RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers
RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers Prakashan Solutions Chapter-19. We provide step by step Solutions of Exercise / lesson-19 Volume And Surface Area of Solids for ICSE Class-9 RS Aggarwal Mathematics .
Our Solutions contain all type Questions with Exe-19 and Notes on Volume And Surface Area of Solids to develop skill and confidence. Visit official Website CISCE for detail information about ICSE Board Class-9 Mathematics.
RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers Prakashan Chapter-19
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Notes on Volume of Solids
Volume Formulas of Solid Figures
Some of the formulas to find out volumes of basic shapes are –
| Shapes | Volume Formula | Variables |
|---|---|---|
| Rectangular Solid or Cuboid | V = l × w × h | l = Length,
w = Width, h = Height |
| Cube | V = a3 | a = length of edge or side |
| Cylinder | V = πr2h | r = radius of the circular edge,
h = height |
| Prism | V = B × h | B = area of base, (B = side2 or length.breadth)
h = height |
| Sphere | V = (4⁄3)πr3 | r = radius of the sphere |
| Pyramid | V = (1⁄3) × B × h | B = area of the base,
h = height of the pyramid |
| Right Circular Cone | V = (1⁄3)πr2h | r = radius of the circular base,
h = height (base to tip) |
Exercise 19 , RS Aggarwal Class-9 Volume And Surface Area of Solids ICSE Goyal Brothers Prakashan
Question-1
Find the volume and total surface area and the lateral surface area of a rectangular solid having :
(i) Length =8.5 m, breadth = 6.4 m and height = 50 cm.
(ii) Length =5.6 dm, breadth = 2.5 dm and height = 1 m.
Answer-1
(i) Length =8.5 m, breadth = 6.4 m and height = 50 cm = 0.5 m
(a) Volume = l x b x h
= 8.5 m, x 6.4 m x 0.5 m
= 27.2 m³
Now perimeter of cross section of the tunnel
= 8 + 2.6 + 2.6 + 6
= 19.2 m
length = 40 m
internal surface area of of the tunnel excluding floor
=19.2 x 40 -40 x 8
= 768 – 320
=448 m²
Rate of painting = 5 Rs / m2
So Total cost of painting
= 5 x 448
= Rs 2240 ans
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