# RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers

RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers Prakashan Solutions Chapter-19. We provide step by step Solutions of Exercise / lesson-19 Volume And Surface Area of Solids for ICSE Class-9 RS Aggarwal Mathematics .

Our Solutions contain all type Questions with Exe-19 and Notes on Volume And Surface Area of Solids to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-9 Mathematics.

## RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers Prakashan Chapter-19

– : Select Topics : –

Notes on  Volume of Solids

Exercise 19

### Notes on  Volume of Solids

#### Volume Formulas of Solid Figures

Some of the formulas to find out volumes of basic shapes are –

Shapes Volume Formula Variables
Rectangular Solid or Cuboid V = l × w × h l = Length,

w = Width,

h = Height

Cube V = a3 a = length of edge or side
Cylinder V = πr2h r = radius of the circular edge,

h = height

Prism V = B × h B = area of base, (B = side2 or length.breadth)

h = height

Sphere V = (4⁄3)πr3 r = radius of the sphere
Pyramid V = (1⁄3) × B × h B = area of the base,

h = height of the pyramid

Right Circular Cone V = (1⁄3)πr2h r = radius of the circular base,

h = height (base to tip)

### Exercise 19 , RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers Prakashan

Question-1

Find the volume and total surface area and the lateral surface area of a rectangular solid having :

(i) Length =8.5 m, breadth = 6.4 m and height = 50 cm.

(ii) Length =5.6 dm, breadth = 2.5 dm and height = 1 m.

(i) Length =8.5 m, breadth = 6.4 m and height = 50 cm = 0.5 m

(a) Volume = l x b x h

=  8.5 m, x 6.4 m x  0.5 m

= 27.2 m³

Now perimeter of cross section of the tunnel

= 8 + 2.6 + 2.6 + 6

= 19.2 m

length = 40 m

internal surface area of of the tunnel excluding floor

=19.2 x 40 -40 x 8

= 768 – 320

=448 m²

Rate of painting = 5 Rs / m2

So Total cost of painting

= 5 x 448

= Rs 2240  ans

–: End of RS Aggarwal Class-9 Volume And Surface Area of Solids Solutions  :–

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