b by
(a) the HCF of a and b (b) the LCM of a and b (c) ab (d) none of these
Sol: (a) the HCF of a and b
Reason: The ratio a : b is said to be in the simplest form if the H.C.F. of a and b is 1. If the H.C.F. of ‘a’ and ‘b’ is not 1, then divide ‘a’ and ‘b’ by the H.C.F. of ‘a’ and ‘b’, the ratio will be reduced to the lowest form.
— : Ratio and Proportion MCQs Class 6 RS Aggarwal Exe-8C Goyal Brothers ICSE Maths Solutions :–
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