Absorption by Roots ICSE Class-10 Concise Selina Biology Solutions Chapter-4. We Provide Step by Step Answer of Progress Check 1, 2, 3, 4 , MCQs, Very Short Answer Type, Short Answer Type, Long Answer Type Questions and Structured / Applications / Skill Type Questions of Exercise-4 Absorption by Roots. Visit official Website CISCE for detail information about ICSE Board Class-10.
| Board | ICSE |
| Publications | Selina Publishers PVT LTD |
| Subject | Concise Biology |
| Class | 10th |
| writer | HS Vishnoi |
| Chapter-4 | Absorption by roots |
| Topics | Solutions of MCQs, Very Short ,Descriptive and Structural/Skill Questions and Progress Check 1, 2, 3, 4, |
| Edition | 2021-2022 |
Absorption by Roots ICSE Class-10 Concise Selina Biology Solutions Chapter-4
-: Select Topics :-
A-MULTIPLE CHOICE TYPE
B. VERY SHORT ANSWER TYPE
C. SHORT ANSWER TYPE
D. DESCRIPTIVE ANSWER TYPE
E. STRUCTURED/APPLICATION/SKILL TYPE
A. MULTIPLE CHOICE TYPE
Absorption by Roots ICSE Class-10 Concise Selina Biology Solutions
Page 51
Question 1
Absorption of water by the plant cells by surface attraction is called:
a) Diffusion
b) Osmosis
c) Imbibition
d) Endosmosis
Answer 1
Question 2
A plant cell placed in a certain solution got plasmolysed. What was the kind of solution?
a) Isotonic sugar solution
b) Hypotonic salt solution
c) Hypertonic salt solution
d) Isotonic salt solution
Answer 2
Question 3
The state of a cell in which the cell wall is rigid and stretched by the increase in volume due to the absorption of water is called
a) Flaccidity
b) Turgidity
c) Capillarity
d) Tonicity
Answer 3
Question 4
Which one of the following is a characteristic NOT related with the suitability of the roots for absorbing water?
a) Tremendous surface area
b) Contain cell sap at higher concentration than the surrounding water
c) Root hairs have thin cell walls
d) Grow downward into the soil
Answer 4
Question 5
Movement of molecules of a substance from the region of their higher concentration to the region of their lower concentration without the involvement of a separating membrane, is called:
a) Osmosis
b) Diffusion
c) Active transport
d) Capillarity
Answer 5
Question 6
Osmosis and diffusion are the same except that in osmosis there is
a) a freely permeable membrane
b) a cell wall in between
c) a selectively permeable membrane in between
d) an endless inflow of water into a cell
Answer 6
c) a selectively permeable membrane in between
Question 7
The highest water potential (capacity to move out to higher concentrated solution) is that of
a) Pure water
b) 10% salt solution
c) Honey
d) 50% sugar solution
Answer 7
Question 8
The space between the cell wall and plasma membrane in a plasmolysed cell is filled with
a) isotonic solution
b) hypotonic solution
c) hypertonic solution
d) water
Answer 8
Question 9
What is responsible for guttation?
a) Osmotic pressure
b) Root pressure
c) Suction pressure
d) Capillarity
Answer 9
Question 10
The most appropriate characteristic of semi-permeable membrane is that
a) it has minute pores
b) it has no pores
c) it allows the solute to pass through but not the solvent
d) it allows a solvent to pass through freely but prevents the passage of the solute
Answer 10
.
B. VERY SHORT ANSWER TYPE
Absorption by Roots ICSE Class-10 Concise Selina Biology Solutions
Page 51-52
Question 1
Name the following:
(a) The condition of a cell placed in a hypotonic solution.
(b) Process by which intact plants lose water in the form of droplets from leaf margins.
(c) Process by which water enters root hairs.
(d) The tissue concerned with upward conduction of water in plants.
(e) The term for the inward movement of solvent molecules through the plasma membrane of a cell.
(f) The process by which molecules distribute themselves evenly within the space they occupy.
(g) The pressure which is responsible for the movement of water molecules across the cortical cells of the root.
Answer 1
(a) Turgidity
(b) Guttation
(c) Osmosis
(d) Xylem
(e) Endosmosis
(f) Diffusion
(g) Root pressure
Question 2
Give the equivalent terms for the following:
(a) Pressure exerted by the cell contents on the cell wall.
(b) The condition in which the cell contents are shrunken.
(c) Loss of water through a cut stem.
Answer 2
(a) Turgor pressure
(b) Flaccidity
(c) Bleeding
Question 3
Complete the following statements:
(a) Hypotonic solution is one in which the solution kept outside the cell has lower solute concentration than __________ the cell.
(b) Active transport is one in which the ions outside the roots move in with expenditure of energy __________.
(c) The bending movements of certain flowers towards the sun and the sleep movements of certain plants at night are examples of _____.
Answer 3
(a) the fluids inside
(b) from the region of their lower concentration outside to the region of their higher concentration inside
(c) turgor movements
Question 4
Fill in the blanks by choosing the correct alternative from those given in brackets:
(a) When placed in a more concentrated solution, the cell contents will ……….. (shrink/swell up)
(b) The pressure by which the …………. molecules tend to cross the semi-permeable membrane is called osmotic pressure. (salt/water)
(c) Active transport is in a direction ………….. to that of diffusion. (opposite/same)
Answer 4
(a) shrink
(b) water
(c) opposite
Question 5
Match the terms in column I those in column II
| Column I | Column II | |
| a | Xylem | (i) semi-permeable |
| b | Phloem | (ii) permeable |
| c | Cell membrane | (iii) downward flow of sap |
| d | Root pressure | (iv) upward flow of water |
| e | Cell wall | (v) guttation |
Answer 5
| Column I | Column II | |
| a | Xylem | (iv) upward flow of water |
| b | Phloem | (iii) downward flow of sap |
| c | Cell membrane | (i) semi-permeable |
| d | Root pressure | (v) guttation |
| e | Cell wall | (ii) permeable |
C. SHORT ANSWER TYPE
Absorption by Roots ICSE Class-10 Concise Selina Biology Solutions
Page 52
Question 1
Differentiate between the following :
(a) Plasmolysis and deplasmolysis
(b) Turgor pressure and wall pressure
(c) Hypotonic and hypertonic Solution
(d) Turgidity and flaccidity
Answer 1
(a)
| Plasmolysis | Deplasmolysis |
| 1. It refers to the shrinkage of the cytoplasm and withdrawal of the plasma membrane from the cell wall caused due to the withdrawal of water when placed in a hypertonic solution.
2. In Plasmolysis, the cell becomes flaccid. |
1. Deplasmolysis is the recovery of a plasmolysed cell when it is placed in water, wherein the cell’s protoplasm again swells up due to the re-entry of water.
2. In deplasmolysis, the cell becomes turgid. |
(b)
| Turgor pressure | Wall pressure |
| Turgor pressure is the pressure of the cell contents on the cell wall. | Wall pressure is the pressure exerted by the cell wall on the cell content. |
(c)
| Hypotonic | hypertonic |
| A hypotonic solution is one in which the solution kept outside the cell has lower solute concentration than the fluids inside the cell. | In a hypertonic solution, the solution outside the cell has higher solute concentration than the fluids inside the cell. Therefore, water flows out from the plant cell due to exosmosis. |
| Turgidity | Flaccidity |
| 1. It is the state of a cell in which the cell cannot accommodate any more water and it is fully distended. | 1. It is the condition in which the cell content is shrunken and the cell is not tight. |
Question 2
Mention whether the following statements are true or false. Correct the false statements by alternating the last word only.
(i) Addition of salt to pickles prevents growth of bacteria because they turn turgid.
(ii) Cells that have lost their water content are said to be deplasmolysed.
(iii) Xylem is the water conducting tissue in plants.
(iv) The protoplasm shrinks, when a cell is kept in hypertonic solution.
(v) The cell wall of the root cell is a differently permeable membrane.
Answer 2
(A) Mention whether the folllowing statemts are true or false.
(i) Addition of salt to picles prevents growth of bacteria because they turn turgid. (False)
(ii) Cells that have lost their water content are said to be deplasmolysed. (True)
(iii) Xylem is the water conducting tissue in plants. (True)
(iv) The protoplasm shrinks, when a cell is kept in hypertonic solution. (False)
(v) The cell wall of the root cell is a differiantlly permeable membrane. (False)
Correct the false statements by alternating the last word only.
(i) Addition of salt to picles prevents growth of bacteria because they turn Flacid.
(ii) Cells that have lost their water content are said to be deplasmolysed.
(iii) Xylem is the water conducting tissue in plants.
(iv) The protoplasm shrinks, when a cell is kept in not hypertonic solution. (False)
(v) The cell wall of the root cell is a total permeable membrane.
Question 3
Mention whether the following statements are true (T) or false (F) and give explanation in support of your answer.
(a) Guttation is another name for bleeding in plants.
(b) Soaked seeds burst three seed coats
(c) If the phloem of a twig is removed keeping the xylem intact, the leaves of a twig wilt.
(d) Guttation in plants occurs maximum at mid-day.
(e) Raisins when submerged in water swell up due to endosmosis.
Answer 3
(a) False.
Guttation is the process by which drops of water appear along leaf margins due to excessive root pressure whereas bleeding is the loss of cell sap through a cut stem.
(b) False.
There is only one seed coat in a seed.
(c) False.
The leaves of the twig remain turgid since its xylem is intact and xylem is responsible for water conduction in plants.
(d) False.
Guttation occurs due to excessive root pressure. It is maximum when root pressure is maximum which occurs in the early mornings or at night. This is because during these times, transpiration is very low and water absorption is very high.
(e) False.
D. DESCRIPTIVE ANSWER TYPE
Absorption by Roots ICSE Class-10 Concise Selina Biology Solutions
Page 52
Question 1
Answer 1
Examples of turgor movements in plants:
(i) In Mimosa pudica, a sensitive plant, the stimulus of touch leads to loss of turgor at the base of the leaflets and at the base of the petioles called pulvinus. This causes the folding and drooping of leaves of the plant.
(ii) The leaves of insectivorous plants close up to entrap a living prey. When the insect come in contact with the leaf, it loses it turgor hence closing the leaves of the plant.
(iii) The bending movements of certain flowers towards the sun.
(Any two)
Question 2
Define the following terms :
(a) Imbibition
(b) Diffusion
(c) Osmosis
(d) Osmotic Pressure
(e) Active transport
(f) Tonicity
(g) Root pressure
Answer 2 :
(a) Imbibition : The absorption of one substance by another, in particular the uptake of water by a plant or seed.
(b) Diffusion : Diffusion is the process of movement of molecules under a concentration gradient. It is an important process occurring in all living beings. Diffusion helps in the movement of substances in and out of the cells.
(c) Osmosis : Osmosis is a passive process and happens without any expenditure of energy. It involves the movement of molecules from a region of higher concentration to lower concentration until the concentrations become equal on either side of the membrane.
(d) Osmotic Pressure : The pressure that must be applied to the solution side to stop fluid movement when a semipermeable membrane separates a solution from pure water.
(e) Active transport : Active transport is a kind of cellular transport where substances move against a concentration gradient. This means that the direction is from an area of lower concentration to an area of higher concentration.
(f) Tonicity : Tonicity describes how an extracellular solution can change the volume of a cell by affecting osmosis. A solution’s tonicity often directly correlates with the osmolarity of the solution. Osmolarity describes the total solute concentration of the solution.
(g) Root pressure : Root pressure, in plants, force that helps to drive fluids upward into the water-conducting vessels (xylem). It is primarily generated by osmotic pressure in the cells of the roots and can be demonstrated by exudation of fluid when the stem is cut off just aboveground.
Question 3
Give the reason for the following :
(a) If you sprinkle some common salt on grass growing on a lawn, it is killed at that spot.
(b) If you uproot a plant from the soil, its leaves soon wilt.
(c) It is better to transplant seedlings in a flower-bed in the evening and not in the morning.
(d) A plant cell when kept in a hypertonic salt solution for about 30 minutes turns flaccid.
(e) Potato cubes when placed in water become firm and increase in size.
Answer 3 :
(a) When a plant cell is placed in a hypertonic solution, the water which is inside the cell’s cytoplasm diffuses out of it and as a result of that, the plant cell becomes flaccid.
(b) If a plant is uprooted, the leaves continue losing water by transpiration, but there is no chance for absorbing water through the roots. This does not allow the compensation for the loss of water by transpiration, hence the leaves of the uprooted plant wilt soon.
(c) Transplantation causes stress to the seedlings. If the seedlings are transplanted in the morning, they would have to immediately bear the additional stress of excessive transpiration occurring during the hot afternoon. Transplantation in the evening helps the seedlings to adjust for a longer time during the night (cooler temperatures) because the quantity of water absorbed exceeds the loss of water through transpiration. Therefore, it is better to transplant seedling in a flower bed in the evening and not in the morning.
(d) In a hypertonic solution, the solution outside the cell has higher solute concentration than the fluids inside the cell. Therefore, water flows out from the plant cell due to exosmosises. The cytoplasm shrinks and the plasma membrane withdraws away from the cell wall and this the cell becomes flaccid. Hence a plant cell when kept in a hypertonic salt solution for about 30 minutes turns flaccid.
(e) The potato cell has cell sap more in concentration inside the cell than in the surrounding water. So due to this, endosmosis occurs which results in the transfer of water molecule: that is solvent from lower concentration to the higher concentration, this result in making the cell firm. Due to the flow of water in the cell, they become turgid and the cubes become firm and increase in size.
Question 4
Answer 4
The closing and opening of the stomata depends on the turgidity of the guard cells. Each guard cell has a thicker wall on the side facing the stoma and a thin wall on the opposite side. Guard cells contain chloroplasts. As a result of the synthesis of glucose during photosynthesis and some other chemical changes, the osmotic pressure of the contents of the guard cells increases and they absorb more water from the neighbouring cells, thus becoming turgid. Due to turgor, the guard cells become more arched outwards and the aperture between them widens, thereby opening the stoma.
At night or when there is shortage of water in the leaf, the guard cells turn flaccid and their inner rigid walls become straight, thus closing the stomatal aperture.
Question 5
Answer 5
As water is lost from the leaf surface by transpiration, more water molecules are pulled up due to the tendency of water molecules to remain joined i.e. cohesion. This produces a continuous column of water throughout the stem which is known as ‘transpiration pull’. A negative pressure or tension is produced in the xylem that pulls the water from the roots and soil. Transpirational pull is an important force which causes the ascent of sap.
E. STRUCTURED / APPLICATION / SKILL TYPE
Absorption by Roots ICSE Class-10 Concise Selina Biology Solutions
Page 52-54
Question 1
A leaf cell of a water plant was placed in a liquid other than pond water. After sometime, it assumed a shape as shown below:
(a) Give the term for the state of the cell it has acquired.
(b) Name the structure which acts as a selectively permeable membrane.
(c) Comment on the nature (tonicity) of the liquid surrounding the cell.
(d) Name any one feature of this plant cell which is not present in an animal cell.
(e) Redraw in the space provided, the diagram of the cell if it is soon placed in ordinary water for some time.
Answer 1
(a) Flaccid Cell
(b) Cell membrane
(c) The liquid is hypertonic solution. It has higher solute concentration outside the cell than the fluids inside the cell.
(d) Chloroplast is only present in a plant cell not in an animal cell
(e)
Question 2
The diagram given below represents an experimental set-up to demonstrate a certain process. Study the same and answer the questions that follow:
(a) Name the process.
(b) Define the above-named process.
(c) What would you observe in the experimental set-up for comparison?
(d) What control experiment can be set up for comparison
(e) Keeping in mind the root -hair ,cell and its surroundings,name the parts that correspond to (1) concentrated sugar solution (2) parchment paper and (3) water in the beaker.
(f) Name any other substance that can be used instead of parchment paper in the above experiment.
(g) Mention two advantage of the process to the plants.
Answer 2
(a) Osmosis
(b) Movement of molecules from lower concentration of higher concentration.
(c) Level of sugar solution increase.
(d) Level of sugar solution increase.
(e) (i) Root cell Sap
(ii) Cell membrane.
(iii) Water in soil.
(f) Cellophane paper.
(g) Plant absorb root water.
Question 3
The diagram below represents a layer of epidermal cells showing a fully grown root hair. Study the diagram and answer the questions that follow:
(a) Name the parts labelled A, B, C and D.
(b) The root hair cell is in a turgid state. Name and explain the process that caused this state.
(c) Mention one distinct difference between the parts labelled A and B.
(d) Draw a diagram of the above root hair cell as it would appear when a concentrated solution of fertilizers is added near it.
Answer 3
(a)
A – Cell wall
B – Cell membrane
C – Cytoplasm
D – Nucleus
(b)
A root hair gets turgid because of the absorption of water from the surrounding. Absorption of water by root hair is achieved by the process of osmosis. The concentration of water in the surrounding is more than that of the interior of the cell; this causes the water from the surrounding to move in because of endosmosis.
(c)
| Cell wall | Cell membrane |
| The cell wall of a root hair is freely permeable and allows both salt and water to pass through. | The cell membrane of a root hair is semi-permeable and does not allow large dissolved salt molecules to pass through. |
(d)
Question 4
Study the diagram given below and answer the questions that follow:
(a) Name the process being studied in the above experiment.
(b) Explain the process mentioned in (a) above
(c) Why is oil placed over water?
(d) What do we observe with regard to the level of water when this set up is placed in (1) bright sunlight (2) humid conditions (3) windy day?
(e) Mention any three adaptations found in plants to foster the process mentioned in (a) above
Answer 4
(a) The process of water absorption by plant roots through osmosis is being studied here.
(b) A root-hair contains cell sap which contains higher concentration of salts as compared to outside soil water. This difference sets off osmosis and outside water diffuses into the root-hair. From the cell bearing root-hair, water passes into adjoining cells one after another to finally the xylem vessels.
(c) The surface of water was covered with oil to prevent any loss of water by evaporation.
(d) Roots absorb water and hence, the level of water in set up A falls down. Since the surface of water was covered with oil, there will be no effect of factors such as bright sunlight, humid conditions and windy day on the given set up. Hence, the level of water
(e) Adaptations in plants to foster the process of absorption of water by plant roots:
- Large surface area provided by rootlets and root hairs
- Root hairs containing cell sap at a higher concentration than that of the surrounding water
- Root hairs with thin walls
Question 5
Three cylinder of of potato were carefully dried on a blotting paper and weighed. Each piece weighed 3 grams. Each one was placed in the beaker as shown below :
Answer the following question :
(a) After 48 hours, which potato cylinder would be the heaviest ?
(b) The movement of ………….. in the potato cylinders ?
(c) Name and define the process …………….. mentioned in answer (b)
(d) Write specific names ……… defined in answer (c).
(e) Would there be any difference in the …………… Give reason.
Answer 5 :
(a) Cylinder B: In distilled water.
(b) When the potato cube is placed in water, the water starts entering the potato cube thus causing an increase in its size and due to pressure of cell contents on the cell wall, there appears a firmness in the wall of the cube.
(c) The physical process which is responsible for the movement of substance mentioned in answer (b) is osmosis. Osmosis is the movement of water molecules from their region of higher concentration to their region of lower concentration through a semi-permeable membrane.
(d) The process that takes place in beaker B is osmosis, which is diffusion of water across the membrane of the potato slice cells. Plasmolysis occurs in beaker C as the potato shrinks due to hypotonic solution of 20% sucrose solution.
(e) The weight of the potato cylinder in beaker A will be less as compared to initial phase after 48 hours due to loss of water to the surroundings through plasmolysis.
Question 6
The figure given below is a diagrammatic representation of a part of the cross-section of the root in the root hair zone. Study the same and then answer the questions that follow :
(a) Name the part indicated by guidelines 1 to 5
(b) Is the root hair cell unicellular or multicellular ?
(c) Explain what would ………….. soil close to it.
(d) Name the process responsible ……………. and then into A2.
(e) What pressure is responsible ……………… by arrows ?
(f) How is this pressure set up ?
Answer 6:
(a)
1. Vacuole (containing cell sap)
2. Soil particles
3. Xylem vessel
4. Cortex cells
5. Vacuole in cortical cells
(b) Root hair cell is unicellular
(c) See diagram alongside.
(d) Osmosis
(e) Osmotic pressure
(f) This pressure is set up due to difference in osmotic gradient.
Question 7
Show by a series of diagrams, the change which a plant cell will undergo when placed in
(a) Hypertonic salt solution and
(b) Hypotonic salt solution.
Answer 7
Question 7
Study the experimental setup in the figure and then answer the questions that follow.
(a) What phenomenon is being studied by this setup?
(b) Explain the phenomenon mention in (a) above.
(c) What is meant by ‘semipermeable membrane’?
(d) What will you observe in the setup after about half an hour? Give reasons for your answer.
Answer 7
(a) Osmosis
(b) Osmosis is the movement of water molecules from their region of higher concentration (dilute solution) to their region of lower concentration (concentrated solution) through a semipermeable membrane.
(c) A semipermeable membrane is a membrane which allows the passage of molecules selectively. It allows a solvent such as water molecules to pass through it freely but prevents the passage of the solute (sugar or salt molecules in solution).
(d) Water molecules will continue to pass from 5% sucrose solution to 10% sucrose solution through the semipermeable membrane due to osmosis. This will continue till the concentration of water molecules becomes the same in both ends of the setup.
Question 8
A candidate in order to study the process of osmosis has taken 3 potato cubes and put them in 3 different beakers containing 3 different solutions. After 24 hours, in the first beaker the potato cube increased in size, in the second beaker the potato cube decreased in size and in the third beaker, there was no change in the size of the potato cube. The following diagram shows the result of the same experiment.
(a) Give the technical terms of the solutions used in the beakers 1, 2 and 3.
(b) In beaker 3, the size of the potato cube remains the same. Explain the reason in brief.
(c) Write the specific features of the cell sap of root hair which helps in absorption of water.
(d) What is osmosis?
(e) How does a cell wall and a cell membrane differ in their permeability?
Answer 8
(a) Solution 1 – The Hypotonic solution
and Solution 2 – It Hyper tonic solution
while Solution 3 – An Isotonic solution
(b) In beaker 3, the solution present is an isotonic solution, i.e. the relative concentration of water molecules and solutes is the same in the solution as well as inside the cell. There is no movement of water molecules across the cell membrane. Hence, the size of potato cubes remains the same.
(c) The cell sap of root hair has a higher concentration of solute than the surrounding water.
(d) Osmosis is the diffusion of water molecules across a semi-permeable membrane from the region of dilute solution (i.e. a lower solute concentration) to the region of concentrated solution (i.e. a higher solute concentration).
(e) The cell wall is freely permeable to all substances, while the cell membrane is selectively permeable and allows only certain substances to enter or exit the cell.
Return to Concise Selina ICSE Biology Class-10
Thanks
