Banking Class 10 OP Malhotra Exe-2 ICSE Maths Solutions Ch-2. We Provide Step by Step Solutions / Answer of Exe-2 Banking of S Chand OP Malhotra Maths . Visit official Website CISCE for detail information about ICSE Board Class-10 Mathematics.
Banking Class 10 OP Malhotra Exe-2 ICSE Maths Solutions Ch-2
| Board | ICSE |
| Publications | S Chand |
| Subject | Maths |
| Class | 10th |
| Chapter-2 | Banking |
| Writer | OP Malhotra |
| Exe-2 | Solved Questions on Banking |
| Edition | 2024-2025 |
Practice Questions on Banking
Banking Class 10 OP Malhotra Exe-2 ICSE Maths S Chand Solutions Ch-2
Exe-2
Que-1: Mr. Rajiv Anand has opened a recurring deposit account of Rs. 400 per month for 20 month in a bank. Find the amount he will get at the tie of maturity, if the rate of interest is 8.5% p. a., if the interest is calculated at the end of each month.
Sol: From the question, we have P = Rs. 400, n = 20 months, r = 8.5%.
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ SI = 400 x 20 x (20 + 1) x 8.5 / 2400
⇒ SI = 595
Thus, the maturity value is MV = Pn + SI
= (400 x 20) + 595
= Rs. 8595
Que-2: Mr. Savita Khosla deposits Rs 900 per month in a recurring account for 2 years. If she gets Rs. 1800 as interest at the time of maturity, find the rate of interest if the interest is calculated at the end of each month.
Sol: From the question, we have P = Rs. 900, n = 24 months, SI = Rs. 1800
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ 1800 = 900 x 24 x (24 + 1) x r / 2400
⇒ r = 8
Thus, the required rate of interest is 8% p.a.
Que-3: Mr. Brown deposits Rs. 1100 per month in a cumulative time deposit account in a bank for 16 months. If at the end of maturity he gets Rs. 19096, find the rate of interest if interest is calculated at the end of each month.
Sol: From the question, we have P = Rs. 1100, n = 16 months, MV = 19096,
So, SI = MV – Pn =
19096 – (1100 x 16)
= Rs. 1496
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ 1496 = 1100 x 16 x (16 + 1) x r / 2400
⇒ r = 12
Thus, the required rate of interest is 12% p.a.
Que-4: Sandhya has a recurring deposit account in Vijaya Bank and deposits Rs 400 per month for 3 years. If she gets Rs 16176 on maturity, find the rate of interest given by the bank.
Sol: From the question, we have P = Rs. 400, n = 36 months, MV = 16176,
So, SI = MV – Pn
= 16176 – (400 x 36)
= Rs. 1777
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ 1777 = 400 x 36 x (36 + 1) x r / 2400
⇒ r = 8
Thus, the required rate of interest is 8% p.a.
Que-5: A man deposits Rs 600 per month in a bank for 12 months under the Recurring Deposit Scheme. What will be the maturity value of his deposits if the rate of interest is 8 % p.a. and interest is calculated at the end of every month?
Sol: From the question, we have P = Rs. 600, n = 12 months, r = 8%.
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ SI = 600 x 12 x (12 + 1) x 8 / 2400
⇒ SI = 312
Thus, the maturity value is MV = Pn + SI
= (600 x 12) + 312
= Rs. 7512
Que-6: Anil deposits Rs 300 per month in a recurring deposit account for 2 years. If the rate of interest is 10% per year, calculate the amount that Anil will receive at the end of 2 years, i.e at the time of maturity.
Sol: From the question, we have P = Rs. 300, n = 24 months, r = 10%.
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ SI = 300 x 24 x (24 + 1) x 10 / 2400
⇒ SI = 750
Thus, the maturity value is MV = Pn + SI
= (300 x 24) + 750
= Rs. 7950
Que-7: Sudhir opened a recurring deposit account with a bank for 1 ½ years. If the rate of interest is 10% and the bank pays Rs 1554 on maturity, find how much did Sudhir deposit per month?
Sol: From the question, we have n = 18 months, r = 10%, MV = Rs. 1554
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ SI = P x 18 x (18 + 1) x 10 / 2400
⇒ SI = 57P/40
Since the maturity value is MV = Pn + SI
⇒ 1554 = 18P + 57P/40
⇒ P = Rs. 80 per month.
Que-8: Renu has a cumulative deposit account of Rs. 200 per month at 10% per annum. If she gets Rs 6775 at the time of maturity, find the total time for which the account was held.
Sol: From the question, we have P = Rs. 200, r = 10%, MV = Rs. 6775
Putting these values in SI formula, we get
SI = Pn(n + 1)r/2400
⇒ SI = 200 x n(n + 1) x 10 / 2400
⇒ SI = 5n(n + 1)/6
Since the maturity value is MV = Pn + SI
⇒ 6775 = 200n + 5n(n + 1)/6
⇒ n2 + 241n – 8130 = 0
⇒ (n – 30)(n + 271) = 0
⇒ n = 30 months = 2*(1/2) years.
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